Fantastic explanation! very good job.. thank you very much Students nowadays are so lucky there is literally no excuse for not doing well. When I went to college circa graduation 1979 there was nothing to help except a pay tutor or family member no PCs no You tube , maybe a library but no calculators....nothing. I picked up my 41 yr old text book and tried to do a problem but no avail so listened to this video and within 15 minutes it all came back.
One of the best explained videos regarding vectors thank you so much. you got me out of a big hole by your skill of explaining these equations. Everything kicked in after watching your video. Thank you Aggieer
Thank you soo much *-*, Even my classmates were seeking help from me after I understood this thanks to your video! Really! this was really a good help for me since I'm kinda bad with numbers!
Even 10 years later this remains useful, never got taught this method probably because I don’t live in America but man this makes everything so much simpler
@ archie lim: Trigonometric functions use standard notation that is defined from the x-axis. So the 160lb force has an angle that is referenced to the x-axis and we use it. The other two forces have angles referenced to the y-axis, so we must find the angle they make with the x-axis and use it. I hope this helps.
Darlina Dzaqura Yes, the resultant force is the magnitude of the three forces combined. Every vector has both magnitude and direction. The magnitude will be a unit (kg, lbs, m/s, etc) and the direction will be which way that magnitude is pointing.
Excellent tutorial.. it was so simplified with full details of everything required 😌 thanks a bunch ... I'm having my physics exams tomorrow and this has really helped me alot😊❤🎉
Thanks for this video! I was looking for one on how to find a vector using the resultant and one vector and your table really helped be see how to work it backwards!
It is just a way to organize your numbers so that you don't "misplace" any. When working structural problems where you have forces and moments in three dimensions, it makes it a lot easier to keep up with all the information. Glad that it could help you.
An angle of 270 degrees is on the negative y axis, so the x component would be zero and the y component would be -y (or -r in vector terminology). So if you have a force of 400 lbs at 270 degrees, the x component would be x=0, and the y component would be y = -400. Hope that helps.
Would love to see videos of Statics (structural engineering maths like are used in both engineering and architecture). I found your video on resultant of 3 vectors (this video) and you explained it so much more easily than the professor of the class my adult kid is taking. You do a great job of, how do we say, "explain it like I'm 5 years old", which is exactly what lost students need more of! Or reach out if you do any tutoring :)
I would eventually like to do a statics series of videos, but the amount of time it takes vs the reward through you tube is so small. One day I hope to be able to get to that.......
Make sure you put the negative component in parentheses. Many calculators are programmed such that -2 squared is -4 but (-2) squared is 4. Also, make sure you are using the negative key and not the subtraction key. The negative key is usually look like (-) or +/- Please let me know if this solved your problem.
I have lots more videos (and will actually be uploading a large bunch later this semester) but they are math videos. Since I am a math teacher, that is what I focus on. I am hopeful that some of my videos can help you in physics. Search through my others, as there are many trig videos that can help. Glad this one helped you.
@zepfuck - Not sure what you are asking, could you rephrase your question? By definition in mathematics all clockwise angles are considered in the negative direction if that is what you are referring to. If you can clarify your question, I would be glad to help.
Both are forces, so the problem would be the same. If you change the units in the problem to N, the resultant force would be the same number, but the units would be N. I hope this helps.
Just a quick back of the napkin calculation, I come up with a resultant of roughly 152 N. Because all of these are East of North, they will be additive......I think 70 N is way too low.
How do you know what direction the vectors are supposed to be pointing? When that one vector says 160 lbs at 25 degrees, is that 25 north and south of the X axis? Y axis? Negative X or Y?
Standard position of an angle is from the positive x axis, rotating counter clockwise. Depending on how you solve the problem, you will usually get angles as reference angles. I have some other videos that talk about Standard position vs. reference angles. Best to check those out. If you don't have a strong grasp of trigonometry rules, vectors will give you a lot of trouble.
Is there a topic from Statics that you would like to see? I am a math teacher, but my background is mechanical engineering, so I would be glad to help.
@@justcharacter2098 all of our basic trigonometric definitions are based on the x-axis, so you will see that I do everything from that axis. You can reference from the y-axis, but it takes some work. I find that trying to explain that in a video tends to overcomplicate it. So the simplest way to work any problem involving trigonometry - always reference to the nearest x-axis. I hope that helps explain it.
