Some commenters have made an important point: there are definitely times when you do NOT want to be Eule-y to the max. Sometimes you need to break away from the rigid rules of the game. For example, if you have 100 slips in The Game of Googol and one of your sample slips contains a number with 99 zeroes, you’d want to commit to it. You understand that the number is very close to the maximum, and with something like 90 slips left, the odds that you’d draw a number higher than that are extremely low. There just aren’t enough options, so it just wouldn’t make sense to keep turning over slips just because your system tells you to. A reliable, math-based system is awesome... but when you know, you know.
If it's a random selection from 0 to 10^100, wouldn't 1x10^99 be in the bottom 10th percentile? Anyway, I gotta go talk to 3.8billion/e women real quick if I want to find "the one"
Something's missing, how long do you continue if you do not pick a number higher than one in the first 40%? (Also screw e right, fourty %) If we've no idea of the top #, how much longer do we pick until we settle for something less?
I think the key assumption that makes The Game of Googol admit a better strategy is that you know a priori the range of numbers allowable. So you should be able to use this to avoid the initial search and instead determine the value to be exceeded at the start of your search.
@@SCOOTYBOOTYPATOOTY Surely you can't start to stop until you've started starting to stop, and you can't start starting to stop until you've started starting starting to stop... (ad infinitum).
"When should I stop, I honestly don't know" Five seconds later: "The odds of my me choosing correctly are 1 in 3 because I'm going to employ optimal stopping theory."
Well the idea for "should" stop isn't confined to what WE know, but to what there is. So he still honestly didn't know when he should stop, just when is statistically the best time to.
Soooooooo for the love of my life I just have to date approximatly 1.2 billion women and then take the next one that's better and I'll have the love of my life... sounds easy enough
You're a primate. You have a social sphere of roughly 150 people. ~75 women. Let's argue that MAYBE 10% could be considered sexually available to you. Date 3. Marry the next one who is better than the previous 3 - unless of course you find a complete stand out earlier on. Data indicates people with fewer sexual partners live happier lives - despite what modern media tends to suggest. Yes, ~50% of marriages end in divorce, but that means ~50% of marriages last until death - that's not a bad rate of success for any multi decade endeavour. IIRC small businesses fail in the first few years ~2/3rds of the time.
@@c6q3a24 "yes 50% of marriages end in divorce" if that was all there was to it, then it wouldn't be a scary thing at all and you'd be crazy to not play the odds. problem is, that 50% chance of divorce translates to a 50% chance of losing everything you've ever managed to obtain up until now and most of what you will make in the future until death. enjoy trying to roll the dice with another woman whilst being homeless and having to give over half of your paycheck to your ex-wife. Looking at it like that, you have ONE chance and only one chance.
This is the type of math I wish I could have figured out when I used to watch deal or no deal. I always felt like it logically made sense to open up a certain number of cases first before even thinking to settle on one
You don't need this for that, it's a pretty simple math problem to calculate ev. It's basically always better to keep opening, the game is more about how risk adverse you are
The thing with a lot of these generalized optimization of stopping problems is that you know the best spot you can find, or at least the limit that you’d be happy with. For instance, I may not know that this is the best video on the entirety of the internet, but it’s one that I will find enjoyment in watching, so I watched it.
Bill gates was studying law at Havard , lowest period to complete degree was 5.5 years . 5.5 years = 66 months .... 66 / 2.71828 = 24 months . Bill Gates quit after 2 years .
Kevin: You just need to quit Also Kevin: This is sponsered by LastPass Computer: What is your Password? Me: I'm so confused if I should quit remembering or use LastPass
Thanks for uploading this, it is very similar to a strategy I read about for deciding which checkout to use in a supermarket to maximise your chance of being in the shortest queue. It said walk past 1/3 of the checkouts then join the next queue you come to that is shorter than any you have so far seen. I do actually use this strategy in real life and it does seem to work.
