You really should have checked those complex solutions. Their quartic roots are not equal to their bases. All four satisfy x = x^4, but only the real solutions satisfy x = [x^(1/2)]^(1/2).
Squaring the original equation is no equivalence transformation, so you have increased the solution set. The complex values are no solution of the original equation.
You really should have checked those complex solutions. Their quartic roots are not equal to their bases. All four satisfy x = x^4, but only the real solutions satisfy x = [x^(1/2)]^(1/2).
0 or 1 or 2 solutions from c😊mplex plane byt did you check it? Sqrt of complex numbers giving multiple answers
The music is fine But the problem is worthy
I can't assume x=x^1/4
At the first instance anyone can tell either x=0 or x=1
Squaring the original equation is no equivalence transformation, so you have increased the solution set. The complex values are no solution of the original equation.
X=0,1 solved in mind
Could you write any slower?
?
You can slow down the video.