My daughter has been struggling with the loop rules until your video appeared, she immediately had smiles on her face she have understanding now thank you so much
As a electrical engineering all I can say is good explanation of this topic.These videos are a good thing for remembering small stuff I learned in first years in my university. Do you have in plan maybe making a video of solving a circuit same as last one but this time including inductors and capacitors???
This is the second UA-cam tutorial I’ve seen that says current flows out of the positive terminal of a power source. In the case of two batteries in series, the current will flow out of the negative terminal of the battery with the highest voltage and flow into the negative terminal of the battery with the lower voltage. This is why you need a 14 volt source to charge a 12 volt car battery.
Current flowing out of the positive terminal is called conventional current. Current flowing out of the negative terminal is called electron current. Electron current is obviously what actually happens but conventional current is the standard that most of the world follows.
Can you pls make a video on transistors and capacitor and all other electronic devices and also their calculations, and thank you for helping me for my education , God bless you
If our direction of journey and current is in same direction so it will be negative voltage if our direction of journey and current is opposite so voltage is positive 🙂🙂
At 6:52 you can see 18V - (90Ω)I = 0 Using algebra, we subtract 18V from both sides to get - 90(Ω)I = -18V Divide both sides by -90Ω to get I = -18V/-90Ω Put that into a calculator (-18/-90) and you get .2 A
My daughter has been struggling with the loop rules until your video appeared, she immediately had smiles on her face she have understanding now thank you so much
Same to u also
As a electrical engineering all I can say is good explanation of this topic.These videos are a good thing for remembering small stuff I learned in first years in my university. Do you have in plan maybe making a video of solving a circuit same as last one but this time including inductors and capacitors???
This is the second UA-cam tutorial I’ve seen that says current flows out of the positive terminal of a power source. In the case of two batteries in series, the current will flow out of the negative terminal of the battery with the highest voltage and flow into the negative terminal of the battery with the lower voltage. This is why you need a 14 volt source to charge a 12 volt car battery.
Current flowing out of the positive terminal is called conventional current. Current flowing out of the negative terminal is called electron current. Electron current is obviously what actually happens but conventional current is the standard that most of the world follows.
Excellent work
Can you pls make a video on transistors and capacitor and all other electronic devices and also their calculations, and thank you for helping me for my education , God bless you
Please make a video where are solving complex series and parrallel circuit
Hi there, I really like your presentation, clear and concise. I learned a lot from this video.
Glad you liked it di do :)
Thanks Chris... U are a genius
i apreciate your work
Why isn’t +I(40)oms at 5:46
Why the voltages changes over the resitors are negative?
If our direction of journey and current is in same direction so it will be negative voltage if our direction of journey and current is opposite so voltage is positive 🙂🙂
Wait if you make the loop in a direction of counter clockwise. Isn't the answer will be the same?
I see Setting the direction so important thx again :)
Glad to help Oussama :)
Is loop law applicable to all circuit?
hello I love your tutorials
I raelly love mathematics this is my favourit subject
Mine too Khurram :)
Can you make a video on differentiation
This is good.
Thanks Mech!
1.2A
Where i = .2 A come from? I don't get it 🙁
I'm struggling with this please help 🙁
At 6:52 you can see 18V - (90Ω)I = 0
Using algebra, we subtract 18V from both sides to get - 90(Ω)I = -18V
Divide both sides by -90Ω to get I = -18V/-90Ω
Put that into a calculator (-18/-90) and you get .2 A
There are 2 variables how DoD u solve
Why its not + ohms
Shuldn't it be, 18V - (-90 hms)I = 0?
Satyam Srivastav if this is the answer, then negative current means assumption of true current direction is wrong.
Can you help me sir
especially, this ine
I'm not sure we can trust a teacher who doesn't know how to spell Kirchhoff...
Lol if I put resistance I in wrong direction voltage will increase XD
Alright! lol
I hate math
I hope these videos make you hate math a little less Selena :)
Love math feel magic
Math Meeting... I have completed Btech in Electronics and communication . I would like to work in core companies. What should i do for that???