You're the best. Seriously, thank you for sharing your gift of teaching with those who are not able to have a professor like you. :) Your videos have helped me a lot, and I know I'm not alone! Way to help build the future!
look to you bro and you are one of the most popular person who teach the numerical method in the world and you are the reference for all engineering student respect bro respect
@@randyrockranaq Thank you. Please subscribe and ask your friends to subscribe - our goal is to get to 100,000 subscribers by the end of 2021. To get even more help, subscribe to the numericalmethodsguy channel ua-cam.com/users/numericalmethodsguy, and go to MathForCollege.com/nm and MathForCollege.com/ma for more resources. Follow the numerical methods blog at AutarKaw.org. You can also take a free massive open online course (MOOC) at canvas.instructure.com/enroll/KYGTJR Please share these links with your friends and fellow students through social media and email.
@@بشمهندسمان Thank you. Please subscribe and ask your friends to subscribe - our goal is to get to 100,000 subscribers by the end of 2021. To get even more help, subscribe to the numericalmethodsguy channel ua-cam.com/users/numericalmethodsguy, and go to MathForCollege.com/nm and MathForCollege.com/ma for more resources. Follow the numerical methods blog at AutarKaw.org. You can also take a free massive open online course (MOOC) at canvas.instructure.com/enroll/KYGTJR Please share these links with your friends and fellow students through social media and email. Support the channel if you able to do so at ua-cam.com/users/numericalmethodsguy/store
@@بشمهندسمان Thank you. Please subscribe and ask your friends to subscribe - our goal is to get to 100,000 subscribers by the end of 2021. To get even more help, subscribe to the numericalmethodsguy channel ua-cam.com/users/numericalmethodsguy, and go to MathForCollege.com/nm and MathForCollege.com/ma for more resources. Follow the numerical methods blog at AutarKaw.org. You can also take a free massive open online course (MOOC) at canvas.instructure.com/enroll/KYGTJR Please share these links with your friends and fellow students through social media and email. Support the channel if you able to do so at ua-cam.com/users/numericalmethodsguy/store
Thank you. To get even more help, go to MathForCollege.com/nm for more resources. Follow my numerical methods blog at AutarKaw.org. You can also take a free online course at www.canvas.net/?query=numerical%20methods
Thank you. To get even more help, subscribe to the numericalmethodsguy channel, and go to MathForCollege.com/nm and MathForCollege.com/ma for more resources and share the link with your friends through social media and email. Support the site by buying the textbooks at www.lulu.com/shop/search.ep?keyWords=autar+kaw&type= Follow my numerical methods blog at AutarKaw.org. You can also take a free online course at www.canvas.net/?query=numerical%20methods Best of Learning Autar Kaw AutarKaw.com
Thank You for your explanations! Great job! I needed to refresh quickly numerical methods. With your videos I did it in couple of evenings! Thank You very much
To get even more help, subscribe to the numericalmethodsguy channel, and go to MathForCollege.com/nm and MathForCollege.com/ma for more resources and share the link with your friends through social media and email. Support the site by buying the textbooks at www.lulu.com/shop/search.ep?keyWords=autar+kaw&type= Follow my numerical methods blog at AutarKaw.org.
@MachiP0p0 Es means pre-specified tolerance. It is a stopping criteria to stop iterations. When the absolute relative approximate error is less than pre-specified tolerance, then we can stop the iterations. How do we choose Es? Go to numericalmethods(.)eng(.)usf(.)edu and click on Measuring Errors under Introduction. See pages 5-7 of the pdf file of the texbook chapter.
@fullheavy Just follow the example given in the Newton-Raphson playlist. It is not a difficult problem to do. Be sure that your calculator is set to the radians mode. Once the 5 decimal places do not change in the answer, you have your answer.
thank you for this nice explanation :) actually I'm doing my master thesis and I'm taking computational methods course so you just helped me a lot>>> BY THE WAY, i just subscribed! :)
Hi there, I love your videos, every single one. Your explainations are really clear, your lecture ignites my passion in numerical method. Hope that you could construct a youtube curricular for the course
I do not know of a general technique to do so. If the problem is connected to a physical phenomenon, you can use the knowledge of the physical problem to choose a good initial guess.
@xTabbyCat I do not know of a general technique to do so. If the problem is connected to a physical phenomenon, you can use the knowledge of the physical problem to choose a good initial guess. Go to numericalmethods(.)eng(.)usf(.)edu and click on Newton Raphson Method. Click on the textbook chapter to see a physical problem.
