Відео

I freeze up every single time I see a question I know I will have to do dimensional analysis for. No matter how much I practice, under pressure, I do not stand a chance. I am looking forward to trying these tricks in detail.

I'm so glad you found this helpful... it will make a difference on MCAT! Thank You for watching! The book will have a ton more practice questions and examples with detailed explanations, when you receive it!

If you are referring to the third example at 3:12, it is cis because the CH3 on the left C= is priority and the CH2CH3 on the right =C is priority is priority, and they are both on the same side as the double bond. This one only looks trans at first glance, because our eyes see immediately see the two CH3 groups across from each other, but be careful... the CH3 on the right =C is not the priority.

@PraxisAcademic understood thank u

That row was placed there because those transition metals have valence electrons in the 3d subshell plus they have valence electrons in the 4s subshell [whereas the elements in the third row do not have any electrons in the 3d subshell]. The "3d transition metals cannot be placed in the third row, because they have the 4s subshell, so they were moved down to the fourth row because they have the 4s subshell, in other words, hey were not placed in the third because of having the 4s.

Thank You so much! I feel I might have been one of those profs who taught things too complicatedly back in my teaching days, but since I have slowed it down with only one-on-one tutoring, I have been able to see the simplicity in crazy science concepts, and only ever hope students will see the simplicity as well! LOL... long story short... thank you for subscribing!

I am so glad this helped! And thank you for watching, liking, and subscribing!

I am so glad this helped make it simpler... it has helped my students better understand and write e-configurations, so I thought I'd share with others!

I'm so glad this helped... lol... saved your life! Thank You for watching!

I'm glad this helped with sigfigs! Thanks for watching!

Thank you for watching! I'm happy this explanation helped you see the connections between the trends!

I am so glad this helped you... orgo is totally a foreign language sometimes. Thank You for watching!

Thank you for your much appreciated feedback!! I am working on sharing more insights... your feedback encourages me you work faster at it... lol. Thank You! 💟

Thank You for your constructive feedback... I'll make sure I have chiral molecule with a benzene substituent on it in the 2.0 version of this video that I plan on getting to soon. Thank You!

Valence electrons are the electrons in the outermost shell (highest energy level) whether the shell is full or not; valence electrons are the ones that may be lost resulting in cations, or ones that may share half-filled orbitals for binding, and valence shells can also accept electrons resulting in anions. Core electrons are the electrons in the inner shells (lower energy levels) which are completely full; core electrons cannot be lost, and cannot share orbitals for binding or accept electrons since all core orbitals are full.

I am glad this helped!

I am glad this helped!

Thank You so much! I'm glad this helped. And thank you for watching!

First, thank you for watching the video! Second, thank you for purchasing the book; it'll be a game changer on MCAT! As far as solving for the question you posted: since Planck's constant already has the J you need in the answer and we just need to cancel the s out, start by converting 610 THz to 610x10^-12 Hz, and then Hz breaks open into 1/s giving 610x10^-12 1/s which should be written as 610x10^-12/s (610x10^-12 in the numerator and s in the denominator). Now, dimensional analysis: 6.6x10^-34 Js • 610x10^-12/s The s will cancel out leaving only J, so then multiply 6.6x10^-34 times 610x10^-12 to get 4026x10^-22 J, and if the answers are in exact scientific notation, then move the decimal to the left 3 places to get 4.026x10^-19 J. I used calculator cuz I'm lazy tonight, but you'll learn some math-without-calculator and rounding tricks in the book.

If you'd like to see an image of the work I described above, simply email the question to inquiry@praxisacademic.com, and I'll send it... unless you know how to post images in replies here... lol... I don't.

@@PraxisAcademic Thank you so much for taking the time to write this all out! I will be emailing you for the image. I kept getting confused as to why the exponent came out to -22. I thought when you multiply in scientific notation, you add the exponents. So -34 + -12 = -46 not -22 but then I realized Tera is positive 12 not -12. I definitely need math-without-calculator tricks, I had no idea how to multiply 6.6 by 610 any quicker than using lattice lol. Thank you again.

@@cristinamruiz2 You also learn a couple quick and easy tricks to convert metrics in the book! I will look out for your email. Thanks!

@@PraxisAcademic Hi! I tried emailing you but it said your email is "blocking" my message.

Thank You! I'm happy you see orgo as fun after this!

I will work on a trick for that. Thank You for watching!

I am glad this helped!

I am so glad this helped make it more clear! Thank You for watching!

Awww... that's so sweet of you! I appreciate you liking it!

Thank You!

Thank You for watching and using my trick. I hope the exam went well!