Q1) I. 30g II. 30gf Q2) Apparent weight of floating body is weight of body when it is fully or partially immersed in water. Q3) I. 5000 cubic centimetre II. 4000 g
The best physics channel on UA-cam - he pauses as he’s talking so you can take notes and think about the concept, the visual demonstration, the simplicity of the equation, puts some example problems and make it very applicable to everyday life with the example he gave about swimming with his daughter. Very good!!
Great to hear that video was helpful :) Thanks!! Also try the Quiz and Top 3 Questions for this video here: www.manochaacademy.com/physics/archimedes-principle/l/archimedes-principle
1-loss in weight is 200 -170=30. (ii) buoyant force is equal to liquid displaced so it is 30g f. 2- New weight of object while coming in contact with fluid due to upward force or buoyant force. 3- (i) volume of body is equal to volume displaced so it is 1000cm3. (ii) It is 3kg.
I appreciate so much when someone can explain a complex subject in a easier way. I always hated physics, but with your lectures, you changed my feeling about physics. Congratulations, Sir. You deserve an award price!!! You are the best.
Sir you spent so much time for replying and reading our comments. This video was uploaded 3 years ago and you are still reading and replying to our comments. Salute to you.
I am completed engineering last one year. now I can understand Archimedes principle along with applied level This type of teach need our education system
Honestly, I haven't read the explanation on my module and just watch this video. This is the best explanation for this topic! I didn't regret watching this. Thank you, Sir.
Ok I will be honest.....I just hated This Topic in my textbook...But you saved me sir....I understood it from you....and now I am commenting because a whole long question on Archimedes Principle came in our exam....And I was able to answer it perfectly.....Thank you so much Sir
This is great. I enjoyed it better than I did over 20 years ago in secondary school. Spurred by curiosity, I was waiting you would pour the displaced water (200g) in the second trasparent flask back into the main flask so that the red ball (at the depth of the main flask)can gain upward thrust and float again.
1st) a)loss of weight = weight in air - weight in water 200gf-170gf = 30gf b) buoyant force = upward force buoyant force = loss of weight so buoyant force = 30N 2) apparent weight of a floating body is the weight of the body in water
Please sir check my answers 1. 30gf 1b. Buoyant force is also known as upward force, if upward force is equal to the weight of the fluid displaced, therefore buoyant force is =30gf 2.the apparent weight of a floating body is the weight of a body in a fluid. 3. Apparent weight of the body in water, I changed 5kg to grams having 5000gf, I subtract it from the displaced water 1000 5000-1000=4000 So I have 4000 as my apparent weight Please sir check I I am correct and thanks for the lecture.
Q1 answer is correct :) Q3 volume is 1000 cm3 and apparent weight = 4kgf or 40 N. For more detailed answers you can see the solutions video: ua-cam.com/video/TBX5Za2SxT8/v-deo.html
Man, I really appreciate it, I'm studying right now for my experimental physics test 1 which is in a few hours, as each experiment is a week and can't be repeated, I was having difficulty finding teaching material in video format on the internet, incredible video
Q2 define coz it is not related to Q1 for me Q3b =4kg or 40N since density of water =1000kg/m^3 units conversion matters upward force=10N or 1kg | Fup=1000kg/m^3 *0.0001m^3*10N/kg =10N | Fup=Real-Apparent | =5kg-1kg
This is great 👍 I love the fact that you explain it in a different voice. Thank you for breaking it down Other videos don’t break it down, they just do it
Sir can you please tell me the ans. of: Q. If two balls made of iron and aluminium of equal volumes are immersed in a liquid then will they experience equal upthrust?? Justify.
Good question! Yes they will experience equal upthrust. As I discussed in the video, upthrust = volume of displaced liquid x density of liquid x g. Since the two balls have same volume and both will sink, so volume of displaced liquid will be equal. That's why upthrust will be same.