Thank you. Please subscribe and ask your friends to subscribe - our goal is to get to 100,000 subscribers by the end of 2021. To get even more help, subscribe to the numericalmethodsguy channel ua-cam.com/users/numericalmethodsguy, and go to MathForCollege.com/nm and MathForCollege.com/ma for more resources. Follow the numerical methods blog at AutarKaw.org. You can also take a free massive open online course (MOOC) at canvas.instructure.com/enroll/KYGTJR Please share these links with your friends and fellow students through social media and email. Support the channel if you able to do so at ua-cam.com/users/numericalmethodsguy/store
Sir, could you help me with this question? Use the Newton-Raphson process to determine a value of x near x1 = 0 for which f(x) = 0, where f(x) = 9 x+0.4−8 sin( x ) giving your answer (and the interim results we ask for) correct to 5 decimal places. What are the values of x and f(x) at the second iteration? What are the values of x and f(x) at the third iteration? The value of x (correct to 5 decimal places) such that f(x) = 0.
why is the tangent of theta the same as the derivative of the function at x sub i? I mean, shouldn't it be that the theta is the slope of the line in any case? But he is talking about tangent of theta, and that's where it doesn't make sense
If you remember the slope of the tangent line is given by tan(theta)=rise/run. Now think about derivative is (f(x+dx)-f(x))/dx as dx ->0. What is the numerator dy (difference between y values at x+dx and x).
How do I find use the tangent to find the initial estimate? I have a graph of two curves; (y=e^x) and (y=4/x) And it says I have to find the initial estimate for the root of the equation: x e^x - 4 = 0 The answer is that the solution is the intersection of f(x) - e^x and f(x) = 4/x but that doesn't help me find the actual NUMBER for the initial estimate. How would I go about finding the initial estimate NUMBER?
Thank you. To get even more help, go to MathForCollege.com/nm and MathForCollege.com/ma for more resources and share the link with your friends. Follow my numerical methods blog at AutarKaw.org. You can also take a free online course at www.canvas.net/?query=numerical%20methods
+Nutan Kumari Epsilon-s is prespecified tolerance. That is an input. You can however relate epsilon-s to how many significant digits do you want at least correct in your answer. If you want m significant digits to be correct,then epsilon-s is 0.5*10^(2-m) percent. Check nm.mathforcollege.com/topics/measuring_errors.html for more info.
+Nutan Kumari I do not know of a general technique to do so. If the problem is connected to a physical phenomenon, you can use the knowledge of the physical problem to choose a good initial guess. Go to nm.mathforcollege.com/topics/newton_raphson.html and look at the examples from other majors.
+Nutan Kumari Just put x=0,1,2... in f(x). The two consecutive values for which the f(x) changes its sign (-ve to +ve or vica-versa) (say 2 and 3), then you can take initial approximation between those two points (between 2 and 3 i.e. 2.5). For trigonometric functions, just put the values (0,pi/4,pi/2....) and for the values say pi/4 and pi/2, the f(x) changes its sign, then the initial approximation can be taken as (3*pi/4). This works in all the questions I've done.
Because it is not bracketed. We have only one initial guess. Two initial guesses do not make a method bracketed as is the case in secant method. Why? Because the two initial guesses do not have to bracket a root. Bisection method is a bracketing method.
@@muhammadroshan7315 Indians are not generally excellent in math. We got 1.3 billion people and we better have many people who are excellent in math. The cramming you talk about is a good start in being creative. How would one get a creative thought without having a base knowledge?
welcome to 13 years from when this method was posted... this video helped me ace my presentation on newton's raphson method
All professors should aspire to be just like you. Thank you so much! you are a titan!
Marcos Martinez agree👍
Agree with you
This video was published 12 years ago but still very helpful! Thank you!
You're the best. Seriously, thank you for sharing your gift of teaching with those who are not able to have a professor like you. :) Your videos have helped me a lot, and I know I'm not alone! Way to help build the future!
80 seconds in, and I already got what I needed. Excellent explanation
Thanks for your comments. We will have about 200 videos by end of June 2009.
Bro you gawd
look to you bro and you are one of the most popular person who teach the numerical method in the world and you are the reference for all engineering student
respect bro respect
@@randyrockranaq Thank you. Please subscribe and ask your friends to subscribe - our goal is to get to 100,000 subscribers by the end of 2021.
To get even more help, subscribe to the numericalmethodsguy channel ua-cam.com/users/numericalmethodsguy, and go to MathForCollege.com/nm and MathForCollege.com/ma for more resources.
Follow the numerical methods blog at AutarKaw.org. You can also take a free massive open online course (MOOC) at canvas.instructure.com/enroll/KYGTJR
Please share these links with your friends and fellow students through social media and email.
@@بشمهندسمان Thank you. Please subscribe and ask your friends to subscribe - our goal is to get to 100,000 subscribers by the end of 2021.