@@weckar That depends on the layout of the store and the amount of people in line. If the isles are too close in relation to the check out line, you would most likely only be able to see 4-7 at a time. If there are 20 check out lines, due to the narrow path between the isles and the checkout line, you won't be able to get a large enough angle from your vantage point to see all of the lines at once. Your chances are basically doubled if you start towards the middle of the 20 lines because you can look to the left and right of yourself. This happens to me at most Walmarts or chain grocery stores in my city. But if it's a smaller store, then you're definitely right. Have a nice day, I hope that made sense. I have a brain injury so it might not have. 😅
I actually stop before 1/3 when the first ones are empty, this is slightly different from this problem, because you sometimes know, there can't be better option later.
actually is youtube that suggest the video on the right side, and since i usually watch V sauce videos i just did it. i don't think there was any chances in play lol
But what if you quit because someone tells you to quit since you dont quit now you'll have to quit later but since you are quitting in the moment based on anothers actions, is it really quitting?
How did you see vsauce without scanning? In your case, the first video you saw was Vsauce. Or maybe you determined the most optimum video to watch was vsauce and therefore just chose the first Vsauce video you saw. In either case you still had to "scan" through the videos.
@@SDCGI you can also count them individually. Even if it's like a trillion or something that you have to count. It optimizes your probability if you use the equation.
If the numbers are randomly split in a group of googol and you take a sample group of a usuable amount of numbers, wouldn't that ensure that the theory still works and is therefor useable on any group size that is randonly distributed? Like Kevin did with his group of ten.
@@enrique.guzman891 I think he meant when the number of choices is indeterminate, like dating. How many options would you have if you just kept dating?
@@Chizypuff You can apply it to time as well. Lets say you start dating at 18 and you'd want to be married by 35. Date, but don't marry anyone you meet before 24 yo (37% of the way) and than propose to the next person you date that's better than every person before that. But of course you need to assume things and set a limit, to be able to calculate the 37%.
@@qtulhoo as far as i know you just have to be as confident and selfish as you can possibly be and women will want you. am 23 and had only 3 so far so am not really an expert.
This won’t help me find the love of my life because 0 divided by e is still 0 Edit: 2 days after posting this comment someone I really like asked me out o_o
I remember learning about online algorithms in CS classes. Never get the chance to use it in real world applications, but they sure are fun to think about.
Two years ago, wether a UA-cam poll had 5 options on it, users would purposefully select options where option 1, 3 and 5 have the most votes while options 2 and 4 had the least votes. This caused different lengths in the voting options resulting in a letter ‘E’.
I like it how he’s like “we won’t want to stop at 9 cause the chances are we would have passed over the highest number” ...and then it turns out to be 9 😂
Essentially - if you need to maximize by choosing 1 item from a set where the options are presented 1 at a time: 1. Define the "maximum score" in this context. 2. How many items are in this set (or: how much time do you have to choose)? 3. Go through n/e options (roughly 10% more than 1/3) and keep track of the item with the best score. 4. Go through the remaining options (or time) and select the first item with a higher score than the one you had.
So the basic idea is, look at 37% of the items, and pick the next item that beats all of the first 37%. But then what if the biggest number happens to be in that first 37%? You just get whatever number is at the end in that case.
Think about life choices. You will still have a great chance to make the top 10% of all choices. Life isn't always about being first or the best on every decision. But making close to the best will keep you on a forward moving path
Thats why u lose 1/3 times over there and have a 1/3 chance to get a number greater than the first 3rd and get less than the last 1/3rd adding up to 2/3rd losing rate Pretty simple??
@@CellXD It seems like you'd have a 1/3 chance of it being the highest number selected SO FAR, but afar lesser chance of it being the highest number out of all of them.
I don't need to scroll through every UA-cam video, as soon as I see "Vsauce2" I know it's gonna be a good one. And I don't have to commit to just one, I can watch all of them.
*_"That this is the UA-cam video I am gonna watch, without realising you played the game of googol while watching a video about googol"_* You got me there
E is the one of the most important things in math, the english language, and even computers. Oh look at that, 3 choices and 1 was disowned, it's 1/3! RIP internet explorer chan.
so im gonna be a theorist here rn. googol is game game of you deciding when to stop. so googol is pretty much google but actually teaching you about a small loophole of the random thing your gonna do in life or whenever anything is gonna stop in the unaverse like an atom. it could stop existing but it doesn't. and so there's a lot of theories that can be made with a simple game that a bored person made. but either way i love things like this that leave you thinking its the ground base of learning and creating with a simple theory or question. and loopholes as e definition is a loophole itself......... keep up the grate work guys!!!!!
