Existential Quantifiers - Examples

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  • Опубліковано 25 гру 2024

КОМЕНТАРІ • 62

  • @Ianjalibehera
    @Ianjalibehera 3 роки тому +60

    Why this videos are soo underrated i mean... The explainer is just perfect in his job! ❤️💯

    • @devkumar9889
      @devkumar9889 2 роки тому +12

      bcz people watch it while preparing for exams and they dont have time to like videos

  • @VamsiKrishna-ym3cr
    @VamsiKrishna-ym3cr 4 роки тому +123

    truth values for the given homework problem.
    A.) True...since it satisfies when x is square root of 2
    B.) False...Because domain is real numbers...
    C.) False.. Because domain is real numbers...

    • @dakshkalucha5408
      @dakshkalucha5408 2 роки тому

      A.) is False, because root 2 is an irrational number... and our domain is rational numbers only.

    • @kisatsronal256
      @kisatsronal256 2 роки тому +3

      For C wen X= 1/2, x^2

    • @toqx
      @toqx 2 роки тому +4

      @@kisatsronal256 If x = 1/2, x^2 will be equal to 1/4 which is 0.25.
      and 0.25 is greater than zero.

    • @kisatsronal256
      @kisatsronal256 2 роки тому +3

      @@toqx oooh, thks so. I had mistaken it, poor me.🤪🤪

    • @219_vipulbagde7
      @219_vipulbagde7 2 роки тому +2

      @@toqx we need smaller than 0

  • @suriyaprakashgopi
    @suriyaprakashgopi 3 роки тому +53

    1. True ---- > for x equal to sqrt(2)
    2. False ---- > negative number multiplied by a negative number is always positive
    3. False ---- > Square a number can never be less than zero

    • @karankakreja0118
      @karankakreja0118 Рік тому +3

      You can take 1/2, 1/3,1/4......

    • @thisaranidias
      @thisaranidias Рік тому +10

      ​@@karankakreja0118And yet the square of a number is never negative. So it can never be -1 or less than 0

    • @anishanish9497
      @anishanish9497 8 місяців тому

      ​@@thisaranidiasin case of iota square will result in -1 so this possibility must be taken under consideration

    • @ihfazhakimsulvi6494
      @ihfazhakimsulvi6494 7 місяців тому +1

      ​@@anishanish9497but i is imaginary number,not real!

    • @sheikharooj5762
      @sheikharooj5762 5 днів тому

      ​@@karankakreja0118still would be greater tgan 0 ..i.e 0.5 0.333 0.25

  • @uuitgaurav
    @uuitgaurav 11 місяців тому +3

    Tomorrow is my exam and i have completed almost 80 lectures from your playlist of 148 videos.
    I am going to top this exam.

  • @syedhashim3115
    @syedhashim3115 9 місяців тому +2

    for x^2 = -1 and x^2

  • @studywithsisters3265
    @studywithsisters3265 Місяць тому

    Thankyou Sir you are really helping a lot...very awesome explanation...ek ek topic dhang se clear ho raha hai...Thankyou so much Sir 🙏

  • @veenathalanki2427
    @veenathalanki2427 3 роки тому +8

    1) true sqrt of 2
    2) false domain real
    3) true 1/2

    • @purplewow9550
      @purplewow9550 3 роки тому +10

      bruhhh.. 0.5 squared is 0.25 which is still greater than 0, the last one is false.

  • @randomguy2139
    @randomguy2139 4 роки тому +16

    tommorow is my automata theory exam and i am going to watch your videos in 2X now
    *10TH LIKE*

  • @DoubleL_Leo
    @DoubleL_Leo 2 роки тому +1

    Thanks for this sir,

  • @mahvish2651
    @mahvish2651 Рік тому +2

    Someone please tell in ex3 how we would know that to take positive or negative value as to get correct answer?

    • @niccolopaganini1782
      @niccolopaganini1782 10 місяців тому

      Hit & Trial most probably, the solution wouldn't be that complicated.

  • @Haritha__sree__11
    @Haritha__sree__11 4 роки тому +2

    Tqq sir....

