Holy -every cuss possible-, Melissa, I was just going to go from chemistry being my favourite subject to chemistry being my absolute nightmare until I came across your channel. I'm in love with the way you teach; it's so straightforward and easy to understand and the presentation is neat and really nice to look at. Thank you so, so much. From now on I hope my chemistry will go better from here!
Here I am in Chem 2, reunited with my trusty chem homegirl Melissa! You got me through Gen Chem & I thank you & UA-cam for uniting us because I was struggling 😂
love this page! super informative and to the point. the way you organized your notes and explanation in such a condensed amount of time is amazing! appreciate it
Extremely helpful video! Thankfully, problem cases such as this aren’t in the kinetics course I am taking, but this is still such a good and helpful video!
A lot of effort has been put into this, and I really appreciate it. But what can we do in case there are no like values given among the reactant concentrations, i.e if the concentrations of each reactant used in each trial is different?
You use a variable something like “x” in place of where the concentration would be, then you do k= products/reactants (make sure to include rate order) and solve for x
Because in the previous video they followed a pattern(the same numbers were found in 2 different trials for both x and y). Here, she found the same x value in a different trial but not the same y value, so they're not following a pattern. For this we take the average of all Ks
So this video is one of my Rate law videos which is part of Chemical Kinetics. I can also recommend other videos from different youtubers. ua-cam.com/video/irJ4ANrUXPI/v-deo.html ua-cam.com/video/2LMdj91x2HA/v-deo.html
i don't understand what the purpose of a "constant" is if it is changing from trial to trial, to where you have to take an average. that seems very un-constant-y to me.
Only if they can close colleges and stop taking our money for tuition and just let us learn on UA-cam. It took me 3 min to understand what I have been reading for 2 days. Thank you for saving me 24 more hours of my life.
required ALEKs we need videos how to do this on ALEKS as not to waste time on requirements of that program which is only 15% of my grade but takes hours
i cant believe you taught this in 3 minuetes so well and i sat in a classroom for 1.5 hours debating if i should change my major lol THANK YOU!!
hey if you have a real joy in solving and understanding your subjects , never ever even think of dropping it.
bruh i’m doing this as a sophomore in high school :(
@@chase4780 I’m in year 1 Uni and I’m doing this lol
@@chase4780 don't take it for granted. i feel like you hs teachers teach better than uni prof's
Holy -every cuss possible-, Melissa, I was just going to go from chemistry being my favourite subject to chemistry being my absolute nightmare until I came across your channel. I'm in love with the way you teach; it's so straightforward and easy to understand and the presentation is neat and really nice to look at.
Thank you so, so much. From now on I hope my chemistry will go better from here!
You're so amazing at explaining it. You're presentation is satisfying, it keeps me focused and alert. Thank you!
I been watching melissa since intro to chemistry, I am now in chem 102. Thank you for your videos they are extremely helpful.
Never stop doing this you are so GREAT!!
Here I am in Chem 2, reunited with my trusty chem homegirl Melissa! You got me through Gen Chem & I thank you & UA-cam for uniting us because I was struggling 😂
Chem 1, now Chem 2 your saving my life right now!!! THANK YOU AS ALWAYS!!!!!!!!#TeamMaribel
me too
very extremely helpful that you provided entire ratio so we could see where it came from
Yay! Happy to hear 😊
MY LIFE SAVER THANK YOU 😭💗💗💗💗
love this page! super informative and to the point. the way you organized your notes and explanation in such a condensed amount of time is amazing! appreciate it
soooo helpful! awesome work man, saving chem students everywhere!!
Girl u made this so easy to understand THANK YOU
Extremely helpful video!
Thankfully, problem cases such as this aren’t in the kinetics course I am taking, but this is still such a good and helpful video!
Thank you! Thank you! Thank you! 🥰🥰🥰
A lot of effort has been put into this, and I really appreciate it. But what can we do in case there are no like values given among the reactant concentrations, i.e if the concentrations of each reactant used in each trial is different?
You use a variable something like “x” in place of where the concentration would be, then you do k= products/reactants (make sure to include rate order) and solve for x
Everything you need to know for Kinetics is right here in my Kinetics Notes: melissa.help/kineticsnotes
Seriously this is a grade changer!
You're awesome!!! Thanks, enormously! Your videos saved my day.
This is the best explanation I have seen!
Thank you so much for this video!!!!!! I appreciate the help!
Amazing explanation ma'am
THANK YOU OMG
Your videos have been awesome! I hope I pass tomorrow!
I passed! Thank you!
Yay!! Congratulations 🎉
so helpful! Thank you so much
Thanks So much mam from India
It's important to note that she rounds all her values
I really like your way to video it's not boring and you clear everything thank you
Ms.Maribel I tried it with the equation of trial 3 over trial 2 and it gave me x=0? should that even be possible?
Hi
In the previous video, why you did not use the same method and take the average ?
Because in the previous video they followed a pattern(the same numbers were found in 2 different trials for both x and y). Here, she found the same x value in a different trial but not the same y value, so they're not following a pattern. For this we take the average of all Ks
I am a fan! Thanks alot
I also looked through your notes but I'm not sure which ones to purchase in order to get help with this concept
is there any other way to find the k value without finding the average as this method will be time consuming for me since we don't use calculators
Hello Melissa🌹, I would like you to help me with this topic :
Chemical Kinetics
PLEASE
So this video is one of my Rate law videos which is part of Chemical Kinetics. I can also recommend other videos from different youtubers.
ua-cam.com/video/irJ4ANrUXPI/v-deo.html
ua-cam.com/video/2LMdj91x2HA/v-deo.html
i don't understand what the purpose of a "constant" is if it is changing from trial to trial, to where you have to take an average. that seems very un-constant-y to me.
For 1st order reaction,did the titration value is coming decreased or increased
Thanks so much love you
You are the best
My best
Only if they can close colleges and stop taking our money for tuition and just let us learn on UA-cam. It took me 3 min to understand what I have been reading for 2 days. Thank you for saving me 24 more hours of my life.
Hey is there any way to email questions to you without using twitter?? I don't have one but I really need help with The Clausius-Clapeyron Equation
Just emailed you back
why is it 7.7 x 10 raise to 5? i think its raise to 13?
yeah that is what i got too...
required ALEKs we need videos how to do this on ALEKS as not to waste time on requirements of that program which is only 15% of my grade but takes hours
⭐️⭐️⭐️⭐️
Women can really explain it 😮
I hope something like this does not come on MCAT