Chapter 8: Activity Calculation Example | CHM 214 | 080

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  • Опубліковано 4 лис 2024

КОМЕНТАРІ • 3

  • @Eli-s1g8r
    @Eli-s1g8r 10 місяців тому +1

    At ksp equation, Why didnt we multiply the 0.05 M concentration by 2 because of 1:2 ratio of Caf2 to 2F - ions? We assumed it is equal to caf2 molarity still. Is it due to the fact that caf2 does not solubilize well? And also i think we should also muktiply 0.p5 by 2 in the ionic strength calculation. Why we didnt?

    • @jacobstewartchem
      @jacobstewartchem  10 місяців тому +6

      The reason we don't multiply the 0.05 M concentration of F- by 2 is because the F- is essentially all coming from the NaF that's in the solution. Only a very very small amount will come from the dissociation of CaF2, and we can neglect that contribution, which is a very good approximation and makes the math much simpler.

  • @LaibaDar-wl4dg
    @LaibaDar-wl4dg 18 днів тому

    hold on, @2;56 charge for Ca is +2, it only has one ion, arent you supposed to multiply 0.050M with +2 instead?