Obviously!That's why if you study physics book of good author,say HC verma,you will find that they had given this concept in the chapter Newton's law of motion
At 60 y/o I did not understand this. I appreciate very much your explaining it so I am able to understand. I'm not "physics" literate at all but find the topic fascinating. Now, using this same swimming example...please explain to me (because forensics is also fascinating to me) when one is swimming..water helps us stay afloat however, at some point the body will sink rather than float (because of loss of life for example 《drowning》). What causes this? Simplified please as done in this video. Thank you so much. Sharing your knowledge with others is so generous of you and greatly appreciated.
the video is just amazing, you took your time to eplain the topic but didnt take forever. With classes being all online due to COVID-19, the labs have been tough but you explain it well. thank you:)
I watched a few videos that explained the topic, but I could not get a solid grasp on the concept. I felt dumb due to all the positive comments the videos had, wondering why it was difficult for me to understand. Your videos finally made it clear for me. Thank you.
please check if my answers are correct i. 30gf ii. 0.3N 2.It is the weight of the body when fully or partially immersed in a fluid 3i. 1000 cubic cm ii. 4N thanks a million Mr. Manocha👍
very easy way to get Archimedes principle. Thank you, man! You are the greatest teacher. Can you say, where did you get this ball with coins? It's very useful
I watched many videos but nothing seemed convincing. We had to write a report on this topic for physics as this is a deleted topic for 2020-21. So I had to learn about it and write. This video made me understand completely. Thank u so much
I am Doing Engineering from mechanical branch (1st year) & i came here just to revise my concept on this topic , but surprisingly it gave me much better concept than previous one !! Thanks a lot sir , you are just simply Awesome 👍🏻👍🏻👍🏻
@@ManochaAcademy sir please make videos on 11&12th physics , like you make on this "Archimedes" Topic , it will be very helpful for us bcoz the way of your teaching is Excellent !! 🙏🏻
Could you please tell me for what class it is recommended but I don't know what class it is recommended and I am 9th class and I learnt that Archimedes principle it is very easy to understand for myself without anyone help and I am a big fan of you sir in studies of course I suggested this channel to my friends thank you sir so if you don't mind could you please make a video on reflection of light at curved surfaces and I wish you to make many important videos like this for students in a simple way of course you are explaining in in a simple way again a big thank you sir
Peace, mercy and blessings of Allah . I am from the tenth grade of primary school, from Jordan , I speak Arabic, but the method of explanation is very beautiful, and I enjoy your explanation. Your terms are craving English. May Allah grant you success and happiness. My prayer to you is luck and success.
I’ve always struggled with physics, but after watching your video on Archimedes’ Principle, you are now my favorite physics teacher. The way you break it down is so much easier to understand than how my teacher explains it in class. Thank you for helping me finally grasp this concept!
F = ma (F = Force, m = mass & a = acceleration) (1N = 1 kg × 1m/s^2) W = mg (W = weight, m = mass & g = acceleration due to gravity = 9.81m/s^2) 0.6 = m × 9.81 m = 0.6/9.81 = 0.06116kg = 61.16g Desity of water = 1 g/cc 1g of water = 1cc 61.16g of water = 61.16cc Volume of body = 61.16cc
1,(i) 30g (ii)30gf 2 (i) Equal to the real weight 3,(i) we know volume of object=volume of displaced fluid 1000cm^3 (ii)apparent weight = 4kg or 4000g Sir please leave a comment below if my answers are correct
the second question answer is 0. when an object is floating ,it is said that its real weight is equal to the upthrust. then,apparent weight= real weight - loss in weight or upthrust . as both gets cancelled as they are equal ,the answer is 0.
Answer to Q3 (1) We got Buoyancy = 1000 cm Density of water = 1000 kgm cube Acceleration due to gravity = 9.8 m/s We know , U = vdg 10 = v . 1000 . 9.8 (10/9800) = v Therefore, v= 1/980 m cube
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I am the first one to like this
If this way Physics was teached in my school,i would have loved it.Well explained Sir!!
Happy to help
Me to but our teachers was telling us funny things.
@@habiyt1286 yeah koi tarika haii bhik magne ka?
@@aryanpathak23 Bhai ham bhik Nahi many rahe h
@@habiyt1286 toh bhai kitne bade subscribers? 9k?🤣
Watching as a 45 year old to teach my son , I was blown away by the simplicity of your explanation. Excellent job . Keep it up .