Actually i watched your 1000 vs 1000 plus 0 or 1000000 candies video and saw this in the recommended, wanted to look at my subscriptions first and came back to this video later. So jokes on you!
unfortunately to swipe through 37% you'd need to know in advance how many potential matches you have. That said, I'm actually pretty curious how a pickup line based on the optimal stopping theorem would go over. Almost tempted to try.
@@SirPhysics Do you need to know how many matches you have? or just how many you are willing to look at? If you are only willing to look at say 100 people then it doesnt matter if you actually have 500 matches. just apply 37% to w/e number of people you actually are willing to look at. ofc tinder, or similar algorithms do not limit you to just picking one, and picking or not picking will influence future options.
my IQ is EEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE
Well, it depends on what you consider the entire pool of mates. If 11 people is the most you're willing to date before settling down, then that's correct.
@@pekuja Actually, if you are willing to date 11 possible mates and then settle down, you should actually meet all 11 of them, cause there's no rule you have to choose the last one met, you can marry the best of the whole pool. Unless of course, the cost of meet-ups is prohibitively high.
@@desarankoe3939 I think the point is that you won't know if you're a good match until you've actually dated them, and you probably can't date and break up with ten people and then get back together with the one you liked best. Also, it's not that you have 11 people preselected, but it's the 11 potential people you'd date over a long time. You probably don't know all of them to start with.
Great explanation and video. One "mistake": including the choice of which UA-cam video to watch doesn't fit with the rest of your examples in that a viewer might be watching many videos - they don't have to choose only one. Also they can "go back" and watch a video that they passed over the first time. In fact, I've been spending my evening procrastinating by watching UA-cam videos, and passed over this video five or six times before I decided to watch it.
Some commenters have made an important point: there are definitely times when you do NOT want to be Eule-y to the max. Sometimes you need to break away from the rigid rules of the game.
For example, if you have 100 slips in The Game of Googol and one of your sample slips contains a number with 99 zeroes, you’d want to commit to it. You understand that the number is very close to the maximum, and with something like 90 slips left, the odds that you’d draw a number higher than that are extremely low. There just aren’t enough options, so it just wouldn’t make sense to keep turning over slips just because your system tells you to.
A reliable, math-based system is awesome... but when you know, you know.
If it's a random selection from 0 to 10^100, wouldn't 1x10^99 be in the bottom 10th percentile?
Anyway, I gotta go talk to 3.8billion/e women real quick if I want to find "the one"
Something's missing, how long do you continue if you do not pick a number higher than one in the first 40%? (Also screw e right, fourty %) If we've no idea of the top #, how much longer do we pick until we settle for something less?
Can you tell how wormholes work (the paradox)
I think the key assumption that makes The Game of Googol admit a better strategy is that you know a priori the range of numbers allowable. So you should be able to use this to avoid the initial search and instead determine the value to be exceeded at the start of your search.
That's probably what all that math you had there and tossed out said.
8:54 Kepler:
"Hey, sorry I rejected you, I just thought I could do better. Guess I was wrong."
p01ar b3ar DONT LIKE THE COMMENT! (69)
E
His chances are 1/3. Same as every other marriage in history : )
Lol
If Kepler is a player, then he’s playing in the higher difficulty
Everyone: The game is all about luc-
Kevin: E
Luce?
@@mariafe7050 luck
maria fe everyone thinks the game is about luck, but then kevin just talks about e in this video (if u still didnt get the joke, what is ur life?)
e*
_the number e_
Me: *doesn't quit*
Game: Wait. This is Illegal.
I Did The Same
That's*
NitroOne seeing someone mess up a meme pains me
I made this comment have 666 likes I am Satan! 😈
@@mariafe7050 Ha.
Someone challenges me to a game of googol
Me: Hand me a calculator.
No divide by 4 if you round it up
E
@@yeetboy9231 what?
The most important question here:
How does a googol fit on such a small piece of paper?
10^100
@@kasimhanif3478 you forgot the ( ) maifren
Edit: very well now
E
@@sansleskeleton5570 --e
Maybe write "G" instead
"When exactly, mathematically, do we start stopping?"
From what i understood you immediately stop after finding the number higher than the sample with the highest number
Right before you stop starting.
@@grutfrut5817 and right after you start farting
@@DoctrZhivago you start stopping when you stop starting stopping
@@SCOOTYBOOTYPATOOTY Surely you can't start to stop until you've started starting to stop, and you can't start starting to stop until you've started starting starting to stop... (ad infinitum).