  • @prathibhasmily9151
    @prathibhasmily9151 4 роки тому +2

    Tq so much😊

  • @MuhammadGulfamAfzal
    @MuhammadGulfamAfzal 8 місяців тому +1

    In 2nd question if we take sq root of -1 And its square will cancel its square and then it give -1 that we wanted

    • @sherazakbar6544
      @sherazakbar6544 8 місяців тому

      The square change negative in positive so -1^2 will become+1so LHS is not equal to RHS that's if wchic is false

    • @hmm4768
      @hmm4768 4 місяці тому

      sq root of -1 is a complex number , generally known as iota

  • @rishabhverma6318
    @rishabhverma6318 2 роки тому +1

    homework problems solution:
    a ) true when x is square root of 2
    b ) false because square of nay number can't be equal to -1
    c ) false because square of a number can't be less than 0

    • @rimmi_ram
      @rimmi_ram 2 роки тому

      From which university

    • @rishabhverma6318
      @rishabhverma6318 2 роки тому

      @@rimmi_ram National institute of technology,Surathkal

  • @brickby3025
    @brickby3025 4 роки тому +2

    where was this series when i was doing discrete maths course

  • @siddhantswarupmallick6710
    @siddhantswarupmallick6710 3 роки тому +1

    1. True for root 2.
    2. False
    3. False.

  • @jayxcoder
    @jayxcoder 2 роки тому

    a) True
    b) False
    c) False

  • @cahyadesthian.widigda
    @cahyadesthian.widigda 4 роки тому +21

    📄 Homework problem
    1. TRUE, since the domain is real number, we can use x equals root of two, then (√2)^2=2
    2. FALSE, because all real numbers result positive when its squared
    3. FALSE , because all real numbers result positive when its squared and it greater than zero

    • @BharathiBlogs
      @BharathiBlogs 3 роки тому +1

      Wow! Thanks friend :)

    • @srijaksingh1522
      @srijaksingh1522 3 роки тому +1

      it will be true for all the three cases as if we take root 2 for the first one after squarring root will be removed so it satisfies similarly for second root -1 after squarring it willl still be -1 as only root will be removed and same for the third one

    • @chakradharthota1100
      @chakradharthota1100 3 роки тому +2

      @@srijaksingh1522 we can't take root of -1 because it is a complex number and not a real number 👍

  • @AlokSingh-jw8fr
    @AlokSingh-jw8fr 3 роки тому

    Homework problem answer
    T F F

  • @kajalmondal9745
    @kajalmondal9745 4 роки тому

    Sir, in your last video of data structure where we add a list in a given position what happen if we gave a position which is not existing in our list? Please sir reply.....

  • @letsbethechange481
    @letsbethechange481 4 роки тому

    TFF

  • @sakinasajjad3623
    @sakinasajjad3623 Рік тому

    Comments not showing

  • @atikhasan280
    @atikhasan280 2 роки тому +1

    1. When x=root 2
    then x^2=2
    =>(root 2)^2 = 2
    =>2=2
    so, Ex(x^2 = 2) is True.
    2. false
    3. false

    • @aishjk
      @aishjk 2 роки тому +2

      what if we put the value of x =1/2 in third part of homework

  • @manichandu2742
    @manichandu2742 3 роки тому +3

    Who watches comments hit like

  • @Neha-Khan-630
    @Neha-Khan-630 2 роки тому

    can`t we take root values?

  • @arvind-6010
    @arvind-6010 4 роки тому +2

    Broo nxt video

  • @suryas7797
    @suryas7797 4 роки тому +1

    Sir please complete full syllabus before December 🙏🙏.still I am preparing gate 2021 sir

  • @arvind-6010
    @arvind-6010 4 роки тому

    Sir plz upload the nxt topic fast

  • @kunaldhyani
    @kunaldhyani 2 роки тому +1

    a) True
    b) False
    c) False
    Please correct me if I am wrong.

  • @fit173-pandeyayush4
    @fit173-pandeyayush4 3 роки тому +2

    ANSWER: both a, b, c are true
    A:when x equal square root of 2 then x^2=2;
    B: whan x equal to (-1)^3 then x^2=(-1)^5=-1;
    C: When x equal to (-1)^3 then
    X^2=(-1)^5=-1

    • @kakisudha3585
      @kakisudha3585 3 роки тому +1

      But we take in real numbet form.not square or cube anything.

    • @anwarulislamutso4085
      @anwarulislamutso4085 10 місяців тому

      B is False.
      You do a mistake ,
      To solve this expression, follow the order of operations, which is parentheses, exponents, multiplication and division (from left to right), and addition and subtraction (from left to right).
      So, first, evaluate the expression within the innermost parentheses: (-1)^3 = -1.
      Now, we have (-1)^3 raised to the power of 2. So, (-1)^3 = -1, and (-1)^3 squared means multiplying -1 by itself, so (-1)^3 squared = (-1) * (-1) = 1.
      Therefore, the answer is 1.
      Same rules follow in answer C, so that will be also False

  • @sarveksha2110
    @sarveksha2110 3 роки тому +2

    (true, false,false)

  • @shobansuresh3196
    @shobansuresh3196 Рік тому

    T F F

  • @cse115saraudaykiran2
    @cse115saraudaykiran2 2 роки тому

    true
    false
    false

  • @saurabhgupta1595
    @saurabhgupta1595 4 роки тому

    T, T, F

  • @adityakharbanda4080
    @adityakharbanda4080 2 роки тому

    true
    false
    false