Example 3: Factoring quadratics by taking a common factor and grouping | Algebra II | Khan Academy

Поділитися
Вставка
  • Опубліковано 26 січ 2025

КОМЕНТАРІ • 11

  • @cRaZyBeautyyful
    @cRaZyBeautyyful 11 років тому +4

    You make it so simple! Great video!

  • @cartergrossnickle1816
    @cartergrossnickle1816 4 роки тому +4

    Makes so much sense now

  • @Christaingrey
    @Christaingrey 9 років тому +4

    Im sorry, but from where it leads that product of two numbers must be 7*-3?

    • @Galdring
      @Galdring 9 років тому +1

      +Christaingrey
      Well, the two integers of the factored expression must have the product -3, in order for the factored expression to be equivalent to the unfactored one. However, during factoring, either A or B will have the factor 7k factored out. So, a*b must be -3 _after_ (a or b, it doesnt matter) has been divided by 7k. In other words, (a*b)/7=-3 (devided by 7 because 7 will be factored out), or a*b=7*-3.
      I am sorry if this is wrong, or too chaotic to be comprehensible. I'm new to this too, and don't usually do maths in english, so I dunno the proper terms.

  • @JordanIEmerson
    @JordanIEmerson 7 років тому +7

    I'd just like to say that this really makes no sense how the sum of 7 and 3 =20 like honestly thsi subject makes me watn to throw myself down a flight of stairs

  • @richiericardo1225
    @richiericardo1225 9 років тому +2

    I'm (35k^2 + 100k - 15)% sure that this guy just made up everything he said.

  • @erinstacyamoin6442
    @erinstacyamoin6442 7 років тому +2

    can someone answer this correctly ☺
    (3x-4) (x+3) = x-8
    i can't solve this bc all examples i see is something like "(3x-4)(x+3)=60" like that, thanks in advance!

    • @kayraozbakir9517
      @kayraozbakir9517 4 роки тому +4

      Erin Stacy Amoin
      1) Open up the paranthesis, you get: 3x^2 + 3x - 12 = x - 8
      2) now get the x - 8 to the other side so we can equalize the equation now to zero, we get:
      3x^2 + 2x - 4 = 0
      3) now you can solve the rest with the technique he explains in the video
      Your questions is from two years ago but maybe this helps someone who sees this😂

    • @jaysuson1
      @jaysuson1 4 роки тому +1

      @@kayraozbakir9517 hope he found it even after three years, thanks for your help