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Apart from other tutors that explain online, this organic chemistry tutor is the best one who has a fair understanding of all other science courses as well.
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My doubts were clarified in the first minutes. But this video is so good that I watched until the final. The examples are well explained. Thanks for the video ❤
For anyone confused about 24:01 , this is why I think it's equitorial and not axial. CH3 and OH, according to the structure needs to be CIS. This means both have to be pointing up. Axial and equitorial bonds alternate up and down, shown in 1:17. If you go in order, axial bonds in carbon 1 should go UP. Carbon 2 axial bonds should go DOWN. Carbon 3 axial bonds should go UP. And carbon 4 axial bonds need to go DOWN. That's why the OH group cant be axial up because any axial group on the carbon 4 needs to be DOWN. Hence, you're forced to put the OH group in an equitorial up position since if you go in order (again), Carbon 1 equitorial bonds should go DOWN, Carbon 2 equitorial bonnds should go UP, carbon 3 equitorial bonds go DOWN, and carbon 4 equitorial bonds go UP. CH3 and OH need to be CIS and the only way to do that is if you do an axial up CH3 and an equitorial up OH.
Wow! Just have to say like everyone else that this video was super helpful and clear! Literally game-changing to understanding such an abstract and visual concept!
At 16:20, when you're doing a chair flip from form B to form A, you said that you move the carbons in a couterclockwise direction, but is it necessary to reverse the direction of the carbons, or just move them back one place? By the way, your videos are amazing, and I use them for practically every subject in school! Thank you so much!
Reading the textbook sent me on a downward spiral lol. 🌀, thanks for your very clear and concise explanation. Sometimes the textbook helps but like sometimes not at all. 😂
Im confused on how you know if the substituents is either axial or equatorial and if they are up or down on on the chair. I understand the ring flip and which one would be more stable but I just dont understand the inital drawing process, someone plzzzzzzzzzz help
Could someone explain to me @21:03. Why the second option has the carbon number starts 1 carbon shifted clockwise rather than at the same place as the first possible chair conformation? Thank you so much!
Hi! Since CH3 is a wedge it needs to be in the upward position regardless of whether it is in the axial or equatorial... in the first diagram he drew CH3 in axial up, which leaves the remaining position to be equatorial down... because of that, for the second diagram, he shifted the numbers clockwise because the next position has equatorial up open so that could be occupied then... I hope this helps
For anyone confused about 24:01 , this is why I think it's equitorial and not axial. CH3 and OH, according to the structure needs to be CIS. This means both have to be pointing up. Axial and equitorial bonds alternate up and down, shown in 1:17. If you go in order, axial bonds in carbon 1 should go UP. Carbon 2 axial bonds should go DOWN. Carbon 3 axial bonds should go UP. And carbon 4 axial bonds need to go DOWN. That's why the OH group cant be axial up because any axial group on the carbon 4 needs to be DOWN. Hence, you're forced to put the OH group in an equitorial up position since if you go in order (again), Carbon 1 equitorial bonds should go DOWN, Carbon 2 equitorial bonnds should go UP, carbon 3 equitorial bonds go DOWN, and carbon 4 equitorial bonds go UP. CH3 and OH need to be CIS and the only way to do that is if you do an axial up CH3 and an equitorial up OH.
I think the equatorial position should be parallel to the C -C bond either to the right or left. I have noticed that you have made some mistakes in drawing the correct structure. Otherwise, you the best tutor that I would always like your videos that simplifies everything. thank you very much.
Thank you so much for your explanation sir! And I have a doubt @24:02 Why do we put the Hydroxyl group in the equatorial up position but not in the axial up position sir?
At 23:05 or even for the previous question, why can't both the groups be in the equitorial plane ? Why one needs to be in the axial and the other in the equitorial plane Having both the groups in the equitorial plane will make the compound more stable by avoiding 1-3 repulsion
@@Christophero Because they're cis, they either both have to be up or both have to be down. They're also right next to each other in positions 1 and 2. The way the chair is set up you can't have axial and equatorial bonds next to each other in the same direction. So, they alternate directions. Therefore, the set-up with the lowest energy is one with the bulkier group on the equatorial bond and the smaller group on the axial bond. This way they are right next to each other and still pointing in the same direction. Does that make sense?
This actually comes down to the geometry of the carbon atoms. Notice they are all sp3 hybridized - if they were to be in the same plane, the ideal bond angle for sp3 hybridized atoms (109.5) would be deviated from which would further destabilize the molecule.
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For anyone confused about 24:01 , this is why I think it's equitorial and not axial. CH3 and OH, according to the structure needs to be CIS. This means both have to be pointing up. Axial and equitorial bonds alternate up and down, shown in 1:17. If you go in order, axial bonds in carbon 1 should go UP. Carbon 2 axial bonds should go DOWN. Carbon 3 axial bonds should go UP. And carbon 4 axial bonds need to go DOWN. That's why the OH group cant be axial up because any axial group on the carbon 4 needs to be DOWN. Hence, you're forced to put the OH group in an equitorial up position since if you go in order (again), Carbon 1 equitorial bonds should go DOWN, Carbon 2 equitorial bonnds should go UP, carbon 3 equitorial bonds go DOWN, and carbon 4 equitorial bonds go UP. CH3 and OH need to be CIS and the only way to do that is if you do an axial up CH3 and an equitorial up OH.
