I’m glad you enjoyed the video! Make sure to check out my website adampanagos.org for additional content (600+ videos) you might find helpful. Thanks, Adam
Yes, we're taking the limit as N goes to infinity of the ratio (N+1)/(2N+1). The numerator has an N, the denominator has a 2N. As N gets large, these terms dominate and the ratio is 1/2. Hope that helps, Adam
Thank you so much. This was a bigger help than my professor.
Glad I could help, thanks for watching.
The video content is so excellent, congratulations
I’m glad you enjoyed the video! Make sure to check out my website adampanagos.org for additional content (600+ videos) you might find helpful. Thanks, Adam
Thanks a lot, needed this extra explanation !!!
Glad I could help, thanks for watching!
hello , you are a big professor, I have one question , in the minute 7:49 ; N+1/2N+1 = 1/2? Tk
Yes, we're taking the limit as N goes to infinity of the ratio (N+1)/(2N+1). The numerator has an N, the denominator has a 2N. As N gets large, these terms dominate and the ratio is 1/2. Hope that helps,
Adam
@@AdamPanagos Great
Lim N->Inf (N+1)/(2N+1)=Lim N->Inf N(1+(1/N))/N(2+(1/N))=Lim N->Inf (1+(1/N))/(2+(1/N))=1/2.
For the first problem if we take impulse(k+3) what will be the answer?
why is alpha raised to power k decreasing on the graph? isnt alpha to the power of 0 less than alpha to the power of 1?
is it because alpha is less than 1?
@@olamideajayi247 Yes, this problem assumes alpha < 1. So, alpha^0 = 1, and alpha^1 < 1. Hope that helps,
Adam
I love you