baka! if the opposite sides are equal then how is it a trapezium, by the statement given by mam it is proved that it is a parallelogram or rectangle or square etc.. visualize to understand. BAKA!😅😂
Marvelous explanation mam😄 🔴 HOMEWORK- IF PQ=7CM, CP=CQ=3.5cm( SINCE, C IS MIDPOINT) SIMILARLY, PB=BR=4.5cm AND, QA=AR=4cm BY THEOREM: IF MIDPOINTS OF THREE SIDES OF TRIANGLE ARE JOINED FOUR SMALLER TRIANGLES ARE CONGRUENT, IN TRIANGLE ABC, AB=CP=3.5cm BC=QA=4cm CA=BR=4.5cm PERIMETER OF TRIANGLE= SUM OF ALL SIDES... HENCE, PERIMETER OF TRIANGLE ABC= 4+4.5+3.5=12cm(answer)
->Home Work Question "The perimeter of the Triangle ABC is 12 cm, due to Mid-Point Theorum" -> This Class Actually made MPT Very Easy and helped me a lot
Hw Given : triangle pqr C is the midpoint of pq B is the midpoint of pr A is the midpoint of qr Pq=7cm Qr=8cm Pr=9cm To prove :perimeter of triangle abc Proof Cb=1/2qr(by midpoint theorem) Cb=1/2*8=4cm Ca =1/2pr Ca=1/2*9=4.5cm Ba=1/2pq Ba=1/2*7=3.5cm Perimeter of triangle abc 4+3.5+4.5=12 cm
Ma'am didn't give full explanation, auctually since E is mid point of AB it mean AE = EB and since we already know that AE = CD (PROVED BY CPCT EARLIER) we can can EB is = DC and parallel therefore since one pair of sides is equal and parallel, we can say that Quad EBCD is a Parallelogram. I hope that clears any confusion.
IF PQ = 7CM THEN AB = PQ/2 Therefore AB = 3.5 QR = 8CM THEN CB = QR/2 THEREFORE CB = 4 PR = 9CM CA = PR/2 THEREFORE CA = 4.5 NOW PERIMETER OF ∆ABC = AB+BC+CA PERIMETER OF ∆ABC = 3.5+4+4.5 PERIMETER OF ∆ABC = 12CM
Mam I am Pallavi Raj Thank you mam for this amazing session and make this theorem halwa theorem 😇😀😀 🔴HOMEWORK QUESTION🔴 Given - 🔺️PQR , A, B and C are mid points and PQ is 7 cm , QR is 8 cm and PR is 9 cm. To find - perimetre of 🔺️ABC ➡️ By MPT CB = 1/2QR = 4cm BA = 1/2PQ = 3.5cm AC = 1/2RP = 4.5cm Perimeter of 🔺️ABC = CB+BA+AC =4cm+3.5cm+4.5cm =12cm
Given : PQ=7cm QR=8cm PR=9cm Since, PQ=7cm PC=CQ=3.5cm QR=8cm QA=AR=4cm PR=9cm PB=BR=4.5cm PC=AB PB=CA QA=CB In ∆ABC AB+CA+CB=Perimeter of ∆ 3.5+4.5+4=12cm Perimeter of ∆ ABC is 12 cm
Hello kids! Check your understanding of the Quadrilaterals chapter by answering these 5 quick questions in the form: forms.gle/wgNDbNijsWhEoAfQA
13:33 If one pair of opposite sides are equal then it is known as Trapezium 14:35
baka! if the opposite sides are equal then how is it a trapezium, by the statement given by mam it is proved that it is a parallelogram or rectangle or square etc.. visualize to understand. BAKA!😅😂
Marvelous explanation mam😄
🔴 HOMEWORK-
IF PQ=7CM, CP=CQ=3.5cm( SINCE, C IS MIDPOINT)
SIMILARLY,
PB=BR=4.5cm
AND, QA=AR=4cm
BY THEOREM: IF MIDPOINTS OF THREE SIDES OF TRIANGLE ARE JOINED FOUR SMALLER TRIANGLES ARE CONGRUENT,
IN TRIANGLE ABC,
AB=CP=3.5cm
BC=QA=4cm
CA=BR=4.5cm
PERIMETER OF TRIANGLE= SUM OF ALL SIDES...