To get even more help, subscribe to the numericalmethodsguy channel ua-cam.com/users/numericalmethodsguy, and go to MathForCollege.com/nm and MathForCollege.com/ma for more resources.
Follow the numerical methods blog at AutarKaw.org. You can also take a free massive open online course (MOOC) at canvas.instructure.com/enroll/KYGTJR
Please share these links with your friends and fellow students through social media and email.
Support the channel if you able to do so at ua-cam.com/users/numericalmethodsguy/store
@@بشمهندسمان Thank you. Please subscribe and ask your friends to subscribe - our goal is to get to 100,000 subscribers by the end of 2021.
To get even more help, subscribe to the numericalmethodsguy channel ua-cam.com/users/numericalmethodsguy, and go to MathForCollege.com/nm and MathForCollege.com/ma for more resources.
Follow the numerical methods blog at AutarKaw.org. You can also take a free massive open online course (MOOC) at canvas.instructure.com/enroll/KYGTJR
Please share these links with your friends and fellow students through social media and email.
Support the channel if you able to do so at ua-cam.com/users/numericalmethodsguy/store
Thanks so much for this. This derivation has been bothering me for ages as it hadn't been explained to me in the context of tan. Really clear.
Thank you. To get even more help, go to MathForCollege.com/nm for more resources. Follow my numerical methods blog at AutarKaw.org. You can also take a free online course at www.canvas.net/?query=numerical%20methods
Wow! Thank you very much for this! Your explanation is clear and concise. Very easy to understand. Thank you very much, indeed. From Pakistan
Sir, you are a legend. Many thanks to you for making life a lot easier.
Surprisingly clear and thorough :)
Really enjoyed your teaching...one of my most favorites youtube teacher. Thanks Prof!
Thank you.
To get even more help, subscribe to the numericalmethodsguy channel, and go to MathForCollege.com/nm and MathForCollege.com/ma for more resources and share the link with your friends through social media and email.
Support the site by buying the textbooks at www.lulu.com/shop/search.ep?keyWords=autar+kaw&type=
Follow my numerical methods blog at AutarKaw.org. You can also take a free online course at www.canvas.net/?query=numerical%20methods
Best of Learning
Autar Kaw
AutarKaw.com
best video for numerical analysis..
You have very neat board writing. Thanks for the video.
Thank You for your explanations! Great job! I needed to refresh quickly numerical methods. With your videos I did it in couple of evenings! Thank You very much
Thanks agian....another ace on exam in a few hours...u are a great teacher
My computational physics teacher told me the Newton-Raphson method is this formula... That was my lesson.
Sorry to hear that. Go here for all resources. nm.mathforcollege.com/ Tell your classmates.
Thanks for the clear and wonderful explanation!
That's a very neat and intuitive explanation, thank you for sharing :)
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Follow my numerical methods blog at AutarKaw.org.
ty, great teacher and simple explanation
@MachiP0p0 Es means pre-specified tolerance. It is a stopping criteria to stop iterations. When the absolute relative approximate error is less than pre-specified tolerance, then we can stop the iterations. How do we choose Es? Go to numericalmethods(.)eng(.)usf(.)edu and click on Measuring Errors under Introduction. See pages 5-7 of the pdf file of the texbook chapter.
simple and nice explanation
Great, really helped me to understand why it works
@fullheavy Just follow the example given in the Newton-Raphson playlist. It is not a difficult problem to do. Be sure that your calculator is set to the radians mode. Once the 5 decimal places do not change in the answer, you have your answer.
thank you for this nice explanation :) actually I'm doing my master thesis and I'm taking computational methods course so you just helped me a lot>>> BY THE WAY, i just subscribed! :)
GREAT VIDEO,VERY HELPFUL
Brilliant sir, thanks to you I'll pass.!
Really helpful. Thanks sir 👍
Nice explanation...
Hi there, I love your videos, every single one. Your explainations are really clear, your lecture ignites my passion in numerical method. Hope that you could construct a youtube curricular for the course
nm.mathforcollege.com
@NancyEng It is the second guess or a better guess than xi . It is closer to the root. Hence it is called xi+1.
I do not know of a general technique to do so. If the problem is connected to a physical phenomenon, you can use the knowledge of the physical problem to choose a good initial guess.
@xTabbyCat I do not know of a general technique to do so. If the problem is connected to a physical phenomenon, you can use the knowledge of the physical problem to choose a good initial guess. Go to numericalmethods(.)eng(.)usf(.)edu and click on Newton Raphson Method. Click on the textbook chapter to see a physical problem.
In my humble opinion you are an excellent teacher. Many thanks.
Regards, John Roberts.
x(i+1) is the next iterative value of the root after x(i). There is no restriction that x(i+1) has to be greater than x(i).