"When should I stop, I honestly don't know" Five seconds later: "The odds of my me choosing correctly are 1 in 3 because I'm going to employ optimal stopping theory."
I decided to stop scrolling when I reached this comment
When exactly should I stop?
I honestly don't know, but this system gives me a 12.5% chance of getting the best result, by surveying ~37% of the pool.
Sounds like an anime character being extra smart for no reason
Well the idea for "should" stop isn't confined to what WE know, but to what there is. So he still honestly didn't know when he should stop, just when is statistically the best time to.
Same but 4 years later@@Jessiemats
Me: what’s your favorite number
Kevin: EEEEEEEEEEE
E
EEEEEEEEEEEEEEEEEEEE
EEEEEEEEEEEEEEEEEEEE
EEEEEEEEEE
E
E
E
E
EEEEEEEEEE
E
E
E
E
EEEEEEEEEE
Whoa. Calm down there, Wall-E.
Soooooooo for the love of my life I just have to date approximatly 1.2 billion women and then take the next one that's better and I'll have the love of my life... sounds easy enough
dont worry no one wants to date you, 0/e is 0
You're a primate. You have a social sphere of roughly 150 people. ~75 women. Let's argue that MAYBE 10% could be considered sexually available to you. Date 3. Marry the next one who is better than the previous 3 - unless of course you find a complete stand out earlier on.
Data indicates people with fewer sexual partners live happier lives - despite what modern media tends to suggest. Yes, ~50% of marriages end in divorce, but that means ~50% of marriages last until death - that's not a bad rate of success for any multi decade endeavour. IIRC small businesses fail in the first few years ~2/3rds of the time.
@@c6q3a24 "yes 50% of marriages end in divorce" if that was all there was to it, then it wouldn't be a scary thing at all and you'd be crazy to not play the odds. problem is, that 50% chance of divorce translates to a 50% chance of losing everything you've ever managed to obtain up until now and most of what you will make in the future until death. enjoy trying to roll the dice with another woman whilst being homeless and having to give over half of your paycheck to your ex-wife. Looking at it like that, you have ONE chance and only one chance.
You can also think of it as "the amount of women you will meet before in a lifetime"/e
Actually, no. You have 1/3 odds of choosing the best one. Fortunately for all of us, there are lots of people that are good matches.
I found the love of my life hidden in plane math. I'm an aeronautical engineer.
What?
i was thinking about going into Aeronautics, got any tips?
Quit
@@miguelyepez8413 i haven't started yet
@@jessespence8332 i'm going to Uni soon to do that.
"will you go out with me?"
"hol up, lemme check"
*opens desmos app*
Hey Vscause, Kevin here, and-
Me: *gets ready for the intellectual bomb*
Vscause2: *_I HAVE A 100 PIECES OF PAPER_*
1000IQ gained
Vsauce*
♾ IQ received every time
Noice
*Vsause lol
Kevin: "e. The number."
Me: *distant screaming
lmaooo me_irl
*Confused screaming*
I winder how you'll respond to the number 'i'
*broken mind noises*
I am confused confuaing confusion
This is the type of math I wish I could have figured out when I used to watch deal or no deal.
I always felt like it logically made sense to open up a certain number of cases first before even thinking to settle on one
True, I never thought about applying it to that game!
You don't need this for that, it's a pretty simple math problem to calculate ev. It's basically always better to keep opening, the game is more about how risk adverse you are
I can’t wait for the April Fool’s Vsauce2 video. You just know there’s gonna be one.
Ayyyy! I loved your Lost in Silence vid! Tom beating up Paul!!!
DCO Nightingale i hope they teach us something real and watch as everyone tries to find whats wrong
MarbleSwan666 It’ll be some game that’s total nonsense and Kevin will be presenting it as if he’s serious.
Explaining how 0 is equal to 1
About some game that he completely makes up, with a mathematical principle that he completely makes up.
VSauce2: The key is E!
Markiplier: Am I a joke to you?
Jacksepticeye: SPEED IS KEYYY!!!
Doesn’t really make sense but okay
@@dabs5081 Yes it does: ua-cam.com/video/1bG8WcFk17Y/v-deo.html
Sub to PEWDIEPIE and KREATIVITYBOOST also plz!
