Sir, you're the best. The explanation is vivid and simple. i feel the change from this tutorial. At first,I thought bisection method is complicated but now I find it to be easy with the help of this . Thank you.
Thank you! To get even more help, subscribe to the numericalmethodsguy channel, and go to MathForCollege.com/nm and MathForCollege.com/ma for more resources and share the link with your friends through social media and email. Follow my numerical methods blog at AutarKaw.org. You can also take a free online course at canvas.instructure.com/enroll/KYGTJR
Thank you. To get even more help, subscribe to the numericalmethodsguy channel, and go to MathForCollege.com/nm and MathForCollege.com/ma for more resources and share the link with your friends through social media and email. Support the site by buying the textbooks at www.lulu.com/shop/search.ep?keyWords=autar+kaw&type= Follow my numerical methods blog at AutarKaw.org. You can also take a free online course at www.canvas.net/?query=numerical%20methods
Thank you. To get even more help, subscribe to the numericalmethodsguy channel ua-cam.com/users/numericalmethodsguy, and go to MathForCollege.com/nm and MathForCollege.com/ma for more resources. Follow the numerical methods blog at AutarKaw.org. You can also take a free massive open online course (MOOC) at canvas.instructure.com/enroll/KYGTJR Share these links with your friends through social media and email.
Thank you. To get even more help, subscribe to the numericalmethodsguy channel ua-cam.com/users/numericalmethodsguy, and go to MathForCollege.com/nm and MathForCollege.com/ma for more resources. Follow the numerical methods blog at AutarKaw.org. You can also take a free massive open online course (MOOC) at canvas.instructure.com/enroll/KYGTJR Share these links with your friends through social media and email.
Sir this explained the concept very well. I am currently learnin newtons method and the bisection method was mentioned during lecture so I am very glad that this video exists.
this looked impossibly complicated on my professor's lecture notes, especially with him combining MATLAB code. After this video, this stuff is child's play.
Thank you. To get even more help, subscribe to the numericalmethodsguy channel, and go to MathForCollege.com/nm and MathForCollege.com/ma for more resources and share the link with your friends. Follow my numerical methods blog at AutarKaw.org. You can also take a free online course at www.canvas.net/?query=numerical%20methods
To get even more help, go to MathForCollege.com/nm and MathForCollege.com/ma for more resources and share the link with your friends. Follow my numerical methods blog at AutarKaw.org. You can also take a free online course at www.canvas.net/?query=numerical%20methods
Thank you. To get even more help, subscribe to the numericalmethodsguy channel, and go to MathForCollege.com/nm and MathForCollege.com/ma for more resources and share the link with your friends through social media and email. Support the site by buying the textbooks at www.lulu.com/shop/search.ep?keyWords=autar+kaw&type= Follow my numerical methods blog at AutarKaw.org. You can also take a free online course at www.canvas.net/?query=numerical%20methods
with regards to the steps of finding the changing the sign? Mine do not change the at some interval between the work, so I want to know how do I proceed?
That is not possible. If you have a valid starting interval, and the function is continuous in that interval, then one of the two new intervals has to be valid.
when you were writing the conditions, (f(XL).f(XM) < 0 and others) why didn't you just write f(XM) and look for its sign? If f(XM) is positive then your upper limit becomes XM and lower limit stays same. If f(XM) is negative then your lower limit becomes XM and upper limit stays same. Why do you bother yourself with f(XL)
+Giovanni Valpiani you might be confused with Xm as mid point. The way we are calculating midpoint is by taking average. The formula for avg is sum of terms/# of terms. hope its clear!
@@fremanpool4575 But that does not mean it is not correct. Yes, if fx1*fx2 is greater than 0, we cannot say if a solution exists or not between x1 and x2. All numerical methods have pros and cons. That does not make them incorrect!
Sir, you're the best.
The explanation is vivid and simple.
i feel the change from this tutorial.
At first,I thought bisection method is complicated but now I find it to be easy with the help of this .
Thank you.
Thank you! To get even more help, subscribe to the numericalmethodsguy channel, and go to MathForCollege.com/nm and MathForCollege.com/ma for more resources and share the link with your friends through social media and email.
Follow my numerical methods blog at AutarKaw.org. You can also take a free online course at canvas.instructure.com/enroll/KYGTJR
very rare that i stop and comment on the skill of a teacher's ability to explain something so clearly. This guy is amazing
Very clearly explained 15 year old video. Thanks a lot.
Those videos are so good and I is saving me from getting bad grades in Numerical Method course. Indeed helpful.
i just discover this channel now, the way the lecture is given is so clear thanks
Thank you.
To get even more help, subscribe to the numericalmethodsguy channel, and go to MathForCollege.com/nm and MathForCollege.com/ma for more resources and share the link with your friends through social media and email.
Support the site by buying the textbooks at www.lulu.com/shop/search.ep?keyWords=autar+kaw&type=
Follow my numerical methods blog at AutarKaw.org. You can also take a free online course at www.canvas.net/?query=numerical%20methods
THIS GUY IS GOD. YOU SAVED ME FROM MY NUMERICAL METHODS MIDTERM
My midterm is in 3 days... I hope I can bring good news :D
YOU ARE THE MAN.
numericalmethodsguy > everyone else
What an amazing explanation he delivers! Thanks a lot, sir!
thank u so much...iwas so worried about the concept of bisection method...but wheni saw ur vedio i got all in all thankz alot its rili helpfull...
