I am not an Indian but I love watching tutorials made by an Indian because it is very understandable and I learn alot.. I don’t care abt their accent, the thing that matter is they really teach good!
As I think you are the best Science Teacher and if you will regularly upload Mathematics videos then you will become best Mathematics teacher too. If you all agree then Hit the Like button.
Here is the summary and related questions: The video discusses how to apply trigonometry to measure heights and distances without directly measuring them. It covers examples such as finding the height of a tall building, the width of a river, and the distance between ships using trigonometric ratios. Key moments: 00:00 Trigonometry can be used to measure heights and distances without physically measuring them by utilizing ratios and angles in right angle triangles. Understanding trigonometric ratios like sine, cosine, and tangent is crucial for these calculations. -The video explains how to apply trigonometry to measure heights and distances without direct measurement, simplifying complex calculations using ratios and angles in right angle triangles. -Understanding trigonometric ratios such as sine, cosine, and tangent is fundamental for accurately calculating heights and distances in trigonometry, making the process more efficient and practical. 06:09 To find the height of a building, use trigonometric ratios like tan theta with known values to calculate the height accurately. The process involves identifying the unknown, applying the appropriate ratio, and solving for the height. -Calculating the height of a building using trigonometry. It involves identifying the angle, applying tan theta, and solving for the height accurately. -Visualizing and solving for the angular elevation of the Sun. By drawing a diagram, using tan theta with known values, and finding the angle accurately. -Understanding the concept of angle of depression. Explaining how to calculate the angle from the top of a building using trigonometry and known values. 12:48 Understanding angles of depression and elevation helps in solving trigonometry problems involving heights and distances. By visualizing and applying trigonometrical ratios to right angle triangles, complex questions can be easily solved. -Explaining the concept of angles of depression and elevation and their significance in trigonometry. Visualizing and drawing diagrams to solve height and distance problems efficiently. -Analyzing the given question about finding the width of a river using angles of depression, heights, and trigonometry. Breaking down the problem into smaller parts for systematic solution. 19:30 The video explains how to use trigonometric ratios to find unknown sides in triangles. In one example, the width of a river is calculated by adding the lengths found using trigonometry. -Using trigonometric ratios to find unknown sides in triangles. The video demonstrates using ratios like tan 30 and tan 45 to calculate side lengths. -Calculating the width of a river using trigonometry. By adding the lengths found for X and Y, the width of the river is determined. -Applying trigonometry to solve a real-world problem. The video presents a scenario involving a lighthouse and two ships to demonstrate trigonometric calculations. 26:38 To find the distance between two ships, trigonometry is used to set up and solve equations based on angles and side ratios, resulting in the distance of 54.90 meters. For a statue and pedestal, trigonometric ratios are applied to determine the height of the pedestal as 1.2 meters. -Trigonometry is utilized to calculate the distance between two ships by setting up and solving equations based on angles and side ratios, resulting in a distance of 54.90 meters. -Applying trigonometric ratios in a scenario involving a statue and pedestal to determine the height of the pedestal as 1.2 meters by setting up and solving equations based on angles and side ratios. 33:38 To find the height of a hill, rationalize the denominator in the calculation to simplify the process and get an accurate result efficiently. Trigonometry can help determine distances and heights in geometric problems involving angles of elevation and depression. -Rationalizing the denominator simplifies calculations with irrational numbers, enhancing accuracy and efficiency in mathematical solutions. -Trigonometry aids in solving geometric problems by utilizing angles of elevation and depression to determine distances and heights in a structured manner. 40:21 The height of the hill is found to be 40 meters and the distance from the ship to the hill is 17.32 meters, demonstrating a simple application of trigonometry in real-world scenarios. -Trigonometry is used to find the height of the hill and the distance from the ship, showcasing practical applications of mathematical concepts. -The video encourages viewers to attempt solving a question involving the speed of a plane and provides resources for further practice and learning in heights and distances.