Thank you. Please subscribe and ask your friends to subscribe - our goal is to get to 100,000 subscribers by the end of 2021.
To get even more help, subscribe to the numericalmethodsguy channel ua-cam.com/users/numericalmethodsguy, and go to MathForCollege.com/nm and MathForCollege.com/ma for more resources.
Follow the numerical methods blog at AutarKaw.org. You can also take a free massive open online course (MOOC) at canvas.instructure.com/enroll/KYGTJR
Please share these links with your friends and fellow students through social media and email.
Support the channel if you able to do so at ua-cam.com/users/numericalmethodsguy/store
Great explanation. Thank you very much!
Thank you so much!!
YOU ARE THE BEST
Awesome video!!!!
Sir, could you help me with this question?
Use the Newton-Raphson process to determine a value of x near x1 = 0 for which f(x) = 0, where
f(x) = 9 x+0.4−8 sin( x )
giving your answer (and the interim results we ask for) correct to 5 decimal places. What are the values of x and f(x) at the second iteration?
What are the values of x and f(x) at the third iteration?
The value of x (correct to 5 decimal places) such that f(x) = 0.
why is the tangent of theta the same as the derivative of the function at x sub i? I mean, shouldn't it be that the theta is the slope of the line in any case? But he is talking about tangent of theta, and that's where it doesn't make sense
If you remember the slope of the tangent line is given by tan(theta)=rise/run. Now think about derivative is (f(x+dx)-f(x))/dx as dx ->0. What is the numerator dy (difference between y values at x+dx and x).
@@numericalmethodsguy yes, it suddenly dawned on me what you were saying. Thank you
who is this legend
How do I find use the tangent to find the initial estimate?
I have a graph of two curves; (y=e^x) and (y=4/x)
And it says I have to find the initial estimate for the root of the equation: x e^x - 4 = 0
The answer is that the solution is the intersection of f(x) - e^x and f(x) = 4/x but that doesn't help me find the actual NUMBER for the initial estimate.
How would I go about finding the initial estimate NUMBER?
great videos
thank you very much sir
Can i just ask why Xi+1 is behind the point Xi ? in the graph ?
Yes, if that is what it turns out to be.
Legends who watching 2022. Like it
that was amazing thank you
Thank you so so so much!!!
Thank you very helpful
Why does the error = ( xi-x0)/xi and not (xi-x0)/x0?
Why does roots are define at f(x) = 0?
You always compare with current approximation. Second question needs more clarification.
Amazing
thank you sir
Thank you. To get even more help, go to MathForCollege.com/nm and MathForCollege.com/ma for more resources and share the link with your friends. Follow my numerical methods blog at AutarKaw.org. You can also take a free online course at www.canvas.net/?query=numerical%20methods
The whole curriculum with videos will be done by June 2009. Just visit numericalmethods(dot)eng(dot)usf(dot)edu
thank you sir..
What mean by Es?
Could anybody please clarify how to calculate (E)s that is ebslons s?
+Nutan Kumari Epsilon-s is prespecified tolerance. That is an input. You can however relate epsilon-s to how many significant digits do you want at least correct in your answer. If you want m significant digits to be correct,then epsilon-s is 0.5*10^(2-m) percent. Check nm.mathforcollege.com/topics/measuring_errors.html for more info.
Thanks for the answer.could you please explain how to guess the value initially in this method.?
+Nutan Kumari I do not know of a general technique to do so. If the problem is connected to a physical phenomenon, you can use the knowledge of the physical problem to choose a good initial guess. Go to nm.mathforcollege.com/topics/newton_raphson.html and look at the examples from other majors.
+Nutan Kumari Just put x=0,1,2... in f(x). The two consecutive values for which the f(x) changes its sign (-ve to +ve or vica-versa) (say 2 and 3), then you can take initial approximation between those two points (between 2 and 3 i.e. 2.5). For trigonometric functions, just put the values (0,pi/4,pi/2....) and for the values say pi/4 and pi/2, the f(x) changes its sign, then the initial approximation can be taken as (3*pi/4). This works in all the questions I've done.
Why is this called an open method?
Because it is not bracketed. We have only one initial guess. Two initial guesses do not make a method bracketed as is the case in secant method. Why? Because the two initial guesses do not have to bracket a root. Bisection method is a bracketing method.
dat derivation doe
Nicely done but a little too slow
O! NICE
boy, indians are excellent at math for some reason XD..
You mean in cramming math. Yeah I can agree on that. But definitely not on creativity
@@muhammadroshan7315 Indians are not generally excellent in math. We got 1.3 billion people and we better have many people who are excellent in math. The cramming you talk about is a good start in being creative. How would one get a creative thought without having a base knowledge?
hi.
dhon bujlam na kisu
great video