Reaction Rates and Stoichiometry- Chemistry Tutorial

Поділитися
Вставка
  • Опубліковано 7 вер 2024
  • This chemistry tutorial includes examples of calculating average reaction rates as well as calculating reaction rates of reactants or products relative to other reactants or products using stoichiometry.
    www.thechemsolution.com

КОМЕНТАРІ • 75

  • @Indyin
    @Indyin 5 років тому +121

    Your voice is so calm, I wish my parents spoke like this.

    • @RicardoPerez-fd7bh
      @RicardoPerez-fd7bh 3 роки тому +8

      Stop disappointing them for once and maybe it will change

    • @greenskiesandsunnyshines
      @greenskiesandsunnyshines 3 роки тому +24

      @@RicardoPerez-fd7bh lmao what makes you so miserable to think they're disappointing their parents?

    • @aliaminu8226
      @aliaminu8226 3 роки тому

      Cheeeewwww

    • @aliaminu8226
      @aliaminu8226 3 роки тому +1

      Y making example with ur parent

    • @jintan8112
      @jintan8112 3 роки тому +3

      Plot twist: She's your parent.

  • @RokShox1
    @RokShox1 4 роки тому +26

    Thank you for explaining this. Your voice is also very pleasant to listen to. Keep doing great work.

  • @kids_network1999
    @kids_network1999 Рік тому +4

    You're really a genius, I can solve rate reaction in a second. Thanks so much for helping me on this tutorial 🙏🙏

  • @boomfiziks
    @boomfiziks 4 роки тому +20

    Wow! That was helpful! Thank you. I was getting hung up on lumping the fractions with the initial rates and why my problems were not working out correctly. Plus, the last part of using stoichiometry gave me a nice alternative and a means to check my work. Thank you again!

  • @lovelyricaabelong4593
    @lovelyricaabelong4593 3 роки тому +7

    how did you get 3/2???

  • @len7894
    @len7894 4 роки тому +8

    Please make more videos for gen chem 2 :) ex. kinetics, more rate law videos, equilibrium

  • @saintly0314
    @saintly0314 2 роки тому +3

    Thank you for explaining this in a way that I could understand :)

  • @ndapunikwanekonda5812
    @ndapunikwanekonda5812 2 роки тому +2

    Thank you ma'am. It was indeed helpful

  • @fransce5065
    @fransce5065 5 років тому +7

    Oh hey, welcome back

  • @suleimanabdulrahman1666
    @suleimanabdulrahman1666 3 роки тому +1

    Love ur voice... It made me understand even better due to concentration 😁

  • @micahlanboney7830
    @micahlanboney7830 Рік тому +2

    Super helpful! Thank you!!

  • @feebleh
    @feebleh 3 роки тому +3

    finally understood it somehow thanks!

  • @rowenapelaez1632
    @rowenapelaez1632 2 роки тому +3

    Thank you so much this was so helpful!!!

  • @offodemi
    @offodemi 5 років тому +7

    Your voice though ♥️♥️♥️

  • @genesislopez6619
    @genesislopez6619 4 роки тому +2

    Thanks a lot, you really help me.

  • @user-fy4mp6vy6s
    @user-fy4mp6vy6s Рік тому +1

    What happened to the negative on the 1/3? Should it be -3/2?

  • @winifrednainmobu7192
    @winifrednainmobu7192 2 роки тому

    Thanks Soo much for that explanation, please for more examples

  • @jeisongarrido7376
    @jeisongarrido7376 2 роки тому

    Indeed, that was really helpful!

  • @idahchilembo4117
    @idahchilembo4117 2 роки тому

    Thanks was really so helpful

  • @MohaleNdlovu
    @MohaleNdlovu 3 місяці тому

    Wht about the negative sign of reactant do you include or not include in calculationb of disappearence of H2

  • @Jehohananokeke
    @Jehohananokeke 2 роки тому

    This helped me, thank you so much.🖤

  • @pavellambracht5823
    @pavellambracht5823 4 роки тому +3

    Super useful and helpful! Thanks!

  • @resilientlemon1302
    @resilientlemon1302 3 роки тому +2

    For Example 2 should you not have divided the equation by -1/3 instead of 1/3?

    • @lindsayk616
      @lindsayk616 2 роки тому +1

      The negative is only there in front of the 1/3 to make the rate positive for the reactant, since the reactant is disappearing. If you didn't have the negative there, you'd end up with a negative rate for the reactant, since in your numerator you'd be subtracting a larger number from a smaller one (b/c the concentration of the reactants decreases over time, so concentration2 will be less than concentration1, and change in concentration is defined as concentration2 - concentration1) You don't have that issue with products; their numerators will be positive values since they increase in concentration. Thus you only need to divide by 1/3. I hope that made sense.