Subscribe to PEWDIEPIE and KREATIVITYBOOST
Subscribe to PEWDIEPIE and KREATIVITYBOOST
The thing with a lot of these generalized optimization of stopping problems is that you know the best spot you can find, or at least the limit that you’d be happy with. For instance, I may not know that this is the best video on the entirety of the internet, but it’s one that I will find enjoyment in watching, so I watched it.
A satisficing decision criterion.
Education: spend 20 years in school then u might make 60 000 a year
VsauceKevin: *QUIT*
This is a white ELEPHANT Quit, but only after 20/e years
This is a white ELEPHANT exchange
@@Dylzhaar 7.35758882343
Bill gates was studying law at Havard , lowest period to complete degree was 5.5 years . 5.5 years = 66 months .... 66 / 2.71828 = 24 months . Bill Gates quit after 2 years .
Bhaalspawn84 Yeah, socialism ftw. JK, no sane person would want to pay that high taxes
I ended up recreating this game in Excel and playing for like an hour. There goes my lunch break I guess...
E
How?
@@kabirghai8709 by using excel you moron
@@Xanthopathy Ik he uses Excel, I’m asking what to do IN Excel
@@Xanthopathy why so mean 😂
Kevin: You just need to quit
Also Kevin: This is sponsered by LastPass
Computer: What is your Password?
Me: I'm so confused if I should quit remembering or use LastPass
E
Thanks for uploading this, it is very similar to a strategy I read about for deciding which checkout to use in a supermarket to maximise your chance of being in the shortest queue. It said walk past 1/3 of the checkouts then join the next queue you come to that is shorter than any you have so far seen. I do actually use this strategy in real life and it does seem to work.
Couldn't you just see all of them at once?
@@weckar That depends on the layout of the store and the amount of people in line. If the isles are too close in relation to the check out line, you would most likely only be able to see 4-7 at a time. If there are 20 check out lines, due to the narrow path between the isles and the checkout line, you won't be able to get a large enough angle from your vantage point to see all of the lines at once. Your chances are basically doubled if you start towards the middle of the 20 lines because you can look to the left and right of yourself. This happens to me at most Walmarts or chain grocery stores in my city.
But if it's a smaller store, then you're definitely right.
Have a nice day, I hope that made sense. I have a brain injury so it might not have. 😅
I actually stop before 1/3 when the first ones are empty, this is slightly different from this problem, because you sometimes know, there can't be better option later.
it’s just like the way to pick the best toilet stall strategy.
Couldn't you just go back
Actually no I opened up youtube and accidentally tapped on this video...
Edit: kinda glad I did though!
Caleb Flores same
auto play
I actually added this video in my watch later list and then came back to it :/
actually is youtube that suggest the video on the right side, and since i usually watch V sauce videos i just did it. i don't think there was any chances in play lol
Actually I open every video I want in a new tab and continue scrolling
Kevin: let's get euel-y
Ricardo: *_been there done that_*
Pssred
E
Let's get djdidisiaabdncjzosjdcnxnxkxoso'd
Not if I quit before you tell me to quit, that's it I quit
Spongebob SquarePants I quit
lol what? never mind I quit
@@kazumades5283 i dont understand, oh well might as well quit
But what if you quit because someone tells you to quit since you dont quit now you'll have to quit later but since you are quitting in the moment based on anothers actions, is it really quitting?
False Kevin, I see vsauce, I click. I didn't scan lol
How did you see vsauce without scanning? In your case, the first video you saw was Vsauce. Or maybe you determined the most optimum video to watch was vsauce and therefore just chose the first Vsauce video you saw. In either case you still had to "scan" through the videos.
@@laserbean00001 Hey bud, take a joke
@@CatIsMad If that was a joke, it was a really poor attempt in my opinion.
obviously its a joke, he said lol
Haha mine was on auto play
3:05
"The key is... e."
Kevin, Vsauce2
The number e
*E*
E
E
E
So lastpass is why you haven't forgotten your password, unlike vsauce 1 and 3
oh yeah yeah
explain
( ͡° ͜ʖ ͡°)
oof
This only works if you know the number of choices you have.
Toxic Kandy ofc is part of the equation
@@SDCGI you can also count them individually. Even if it's like a trillion or something that you have to count. It optimizes your probability if you use the equation.
