Design of circular column with helical reinforcement
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- Опубліковано 5 кві 2020
- In the following video the design of the column is done as per IS456:2000.
And,
Check this out guys to learn the design of staircase as per Is 456:2000
• Design of Staircase ||...
Also,
Design of cantilever retaining wall is here👇
• Video
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Really super bro thank you
It came for 15 marks in today's SEM exam (osmania university) !
Best of luck 👍🙂👍👍
Punjab Technical University
Thank you so much 🤗🤗 . Itna badhiya content dene ke liye....
I see many lectures of civil engineering and all are good as your videos but one thing makes you different from them is that you answer and solve the all queries of students and while the other channels only answers 2 or 3 students queries
Thanks alot for your appreciation.
I am trying my best. As much as i can.
Well explained keep going like this
As u had increase the diameter of the column as 420mm..so in case of finding out the 'Asc' why u considered the Ag as the older one. .
Thank you for this instructive video. May I know which standard is used for this design?
Limit state method
God bless U...
Thank you so much
Do formulas differ for ..round axially column and rectangular axially column?
Yes
Sir Area of helix m to longitudinal reinforcement nhi subtract krte h na
Hello dear,
We need to subtract the area of longitudinal reinforcement from the area of helix.
It is because inorder to calculate the pitch of the helix we only need to have the area of helix reinforcement.
And one thing more,
We have considered the the diameter of helix after subtracting (2x40mm) cover from both sides. And u can notice in the inside the core dia. Longitudinal reinforcement is also included. And that's why we need to subtract the area of longitudinal reinforcement.so that the pich of core can be calculated and the codal provision is satisfied.
I hope i met your confusion.
Thanks for your comment.
Have a nice day.
Use Hindi instead of getting disturbed bcz of English rest u r lit God bless you 🙏🏻
Yes, dear it's very much different in starting a conversation and speaking in front of camer. By the way it's improving day by day. Thanks for your compliment.
Helical reinforcement ka dia 8mm kyu liya ? 🥲 ussi ke liye to pura lucture dekha vo hi samjh nhi aaya
Sir which method is used in this numerical?
My question is LSM or WSM?
It's LSM.
@@Civillearningonline Have you uploaded Circular Column Design using WSM?? In any other Video
Not yet. But I will.
Bro plse teach me structural engineering of rec beam for flexure by l.s.m ..please teach this unit bro
Sure
Very helpful video.....please make one more on design of cantilever retaining wall by LSM.
Sure
Design of cantilever retaining wall
ua-cam.com/video/pNw74xSbKVc/v-deo.html
Dear formula of helical
Vus/Vc
A little more explanation is required basically in calculating pitch of helix...
Sure
Calculation of pich is as per the code is 456 2000. Of clause 39.4.1. page 71 and clause 26.5.3.2(d) page 49.
Sir how do you take vhs/vc =0.009😢
Sir please answer
Use full forms bro If use ast,as, these differ
Ok
Pitch condition 2 is not satisfied ❌
See pitch is greater than 1/6 th of core dia
Yes bhai.
So we need to take intermediate value (i. E. Neither large nor smaller).
Hope you got it.
And thanks for your query.👍
Sir how to check what is find in numerical?
When you are asked to design then you need to calculate upto the lateral ties and some checks. Do as shown in this video. It's sufficient.
Remember: design means calculation of reinforcement.
@@Civillearningonline thank you sir
Nepali boln aaudain hjr lai 😜
Aauxa hajur😅
Ath the minute 10.00
How the effective cover is 40
As per IS code
e minimum =20?kha Diya hai
Code me he bhai
I will upload a special video for you in which i will discuss about e minimum =20. Till then stay safe.
Is book ka name batao.
Reinforced concrete design by B. C. Punmia 🤘
But 1.05 times means multiplied by 1.05, right?
Hello dear,
First of all thanks for your comment.
You are right that 1.05 times means multiply by 1.05.
And when you come to read the clause 39.4 of is 456 it already mentioned that "strength of compression member with helical reinforcement = 1.05 Pu"
Where Pu is strength of similar material with lateral ties.
And initially we need to design longitudinal reinforcement before the helical reinforcement.
That's why we need to the the steps
(Given load x factor of safety)/1.05.
And i hope you got your answer. Do comment when you face any kind of difficulty. Stay connected with civil learning online.
Have a nice day.
Please tamil,😭😭
I don't know tamil.