Calculus 2 Lecture 9.9: Approximation of Functions by Taylor Polynomials

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  • Опубліковано 16 гру 2024

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  • @iaahner
    @iaahner 10 років тому +277

    Very quickly in college you realize that there are two types of professors. Those who are there to teach, and those who are there to conduct a class.
    Thank you for teaching mathematics. Professors such as yourself are the reason I have always loved math. This is a wonderful explanation of Taylor polynomials. Keep it up!

  • @ijlala3799
    @ijlala3799 8 місяців тому +15

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    @UROOZFATIMA190 8 місяців тому +2

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      @ProfessorLeonard  7 років тому +49

      Thanks!!! I actually do have a Patreon account set up. I am very happy to have helped you. :)

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    @yixing2301 10 років тому +4

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  • @restitutororbis964
    @restitutororbis964 6 років тому +1

    Tbh Taylor Polnomials are AMAZING. I might sound super nerdy, but being able to approximate ANY number without a calculator just sounds like pure genius its truly amazing.

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  • @lxmon
    @lxmon Рік тому +1

    I didn't see any comments for this but if you are studying for Taylor's Inequality (Taylor's Remainder Theorem)
    - 5:28

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    @HarshitMishra-zd7wf 5 місяців тому +1

    Thank you sir for all you effort...Now finally I understand approx of taylor polynomial

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    @georgesadler7830 Рік тому +1

    Professor Leonard, thank you for an excellent explanation on the Approximation of Functions by Taylor Polynomials in Calculus. The different examples really breakdown and analyze the Approximations of different Functions by Taylor Polynomials. All Transcendental Functions can be represented as Taylor Series/Polynomials. This is an error free video/lecture on UA-cam.

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    @shutnawi6635 Рік тому +2

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    @888777100 3 роки тому +2

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  • @mikarpman
    @mikarpman Рік тому +1

    If some wants a fourth degree approximation of Sine(x) centered at zero, would they have only 2 nonzero terms because the 2nd and 4th derivatives are zero when c=0 ?

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  • @qualquan
    @qualquan 7 років тому +1

    I made the previous comment because to understand Taylor series (which is nothing but a Polynomial constructed by power integration of serially higher differentials) one must have 2 concepts 1) Concept of the Remainder Error (RE) and 2) How the RE requires a subsequent higher differential. For if the subsequent higher differential ever becomes finally zero, as it can with some functions, then a Taylor series, if used, does come to an end. True one may not need a Taylor series in those functions but its a matter of developing the basic concepts of what a Taylor series basically is.

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    @ericsills6484 2 роки тому +1

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  • @kimchigang42
    @kimchigang42 Рік тому +1

    Guys
    So does Z not have to be bigger than C if the given interval gives us a smaller error value??

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    @aabidmushtaq3243 4 роки тому

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  • @valentinakhan1512
    @valentinakhan1512 6 років тому +2

    Professor Leonard i am having problem with derivation of the error.in my book bartle sherbert they used relle's theorem to prove it.but why rolle's theorem is used i can't understand.please explain me .i can"t understand.

  • @Jasonasked1233
    @Jasonasked1233 6 років тому +1

    Can someone explain why in 1:31:06 does f^(n+1) (x) is +- sin or +- cos?

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    @sandilemabika8656 8 років тому +3

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    @仕欣李-l3b 6 років тому

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  • @abdevilliers8561
    @abdevilliers8561 9 років тому +1

    the second statement of lagranges form of remainder i.e, fn-1 is derivable on open interval (a,b)...why not on closed interval? what mistakes would occur if derivable on closed interval?

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    @kbs7744 6 років тому

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    @physicsi-problems7043 2 роки тому +1

    Always helping bro

  • @IlhamAzlanSyah
    @IlhamAzlanSyah 8 років тому +2

    58:46 If x = 5 and c is 4, it doesn't make any sense to pick Z = 3. Didn't you say that Z must be between c and x?

    • @ShaunStruwig
      @ShaunStruwig 8 років тому

      it can be equal to either c or x too

  • @abdevilliers8561
    @abdevilliers8561 9 років тому +1

    and yah what is the meaning of function is centered at c? i think that centered at c means not at centre always,but c is any point between two intervals....

  • @anandantony9848
    @anandantony9848 5 років тому +1

    Is there mistake at 45:10 in which he writes "around X = 4" instead of "around C = 4" ??

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    @michaelgeinopolos6911 5 років тому

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    @Maari300-le2hb 4 місяці тому +1

    great sir

  • @hollywoodbanayad7755
    @hollywoodbanayad7755 4 роки тому

    Thank you for the explanation, Professor Leonard!

  • @drscott1
    @drscott1 7 років тому +2

    Great lecture! Thank you.

  • @ans72411
    @ans72411 11 місяців тому +2

    Why did you stop uploading😢

  • @wajidalikhan4337
    @wajidalikhan4337 5 років тому +1

    wonderfully well explaination

  • @qualquan
    @qualquan 7 років тому

    True one may not need Taylor series for Functions which have a final derivative which becomes zero but in theory and conceptually we can. I mention those chiefly to emphasize the concept of Remainder Error (RE) and how the RE requires a non zero subsequently higher differential.

  • @juancarrillo6993
    @juancarrillo6993 5 років тому +1

    Professor, do you know what is the approximation in series that is use in calculators and computers due that the Taylor series never end?

  • @alimudarres1246
    @alimudarres1246 6 років тому

    So you calculate the biggest possible error. The value calculated by taylor polynomials of that function is a certain number away from the actual value. Does this mean that the approximated value cannot be "more away" than the calculated error? can the approximated be closer to the actual value, thus closer than the calculated error?

  • @hastyvictories
    @hastyvictories 9 років тому

    06:30
    Isn't the remainder another infinite series from the n+1th derivative to infinity?
    Why is the 7:30 Rn just a single derivative?

  • @godussop9882
    @godussop9882 8 днів тому

    How is choosing c making the erorr larger in the lnx example but 1.1 isnt?