At ksp equation, Why didnt we multiply the 0.05 M concentration by 2 because of 1:2 ratio of Caf2 to 2F - ions? We assumed it is equal to caf2 molarity still. Is it due to the fact that caf2 does not solubilize well? And also i think we should also muktiply 0.p5 by 2 in the ionic strength calculation. Why we didnt?
The reason we don't multiply the 0.05 M concentration of F- by 2 is because the F- is essentially all coming from the NaF that's in the solution. Only a very very small amount will come from the dissociation of CaF2, and we can neglect that contribution, which is a very good approximation and makes the math much simpler.
At ksp equation, Why didnt we multiply the 0.05 M concentration by 2 because of 1:2 ratio of Caf2 to 2F - ions? We assumed it is equal to caf2 molarity still. Is it due to the fact that caf2 does not solubilize well? And also i think we should also muktiply 0.p5 by 2 in the ionic strength calculation. Why we didnt?
The reason we don't multiply the 0.05 M concentration of F- by 2 is because the F- is essentially all coming from the NaF that's in the solution. Only a very very small amount will come from the dissociation of CaF2, and we can neglect that contribution, which is a very good approximation and makes the math much simpler.
hold on, @2;56 charge for Ca is +2, it only has one ion, arent you supposed to multiply 0.050M with +2 instead?