दोस्तों, जो भी मेरे भाई - बहन 10th NCERT MATHS पढ़ना चाहते हैं वह Maths Easy 4 You चैनल पर आ जाइए, पुरा MATHS स्टेप बाई स्टेप पढ़ा रहे हैं अब आपको किसी भी टॉपिक के लिए कोचिंग नहीं जाना पड़ेगा ! एक बार देख लो हो सकता है आपका तलाश खत्म हो जाए। अब मैथ्स रटना नहीं, समझना हैं।। 🤗👍👇👇♥️🌹🙏🔥 ua-cam.com/video/dwXGaLDsLfM/v-deo.html
Really a good teacher while watching this it feels like I'm in any foreign school or what?? And by watching this i learn some good pronunciation of words... really helpful 👍👍 thankyou sir
In ∆BAD, tan(angle D)=Opposite/Adjacent Or,tan(angle D)=AB/AD From the trigonometric table, tan(30°)=1/√3 Or,75/AD=1/√3=75√3=15m In ∆BAC, tan(45°)=1 Or,AB/AC=1 Or,75/AC=1 Or,AC=75m Or, Distance between two ships=AC-AD=75-15=60m
Sir tq for your best videos. Before i was very poor in mathematics 😌but now I can able to answer any type of questions really they are very helpful sir thank you thank you so much sir
Hi sir am a Nigerian I love your teaching so much your explanation in a topic make it easy for me to understand 💯 Is my answer correct the question you gave us "300m/s"
Sab students apny exams pass karny k sath sath is ko sahi tarah samjhain b warna meri tarah surveying field mein dobara videos daikh k samjhna pary ga..Thanks sir for great help
First position of plane has distance from the point of observation equal to 1500 m and after 10s the distance from observer equal to 4500m and to find speed v need to use d/t formula. Time will be 10s and distance moved at the time is 4500-1500 =3000. Now substituting on formula 3000/10 we get 300m/s as answer
Sir you are explaining physical science and also mathematics amazing mind blowing sir we are appreciating your talent and we hope you continue this for long time thank you for your teaching 🤗🙏🙏💐💐💅💅💅💅 💅💅💅 💅
very nice class, sir what is your writing tool? because the colour look so pretty and I'd like it if you keep using that tool. This is my first time watching your videos, and I find this one worth my time since lot of other teachers take 2-3 hours to explain the chapter but you did it in just 44 min. it was worth it. for the new commers, I would highly recommend this channel. thank you sm!
दोस्तों, जो भी मेरे भाई - बहन 10th NCERT MATHS पढ़ना चाहते हैं वह Maths Easy 4 You चैनल पर आ जाइए, पुरा MATHS स्टेप बाई स्टेप पढ़ा रहे हैं अब आपको किसी भी टॉपिक के लिए कोचिंग नहीं जाना पड़ेगा ! एक बार देख लो हो सकता है आपका तलाश खत्म हो जाए। अब मैथ्स रटना नहीं, समझना हैं।। 🤗👍👇👇♥️🌹🙏🔥 ua-cam.com/video/dwXGaLDsLfM/v-deo.html
First we have to find the length between point of observation and the plane before the trip ,then we find the length between point of observation and the plane after the trip. Finally dividing it by the time we get 300m/s. Isn't it?
Sir truely my teacher explained this chapter for 2 times but i did not understand...... In this 44mins with the pictures u have shown and explained i loved it sooo much sir... Thank you😊😍😊😊
The speed of the plane is 300 m/s. Sir, you explain very well by that I can understand class 10th topic in class 8th and solve questions it's questions.
Sir the answer is 300 m/s where x=1500m and y=1500m so, x+y=1500+1500=3000m then by the formula speed=distance/time, time is given 10s and distance 3000m=3000m/10s=one 0 is cancel 300m/s answer....
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32:37 32:39 32:40 32:41 32:41 32:41 32:41 32:41 32:41 32:42
Are u korean
I am not an Indian but I love watching tutorials made by an Indian because it is very understandable and I learn alot.. I don’t care abt their accent, the thing that matter is they really teach good!
Glad to hear that. Keep watching and do share with your friends.
From where are you?