    • @ntokozomokwane1329
      @ntokozomokwane1329 2 роки тому

      @@lindsayk616 hey. So it’s basically there for that and the sign is always excluded in calculations?

  • @christiansmith4215
    @christiansmith4215 3 роки тому

    Thank you for helping me !

  • @jirgotaba918
    @jirgotaba918 Рік тому

    Thanks a lot mam!!!

  • @rev_5728
    @rev_5728 4 роки тому

    Very helpful, thanks a lot

  • @Bobby-Hiromozono
    @Bobby-Hiromozono Рік тому

    Thanks for this

  • @daestka5512
    @daestka5512 4 роки тому

    Nice video help me a lot

  • @nancylu4376
    @nancylu4376 2 роки тому

    Thank you so much!

  • @johnngandwe9018
    @johnngandwe9018 4 роки тому

    Thanks ....really helped 😊

  • @ayshanicole2825
    @ayshanicole2825 2 роки тому

    Very helpful ! ty

  • @justiceakyen1271
    @justiceakyen1271 Рік тому

    Thanks so much

  • @RoseKindness-ym2gz
    @RoseKindness-ym2gz 26 днів тому

    I thought the rate of disappearance is supposed to have a negative sign

  • @linsdesk7240
    @linsdesk7240 3 роки тому +1

    Isnt the rate of disappearance should be negative? Since it’s in the reactant side?

    • @resilientlemon1302
      @resilientlemon1302 3 роки тому

      Yeah that's what I was thinking

    • @linsdesk7240
      @linsdesk7240 3 роки тому

      @@resilientlemon1302 - hi! Update: yes, it has to be negative since it is in the reactant side. We had a test last week and Inwas correct.

    • @linsdesk7240
      @linsdesk7240 3 роки тому

      * I was

    • @resilientlemon1302
      @resilientlemon1302 3 роки тому +1

      @@linsdesk7240 nice hope that went well

    • @linsdesk7240
      @linsdesk7240 3 роки тому +1

      @@resilientlemon1302 yepp, i was top 6 in that exam!!

  • @user-pb4qd5yy9f
    @user-pb4qd5yy9f 5 років тому +6

    Long time no see bro

    • @Indyin
      @Indyin 5 років тому +3

      She isn't a "bro". She is girl, xD.

    • @RandomPerson-tw8mn
      @RandomPerson-tw8mn 3 роки тому +1

      @@Indyin People call others bro, dude, girl, no matter the gender

    • @dogperson4436
      @dogperson4436 Рік тому

      Long time bro

  • @omarelsehly2004
    @omarelsehly2004 3 роки тому

    Thank you

  • @abraralharbi6
    @abraralharbi6 2 роки тому

    Thank u!

  • @ynl_rm3411
    @ynl_rm3411 2 роки тому

    Thanks

  • @shakthianistonshakthi6918
    @shakthianistonshakthi6918 4 роки тому

    Thannkyou. Mam.

  • @yeet9703
    @yeet9703 Рік тому

    why turn into 3/2?

  • @ntnjadeabdulhadi3386
    @ntnjadeabdulhadi3386 3 роки тому

    you forgot the negative sign or (minus) on the final result
    because whenever the product appear+ the reactant disappear -

    • @nickc4336
      @nickc4336 3 роки тому +1

      You would be technically correct, but It's usually customary to always write reaction rates as positive. The appearance or disappearance of a reactant or product is differentiated using the phrases "rate of appearance" or "rate of disappearance", or simply checking if the chemical in question is a reactant or product.

  • @yee5510
    @yee5510 3 роки тому

    tysm

  • @blueseamon3564
    @blueseamon3564 3 роки тому +1

    Thank the Lord I found this video

  • @hadid283
    @hadid283 3 роки тому +1

    Stoykeyamatre

  • @shrill_kill9929
    @shrill_kill9929 2 роки тому

    Good mic

  • @cassandrarosales9904
    @cassandrarosales9904 3 роки тому +1

    she kind of sounds like drew barymore

  • @pamela9958
    @pamela9958 4 роки тому +2

    I came here for my exam. Its good but u talk a lot. I mean, can you please answer it directly. Lessen the talk,

    • @shakthianistonshakthi6918
      @shakthianistonshakthi6918 4 роки тому +3

      I’d like to see you try .

    • @__drjay__8599
      @__drjay__8599 3 роки тому +1

      the talking is useful

    • @sofiasirajsirajabdu4258
      @sofiasirajsirajabdu4258 3 роки тому

      @@shakthianistonshakthi6918 loved ur comment😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂

  • @thefemalefuture1
    @thefemalefuture1 Рік тому +1

    5:22

  • @parvezalam1211
    @parvezalam1211 3 роки тому

    Thanks