Professor, you are gold, solid gold!
Thank you.
To get even more help, subscribe to the numericalmethodsguy channel ua-cam.com/users/numericalmethodsguy, and go to MathForCollege.com/nm and MathForCollege.com/ma for more resources. Follow the numerical methods blog at AutarKaw.org. You can also take a free massive open online course (MOOC) at canvas.instructure.com/enroll/KYGTJR Share these links with your friends through social media and email.
Pretty intuitive method. Programming is about encoding instructions that allow computational processes to repeat.
I wish I could give you a hug.
Thank you for this video.
Thank you.
To get even more help, subscribe to the numericalmethodsguy channel ua-cam.com/users/numericalmethodsguy, and go to MathForCollege.com/nm and MathForCollege.com/ma for more resources. Follow the numerical methods blog at AutarKaw.org. You can also take a free massive open online course (MOOC) at canvas.instructure.com/enroll/KYGTJR Share these links with your friends through social media and email.
Sir this explained the concept very well. I am currently learnin newtons method and the bisection method was mentioned during lecture so I am very glad that this video exists.
thanks so much sir..absolute ease of learning NM..
Professor is the best❤️❤️
Thank you so much. you helped me a lot on trying to understand more about this topic. May God bless
Man is goating 14 years ago
perfect Dr numerical
12 years after
Helped me
this looked impossibly complicated on my professor's lecture notes, especially with him combining MATLAB code. After this video, this stuff is child's play.
Woo really nice explanation
The explanation was awesome . thank u sir .
Thank you. To get even more help, subscribe to the numericalmethodsguy channel, and go to MathForCollege.com/nm and MathForCollege.com/ma for more resources and share the link with your friends. Follow my numerical methods blog at AutarKaw.org. You can also take a free online course at www.canvas.net/?query=numerical%20methods
ty, great teacher, simple explanation.
thank you verymuch Sir really helpfully.
Very well presented
Great and clear explanation.
To get even more help, go to MathForCollege.com/nm and MathForCollege.com/ma for more resources and share the link with your friends. Follow my numerical methods blog at AutarKaw.org. You can also take a free online course at www.canvas.net/?query=numerical%20methods
Thank you so much. This helped me a lot.
Awesome professor!
Do you see the description of the video above. Just click on the link and your wish will be granted!
Well explained, thank you.
This is fantastic! Thanks!
it would be nice to know in which order your video goes but thank you! :)
Excelente amigo! Very nice job, I am very very thankfull! (Thanks)(1,000,000)
gonna say Indian people got some gifts with no doubt
There are 1.3 billion of us. Just probablities!
My prof should just play these videos in class it would save us a lot of confusion..
Thank you.
To get even more help, subscribe to the numericalmethodsguy channel, and go to MathForCollege.com/nm and MathForCollege.com/ma for more resources and share the link with your friends through social media and email.
Support the site by buying the textbooks at www.lulu.com/shop/search.ep?keyWords=autar+kaw&type=
Follow my numerical methods blog at AutarKaw.org. You can also take a free online course at www.canvas.net/?query=numerical%20methods
Thank-you sir, I will definity look at your fee online course.
very well done! thank you!
yay goooooo dr. Autar kaw
amazing thanks
good work
with regards to the steps of finding the changing the sign? Mine do not change the at some interval between the work, so I want to know how do I proceed?
That is not possible. If you have a valid starting interval, and the function is continuous in that interval, then one of the two new intervals has to be valid.
You are right
Cloud you solve that on qbasic program? Thanks
thanks sir
May you please upload lecture on regula falsi and fixed methods. I will be grateful if my request is regarded, Sir.
nm.mathforcollege.com/topics/false_position.html from my colleague and friend.
Thanks...
that was amazing
thanks a lot
بہترین
thANKS a LOTS
Thank u so much :)
very nice
ok this guy is good
when you were writing the conditions, (f(XL).f(XM) < 0 and others) why didn't you just write f(XM) and look for its sign?
If f(XM) is positive then your upper limit becomes XM and lower limit stays same.
If f(XM) is negative then your lower limit becomes XM and upper limit stays same.
Why do you bother yourself with f(XL)
It is because f(xl) can be positive and f(xu) can be negative.
there is a little error: Xm=(Xl-Xu)/2 am I right?
+Giovanni Valpiani No, you are not right. It is (xl+xu)/2, same as xl+(xu-xl)/2
+Giovanni Valpiani you might be confused with Xm as mid point. The way we are calculating midpoint is by taking average. The formula for avg is sum of terms/# of terms. hope its clear!
nope，you are wrong
GOOD
Thank you sir
A++
This is not correct
So what is correct would be the question people would ask?
@@numericalmethodsguy we do not know whether there is soln if fx1*fx2 is greater than 0
@@fremanpool4575 But that does not mean it is not correct. Yes, if fx1*fx2 is greater than 0, we cannot say if a solution exists or not between x1 and x2. All numerical methods have pros and cons. That does not make them incorrect!
@@numericalmethodsguy this makes it independable method.