You are indian only
@@himanshuyadavshorts2081 tune uska aadhar card pe check kiya? :D
@@user-lh7th2it7h 😂😂
i like how the class is explained . it was really understandable.
Glad to hear that
@@ManochaAcademy Tan thita = 10m/10 root 3 m = 1/root 3
Thita = 30°
How sir????
Pls explain!!
@@snehamurmu9372 since tan 30°=1/√3
Such a hardworking person. Thank you sir for your efforts.
It's my pleasure
How we taken angle 60 degrees from point O to A
best explanation sir -the use of english helped me a lot as i dont know hindi ;)
Happy to help
I needed this from a long time.... Even my school teacher and coaching teachers were not able to teach this good!!!
💖👈
speed of the plane is calculated by the distance travelled by the plane in 10 sec
=(4500m-1500m)/10s=3000m/10s=300 m/s. ok
Got right answer
Hey
Free fire
As I think you are the best Science Teacher and if you will regularly upload Mathematics videos then you will become best Mathematics teacher too.
If you all agree then Hit the Like button.
Awesome to hear that you like our videos!! Thanks a lot :) Do share it with your friends and family!
Here is the summary and related questions:
The video discusses how to apply trigonometry to measure heights and distances without directly measuring them. It covers examples such as finding the height of a tall building, the width of a river, and the distance between ships using trigonometric ratios.
Key moments:
00:00 Trigonometry can be used to measure heights and distances without physically measuring them by utilizing ratios and angles in right angle triangles. Understanding trigonometric ratios like sine, cosine, and tangent is crucial for these calculations.
-The video explains how to apply trigonometry to measure heights and distances without direct measurement, simplifying complex calculations using ratios and angles in right angle triangles.
-Understanding trigonometric ratios such as sine, cosine, and tangent is fundamental for accurately calculating heights and distances in trigonometry, making the process more efficient and practical.
06:09 To find the height of a building, use trigonometric ratios like tan theta with known values to calculate the height accurately. The process involves identifying the unknown, applying the appropriate ratio, and solving for the height.
-Calculating the height of a building using trigonometry. It involves identifying the angle, applying tan theta, and solving for the height accurately.
-Visualizing and solving for the angular elevation of the Sun. By drawing a diagram, using tan theta with known values, and finding the angle accurately.
-Understanding the concept of angle of depression. Explaining how to calculate the angle from the top of a building using trigonometry and known values.
12:48 Understanding angles of depression and elevation helps in solving trigonometry problems involving heights and distances. By visualizing and applying trigonometrical ratios to right angle triangles, complex questions can be easily solved.
-Explaining the concept of angles of depression and elevation and their significance in trigonometry. Visualizing and drawing diagrams to solve height and distance problems efficiently.
-Analyzing the given question about finding the width of a river using angles of depression, heights, and trigonometry. Breaking down the problem into smaller parts for systematic solution.
19:30 The video explains how to use trigonometric ratios to find unknown sides in triangles. In one example, the width of a river is calculated by adding the lengths found using trigonometry.
-Using trigonometric ratios to find unknown sides in triangles. The video demonstrates using ratios like tan 30 and tan 45 to calculate side lengths.
-Calculating the width of a river using trigonometry. By adding the lengths found for X and Y, the width of the river is determined.
-Applying trigonometry to solve a real-world problem. The video presents a scenario involving a lighthouse and two ships to demonstrate trigonometric calculations.
26:38 To find the distance between two ships, trigonometry is used to set up and solve equations based on angles and side ratios, resulting in the distance of 54.90 meters. For a statue and pedestal, trigonometric ratios are applied to determine the height of the pedestal as 1.2 meters.
-Trigonometry is utilized to calculate the distance between two ships by setting up and solving equations based on angles and side ratios, resulting in a distance of 54.90 meters.
-Applying trigonometric ratios in a scenario involving a statue and pedestal to determine the height of the pedestal as 1.2 meters by setting up and solving equations based on angles and side ratios.
33:38 To find the height of a hill, rationalize the denominator in the calculation to simplify the process and get an accurate result efficiently. Trigonometry can help determine distances and heights in geometric problems involving angles of elevation and depression.
