Archimedes Eureka : Measuring Volume by Displacement | Physics

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Qno1 Ans 300ml
On second we can take a water resistant body open it and fill the soluble substance
1}first measure volume of water resistant body without substance
Assum it is (Xcm^3) or (X ml) by Archimedes Principle of Volume
2}Now measure along with substance again with Archimedes Principle of Volume
Now Assum it is
(X subscripted with 2 cm^3)
Substract 1 from 2
Qno 3- (50×50×40)cm^3

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I know it is the crow! Since Archimedes lived in Greece after such fairy tales. So I believe it is the crow.

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[@shuklahariom1972]

1---- volume is 300 cm3.
2----Using Archimedes principle, and putting into other liquids.
3----displaced volume equal to volume of partially emerged object.40cm3.

[@ManochaAcademy]

Very good!! Q1 and Q2 answers are correct!
For Q2 you should also mention that solid should be insoluble in the liquid.
Q3 answer is not correct.
For full solutions you can watch this video: ua-cam.com/video/8_lKYI9Zeug/v-deo.html

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[@bhavaninelavalli5491]

1st one=300ml
Initial volume=700ml
Final volume when ball is immersed completely=1L=1000ml
Volume of the ball=volume displaced when the ball immersed in liquid-volume of initial beaker=1000-700=300ml

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[@shivashiv8173]

1; 300cm cube
2; By Archimedes principle, when solid soluble completely in water the water level rises up. So i applied when a body is fully immersed the volume of water displaced by object is equal to the volume of object submerged....
3; 62,500 cm cube

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Q1 answer is correct, but you need to convert it into SI units.
For Q2 and Q3 solutions, you can watch this video: ua-cam.com/video/8_lKYI9Zeug/v-deo.html

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Q2. The volume of an irregular solid is measured by dipping the solid into beaker filled with water,then measuring the distance displaced between it.
Q3. 40cm.

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2nd one=
Final volume when solute is mixed in solvent-Initial volume when solute Isin't mixed in solvent like water

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