Anyone ever tell you, you sound like the son on King Of The Hill? well anyways slowly crawling through your play-list because my teacher apparently neglects critical aspects to help curb my learning curve. Great vids!! this is the beginning of a beautiful Subscription.
Thank you so much. What would you do in the case that the vector is at an angle of 270˚. Would the angle be changed to 90˚. Also when the vector is right on the x or y axis how would you know if the x or y values for the eqaution are positive or negative since they're not in a quadrant.
90 and 270 are "basically" equivalent. Here is the quick and dirty.... Your x-components will be positive in Quadrants I and IV because the x-axis is positive there, and negative in Quadrants II and III because it is negative there. Same with y. When a vector lands on a quadrant line, it doesn't have both components. For example, let's say you have 100 pounds at 270 degrees, the components would be < 0, -100> or x = 0 and y = -100. This is due to the fact that the force is acting in the negative y direction. The longer explanation is the value of sine and cosine at quadrantal values (0, 90, 180, 270). Does that help?
On 4:01 - isn't it supposed to be 160(cos(65)) and not 160(cos(25)), because it looked like you were getting the angle 25 from quadrant 3 and not from quadrant 4. In quadrant 4, you should've done 90 - 25 = 65. I might be wrong so please, if so, correct me. Thank you
In trigonometry, all of your functions are defined based on the x-axis. So if not measured from the x-axis, then we need to find the complement (90 minus that angle). Let me know if that makes sense why I did what I did.
The most methodical way this topic was explained. Thanks you & I love your accent.
This guy made more sense than every other tutor on this topic.
Yes
He really did
Thank you for this!
Was lost in Physics lectures and been stumped trying to review notes and do the work, this video made it stick with me.
10/10
You got 10 likes lol
Anyone watching in 2024 best tutor so far on this topic 🙏🙌🙌
I was having a hard time understanding the negative and positives signs. Your explanation is crystal clear. Thank you so much brother.
Fantastic explanation!
very good job..
thank you very much
Students nowadays are so lucky
there is literally no excuse for not doing well. When I went to college circa graduation 1979 there was nothing to help except a pay tutor or family member
no PCs no You tube , maybe a library but no calculators....nothing.
I picked up my 41 yr old text book and tried to do a problem but no avail
so listened to this video and within 15 minutes it all came back.
7 years after this was posted and this really helped me with a problem I was stuck on!! thanks so much
I have spent an hour trying to find a video to help me understand this... you are the ONLY one that I understood! thank you!
This is a very common method in mechanical and civil engineering. Glad you liked it.
you are the tutor ive been looking for
One of the best explained videos regarding vectors thank you so much. you got me out of a big hole by your skill of explaining these equations. Everything kicked in after watching your video. Thank you Aggieer
Great teaching . It is real simple and easy to understand.
brilliant video. I didnt quite understand the mathematics behind finding the answer prior to watching this but now i do. thank you very much :)
This was so helpful! I've been lost in my Honors physics class and this totally cleared it up! Thank you so much :)
I cannot find the words to express just how much gratitude I have towards you
Amazing video and the greatest explanation I have seen so far. Thank you!!
You gave the most amazing explanation. I can't believe how simple you made this out to be!! You rock!! Thank you so much!!
Your pen is so cool :00 and thank you so much for this lesson! It really helped me
I was confused at the negative theta.Now I know how to do it!Thank you sooo much!
Thank you soo much *-*, Even my classmates were seeking help from me after I understood this thanks to your video!
Really! this was really a good help for me since I'm kinda bad with numbers!
This video from 9 years ago made so much more sense than the new videos on this topic. I will be using this table its such a good idea 💡
Im thankful this vid exist. I stucked for long time then get the answer by using your solution . Thank you !
Thank you so much... I was trying to solve mean wind vectors and had forgotten how to solve it!!! Thanks for the concise yet brilliant video!!!
This tutorial was amazing. Really well explained at a pace that was great for me.
You sir, just saved my life. Thank you very much. :)
Even 10 years later this remains useful, never got taught this method probably because I don’t live in America but man this makes everything so much simpler
thank you so much. i kept seeing videos of people solving without reference angles.