-Rationalizing the denominator simplifies calculations with irrational numbers, enhancing accuracy and efficiency in mathematical solutions.
-Trigonometry aids in solving geometric problems by utilizing angles of elevation and depression to determine distances and heights in a structured manner.
40:21 The height of the hill is found to be 40 meters and the distance from the ship to the hill is 17.32 meters, demonstrating a simple application of trigonometry in real-world scenarios.
-Trigonometry is used to find the height of the hill and the distance from the ship, showcasing practical applications of mathematical concepts.
-The video encourages viewers to attempt solving a question involving the speed of a plane and provides resources for further practice and learning in heights and distances.
I don't understand how can People dislike a video like this....
Sir how could u manage so modern way of teaching , sir your teaching is based on USA teaching system ☺️
So nice of you
Sir how could you manage so modern way of teaching, sir your teching is based on USA teaching system😀🙏🙏
Green screen Ka nam suna he
दोस्तों, जो भी मेरे भाई - बहन 10th NCERT MATHS पढ़ना चाहते हैं वह Maths Easy 4 You चैनल पर आ जाइए, पुरा MATHS स्टेप बाई स्टेप पढ़ा रहे हैं अब आपको किसी भी टॉपिक के लिए कोचिंग नहीं जाना पड़ेगा !
एक बार देख लो हो सकता है आपका तलाश खत्म हो जाए।
अब मैथ्स रटना नहीं, समझना हैं।।
🤗👍👇👇♥️🌹🙏🔥
ua-cam.com/video/dwXGaLDsLfM/v-deo.html
@Amos Peters no
Woke up at 4 in the morning to watch this wonderful video 😉
Damn
Really a good teacher while watching this it feels like I'm in any foreign school or what?? And by watching this i learn some good pronunciation of words... really helpful 👍👍 thankyou sir
Most welcome and glad to hear that you are liking them.
Finally a guy who speaks in english
He is a very nice teacher
No other teacher can explain better than him.watching his videos since 2 years
Truely helpful for quick revision one day before preboard : )
I understood the concept clearly
Tqs sir 👍🙏
Great 👍
If it is a tringle with 30°:60°: 90°
The opposite side's ratio= 1:√3:2
And for 45°:45°:90°
Side's ratio=1:1:√2
Such a hard working person thanks for all videos
In ∆BAD,
tan(angle D)=Opposite/Adjacent
Or,tan(angle D)=AB/AD
From the trigonometric table,
tan(30°)=1/√3
Or,75/AD=1/√3=75√3=15m
In ∆BAC,
tan(45°)=1
Or,AB/AC=1
Or,75/AC=1
Or,AC=75m
Or, Distance between two ships=AC-AD=75-15=60m
U are a real mathematics tutor. Thank you so much.
Sir tq for your best videos. Before i was very poor in mathematics 😌but now I can able to answer any type of questions really they are very helpful sir thank you thank you so much sir
Happy to help
Nice teaching and neat handwriting
🙏🙏
Thanks I understand the chapter clearly.
It's my pleasure
@@ManochaAcademy 😊🙏🙏
Superb teaching!! 🔥🔥👌🏻👌🏻👍👍
Thanks a lot 😊
Hi sir am a Nigerian I love your teaching so much your explanation in a topic make it easy for me to understand 💯
Is my answer correct the question you gave us "300m/s"
Thanks sir actually i have math exam today wish me luck!!
All the best
And u decided to watch this at the final day!
this is way better than byjus
But not better than shobit baiya
Agre
Really like the class...
It was amazing 😊
Thanks a lot 😊
I am very happy to find a great teacher
🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏
It's my pleasure
Sab students apny exams pass karny k sath sath is ko sahi tarah samjhain b warna meri tarah surveying field mein dobara videos daikh k samjhna pary ga..Thanks sir for great help
I'm from INDONESIA your channel is so good and your teaching are so marvelous
Thanks a ton!!
