Easy Way To Determine Aromaticity: Aromatic, Antiaromatic, Nonaromatic
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- Опубліковано 20 сер 2024
- Quick and easy tricks to determine whether molecules are aromatic, antiaromatic, or nonaromatic... especially helpful for #dat questions. Common confusions involving hetercyclics and charges is cleared up in this video. And you don't have to memorize Hückel's Rule to determine whether molecules are aromatic, antiaromatic, or non aromatic.
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Impressive explanation mam
Thank you very much. You clear all my doubts in a very easiest way.thanks a lot❤❤
I am so glad this helped make it easier! Thank You for watching!
so helpful! thank you amreen. there truly is no better trainer thank you!
Thank u for saving my time
The best video ever ❤❤
I am glad this helped!
Thank you for yet another helpful video!
Amazingly simplified! Couldn't explain it better, thank you!!
Thank You!
omg.... you made my exact issues with aromatic molecules so much more clear... thanks
I’m glad it cleared aromaticity up for you!
❤❤. Pls continue making it. Pls make a trick for gmp of hydrocarbons.
I will work on a trick for that. Thank You for watching!
Thank you for helping me understand but I only have one question .why aren’t you counting the +charge at 9:15 to make it 8 pi electrons resulting to anti aromatic?
Hi... thank you for watching! A +charge on a carbon indicates that it lost its 4th valence electron and therefore now only has 3 bonds (bond to H not shown) using its 3 remaining valence electrons, and no other electrons, so think of the +charged carbon as "void" of pi electrons (so, no electrons to count there), remembering that pi electrons are either lone pairs or the 2 electrons in a double bond. But we do consider the +charge when determining conjugation, because pi electrons can jump to the +charged carbon since there is a "void" of electrons, like there is a "vacancy" for pi electrons to jump into. It also helps to think about a carbon with a -charge; a negatively charged carbon has its 4th valence electron and gains a fifth electron that pairs up with the 4th to make a lone pair [plus the 3 bonds as mentioned above]; that's why we count the -charges as pi electrons (lone pairs). I hope this helps further understand aromaticity and why +charges are included but not counted as pi electrons.
Good question... btw... it's a common question among my students, and hopefully this helps others better understand aromaticity!
Hello, does the "including in counting as double bonds, but not in counting as pi electrons" apply to both positive and negative charges?
This is so helpful!
I am glad this was helpful!
you so so amazing! thank you so much for your help :)
I am glad this helped! Thank You for watching!
God bless that’s all I gotta say
lol... thank you so much... glad this helped!
You should increase the volume of the sound
Thank You for the feedback! I will make sure to crank it up a bit on all future videos. I was always afraid I was making it too loud; I appreciate the constructive feedback!
Well cyclooctatetraen isn’t planar in the first place
True... cyclooctatetraene predominantly exists as tub-shape due to its irregular bond lengths, however, I intended to show its planar transition state between its tub-shapes which is antiaromatic. I showed its antiaromatic state because that's how they usually show it on DAT or MCAT. If they were to show the 3D tub-shape, then indeed it would be nonaromatic. Thank You for watching!