If the numbers are randomly split in a group of googol and you take a sample group of a usuable amount of numbers, wouldn't that ensure that the theory still works and is therefor useable on any group size that is randonly distributed?
Like Kevin did with his group of ten.
@@enrique.guzman891 I think he meant when the number of choices is indeterminate, like dating. How many options would you have if you just kept dating?
@@Chizypuff You can apply it to time as well. Lets say you start dating at 18 and you'd want to be married by 35. Date, but don't marry anyone you meet before 24 yo (37% of the way) and than propose to the next person you date that's better than every person before that. But of course you need to assume things and set a limit, to be able to calculate the 37%.
plot twist: the first number was the highest
If the first number is the highest, you will probably know the moment you see it :P
But wut if the first number was 10
@@cjfdnqkn4374 there’s still a 1/3 chance of being right
The first number was lower than the second?
it still works because the first munber is very unlikely to be the best amongst the vast selections and the probably is extremely low
Pronouncing the o in googol so you don’t get demonetized.
This guy nah google owns UA-cam
Aidan Flynn You can never be too safe.
I don't think it works that way .... Proper nouns can't be copyright claimed for saying them xD
Actually Google gets its name from Googol, but they misspelled it.
@@ultimasdragon7840 Intentionally
*watches video, then pulls out notebook and figures out love life using e*
USERNAME NOT FOUND
*(0 ÷ e) - (Asexual + Unattractive + Antisocial) = 0*
:(
@@qtulhoo
as far as i know you just have to be as confident and selfish as you can possibly be and women will want you. am 23 and had only 3 so far so am not really an expert.
It will be Markiplier.
“You’re Johannes Kepler, and I’m BACHELORETTE NUMBER 5.”
Kevin Vsause2
E
"You played the Game of Googol to choose to watch this video about the Game of Googol."
*INCEPTION HORN INTENSIFIES*
This won’t help me find the love of my life because 0 divided by e is still 0
Edit: 2 days after posting this comment someone I really like asked me out o_o
Feels bad man
What if you divide by zero?
No its still 1 you got hope buddy
That's the magic of e...never doubt it again.
why not Gp
\o/ praise 2.72
I remember learning about online algorithms in CS classes. Never get the chance to use it in real world applications, but they sure are fun to think about.
I was in the middle of watching another video until a got the notification for Kevin’s video. Long story short, bye bye other video!
LOL Same, i was watching gmod videos xd
Whats the long story?
Sorry Mia Khalifa, next time.
This is one of the best recent vsauce2 videos. I like it when he starts making connections outside of the math problem to the real world.
UA-cam poll: *has 5 options in it*
Everyone:
2:19
i didnt understand
Two years ago, wether a UA-cam poll had 5 options on it, users would purposefully select options where option 1, 3 and 5 have the most votes while options 2 and 4 had the least votes. This caused different lengths in the voting options resulting in a letter ‘E’.
Is LastPass the reason you're the only one uploading regularly, and/or is this sponsorship a message to the other Vsauces?
The thing is he is using Chrome password manager in his demo the lastpass one looks entirely different
@@visaelites4694 Ok, I just thought he used it since he _said he's been using it since about a year ago._
Kabalan Zahouri I use LastPass and it looks like the one he had pulled up
@@phrax6767 That isn't lastpass, that's google.
The Prime Diam oh I see we are talking about different parts. Yes that’s google
Simple. Marry the first girl, who isn't bored by this video.
I'm applying for getting one those girls. 1 to go pls
E
The joke's on you, me and my girlfriend both weren't bored with this video; the two girls who weren't got together instead 😆
how can you get bored by this? lmao
@@puzzleduser lol the first comment was a year ago and this video is still being watched (epic)
I ran a program to test the accuracy of this method and its actually very close to 1/3. Sometimes maths just blows me.
For me, a programmer, math just tends to f*ck me a lot.
Does that mean I'm luckier or unluckier than you?
I like it how he’s like
“we won’t want to stop at 9 cause the chances are we would have passed over the highest number”
...and then it turns out to be 9 😂
Awesome video! Really like how you used the Googol game to explain the quitting processes of the human brain.
I love how Kevin always completely confuses us right before ending the video
Lord Farquaad chose Bachelorette number 3/3. Didnt work in his favor that time...
Of course, it all relates back to Shrek.