Q1) I. 30g
II. 30gf
Q2) Apparent weight of floating body is weight of body when it is fully or partially immersed in water.
Q3) I. 5000 cubic centimetre
II. 4000 g
The best physics channel on UA-cam - he pauses as he’s talking so you can take notes and think about the concept, the visual demonstration, the simplicity of the equation, puts some example problems and make it very applicable to everyday life with the example he gave about swimming with his daughter. Very good!!
😔💔And to think I only found this now after struggling with this for a month. You saved me
Great to hear that video was helpful :) Thanks!! Also try the Quiz and Top 3 Questions for this video here: www.manochaacademy.com/physics/archimedes-principle/l/archimedes-principle
It to
Good
Good teachet
The water toy I worked on for 25 years is above or below this one, on 9-6-2020
1:04 I love the way sir made his voice deeper to tell those quoted words.
1-loss in weight is 200 -170=30.
(ii) buoyant force is equal to liquid displaced so it is 30g f.
2- New weight of object while coming in contact with fluid due to upward force or buoyant force.
3- (i) volume of body is equal to volume displaced so it is 1000cm3.
(ii) It is 3kg.
How 3 kg
it's 4kg not 3kg
I appreciate so much when someone can explain a complex subject in a easier way. I always hated physics, but with your lectures, you changed my feeling about physics. Congratulations, Sir. You deserve an award price!!! You are the best.
Sir you spent so much time for replying and reading our comments. This video was uploaded 3 years ago and you are still reading and replying to our comments. Salute to you.
Thanks
I am completed engineering last one year. now I can understand Archimedes principle along with applied level
This type of teach need our education system
Happy to help
Thank you so much! I was dreading this principle in my MCAT prep and now I can understand it in terms of variables and common language haha
Happy to hear that video was helpful :) All the best for your MCAT prep! Do check out more videos at www.manochaacademy.com
Honestly, I haven't read the explanation on my module and just watch this video. This is the best explanation for this topic! I didn't regret watching this. Thank you, Sir.
You are a great teacher, I had been reading about this principles from my high school to date but not clear to me like know
Glad it was helpful!
I wish you was my Physics teacher. Everything is clear to me now. thank you sir
Ok I will be honest.....I just hated This Topic in my textbook...But you saved me sir....I understood it from you....and now I am commenting because a whole long question on Archimedes Principle came in our exam....And I was able to answer it perfectly.....Thank you so much Sir
Q1
ans 1a is i) loss in weight 30 and ii) buoyant force is 30 N
Q2
the apparent weight is 170
And third
It's wrong apparent weight of a floating body will real weight of the object - bouyant force
@@clashonchappati2345 yeah u r correct
Wrong apparent weight of floting body will be zero
This is great. I enjoyed it better than I did over 20 years ago in secondary school. Spurred by curiosity, I was waiting you would pour the displaced water (200g) in the second trasparent flask back into the main flask so that the red ball (at the depth of the main flask)can gain upward thrust and float again.
Glad you enjoyed it!
1st) a)loss of weight = weight in air - weight in water
200gf-170gf = 30gf
b) buoyant force = upward force
buoyant force = loss of weight so
buoyant force = 30N
2) apparent weight of a floating body is the weight of the body in water
Great job I am from pw
Somebody give this guy an award!✊🏿✊🏿👷
Hats off.... I am a teacher and surely share this video with my atudents
Please sir check my answers
1. 30gf
1b. Buoyant force is also known as upward force, if upward force is equal to the weight of the fluid displaced, therefore buoyant force is =30gf
2.the apparent weight of a floating body is the weight of a body in a fluid.
3. Apparent weight of the body in water, I changed 5kg to grams having 5000gf, I subtract it from the displaced water 1000
5000-1000=4000
So I have 4000 as my apparent weight
Please sir check I I am correct and thanks for the lecture.
There are no teachers like this....... Ever after never before
You are so practical with your lectures and I appreciate that.
Thanks for liking
This channel must have 1 Million subscribers soon.
