Arrhenius Equation Activation Energy and Rate Constant K Explained

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  • Опубліковано 16 гру 2024

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  • @TheOrganicChemistryTutor
    @TheOrganicChemistryTutor  Рік тому +6

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  • @TheOrganicChemistryTutor
    @TheOrganicChemistryTutor  7 років тому +304

    Please note that at 13:59, the equation should be 1/T2 - 1/T1

    • @minestrone3
      @minestrone3 6 років тому +10

      Thanks for clarifying for I was wondering about that. If it was 1/T1-1/T2 there'd be no minus in front of (Ea/R)x(1/T1-1/T2). Correct?

    • @pallingtontheshrike6374
      @pallingtontheshrike6374 6 років тому +2

      correct

    • @sullivanhuott9737
      @sullivanhuott9737 4 роки тому +1

      I thought that was right when you apply that negative to the inside values?

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      @ericpalmateer806 3 роки тому +4

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    • @alexwander1992
      @alexwander1992 2 роки тому

      Naah you wrote correct it will be t1 only it’s in Cengel books too

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  • @alegraasita1575
    @alegraasita1575 3 роки тому +7

    I didn’t know how to solve for K in my mid-term and now I’m prepared for it if it’s in my exams!!! Thank you!

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  • @uceee1
    @uceee1 6 років тому +1

    best ever explanation on Arrhenius

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    @HarrisiQureshi 3 роки тому +2

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  • @kozukioden1177
    @kozukioden1177 3 роки тому +3

    According to the arrhenius equation the units of A should be the same as that of K but we know that the units of K depend on the order of the reaction while the units of A are (time^-1) so how do we explain this?

  • @abhachatterjee8296
    @abhachatterjee8296 3 роки тому +1

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  • @matildawillcox1693
    @matildawillcox1693 5 років тому

    Segment at 8:43 was brill! Cheers

  • @Nocturnal_Deity
    @Nocturnal_Deity 5 років тому +1

    13:37 (1/T2 - 1/T1)

  • @bishnumishra1590
    @bishnumishra1590 7 років тому +2

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  • @casualcasual1234
    @casualcasual1234 3 роки тому

    at 5:45, when conc. of A increase, won't collision frequency of A molecules increases (Z increase), hence a larger value of k i.e. rate constant?

  • @vmiguel1457
    @vmiguel1457 3 роки тому

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  • @samuelwamwere4867
    @samuelwamwere4867 2 роки тому

    Thank you so much. For some reason it dawned to me how Arrhenius Eqn is so similar to Clausius Clapeyron one.

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    @TheZombie462 2 роки тому

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    @intisaraden5748 5 років тому +1

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  • @xy5669
    @xy5669 11 місяців тому

    Thanks bro, you explained it better than my Prof. This is good, but somehow also very sad...

  • @jpatrick4373
    @jpatrick4373 7 років тому +2

    You have different equations for K2 which is really confusing me. 13:59 its (1/T1-1/T2) and at the end its (1/T2-1/T1). Which is correct?

    • @jpatrick4373
      @jpatrick4373 7 років тому +2

      Did algebra myself and its t2-t1. Good to note that is wrong and leave a caption tho

    • @TheOrganicChemistryTutor
      @TheOrganicChemistryTutor  7 років тому +2

      Thanks for letting me know.

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      @BARUCH1111 7 років тому

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  • @tonytruong573
    @tonytruong573 3 місяці тому

    Hi, can someone tell me why at 14:30, you would multiply both side by -R/Ea instead of -Ea/R

    • @maitreyim2218
      @maitreyim2218 3 місяці тому

      Because you want to cancel our Ea and R on the RHS, there is no point in squaring the terms

  • @alishermd4814
    @alishermd4814 4 роки тому

    the best ever explanation
    thank you so much

  • @polymar99
    @polymar99 6 років тому

    when you are calculating something in the exponential term, the units should all cancel because it should be unitless, just keep that in mind.

  • @johnboyca9434
    @johnboyca9434 3 роки тому +1

    Thank you sooo much brother!

  • @yonition
    @yonition 2 роки тому

    A simpler math would be as follows:
    If K1=A.e^(-Ea/RT1)
    And K2=A.e^(-Ea/RT2), dividing eqn2 by Eqn1
    K2/K1 = e^(-Ea/RT2)/e^(-Ea/RT1)
    Or K2/K1 = e^{-Ea/R*(1/T2-1/T1)}
    Then you can do everything else

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    @tishyamoulick293 5 років тому +4

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  • @elizabethbarahona3789
    @elizabethbarahona3789 Рік тому

    Thank you for all your help!

  • @jagdishjyani1538
    @jagdishjyani1538 6 років тому +2

    Is we taking capital log in the formula for activation energy In the place of natural log if not then why

  • @MrNileshagarwal75
    @MrNileshagarwal75 3 роки тому

    thanks sir its help me a lot... god bless u sir

  • @ghadeerahmed3318
    @ghadeerahmed3318 3 роки тому +1

    What about finding the frequency factor A,
    Does it change if the temperature or rate constant change?
    🆙
    Please answer me I have an exam tomorrow🆙

  • @walidhossain4836
    @walidhossain4836 7 років тому

    can anybody please explain me the part from 3:10 - 3:22 .is he saying that since its numerator is an exponent and negative it will give an inverse value which will decrease the rate? thank you in advance and good videos btw keep it up,bro. :)

  • @asmajaved8743
    @asmajaved8743 Місяць тому

    thanks alot, this was really helpful

  • @alexshanto7285
    @alexshanto7285 3 роки тому +1

    4:45 -5:42 may save your hundred hours.

  • @Lelii321
    @Lelii321 4 роки тому

    I highly doubt Ill get an answer right now, but how do you derive the t90 value from T1and T2 and K1 and Ea??

