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Kya baat hai sir bohot hi asan language mein samzaya apne sab. Koi chem teacher bhi na sikha paye. Kaash muze ye channel kuch saal pehle mil jata to aaj mein NET qualified ho jata. Fir se preparation karne ki soch raha hu video dekh kr
Sir please provide us more free lectures on UA-cam...it's so helpful for our preparation and you teach so nicely..so please provide us more free classes. Thank you
Sir,aap jese padhate hai mereko lagta hai ki sare ke sare students...jo IFAS ONLINE LIFESCIENCE follow karte hai wo net qualify karjayenge..You are great sir.
Great work towards the future of our nation......towards the studentsand to those also who were not able to join paid classes online as well as offline . Really it is very very beneficial to students like us ....I hope in future u also provide some important topics like genetics and molecular biology....thanks a lot to whole team of ifas😍😍😍😍 desperately waiting for your next lectures....
Mole concept in such a easy way..... It's just impossible topic become possible for me.... thanks alot for such a wonderful lecture 🙏..... Blessed to be a part of Ur teaching
wonderful explanation sir......best video on this topic....plz sir dont stop make videos...it wll be very beneficial for those student who cannot afford coaching....and i never understand biochemistry but your videos are like majic sir...plz sir complete biochem syllabus...and sir protein aur enzyme bohut tough lagta hai...plz sir if possible yeh bhi parha dijiye
Hello sir... your teaching pattern is extremely good and your lectures have been really helpful to clear the basics.... sir please make one video on reaction kinetics , thermodynamics and colligative properties... I'll be waiting for your reply sir... thank you
Nice lecture sir...... wonderful sir.....it is the best lecture on this topic in you tube .....hats off to your effort sir....plz sir protein aur enzyme bhi parha dijiye....bohut tough hai....it will beneficial for those students who cannot afford teaching sir.....you are the best sir in the world....
The Formula of oxalic acid is H2C2O4. 2H2O (hydrated form), not H2C2O4. Therefore, the equivalent weight of the acid is molecular weight (126 dalton) divided by acidity (valency=2) Therefore,126/2 = 63. thus the equivalent weight of oxalic acid is 63. For For 1 N 1000 mm you need 63 g For 0.5 N 1000 ml you need 63/2 g For 0.5 N 500 ml you need 63/4 g = 15.75 g
Given Molarity of acid = 3.60 M % of suphuric acid =29 you must know MW of sulphuric acid = 98 dalton Mass of H2SO4 present in 1 L (1000 mL) of 3.6 M acid = 3.6 x 98 g = 352.8 g Let 'D' be the density of the acid. Density = Mass/Volume Mass of 1000 mL of acid = (D x 1000) g Given the percentage of H2SO4 in acid = 29 352.9 x 100/1000 D = 29 352.9/10 D = 29 290 D = 352.9 D= 352.9/290 =1.22 Therefore density of H2SO4 = 1.22 g/mL
This lecture covers following topic 00:05:54 What is solution? 00:08:40 What are different types of solution? 00:24:42 what is mole? 00:43:12 How to prepare molar solution? 01:12:53 How to prepare normal solution? 01:23:52 How to go for dilution of solution?
Nacl (MW=58.5) 15 % means 15 g in 100 ml 150 g in 1000 ml 58.5 g in 1000 ml = 1 M 1 g in 1000 ml = 1/58.5 M 150 g in 1000 ml = 150/58.5 M = 2.56 Molarity of 15% NaCl solution is 2.56
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📞 Call IFAS for detail Information: 8600734656/91722-66888
Kya baat hai sir bohot hi asan language mein samzaya apne sab. Koi chem teacher bhi na sikha paye.
Kaash muze ye channel kuch saal pehle mil jata to aaj mein NET qualified ho jata.
Fir se preparation karne ki soch raha hu video dekh kr
First time I understood the biochemistry lecture very well... Good skill of teaching sir
Awsome teaching 👍 app jo smile karke paratey ho . It adds more ❤ to your lecture😊
Thanks!!!
Sir please provide us more free lectures on UA-cam...it's so helpful for our preparation and you teach so nicely..so please provide us more free classes. Thank you
Sir,aap jese padhate hai mereko lagta hai ki sare ke sare students...jo IFAS ONLINE LIFESCIENCE follow karte hai wo net qualify karjayenge..You are great sir.
Great work towards the future of our nation......towards the studentsand to those also who were not able to join paid classes online as well as offline . Really it is very very beneficial to students like us ....I hope in future u also provide some important topics like genetics and molecular biology....thanks a lot to whole team of ifas😍😍😍😍 desperately waiting for your next lectures....
We will try our best. Very happy to know that you liked content. Please keep sharing it with frinds and happy learning!!!
Mole concept in such a easy way..... It's just impossible topic become possible for me.... thanks alot for such a wonderful lecture 🙏..... Blessed to be a part of Ur teaching
You are most welcome
You are doing great work Sir, Salute you Sir🙏🙏🙏🙏
Thanks a lot
Sir first tym I hv solved biochemistry questions very confidently..and correct
Thanks a lot sir. Finally mujhe samjha me aya. Aaj real me biochemistry samjha me aya
I need this video so much
wonderful explanation sir......best video on this topic....plz sir dont stop make videos...it wll be very beneficial for those student who cannot afford coaching....and i never understand biochemistry but your videos are like majic sir...plz sir complete biochem syllabus...and sir protein aur enzyme bohut tough lagta hai...plz sir if possible yeh bhi parha dijiye
I will try my best
Thank you so much sir for your helpful lecture.👌👌.