JEE Aspirants Coming Here to clear their Doubts.😂
Wow! Just have to say like everyone else that this video was super helpful and clear! Literally game-changing to understanding such an abstract and visual concept!
thank u sooo much i just had a lecture on this and it wasnt making sense before
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Insane! Totally get these "chair flips," now!!
You explained everything so clearly, thanks to you I might just ace my next chem test
At 16:20, when you're doing a chair flip from form B to form A, you said that you move the carbons in a couterclockwise direction, but is it necessary to reverse the direction of the carbons, or just move them back one place? By the way, your videos are amazing, and I use them for practically every subject in school! Thank you so much!
You are a great teacher ! Thank you !
Thanks for your efforts , I have an exam tomorrow 🙂
Anyone else listen as they go to sleep in hopes of internalizing the info?
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Why do examples 2 amd 3 from 22:40 onward Not have multiple possible conformations?
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Reading the textbook sent me on a downward spiral lol. 🌀, thanks for your very clear and concise explanation. Sometimes the textbook helps but like sometimes not at all. 😂
17:25 the second demo, second structure, I think the up isopropyl should be shooting toward right
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19:17 can we take the Bromine atom on axial down position as the methyl is on up so we still get a trans isomer
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At 16:30 you drew the equatorial position of the tert-butyl toward the left direction but should it not be toward the right direction?
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on 15:00, the ring flip of the first molecule, was the labelling of axial and equatorial right?
When dealing with 2 substituents, do we have to put them in opposite positions, like axial and equatorial?
Im confused on how you know if the substituents is either axial or equatorial and if they are up or down on on the chair. I understand the ring flip and which one would be more stable but I just dont understand the inital drawing process, someone plzzzzzzzzzz help
Hi @Mohamed Dahcheh, this video helped me understand the placement of substituents! ua-cam.com/video/4xNQwohSRbo/v-deo.html
Good luck!
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Could someone explain to me @21:03. Why the second option has the carbon number starts 1 carbon shifted clockwise rather than at the same place as the first possible chair conformation? Thank you so much!
Hi! Since CH3 is a wedge it needs to be in the upward position regardless of whether it is in the axial or equatorial... in the first diagram he drew CH3 in axial up, which leaves the remaining position to be equatorial down... because of that, for the second diagram, he shifted the numbers clockwise because the next position has equatorial up open so that could be occupied then... I hope this helps
@@eshalshoaib5923 Thank you so much! That makes sense
Why is in the last example the oh in equatorial and not in axial? Because Br is in equatorial so the next one should be in axial???
i want to ask this ques too...
specifically looked in the comments for this question.. isnt it suppose to be axial since Br was equatorial
For anyone confused about 24:01 , this is why I think it's equitorial and not axial. CH3 and OH, according to the structure needs to be CIS. This means both have to be pointing up. Axial and equitorial bonds alternate up and down, shown in 1:17. If you go in order, axial bonds in carbon 1 should go UP. Carbon 2 axial bonds should go DOWN. Carbon 3 axial bonds should go UP. And carbon 4 axial bonds need to go DOWN. That's why the OH group cant be axial up because any axial group on the carbon 4 needs to be DOWN. Hence, you're forced to put the OH group in an equitorial up position since if you go in order (again), Carbon 1 equitorial bonds should go DOWN, Carbon 2 equitorial bonnds should go UP, carbon 3 equitorial bonds go DOWN, and carbon 4 equitorial bonds go UP. CH3 and OH need to be CIS and the only way to do that is if you do an axial up CH3 and an equitorial up OH.
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I think the equatorial position should be parallel to the C -C bond either to the right or left. I have noticed that you have made some mistakes in drawing the correct structure. Otherwise, you the best tutor that I would always like your videos that simplifies everything. thank you very much.
Always so good at explaining
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Thank you so much for your explanation sir!
And I have a doubt @24:02
Why do we put the Hydroxyl group in the equatorial up position but not in the axial up position sir?
were you able to find out? I have the same question!
i think there might be steric hindrance between the methyl group and the hydroxyl group if you put it in the axial up position
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At 23:05 or even for the previous question, why can't both the groups be in the equitorial plane ?
Why one needs to be in the axial and the other in the equitorial plane
Having both the groups in the equitorial plane will make the compound more stable by avoiding 1-3 repulsion
I have this question too, we’re you able to find an answer?
@@Christophero Because they're cis, they either both have to be up or both have to be down. They're also right next to each other in positions 1 and 2. The way the chair is set up you can't have axial and equatorial bonds next to each other in the same direction. So, they alternate directions. Therefore, the set-up with the lowest energy is one with the bulkier group on the equatorial bond and the smaller group on the axial bond. This way they are right next to each other and still pointing in the same direction. Does that make sense?
This actually comes down to the geometry of the carbon atoms. Notice they are all sp3 hybridized - if they were to be in the same plane, the ideal bond angle for sp3 hybridized atoms (109.5) would be deviated from which would further destabilize the molecule.
@@leila8397 thank you.
Thanks bro
Great explaination
little knit picky but I believe that the equatorial bonds in the middle are suppose to be a parallel with the right and left parallel lines.
I’ve had three lectures of not understanding this and you do it in 3 minutes
That’s what she said
Thank you mister Organic Chemistry Tutorial, this helps me to understand chair conformation a lot !!! keep going :)))