Thanks
You do a good job of giving priority to physics first.
1answer = 30gf
2answer = 30gf
And answer of question no 1of 3 = 5000cm cube
2 = four kg
Q1 answer is correct :)
Q3 volume is 1000 cm3 and apparent weight = 4kgf or 40 N.
For more detailed answers you can see the solutions video: ua-cam.com/video/TBX5Za2SxT8/v-deo.html
After watching this video ,I could improve my knowledge about Archimides principle well .I am grateful for you sir ☺️ Much love from Nepal
Man, I really appreciate it, I'm studying right now for my experimental physics test 1 which is in a few hours, as each experiment is a week and can't be repeated, I was having difficulty finding teaching material in video format on the internet, incredible video
You are clear, vivid and comprehensive. Carry on teaching this way buddy. I have recommended your videos to my students and kids.
Ans 1 a) 30 gf
b) 30 gf
Ans 2 0 gf
Ans.3 a) volume of the body= 1000 cm^3
b) apparent weight of the body= 4 kg
Q2 define coz it is not related to Q1 for me Q3b =4kg or 40N since density of water =1000kg/m^3 units conversion matters upward force=10N or 1kg | Fup=1000kg/m^3 *0.0001m^3*10N/kg =10N | Fup=Real-Apparent | =5kg-1kg
Wow... Loved it. I wish I was thought like this in school
Thanks
Manocha Academy Thnx a lot
Best physics teacher ever
Wow ! Thanks
This is great 👍
I love the fact that you explain it in a different voice. Thank you for breaking it down
Other videos don’t break it down, they just do it
Glad it was helpful!
One more thing
Can you not actually say the mathematical formulas pleas like gram force that is confusing
Sir can you please tell me the ans. of:
Q. If two balls made of iron and aluminium of equal volumes are immersed in a liquid then will they experience equal upthrust??
Justify.
Good question! Yes they will experience equal upthrust. As I discussed in the video, upthrust = volume of displaced liquid x density of liquid x g. Since the two balls have same volume and both will sink, so volume of displaced liquid will be equal. That's why upthrust will be same.
@@ManochaAcademy Thank you so much sir..
I'm from Ethiopia 🇪🇹 thank you very much
I was really not understanding this concept before I saw this video thanks for explaining it in a simple way
Glad to hear that
1.) 30 GF
2.) Weightless due to Buoyant force
3.) 40N
Awesome lecture, sir! It was really interactive and interesting.
Many thanks!
archemidies principal is almost like newtons 3rd law of motion which says (EVERY ACTION HAS AN EQUAL AND OPPOSITE REACTION)
Obviously!That's why if you study physics book of good author,say HC verma,you will find that they had given this concept in the chapter Newton's law of motion
@@00ANURAG15 ncert + ncert exampler is enough no need of any other book till grade 10
yeah Quran is right
This is the best explanation video about the Archimedes principle I've seen
Glad it was helpful!
@@ManochaAcademy sir, may I ask, is there a proper details for the experiment?
,
you are really A great teacher, THANKS A LOTTT SIR, MAY GOD BLESS YOU FOR HELPING US TO UNDERSTAND THE CONCEPTS CLEARLY.
You are most welcome
Thanks very much for simplifying this. I'm in my 3rd year studying civil engineering but I never fully grasped the concept of buoyancy.
Q1)1) Loss in weight of the object = 30gf
2) Buoyant force on the body = 30gf
Q2) Apparent weight = real weight -upward force
I have also a teacher in my school who exactly teach like this teacher 😃
Thank you so much sir ☺️💗
It's my pleasure
1(i)apprant weight = 200g - 170g
30g loss of weight
I always think that why only few good teachers are present in schools
At 60 y/o I did not understand this. I appreciate very much your explaining it so I am able to understand. I'm not "physics" literate at all but find the topic fascinating. Now, using this same swimming example...please explain to me (because forensics is also fascinating to me) when one is swimming..water helps us stay afloat however, at some point the body will sink rather than float (because of loss of life for example 《drowning》). What causes this? Simplified please as done in this video. Thank you so much. Sharing your knowledge with others is so generous of you and greatly appreciated.