Kpiyfbjjkvr
Sir thank you for you wonderfull teaching.I understood the cocept very well
I follow you since long time sir !! i really like the way you explain concepts ❤ and also your smile makes me feel happy !!! THANK YOU 😊🙏🏻🙏🏻
Same here
It's my pleasure
First position of plane has distance from the point of observation equal to 1500 m and after 10s the distance from observer equal to 4500m and to find speed v need to use d/t formula. Time will be 10s and distance moved at the time is 4500-1500 =3000. Now substituting on formula 3000/10 we get 300m/s as answer
The speed of the plane is 300 metre per second😊😊😊 sir your videos are quiet helpful to approach the practical learning so thanks a lot Sir🙏🙏🙏
Great 👍
Sir you are explaining physical science and also mathematics amazing mind blowing sir we are appreciating your talent and we hope you continue this for long time thank you for your teaching 🤗🙏🙏💐💐💅💅💅💅 💅💅💅 💅
Thanks and welcome
Ok 👍👍 👍👍 👍👍 👍 sir
NYC explanation sir, it is very helpful for me, this video made this chapter very easy for me, thank you sir.
Mindblowing, outstanding, historical, fantastic, unbelievable, you are really best teacher on▶️▶️. Thanks Sir.
Most welcome
@@ManochaAcademy sir sarminda mat kijiye 🙏🏻🙏🏻🙏🏻
very nice class, sir what is your writing tool? because the colour look so pretty and I'd like it if you keep using that tool. This is my first time watching your videos, and I find this one worth my time since lot of other teachers take 2-3 hours to explain the chapter but you did it in just 44 min. it was worth it. for the new commers, I would highly recommend this channel. thank you sm!
Sir I am an experienced engineer I am amazed by your teaching ability great
Thanks
This concept help you to solve any problem in life!! I hope we solve all problem in r life just like tha!! 💜
Sir after watching the video i tried all the questions I found them to be correct ,thanks a lot sir 👍👍👍👍👍👍👍👍
Well done!
दोस्तों, जो भी मेरे भाई - बहन 10th NCERT MATHS पढ़ना चाहते हैं वह Maths Easy 4 You चैनल पर आ जाइए, पुरा MATHS स्टेप बाई स्टेप पढ़ा रहे हैं अब आपको किसी भी टॉपिक के लिए कोचिंग नहीं जाना पड़ेगा !
एक बार देख लो हो सकता है आपका तलाश खत्म हो जाए।
अब मैथ्स रटना नहीं, समझना हैं।।
🤗👍👇👇♥️🌹🙏🔥
ua-cam.com/video/dwXGaLDsLfM/v-deo.html
Sir ur teaching is awsome
Thanks a lot 😊
Your teaching skills are awesome and fabulous I watch all of your videos in lockdown period.
Glad you like them!
Sir your English is very best and smooth
be my school's math teacher please 😭 you teach way better and i'm actually able to understand, thank you!!
Happy to help!
Thanks sir for making this easy ☺️I'm on track now 👍
Great 👍
Yeah that's true Taniya
💖👍
Your class and preponho are the best classes in english
Byjus 🙄
Vedantu🙄
Thank you! 😃
We,know tan(x)=Opposite/Adjacent=10/10√3=1/√3
From the trigonometric table,
1/√3=tan(30°)
Or,The angular elevation of sun is 30°
Sir your explanation is gooooooooood🎩
😁
👕👍Great!
👖
Thank you sir Very much🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻
I am facing so much difficulty in these but by seeing your video I understood the concept and how to solve❤️❤️❤️❤️❤️
All the best
You really made this ch easy please upload circles and more maths
First we have to find the length between point of observation and the plane before the trip ,then we find the length between point of observation and the plane after the trip. Finally dividing it by the time we get 300m/s. Isn't it?
Sir u r legend in teaching maths in such a graphical method.
Superb teaching. Looking forward to more of your classes.
Awesome, thank you!
Sir pls do a video on triangles it’s a bit difficult and I like your videos
I'll try to put more Maths videos soon!!
Sir truely my teacher explained this chapter for 2 times but i did not understand......
