14.1 Rate Expressions and the Rate of Reaction | General Chemistry

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  • Опубліковано 15 січ 2025

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  • @EdgarLopez-mr1lq
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    • @ChadsPrep
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      Thanks for your kind words - all the best in your academic endeavors!

    • @enoughnonymity
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    @ChristianSpencer-c9g 6 місяців тому +8

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    • @ChadsPrep
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      Welcome to the channel - glad it is helping you!

  • @triple_gem_shining
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    • @ChadsPrep
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      Glad the channel is helping you so much - Happy Studying!

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    • @ChadsPrep
      @ChadsPrep  3 роки тому

      You're welcome, Timothy - and Thank you!

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    You are the best Chemistry Teacher in History

    • @ChadsPrep
      @ChadsPrep  Рік тому +2

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    • @ChadsPrep
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    • @ChadsPrep
      @ChadsPrep  3 роки тому

      Thank you, flora chen - Happy Studying!

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    @reubenMofya 5 місяців тому +1

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    @חנהגבאי-ש2ק 23 дні тому

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    @dragon-ir8te 5 днів тому

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      Glad the channel helped!

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  • @aidanconnors5497
    @aidanconnors5497 9 місяців тому

    Thank you this helped clear up a lot

    • @ChadsPrep
      @ChadsPrep  9 місяців тому

      You're very welcome.

  • @sciencenerd7639
    @sciencenerd7639 3 роки тому +1

    very good explanation👏

    • @ChadsPrep
      @ChadsPrep  3 роки тому +1

      Been loving all the feedback Science Nerd! Really appreciate it!

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    • @ChadsPrep
      @ChadsPrep  Рік тому

      Glad the channel is helping you.

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    @mulopenjapau2837 Рік тому

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    • @ChadsPrep
      @ChadsPrep  Рік тому

      That's great - Happy Studying!

  • @connorkrilow9220
    @connorkrilow9220 4 дні тому

    Chad - what is the rate of Goon over Edge?

  • @nikicari1288
    @nikicari1288 6 днів тому

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    @RebeccaAppling Рік тому

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    • @ChadsPrep
      @ChadsPrep  Рік тому

      You're welcome and Thank You. And thank your teacher for me! Happy Studying!

  • @anyonhaseyoerubun
    @anyonhaseyoerubun Рік тому

    Do we include catalysts in presenting the rate expression of a chemical reaction?

    • @ChadsPrep
      @ChadsPrep  Рік тому

      only if it is a reactant in the rate determining step of a multi-step reaction

    • @anyonhaseyoerubun
      @anyonhaseyoerubun Рік тому

      @@ChadsPrep thank you sir

  • @haneen1920_
    @haneen1920_ 5 місяців тому

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    • @ChadsPrep
      @ChadsPrep  5 місяців тому

      You are very welcome!

  • @dj-xm2uu
    @dj-xm2uu 11 місяців тому

    this made so much sense

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    @sadafwali3846 Рік тому

    what is the difference between the free video vs the mcat prep ones?

  • @austernmunsaka4570
    @austernmunsaka4570 Рік тому

    Does it mean that the rate of reaction of the reactant should equal to the rate of reaction of the product?

  • @Faraah11
    @Faraah11 7 місяців тому

    thank you

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    @kyleighgraves5115 Рік тому

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    • @ChadsPrep
      @ChadsPrep  Рік тому

      Thanks for saying so - Happy Studying!

  • @OyindamolaOlanrewaju-m3s
    @OyindamolaOlanrewaju-m3s 11 місяців тому

    It really was helpful

    • @ChadsPrep
      @ChadsPrep  11 місяців тому

      Glad to hear it!

  • @sarpkaia3666
    @sarpkaia3666 Місяць тому

    buradaydım. thank you so much professor! 12.14.2024 i have a question: say, we have this reaction that can't be simplified: 3X + 2Y 5Z so would our rate of reaction still be (concentration of Y)/2 ?

  • @jackcollison7759
    @jackcollison7759 9 місяців тому

    If we switched this reaction around, would the rate expression then be equal to -Δ[N2]/Δt ? Thanks for the video, super helpful!

    • @not_a_youtuber9597
      @not_a_youtuber9597 7 місяців тому +1

      Yes because the in reverse reaction I believe the N2 is depletingin quantity

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    @milkywaystars1216 Рік тому +1

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    • @ChadsPrep
      @ChadsPrep  Рік тому

      Glad the channel is able to help you out - Happy Studying.

  • @michaelmwenyachileshe2901
    @michaelmwenyachileshe2901 2 роки тому +1

    Spoken like a true Chad

  • @SakeenaManzoor-u4y
    @SakeenaManzoor-u4y Рік тому

    Yes sir I just understand😊

  • @minabekheet4076
    @minabekheet4076 Рік тому

    I have a question
    We always use concentration in the form of Molarity not moles
    If we have Hcl + Naoh = Na cl + H2o
    That means
    1 M of both Naoh and Hcl are consumed to yield I M Nacl
    Acvording to the rate of reaction expression and Ratio
    However if we
    Add I L Naoh 1 M to 1M IL HCl
    Will yield 1mole Naoh in 2L
    That means
    0.5 M of Nacl not 1 M
    Kindly explain
    Thanks

  • @RobertN.
    @RobertN. Рік тому

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    • @ChadsPrep
      @ChadsPrep  Рік тому

      Thank you and Happy Studying!

  • @SakeenaManzoor-u4y
    @SakeenaManzoor-u4y Рік тому

    Sir how rates of all these 3 stuffs could be equal even their stochimetric cofficients are different😮

    • @ChadsPrep
      @ChadsPrep  Рік тому

      What time is this in the video?

    • @SakeenaManzoor-u4y
      @SakeenaManzoor-u4y Рік тому

      @@ChadsPrepsir Sorry l didn't see it😑😑😐

    • @andrewjustin256
      @andrewjustin256 2 місяці тому

      You see they are not the same in the video. N2 is being produced with 0.1 M/s rate, while Ammonia with 0.2 M/s and hydrogen gas at 0.3 M/s rate. However, in order to make it an average or the net rate is equal to their respective rates divided by their stoichiometric ratios. Hope that assists well! 😊😊

  • @BuzzLightyear-tu6ud
    @BuzzLightyear-tu6ud Рік тому

    totally a side question but did you watch/enjoy oppenheimer? I learned most of the important quantum scientists from your vids and my textbook lol

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    @CloudslnMyCoffee 2 роки тому +2

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