Missed a zoom meeting and you saved me. Very easy to follow, especially since you gave us the formulas
Thank you so much! Your explanation is easy to understand for a non-english speaker like me 😢. And you helped me
Thank you, you save my force table lab report. This is much easier than to use parallelogram rule.
IKRRRRRRRRRR
Thank you! Great and simple explanation :)
@ archie lim:
Trigonometric functions use standard notation that is defined from the x-axis. So the 160lb force has an angle that is referenced to the x-axis and we use it. The other two forces have angles referenced to the y-axis, so we must find the angle they make with the x-axis and use it. I hope this helps.
hey is the resultant force same as magnitude. please helpp
Darlina Dzaqura
Yes, the resultant force is the magnitude of the three forces combined. Every vector has both magnitude and direction. The magnitude will be a unit (kg, lbs, m/s, etc) and the direction will be which way that magnitude is pointing.
omg thank you sooo much
Are the formulas Mag=(fx2+fy2)^1/2 and theta=tan-1(Fy/fx) applicable for any problems?
Excellent tutorial.. it was so simplified with full details of everything required 😌 thanks a bunch ... I'm having my physics exams tomorrow and this has really helped me alot😊❤🎉
I love his southern accent and its also super helpful
Sir this video help a lot this topic was giving me a lot of trouble and now its easy
Thanks for this video! I was looking for one on how to find a vector using the resultant and one vector and your table really helped be see how to work it backwards!
It is just a way to organize your numbers so that you don't "misplace" any. When working structural problems where you have forces and moments in three dimensions, it makes it a lot easier to keep up with all the information.
Glad that it could help you.
You r amazing.....👌👌👌
You are a life saver I tried every website I only understood you
always trust a cowboy, great video explained really well and didn't skip anything thanks heaps!!
An angle of 270 degrees is on the negative y axis, so the x component would be zero and the y component would be -y (or -r in vector terminology).
So if you have a force of 400 lbs at 270 degrees, the x component would be x=0, and the y component would be y = -400.
Hope that helps.
This was very helpful and well explained.
Would love to see videos of Statics (structural engineering maths like are used in both engineering and architecture). I found your video on resultant of 3 vectors (this video) and you explained it so much more easily than the professor of the class my adult kid is taking. You do a great job of, how do we say, "explain it like I'm 5 years old", which is exactly what lost students need more of! Or reach out if you do any tutoring :)
I would eventually like to do a statics series of videos, but the amount of time it takes vs the reward through you tube is so small. One day I hope to be able to get to that.......
Great video and very easy to comprehend
Thank you so much for this tutorial. It was much needed !!!
Thank you so much. This is really helping with my physics homework.
Timeless value shared 🙌
Thanks man. Very easy and helpful explination
This guy can teach. Well done
Make sure you put the negative component in parentheses. Many calculators are programmed such that -2 squared is -4 but (-2) squared is 4. Also, make sure you are using the negative key and not the subtraction key. The negative key is usually look like (-) or +/-
Please let me know if this solved your problem.
Very educative.i wish I wish I could go back to school.
thank you so much for such amazing and understandable content.and it really helps me to clear my concept in better way .
Thanks for the concept to find magnitude and direction be blessed
Great Video! I finally got it! Thanks a lot!!!
I have lots more videos (and will actually be uploading a large bunch later this semester) but they are math videos. Since I am a math teacher, that is what I focus on. I am hopeful that some of my videos can help you in physics. Search through my others, as there are many trig videos that can help. Glad this one helped you.
Thanks for the video.
Hi there, just need a clarification on- why it can't be 180-69.68 as well, as tan is negative in 2nd quadrant too? thanks
you help me a lot. thank you so much. you are a great teacher!
Thanks thanks u saved my life ❤❤❤
it'S very good thanks
@zepfuck - Not sure what you are asking, could you rephrase your question? By definition in mathematics all clockwise angles are considered in the negative direction if that is what you are referring to. If you can clarify your question, I would be glad to help.
best explanation ever!!
THANK YOU
THANK YOU SO MUCH THIS WAS SO HELPFUL
Thank you so much sir you are amazing
thank you so much, i had trouble staying awake in class today, you just saved my homework grade.