In this 44mins with the pictures u have shown and explained i loved it sooo much sir... Thank you😊😍😊😊
Excellent
Thank you so much sir helping me so much for my exam😊😊😊😊
Most welcome
Thank you!! You are just amazin! New subscriber ❤️🥰
Gr8 Aswome Explaination.. Totally Clear!✨
Our manocha sir is an all rounder
Thanks. Glad to hear that.
Avuna pinnisetti suhas
Sir you are a magician you just made everything no words to express your explanation 👍👍👍👍😘
Thanks and welcome
Thanks sir your way of teaching is excellent iam now unstoppable 🔥
Keep it up
WOW, Sir.....Thank you very much for helping me out!!!
Ur explanation is brilliant sir...Tqs...
And the ans for last question is=300m/s
You have really teached this chapter so well in this video that i really appreciate sir......thank you for this video!!😊
Most welcome
It is super I understand all questions
SIR HOW DO YOU TEACH SO WELL!!!!
I CAN NOW REMEMBER AND LEARN ANYTHING FROM SCRATCH!
THANK YOU
Glad to hear that
Speed of plane=300m/s
Sir you are brilliant from Nepal😍👏👏
Oe mula
The speed of the plane is 300 m/s.
Sir, you explain very well by that I can understand class 10th topic in class 8th and solve questions it's questions.
Superb explanation.
Thank you so much sir.
Love the way you teaches.
Thanks a lot!! Do share our channel with your friends :)
Love your boards and sketches and teaching toooo
Glad you like them!
Teaching method is so good 👍👍
Thanks for liking
Sir your teaching skills are next level 👌👌
Thanks a ton
Welcome sir
Sir you teach very well and with modern technique
Thanks and welcome
Thankyou soo much you say it soo slowly that anyone could understand I love watching his classes
true
Thanku sir,good explanation 😉👍
Most welcome 😊
Excellent video sir!!
Glad you liked it!
Excellent!!!!! Thank you so much Sir 😊
Most welcome!
Thanks sir for understanding topics the concept and clearing my doubts 😌
ARMY??
@@Churoost Bts
@@Genzaura.07 oo..
Armies ✨in maths session !! 😂
Thankuuu sir
Ur explanation was amazing😊😊🌠
Most welcome 😊
Awesome sir.... Really mind blowing
Thank you so much 😀
Thx for the video sir as my half yearly exam is going to start...
This video really helped me out... Thanks a lot sir. 🙂🙂
Most welcome 😊
Amazing fantastic teaching 👏👏👏
Thank you! 😃
Sir thank you tomorrow my test is there on heights and distances and i was scared what to do but now my concept is totally clear. THANK YOU SIR !!!!
All the best
@@ManochaAcademy Thank You Sir 🙏🏻🙏🏻
Sir the answer is 300 m/s where x=1500m and y=1500m so, x+y=1500+1500=3000m then by the formula speed=distance/time, time is given 10s and distance 3000m=3000m/10s=one 0 is cancel 300m/s answer....
Your teaching is marvellous sir
Thanks and welcome
Crystal clear sir😊
Thank you so much
Welcome 👍
☺
Sir,your explanation is Excellent and the answer for question is 300m/seconds or 1080 Km per hour
I have recently started watching your videos and i really loved them, thank youw for explaining the concepts in an easy and interesting ways
Awesome to hear that :) Do share it with your friends and family!
Excellent, thanks!
Legends like me see this one day before their board exam😂😂😂
For real broo
Yep bro
Me too 🤣
Ya
Yah bro 😂 am here tooo
Good teaching sir 👌👌🖤♥️♥️you have continued this class sir and more helpful to students tq🤝🤝so much sir
I understand all the basic concepts
Amazing sir 👏 best video of heights and distances. I am now very clear. Thank you sir
Most welcome
Really amazing ....extracting roots by brain
Thanks for liking
who is studying this topic in lockdown is really very intelligent #brilliant
Wow sir you reply all comment .which is very good
Your method is best👍👍👍👍👌👌👌