Density is also an index parameters to compare. Pin has high density than water , so it sinks where woods has low density than water, so it floats
Qn3ans:1000cm cube=1000g=1kg there fore apparent wt of body=5-1=4kg. We can also find volume. Writing is required
the video is just amazing, you took your time to eplain the topic but didnt take forever. With classes being all online due to COVID-19, the labs have been tough but you explain it well. thank you:)
Glad you enjoyed it!
Your videos are the best on youtube. Great explanation sir!!! Thank you
Ausum sir......... Very nice....... Good for understanding......
Thanks for liking
I watched a few videos that explained the topic, but I could not get a solid grasp on the concept. I felt dumb due to all the positive comments the videos had, wondering why it was difficult for me to understand.
Your videos finally made it clear for me. Thank you.
This is the first vide I’ve ever found on UA-cam that actually makes me understand science
Super sir Indian students want this type of explanation . Thank you very much sir
please check if my answers are correct
i. 30gf
ii. 0.3N
2.It is the weight of the body when fully or partially immersed in a fluid
3i. 1000 cubic cm
ii. 4N
thanks a million Mr. Manocha👍
U are wrong. Saiiiin
@@freeguy6227 1) ii
30gf
Awesome video❤🔥☺...We watch your video together in our science class with our teacher...She really appreciated you😊 ...Great lesson thank you😇
Glad to hear that. Most welcome
🙌 A few decades out of high school, use of relatable illustrations and easy explanation has unlocked the concept. Keep it up
A.(1) 30gf(30N)
(2)30N
B. Apparent weight is the weight of the body in water
C.(1) 4000
(2)4000
SIR I LOVE YOUR FABULOUS WAY OF TEACHING ...YOU MAKE THE 100% CONCEPT CLARITY 👍👍👍 GREAT WORK SIR
Thanks for liking
I'm from Poland and ur pronunciation is just great for me ;)) perfect video
Thank you! 😃
very easy way to get Archimedes principle. Thank you, man! You are the greatest teacher. Can you say, where did you get this ball with coins? It's very useful
Just fill a empty gems ball with some coins
I watched many videos but nothing seemed convincing. We had to write a report on this topic for physics as this is a deleted topic for 2020-21. So I had to learn about it and write. This video made me understand completely. Thank u so much
Excellent
I am Doing Engineering from mechanical branch (1st year) & i came here just to revise my concept on this topic , but surprisingly it gave me much better concept than previous one !! Thanks a lot sir , you are just simply Awesome 👍🏻👍🏻👍🏻
You are most welcome
@@ManochaAcademy sir please make videos on 11&12th physics , like you make on this "Archimedes" Topic , it will be very helpful for us bcoz the way of your teaching is Excellent !! 🙏🏻
Amazing sir 👌
Thanks a lot
It's very glad to see this type of clean and clear information video 😍
Thank you!! Also try the Quiz and Top 3 Questions for this video here: www.manochaacademy.com/physics/archimedes-principle/l/archimedes-principle
I am really thankful to you sir really appreciated thing
Could you please tell me for what class it is recommended but I don't know what class it is recommended and I am 9th class and I learnt that Archimedes principle it is very easy to understand for myself without anyone help and I am a big fan of you sir in studies of course I suggested this channel to my friends thank you sir so if you don't mind could you please make a video on reflection of light at curved surfaces and I wish you to make many important videos like this for students in a simple way of course you are explaining in in a simple way again a big thank you sir
Peace, mercy and blessings of Allah . I am from the tenth grade of primary school, from Jordan , I speak Arabic, but the method of explanation is very beautiful, and I enjoy your explanation. Your terms are craving English. May Allah grant you success and happiness. My prayer to you is luck and success.
I’m speechless sir...thanks a lot ....all my questions are cleared bcoz of ur video..thanks again👌🏻👏🏻
Great to hear that the video was helpful! Thanks! Do check out more videos at www.manochaacademy.com
You are a fabulous teacher. It became easy for me to understand. Thank you.
