Completing the Square (5 Easy Steps!)

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  • Опубліковано 17 лис 2024

КОМЕНТАРІ • 24

  • @kgube
    @kgube Місяць тому +1

    Super helpful when assisting the kids with hw and refreshing the memory! 🙏🏼 Grateful

  • @SchooltasticJackson
    @SchooltasticJackson Місяць тому +1

    I don’t know if you’ll see this but, thanks. These videos were the reason I went from a f to 85 in AP math. Much props to you!

    • @MariosMathTutoring
      @MariosMathTutoring  Місяць тому +2

      Wow! That’s awesome! Congratulations! Glad to hear my videos have been able to help you. Keep up the good work!

  • @acgenova9239
    @acgenova9239 Місяць тому +3

    Thank you this helped me a lot

  • @shroommy4608
    @shroommy4608 Місяць тому

    this is exactly what i’m learning in school right now! thank you so much for teaching students and helping them learn!!

    • @MariosMathTutoring
      @MariosMathTutoring  Місяць тому

      Glad to hear it was good timing on this video for you…and glad to hear my videos are helping you.

  • @sameeramian1814
    @sameeramian1814 13 днів тому

    Nicely explained thank you so much mr. Mario. You are awsome

    • @MariosMathTutoring
      @MariosMathTutoring  13 днів тому

      Thanks! I’m glad my video helped you understand completing the square.

    • @sameeramian1814
      @sameeramian1814 13 днів тому

      Can we also learn cubic eqautions

  • @hilalahmad7286
    @hilalahmad7286 Місяць тому

    Great explanation!

  • @charlesmitchell5841
    @charlesmitchell5841 Місяць тому

    Great tutorial. Thanks!

  • @ntvonline9480
    @ntvonline9480 Місяць тому

    Thanks for the. Algebra 2 videos . Th

  • @Cxtz_09
    @Cxtz_09 Місяць тому

    Thank you man ❤❤❤

  • @justlistean8579
    @justlistean8579 22 дні тому

    Great

  • @patrickwilliams7411
    @patrickwilliams7411 Місяць тому

    ❤😂 Thanks. I needed this.

  • @MrRichie444
    @MrRichie444 Місяць тому

    || x^2 + 4x + 3 = 0 || x^2 + 1x + 3x + 3 = 0 || x(x + 1) + 3(x + 1) = 0 || since we have two (x + 1)'s, we use only one of it so we get || (x + 3) = 0 and (x + 1) = 0 || therefore we get: x = -3 and x = -1||