HENCE, PERIMETER OF TRIANGLE ABC= 4+4.5+3.5=12cm(answer)
😮
->Home Work Question
"The perimeter of the Triangle ABC is 12 cm, due to Mid-Point Theorum"
-> This Class Actually made MPT Very Easy and helped me a lot
Hw
Given : triangle pqr
C is the midpoint of pq
B is the midpoint of pr
A is the midpoint of qr
Pq=7cm
Qr=8cm
Pr=9cm
To prove :perimeter of triangle abc
Proof
Cb=1/2qr(by midpoint theorem)
Cb=1/2*8=4cm
Ca =1/2pr
Ca=1/2*9=4.5cm
Ba=1/2pq
Ba=1/2*7=3.5cm
Perimeter of triangle abc
4+3.5+4.5=12 cm
Mam wrote BE =CD in proof of converse MPT (I think by mistake)the right one is BE || CD,so don't get confuse.
Yep you are right, it isn't equal but only parallel therefore it is not a parallelogram
Ma'am didn't give full explanation, auctually since E is mid point of AB it mean AE = EB and since we already know that AE = CD (PROVED BY CPCT EARLIER) we can can EB is = DC and parallel therefore since one pair of sides is equal and parallel, we can say that Quad EBCD is a Parallelogram. I hope that clears any confusion.
IF PQ = 7CM THEN AB = PQ/2
Therefore AB = 3.5
QR = 8CM THEN CB = QR/2
THEREFORE CB = 4
PR = 9CM CA = PR/2
THEREFORE CA = 4.5
NOW PERIMETER OF ∆ABC = AB+BC+CA
PERIMETER OF ∆ABC = 3.5+4+4.5
PERIMETER OF ∆ABC = 12CM
The answer of homework questions is
12 cm is the perimeter of triangle ABC
Thankyou so much for explaining this theorem easily
Good job
Mam I am Pallavi Raj
Thank you mam for this amazing session and make this theorem halwa theorem 😇😀😀
🔴HOMEWORK QUESTION🔴
Given - 🔺️PQR , A, B and C are mid points and PQ is 7 cm , QR is 8 cm and PR is 9 cm.
To find - perimetre of 🔺️ABC
➡️
By MPT
CB = 1/2QR = 4cm
BA = 1/2PQ = 3.5cm
AC = 1/2RP = 4.5cm
Perimeter of 🔺️ABC = CB+BA+AC
=4cm+3.5cm+4.5cm
=12cm
Mam please make a lecture on surface area and volume class 9th
Sh maan I live you as a student pls aap har video me padhaiye very very nice explaination
Mam sare ch ka revision karaiye ❤
Hello mam
I am Shagun
Perimeter of triangle=a+b+c
where a=4cm , b=3.5cm and c=4.5 cm
That's why the perimeter will be 12cm ....….
Thank you mam
Thank you mam this video is very helpful
❤ amazing class mam
Amazing Class ma'am
Can you make one shot of theoram on area
Legends watching one day before exam
Tomorrow is my exam so I am watching now 🤣
Jiske exam me na ho. be like:
Oh my goodness 🤯💯💥🔥👑😜🥳
Very very very nice explanation 😊
Perimeter of Triangle ABC is 12cm
Thank you ma'am video was really helpful
Mam thanku YOU ARE A SO CUTE MAM😘😘😘😘😘😘😘😘😘
❤
Bhai vo. Mam h unhe to maaf kr do
Thik hai
Crystal clear mam
Maam you are so cute ❤
the perimeter or triangle abc equal 12
Thanks a lot mam
Yes😮😊😊😊😊
Mam pls teach class 10
Ma'am aren't you teaching us in Class 10?
Maam I have a doubt
HELLO MAM
Pq=7cm
Qr=8cm
Pr=9cm
Proof
Cb=1/2qr(by midpoint theorem)
Cb=1/2*8=4cm
Ca =1/2pr
Ca=1/2*9=4.5cm
Ba=1/2pq
Ba=1/2*7=3.5cm
Perimeter of triangle abc
4+3.5+4.5=12 cm
Given :
PQ=7cm
QR=8cm
PR=9cm
Since,
PQ=7cm
PC=CQ=3.5cm
QR=8cm
QA=AR=4cm
PR=9cm
PB=BR=4.5cm
PC=AB
PB=CA
QA=CB
In ∆ABC
AB+CA+CB=Perimeter of ∆
3.5+4.5+4=12cm
Perimeter of ∆ ABC is 12 cm
toooo lag tooo slow my teacher completed in 20min but u took 1hr omg , but u teach good
12 cm
Mam hello
Mam I am new my name is simran shrivas
Mam u are pretty and beautiful
Thankyou mam
Hii mam
😅
😂🎉
😂🎉🎉😢😮
Hello mam l am lete
So hardd
Yes😮😊😊😊😊