Both are forces, so the problem would be the same. If you change the units in the problem to N, the resultant force would be the same number, but the units would be N.
I hope this helps.
Thank teacher.
THANK YOU! YOU REALLY DID A GOOD JOB! :D
this is really very interesting
Thanks for this video,it was so helpful to me
Thank you very much, my Physics teacher did not explain clearly on how to do this!
Just a quick back of the napkin calculation, I come up with a resultant of roughly 152 N. Because all of these are East of North, they will be additive......I think 70 N is way too low.
Thank you so much!
Thank you for the video. It really helping me
The gift that keeps on giving 🔥
How do you know what direction the vectors are supposed to be pointing? When that one vector says 160 lbs at 25 degrees, is that 25 north and south of the X axis? Y axis? Negative X or Y?
Standard position of an angle is from the positive x axis, rotating counter clockwise. Depending on how you solve the problem, you will usually get angles as reference angles. I have some other videos that talk about Standard position vs. reference angles. Best to check those out. If you don't have a strong grasp of trigonometry rules, vectors will give you a lot of trouble.
Excellent
This was really good! Tysm
We need more professors like you. Can you please make videos for Physics 2? Electromagnetism? and more statics videos as well! Gig'em!
Is there a topic from Statics that you would like to see? I am a math teacher, but my background is mechanical engineering, so I would be glad to help.
@@aggieneer02 hello, may I ask why you also did not subtract the 25 degree angle from 90 degree on quadrant 4?
@@justcharacter2098 all of our basic trigonometric definitions are based on the x-axis, so you will see that I do everything from that axis. You can reference from the y-axis, but it takes some work. I find that trying to explain that in a video tends to overcomplicate it.
So the simplest way to work any problem involving trigonometry - always reference to the nearest x-axis. I hope that helps explain it.
great explanation, thank you
sick video bro
Thanks very much
This man is using a goddamn fountain pen
Still do. Love them!
@@aggieneer02 well sir hats off to your impeccable style!
very simple and answer my query. my query , i am trying to solve but can't , may i learn more from you
Anyone ever tell you, you sound like the son on King Of The Hill? well anyways slowly crawling through your play-list because my teacher apparently neglects critical aspects to help curb my learning curve. Great vids!! this is the beginning of a beautiful Subscription.
THANK YOUUU SOOO MUUCCHHH! I finally understood everything! Thanks!!!
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Thanks you😘😍
Great ,thank you so much :)
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This was so helpful 🔥
I love the fountain pen!
Thank you!
THANK YOU SO MUCH!! so that's how it was done :)
Thank you brother I finally understand it
I can make the time machine now
LOL - good one.
Thank you so much. What would you do in the case that the vector is at an angle of 270˚. Would the angle be changed to 90˚. Also when the vector is right on the x or y axis how would you know if the x or y values for the eqaution are positive or negative since they're not in a quadrant.
90 and 270 are "basically" equivalent. Here is the quick and dirty....
Your x-components will be positive in Quadrants I and IV because the x-axis is positive there, and negative in Quadrants II and III because it is negative there. Same with y. When a vector lands on a quadrant line, it doesn't have both components.
For example, let's say you have 100 pounds at 270 degrees, the components would be < 0, -100> or x = 0 and y = -100. This is due to the fact that the force is acting in the negative y direction.
The longer explanation is the value of sine and cosine at quadrantal values (0, 90, 180, 270).
Does that help?
Yes, thank you so much.
Thanks alooooooot
your explanation helped me
I was struggling to understand it before my physics paper but thanks to I got it
never seen it done this way, its great thanks
On 4:01 - isn't it supposed to be 160(cos(65)) and not 160(cos(25)), because it looked like you were getting the angle 25 from quadrant 3 and not from quadrant 4. In quadrant 4, you should've done 90 - 25 = 65. I might be wrong so please, if so, correct me. Thank you
In trigonometry, all of your functions are defined based on the x-axis. So if not measured from the x-axis, then we need to find the complement (90 minus that angle). Let me know if that makes sense why I did what I did.
@@aggieneer02perfect, I understand thank you 🙏
God bless you and your pen
Thanks for this!
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