I have a crippling among us addiction
E
ratio
Ok
R
I've seen people using this strategy in life, but no one ever said a good word about it
You have taken on a combination of mathematics and human-deciding making in one clip, and I truly understood it! Thank you.
Vsauce fingers here, where are your Michaels?
*where are michaels*
this and many more fun math in *Algorithms to live by*
Vsauce: You didn’t scroll through every UA-cam video and decide to watch this one.
Me: Um... sure 😬
E
Person: "How was work?"
Kevin: "Today I said, 'Let's get oily' and then quit"
lol
E
FBI! Open up!
ok
I matched Tinderette 5... 10/10 works 37% of the time
Essentially - if you need to maximize by choosing 1 item from a set where the options are presented 1 at a time:
1. Define the "maximum score" in this context.
2. How many items are in this set (or: how much time do you have to choose)?
3. Go through n/e options (roughly 10% more than 1/3) and keep track of the item with the best score.
4. Go through the remaining options (or time) and select the first item with a higher score than the one you had.
@@mathguy37 Yes. But, EnterJustice's suggested heuristic of "10% more than 1/3" is more easily remembered, imho.
So the basic idea is, look at 37% of the items, and pick the next item that beats all of the first 37%.
But then what if the biggest number happens to be in that first 37%? You just get whatever number is at the end in that case.
That's why the strategy only works 1/e of the time
Think about life choices. You will still have a great chance to make the top 10% of all choices. Life isn't always about being first or the best on every decision. But making close to the best will keep you on a forward moving path
Thats why u lose 1/3 times over there and have a 1/3 chance to get a number greater than the first 3rd and get less than the last 1/3rd adding up to 2/3rd losing rate
Pretty simple??
@@CellXD It seems like you'd have a 1/3 chance of it being the highest number selected SO FAR, but afar lesser chance of it being the highest number out of all of them.
your theory is not true.
Vsauce 2 is always the channel i'm gonna watch.
gotcha
Giving me a mental crisis here - e is such an amazing and helpful thing in calculations, yet it's the bane of my existence as a Medic main...
Vsauce! Kevin’s here and today i gonna show you a very cool game!
-Kevin left the game.
It seems the only way to win... is not to play.
I do this for things on sale. I'll pick a price after seeing it go on sale a couple times and if it ever goes under that price I buy it
I don't need to scroll through every UA-cam video, as soon as I see "Vsauce2" I know it's gonna be a good one. And I don't have to commit to just one, I can watch all of them.
*_"That this is the UA-cam video I am gonna watch, without realising you played the game of googol while watching a video about googol"_*
You got me there
xd Sanad “googoo”
Lol
@@parthinaxe lmao
This is now one of my favorite Kevin videos
Wow- my mind has been blown ! now I'll never have to worry about that part in my life. Thanks!
I love how instead of an APA citation you literally just threw the paper off screen.
This is like when you're trying to find loot in CoC. You're happy that you found 500k gold, but you never know if you'll get more if you skipped..
so you need to skip (the amount of players in coc)/e to find the best loot, assumung that everyone is active and at the same rank
Not seen an ad for Lastpass for a long time, already a user so instead I'll just say it's excellent. Been using it for a decade now
Guys, keep your money safe, don't gamble with kevin......
me: oh hey kevin uploaded t-
my friend: *w h e r e ‘ s m i c h a e l*
it's insane how eulers seems to be so bloody useful!
you look like the next farcry villian
I watched this video because I subscribe to VSauce2 and watched you since Julius Bloop. No math, just loyalty!
You see, I didn't scan through videos and found this one. It was on the top of my list so I watched it.
Numberphile did a video of this about choosing the best cubicle at a concert
The Mathematical Way Of Choosing A Toilet.
Matt GSM Yeah, with that hot girl
@@gabor6259 That would depend on the urgency, but you might want to choose the first one available xD.
@@eternalreign2313, yeah, you don't really do maths in your head when the grizzly wants to break free.
Can you let us know the link to the Numberphile video you mention. I couldn't find it.
E is the one of the most important things in math, the english language, and even computers.
Oh look at that, 3 choices and 1 was disowned, it's 1/3!
RIP internet explorer chan.