  • @ashrafmuhammad255
    @ashrafmuhammad255 6 років тому

    Sir, can i get reply, actually what i need to understand that from where we can get the value of k constant when we have value of temp, temprature rate and change in concentration of reactants and products, but don,t have value of A( frequency) , Ea ( activation energy) etc, as to get value of Ea by process u told us in video we must have the value of k constant first. How to measure it please.

  • @monaalinejad1334
    @monaalinejad1334 6 років тому +2

    Does anyone know how to measure K(T) from DSC data? Thanks

  • @rebmetano9042
    @rebmetano9042 5 років тому

    Sir if you have the values of k and the temperature, and you are asked to graph then find the slope and after we are asked to find the ln A sir what to do?

  • @uceee1
    @uceee1 6 років тому

    what actually is ln(K) on the graph if i was to plot the epoxy cured in DSC ? Is this second derivative of heating rate?

  • @ferryoctavian4247
    @ferryoctavian4247 5 років тому

    if Ea = - R*slope, what is the unit of the Ea? it confuses me, because slope doesn't have unit, but R's unit is J mol-1 K-1 (8.314 J mol-1 k-1)

  • @uttam2274
    @uttam2274 Рік тому

    It's not that necessary to remember all these three different forms. If we understand this equation : log(k2/k1) = Ea/2.303R × [1/T1 - 1/T2] properly, we could derive other two as well through some simple mathematical operations.
    By the way, it was a great explanation.

  • @sydneytse4448
    @sydneytse4448 4 роки тому

    hey so i wanna ask can we use thing one to calculate all Ks in different types of rate of reactions

  • @IdkaCoolusername
    @IdkaCoolusername 7 років тому +1

    14:05
    Why is it T1 - T2?

  • @Irshadahmad-bv4tr
    @Irshadahmad-bv4tr 4 роки тому +1

    Can u solve this one
    Lnr2/r1=E/R(1/T1-1/T2)

  • @Comrade4213
    @Comrade4213 3 роки тому +1

    Dude doublecheck on K2 because you concluded differently than what you have wrote in the end. I'm talking about the 1/T1 and 1/T2.

  • @bridgetkonadu4649
    @bridgetkonadu4649 2 роки тому

    Please what what happened to the lnA before comparing with the equation of the line

  • @freezinganimenz7835
    @freezinganimenz7835 4 роки тому

    Thanks, good explanation

  • @ngawangr5324
    @ngawangr5324 Рік тому +10

    nastiest equation in chem so far

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      @MASH_ING 20 днів тому

      😂😂you aint seen nothing yet

  • @hayatzeynu6208
    @hayatzeynu6208 4 роки тому

    Thanks my proffesor

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    @josht7238 5 років тому

    this guy is a legend

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    @AshleyNicoleBrickman Рік тому

    I LOVE YOU SO MUCH

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    @derbeym6980 6 років тому

    you a genius bro

  • @sitilathifah3857
    @sitilathifah3857 3 роки тому

    very useful !!! easily to understand. Thank you so much !!!!

  • @fuzeinfinite6148
    @fuzeinfinite6148 4 роки тому

    Qustion, what are the 2 kind of activations energy?

  • @uniteamerica9446
    @uniteamerica9446 Рік тому

    Can someone please calculate the activation energy needed to produce H2 gas from urea compared to the energy produced by burning H2 to produce H2O. I'm trying to figure out if burning H2 gas releases more energy than is consumed. I'm pretty sure it produces a positive energy gain. I've heard that urea is good for producing H2 gas because it takes less energy to split a urea molecule than it does to split a water molecule. I'm not trying to be lazy, I just don't understand where to get the figures to plug into the equation for each element. Maybe I don't understand it at all, I'm sure someone will tell me. Once you get the fuel mixture right it will be possible to run your car or whatever you want to run on H2 gas using your urine. Thank you.

  • @hananameme3564
    @hananameme3564 6 років тому

    Thank you ....but If I have K values (e.g: 4.7 x 10^-5......2.0 x 10^-3......3.0 x 10^-2 ......etc)How could I represent it on graph ......can any one HELP please ????

  • @juulia1605
    @juulia1605 5 років тому

    Does anyone know what is the reaction that its rate decrease with increasing the temperature? and which one is it?

  • @cornelius7653
    @cornelius7653 4 роки тому

    Absolute legend

  • @ghadeerahmed3318
    @ghadeerahmed3318 3 роки тому

    I noticed that A is part of the Arhhenius Basic equation,
    But it isn't mentioned in the equation at different temperature.!!
    (from the slope)
    🆙🆙🆙🆙

  • @aracelliquintana4244
    @aracelliquintana4244 3 роки тому

    thank you soooo much!!!!

  • @MuzhdaAfghanzoi
    @MuzhdaAfghanzoi Рік тому

    you are the best

  • @amytube94
    @amytube94 7 років тому

    Thank you! This was really helpful! :)

  • @mwambamulenga1548
    @mwambamulenga1548 2 роки тому

    Excellent

  • @punishmentbegins
    @punishmentbegins 7 років тому +1

    so helpful

  • @HOCKEYPLAYErus
    @HOCKEYPLAYErus 8 років тому

    What units for R do you use?? J/mol*K?

  • @raymond2908
    @raymond2908 4 роки тому

    can anyone answer me please. Can InK be the pressure(kPa)?

  • @khanyahya2293
    @khanyahya2293 5 років тому

    ITS INDEED VERY HELPFUL THANK YOU

  • @obipaul5434
    @obipaul5434 2 роки тому

    Super good dear

  • @Calyrekt
    @Calyrekt 2 роки тому

    thank you