Reaction Rates and Stoichiometry- Chemistry Tutorial
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- Опубліковано 7 вер 2024
- This chemistry tutorial includes examples of calculating average reaction rates as well as calculating reaction rates of reactants or products relative to other reactants or products using stoichiometry.
www.thechemsolution.com
Your voice is so calm, I wish my parents spoke like this.
Stop disappointing them for once and maybe it will change
@@RicardoPerez-fd7bh lmao what makes you so miserable to think they're disappointing their parents?
Cheeeewwww
Y making example with ur parent
Plot twist: She's your parent.
Thank you for explaining this. Your voice is also very pleasant to listen to. Keep doing great work.
You're really a genius, I can solve rate reaction in a second. Thanks so much for helping me on this tutorial 🙏🙏
Wow! That was helpful! Thank you. I was getting hung up on lumping the fractions with the initial rates and why my problems were not working out correctly. Plus, the last part of using stoichiometry gave me a nice alternative and a means to check my work. Thank you again!
how did you get 3/2???
Please make more videos for gen chem 2 :) ex. kinetics, more rate law videos, equilibrium
Thank you for explaining this in a way that I could understand :)
Thank you ma'am. It was indeed helpful
Oh hey, welcome back
Love ur voice... It made me understand even better due to concentration 😁
Super helpful! Thank you!!
finally understood it somehow thanks!
Thank you so much this was so helpful!!!
Your voice though ♥️♥️♥️
Thanks a lot, you really help me.
What happened to the negative on the 1/3? Should it be -3/2?
Thanks Soo much for that explanation, please for more examples
Indeed, that was really helpful!
Thanks was really so helpful
Wht about the negative sign of reactant do you include or not include in calculationb of disappearence of H2
This helped me, thank you so much.🖤
Super useful and helpful! Thanks!
For Example 2 should you not have divided the equation by -1/3 instead of 1/3?
The negative is only there in front of the 1/3 to make the rate positive for the reactant, since the reactant is disappearing. If you didn't have the negative there, you'd end up with a negative rate for the reactant, since in your numerator you'd be subtracting a larger number from a smaller one (b/c the concentration of the reactants decreases over time, so concentration2 will be less than concentration1, and change in concentration is defined as concentration2 - concentration1) You don't have that issue with products; their numerators will be positive values since they increase in concentration. Thus you only need to divide by 1/3. I hope that made sense.
@@lindsayk616 hey. So it’s basically there for that and the sign is always excluded in calculations?
Thank you for helping me !
Thanks a lot mam!!!
Very helpful, thanks a lot
Thanks for this
Nice video help me a lot
Thank you so much!
Thanks ....really helped 😊
Very helpful ! ty
Thanks so much
I thought the rate of disappearance is supposed to have a negative sign
Isnt the rate of disappearance should be negative? Since it’s in the reactant side?
Yeah that's what I was thinking
@@resilientlemon1302 - hi! Update: yes, it has to be negative since it is in the reactant side. We had a test last week and Inwas correct.
* I was
@@linsdesk7240 nice hope that went well
@@resilientlemon1302 yepp, i was top 6 in that exam!!
Long time no see bro
She isn't a "bro". She is girl, xD.
@@Indyin People call others bro, dude, girl, no matter the gender
Long time bro
Thank you
Thank u!
Thanks
Thannkyou. Mam.
why turn into 3/2?
you forgot the negative sign or (minus) on the final result
because whenever the product appear+ the reactant disappear -
You would be technically correct, but It's usually customary to always write reaction rates as positive. The appearance or disappearance of a reactant or product is differentiated using the phrases "rate of appearance" or "rate of disappearance", or simply checking if the chemical in question is a reactant or product.
tysm
Thank the Lord I found this video
Stoykeyamatre
Good mic
she kind of sounds like drew barymore
I came here for my exam. Its good but u talk a lot. I mean, can you please answer it directly. Lessen the talk,
I’d like to see you try .
the talking is useful
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5:22
Thanks