*_E_*
so im gonna be a theorist here rn. googol is game game of you deciding when to stop. so googol is pretty much google but actually teaching you about a small loophole of the random thing your gonna do in life or whenever anything is gonna stop in the unaverse like an atom. it could stop existing but it doesn't. and so there's a lot of theories that can be made with a simple game that a bored person made.
but either way i love things like this that leave you thinking its the ground base of learning and creating with a simple theory or question. and loopholes as e definition is a loophole itself......... keep up the grate work guys!!!!!
lmfao when u see em partial derivatives in a paper and you’re like
Umm.... FORGET ITT
BY QUITTING!
Me:ties a noose
There are 16 recommendations of videos on youtube below a particular video, and I have always unknowingly chosen the best out of first 5. Idk why??
Actually i watched your 1000 vs 1000 plus 0 or 1000000 candies video and saw this in the recommended, wanted to look at my subscriptions first and came back to this video later. So jokes on you!
Can you show last pass to vSauce, I think he might need it
okay, your mention that youtube is basically this game got me too well, good job
on tinder im just gonna swipe 37% away and then go for the next better one, EASY!
unfortunately to swipe through 37% you'd need to know in advance how many potential matches you have. That said, I'm actually pretty curious how a pickup line based on the optimal stopping theorem would go over. Almost tempted to try.
SirPhysics the optimal time to stop doing that is now
@@SirPhysics Do you need to know how many matches you have? or just how many you are willing to look at? If you are only willing to look at say 100 people then it doesnt matter if you actually have 500 matches. just apply 37% to w/e number of people you actually are willing to look at. ofc tinder, or similar algorithms do not limit you to just picking one, and picking or not picking will influence future options.
No because you can choose more than one
*"when do we start stopping?"*
smashes phone to the floor*
i dont even know why but this comment specifically killed me-
Smashes phone on floor in a confused scream after finding out that E is actually a number*
I actually scrolled through about 40 videos and went back to this one...
You need a high IQ to get the *"E"*
Tbh you need a high iq to understand richarf and mortimer
despacito2
*E*
my IQ is EEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE
If you get an E and think that's high your IQ isn't high
This is actually pretty cool. Math is hella interesting.
When someone else does it for you.
Thanks!
Love the content!
Markiplier knew that E is important
I never quit with the power of the sauce
That math can only be applied IF you know hole many potential mates are available. Usually one doesn't know this.
I'm here at only ten views. Keep up the good work Kevin!
192 views. Appears to be stuck
What I took away from this:
Date, maybe 4 people then settle for the best one after that. Soul mate success chance 33%
Well, it depends on what you consider the entire pool of mates. If 11 people is the most you're willing to date before settling down, then that's correct.
@@pekuja you're right, I take it back, date 10000/e people then find the best one after that
@@pekuja Actually, if you are willing to date 11 possible mates and then settle down, you should actually meet all 11 of them, cause there's no rule you have to choose the last one met, you can marry the best of the whole pool. Unless of course, the cost of meet-ups is prohibitively high.
@@desarankoe3939 I think the point is that you won't know if you're a good match until you've actually dated them, and you probably can't date and break up with ten people and then get back together with the one you liked best. Also, it's not that you have 11 people preselected, but it's the 11 potential people you'd date over a long time. You probably don't know all of them to start with.
Pekka Kujansuu Oh, i guess youre right, you kinda cant go back. Guess theres more to that problem than the algorithmic aspect.
I was startled for a second when he said, "You're Johannes" and I was like, "How'd you know?" o.o 😂
193rd view!!! I love your videos and I’m so happy I’ve been this early! 🤗🤗🤗
it gets stuck at 192, buddy
December mine said 193 so
"The key is e"
Markiplier: *Traumatic flashbacks*
Can someone explain that meme to me?
E
@@carealoo744 no one understands it, the only thing everyone understands is *e*
e
Great explanation and video. One "mistake": including the choice of which UA-cam video to watch doesn't fit with the rest of your examples in that a viewer might be watching many videos - they don't have to choose only one. Also they can "go back" and watch a video that they passed over the first time. In fact, I've been spending my evening procrastinating by watching UA-cam videos, and passed over this video five or six times before I decided to watch it.
How to find the meaning of life:
Quitting...
Liked before even watching
I actually know this, one of my teachers two years ago (still my favorite math teacher) went over a similar case using interviews for jobs.
"this is a game you quit" that's every game you need to be more specific
E
Little axolotl