Most welcome
Thank u sir... Ur teaching style is so good.. Vry easy way to understand all dis
Thankyou Sir 🙏🙏🙏
Before watching this video, ,,,"Muze Ye mere samaj ke bahar hai Aisa he lagta tha" but not now😅
Hello sir... your teaching pattern is extremely good and your lectures have been really helpful to clear the basics.... sir please make one video on reaction kinetics , thermodynamics and colligative properties... I'll be waiting for your reply sir... thank you
Awesome.never got an explanation like this before
Glad it helped!
Nice sir g
thank you so much, sir, for your lecture, you are simple and best.
Love the way you teach
Very useful and easy to understand sir .. Thanks a lot
Keep watching
Good One Thank you sir
Nice lecture sir...... wonderful sir.....it is the best lecture on this topic in you tube .....hats off to your effort sir....plz sir protein aur enzyme bhi parha dijiye....bohut tough hai....it will beneficial for those students who cannot afford teaching sir.....you are the best sir in the world....
Coaching *
It's my pleasure
Nice lectures Sir.
Well done sir.. excellent
Many thanks
Happy Teacher's Day Sir 😊🙏🙏
Very well explained sir 👍
Plz provide lectures on developmental biology also.
Yes will try to provide that.
Good morning dear sir
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Thank u sir, for wonderful explanation
You are most welcome
This video needs 1 mole likes 🔥🔥🔥🔥
Oh my god I discover this channel.
Thanks a lot
Sir classes age continue kriyega sir
Thnku sir
❤❤
Thanks sir
Sir Buffer ke next vedio ka link provide kre plz. Bilkul show nahi ho pa raha.
Jakas sir ji
Sir appka baki classess video kaha par hai?
Thanks a lot sir 🙏
Most welcome
Sir first question me 10 to the power 9 ka exsistance hi ni hua kuch... Sirf mind divert krne ke lia dia h
Good evening sir
🙏
Can u please provide details of online iit jam classes
Sir plzz unit 13 ko bhi start karwa dijiy 1st and 13 ka combination bhi banta h.... Tysm sir
We will try our best.
Sir aap next lectures classes kub se start krenge ..
Guru ji pura krba denge na biochemistry
Try our best.
Good evening
Same to you
Gd evening sir
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Can anyone share the link of the next part of this video
ua-cam.com/play/PLBUibmA0dbhvr-7qG8a-FjneureGb48R6.html
This playlist contain all videos. All the best.
Is video ka notes Kaha Pr Milega aap pe to kuch v free available nhi hai
How to Calculate the quantity (grams) of oxalic acid (HOOC-COOH) that will be required to prepare its 500 mL of 0.5 N solution ...
Pls sir reply
The Formula of oxalic acid is H2C2O4. 2H2O (hydrated form), not H2C2O4. Therefore, the equivalent weight of the acid is molecular weight (126 dalton) divided by acidity (valency=2)
Therefore,126/2 = 63. thus the equivalent weight of oxalic acid is 63. For
For 1 N 1000 mm you need 63 g
For 0.5 N 1000 ml you need 63/2 g
For 0.5 N 500 ml you need 63/4 g = 15.75 g
Ji
sir 2n=48 chromosome hua toh 48/6x10^23=8x10^-23 hoga
very good
How to calculate density g/m
29% h2so4 solution have molarity 3.60
Given
Molarity of acid = 3.60 M
% of suphuric acid =29
you must know MW of sulphuric acid = 98 dalton
Mass of H2SO4 present in 1 L (1000 mL) of 3.6 M acid
= 3.6 x 98 g = 352.8 g
Let 'D' be the density of the acid.
Density = Mass/Volume
Mass of 1000 mL of acid = (D x 1000) g
Given the percentage of H2SO4 in acid = 29
352.9 x 100/1000 D = 29
352.9/10 D = 29
290 D = 352.9
D= 352.9/290 =1.22
Therefore density of H2SO4 = 1.22 g/mL
Sir 2 mg / ml = 2000mg /1000ml = 2g /1000 ml kse hua? Plz tell?
As to form molar sol....final volume shd b 1000 ml ...so in order to make final volume 1000 we had multiple by 1000 both sides
This lecture covers following topic
00:05:54 What is solution?
00:08:40 What are different types of solution?
00:24:42 what is mole?
00:43:12 How to prepare molar solution?
01:12:53 How to prepare normal solution?
01:23:52 How to go for dilution of solution?
What is amount of protein required to prepare 5ml of 1 uM sol? (MW of protein: 25kDa)
Can any one solve this problem? Then please solve
Answer c
Yeh lifescience ka biochemistry part hai kya?....koi mujhey bataye ga kya plzzz
Yes!!!
@@IFASONLINE thanku...app biochemistry pura cmplt karawoo gay kya sir?
Molarity 15% nacl solution
Is 0.389??
.386 M (100ml)
Nacl (MW=58.5)
15 % means 15 g in 100 ml
150 g in 1000 ml
58.5 g in 1000 ml = 1 M
1 g in 1000 ml = 1/58.5 M
150 g in 1000 ml = 150/58.5 M = 2.56
Molarity of 15% NaCl solution is 2.56
Thank you sir
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hi sir
1gm in 100 ml of water
good
Hello,
💐Greetings From IFAS!
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Thanks