Great to hear that you liked the video :) Do check out more videos at www.manochaacademy.com
Really well explained Sir!!
Thank You!
Most welcome!
I am not a science person... floating of ship just popped and I searched....this is the best video for explanation to layman....thanku sir 😁
Glad you liked it!
Wow I understood it now
Thanks alot
I just wish, physics can be taught like this at my side 😪
I’ve always struggled with physics, but after watching your video on Archimedes’ Principle, you are now my favorite physics teacher. The way you break it down is so much easier to understand than how my teacher explains it in class. Thank you for helping me finally grasp this concept!
u r great sir ...u made my doubt clear ......
I started understanding physics thank you sir
😂😂i know the concept but still lost because i wrote 'upwold' instead of upward force 😂😂😂😂😂😂😂😂
Q-1: (1)-30 gs ,(2)-30N
Q-2: Real weight-upward force(or)
Weight in water
Q-3:(1):1000cm3
(2):4 kgs
Thanks for breaking up the definition and making it easier to understand.
Happy to help!
help me this question:
a body lost 0.6N in weight when immersed in water. Calculate its volume in cubic centimetres
Answer: loss in wt=0.6N (1N=100g)
=0.6*100
=60g (1g=1mc^3)
so, 60g = 60cm^3=volume
As, loss in weight = buoyancy= amount of water displaced= volume
than you so much i real appreciate for your help, however there some concept which is not clear to me. forexample when you said 1N=100g??? @@El.Primo0
It is relatio between g and cm³
F = ma (F = Force, m = mass & a = acceleration)
(1N = 1 kg × 1m/s^2)
W = mg (W = weight, m = mass & g = acceleration due to gravity = 9.81m/s^2)
0.6 = m × 9.81
m = 0.6/9.81 = 0.06116kg = 61.16g
Desity of water = 1 g/cc
1g of water = 1cc
61.16g of water = 61.16cc
Volume of body = 61.16cc
Excellent work sir. All my doubts are cleared now
Great to hear that!! Thanks :) Do check out more videos at www.manochaacademy.com
Where is the link to the answers to the questions at the end
1,(i) 30g
(ii)30gf
2 (i) Equal to the real weight
3,(i) we know volume of object=volume of displaced fluid
1000cm^3
(ii)apparent weight = 4kg or 4000g
Sir please leave a comment below if my answers are correct
the second question answer is 0.
when an object is floating ,it is said that its real weight is equal to the upthrust.
then,apparent weight= real weight - loss in weight or upthrust .
as both gets cancelled as they are equal ,the answer is 0.
sir this small practicals are so precious to us please make through full syllabus [imp points]
Thank you! Perfectly explained!
Glad it was helpful!
0:38
sir thankkkkk youuuuu soooooooooooo muchhhhhhhh it really helped me a lot
You are most welcome
thanks for supporting us Sr.
you are doing good work
This is awesome>>>much better than taking short snaps reading Books and even sleeping . Really love it
The real weight have to be measured in vaccum as you said air is fluid it also has upthrust
Wow sir it made me easy to learn whenever I not understand what they given in book immediately I saw ur videos and made me easy and helpful
Glad to hear that
Where's the link to the solutions
His passion is evident from how much effort he puts into his videos
Immense thank u..the text book just made me more flummuxed..now I have clear idea about this concept..Really appreciate your effort..
Archimedes Volume Discovery video link ->
ua-cam.com/video/X1VazJC8OLY/v-deo.html
Thank sir, I scored 95% in my 9 exam
Great. Keep it up
Answer to Q3
(1) We got
Buoyancy = 1000 cm
Density of water = 1000 kgm cube
Acceleration due to gravity = 9.8 m/s
We know ,
U = vdg
10 = v . 1000 . 9.8
(10/9800) = v
Therefore, v= 1/980 m cube
Thank you sir ,I was not able to understand the textbook but your video made it easy for me👍👍
For a sunken object why do they have the same buoyant force? VS a floating object that have different buoyant force?
Itz cuz an object floating on water has a lesser upthrust than a sunken object......Hope ya got it.... :)