Reaction Order Tricks & How to Quickly Find the Rate Law
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- Опубліковано 30 вер 2024
- Reaction Orders are easy to find if you know the right tricks, plus you'll save time on your next Chemistry exam! Reaction Orders help you find the overall rate law of the reaction. This video explains how the rate of reaction and concentration of reactants relate to each other for zero order, first order and second order.
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This makes so much sense! Why couldn't my professor just teach it like this! Thank you!
Wow- you got me through Chem 1- looks like you'll be getting me through Chem 2 as well 😂 Thank you!
Lmao my chem 2 semester almost done . I’m taking orgo next semester
I literally just got over crying because I have a test on this and I had no idea how to find order in a fast manner.... you SAVED me! Thank you SOOOOO much!!!
I literally subscribed to you in first 10 seconds of watching your videos. Just incredible
For a step by step guide on everything you need to know for Kinetics, check out my Kinetics Notes here: melissa.help/kineticsnotes
love how your nails match the background 💙 lol great video!!
Thank you lovely! Nails always gotta be on point 💅😝
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What does it mean if the concentration doubles but the initial rate halves?
I couldnt tell you how helpful this was. Thank you!\
Wow! I think I'm learning super fast with you than my old professor
i think i learn more from these videos than i do in an hour long class
I have a quiz today on chemical kinetics and I was so worried about how I didn't know how to identity reaction orders. Your video is really helpful, thank you❤️
This comment makes me feel so much better about my chemical kinetic test tomorrow! How did you do on the test?
Wow, these are better than tricks, they actually explain, in a simple and understandable way, what the different orders even are. Yes, I'm stupid that I didn't know, but at least I know now lol.
If there is 3rd order reaction then how to solve it please make video of it
OKAY MA'AM, looking effortless while teaching me chem!!
Wow
Thanks for this trick
Mindblowing
You're very welcome! 😊
Best chemistry tutor ever!! ❤️❤️❤️
Aww thank you so much Diana 💕
this is great, but I literally cannot find anything with realistic numbers. How do I know what order it is when I have rates that are all over the place due to a real world experiment. I'm calculating exponents to be 2.5783 or 18.23 or negative values and obviously that doesn't follow these rules. WTF!
You are so talented! the way you make your videos so professional and so easy to understand make you the best! Thank you so much. Keep up the amazing creativity of these extremely helpful videos.
oh my lord i fricking cannot thank you enough you made these so easy. All the other tutorials on youtube complicate it so much my days you're a life saver thank you so much i literally cannot express how happy i am to finally know my way around this topic thanks to you
Thanks Melissa!!
You must include that while Increasing the conc of one reactant the other reactant conc remains const.
🧢
fr
You explained this way better than my chem teacher. I didn’t realize how simple this was and I was so confused 😭
THANK YOU!
I swear my concepts got clear in like 2 secondsss....🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉 i m so happy btw u r beautiful thou.❤
Thank you
Within one minute everything is clear thank you Melissa
Shez straight to the point
Oh my god I love you! I'm so sorry I didn't find this channel earlier!
Aww thank you, so happy you found the channel!
nice edit also❤❤❤❤ as I'm a youtuber.. i recignised everything❤❤
Where are you from??
oh my god i was about to kill myself coz i didn't understand how to calculate the orders but your video helped me so much. I want to genuinely thank you, you saved a life ong
I’m slowww cause I still don’t get it😭 how do you know what number to multiple it by? Do you just guess? Helpppp😂
This just helped me pass my biochemistry quiz. Thanks ❤️
OMW . You just simplified something that has been bothering me for 10months in less than two minutes . thank you.
made it so much simpler to understand THANK YOU!!
You're very welcome!
I was stuck on a tricky problem trying to find the reaction order for a particular reactant and this helped me connect the dots instantly. So much simpler thinking of things this way when looking at tables. Thank you!
She didnt say subscribe coz it was already written like it😄🙂
So can you explain first order and second order I am confused by that
Why can’t teachers literally teach like you lmao
can't we tell order of reaction by seeing only any reaction ?
Y’all taking this in college? 💀 I’m having this in my junior year (high school) it’s pretty easy tbh thanks to her ofc!
Yea you gotta do it twice unless you take dual enrollment or AP chemistry 😞 Chem 1&2 in university is basically a revision of high school chemistry 🥲
@@vertigo_virgo6380 I take ap chemistry 😔 this semester is all about chemical equilibrium. Ohh that’s why thanks for telling me!!
Thank you! Such a great tutorial 😍✨
In which grade u r?
finally i get it in just 2 minutes then in 4 months at school tysm
Watching this before my chem exam in 3 hours
Thanku very muchh this is so helpful ❤
How do you know which trials to compare??
i just finished one problem that took an hour and now i found this video. making chem 100x easier! thank you!!
Thank you so much for this, it is amazing how you can explain this so well in 2 minutes.
wish I found your channel earlier...my ap exam is tomorrow and I've struggled a lot in the class and lost my motivation. Now I'm bingeing your videos the night before the exam hoping I'll at least get a 3.
for third order of reaction is there any trick??
took me 2 mins to understand what would have taken me 2 hrs through textbook info and quiz. thank you :'')
Enjoyed it !!
This is the easy thing.... What if [A] and [B] both doubles? How do we determine the order then?
So beautiful. Thanks
Superb explanation!! It was really difficult to understand before but this video helped me..thanks a lot mam..
In the end you said did you learn something.....well i am gonna say not just something but everything 💯
Wow Ma'am!! You're super cool
I hate our professor she didnt indicate how to identify the order. and thanks u saved me for today's deadline
When I came in have no idea about that but now I'm sure you are going to just help me to go through this Chemistry...
holly shit you are amazing
Why don't they teach it like this.
Omg you made it so much easier
great tricks thanks but how do you determine the overall reaction order in this case?
add the exponents for each species i think
I need to understand it though not know tricks
Which is exactly why I made other longer videos on this. Video 1: ua-cam.com/video/liGCU9gaLcM/v-deo.html
Video 2: ua-cam.com/video/NZMqV-66b1Y/v-deo.html
MY CHEM BOOK SUCKSSSSSS THANK YOU
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You are actually amazing
thank you so much! I don't know why i struggled to understand this so much
This is a bruh moment for me
How do you make each little paper..does it take time? The videos are amazing!!!!
what about 3rd order :-(
This clears the concept up so nicely!! Thank you lots
I shoud've used this for my exam. I failed my first one badly.
Please dont hurry
Thanks. Test tomorrow on Rate Law and 3 other topics.
If the concentration decrease how do you know which order it is?
What if it's a fraction?
What about 3rd order?
Damn smart gurlll 😍
Really informative..
soooo helpful tysmm
love your videos,thanks💘💘
Girl thank u🤍🤍🤍
Thank you for saving the chemistry test which I have to sit for in two hours : )
This is the right way to teach, easy and simple
This helps so much. Wish my teacher would teach this
so what happens when the rate is *2 and the [B] is *4?
You may have found an answer already. By observation of 4^y = 2, y=1/2. Or by using logarithms, you would get 4^y = 2 or y*ln(4) = ln(2) -> y = ln(2)/ln(4) = 1/2
In that case it would be a half order reaction with respect to B, and you may try to find an example of this type of reaction.
Thank you so much, that's really helpful... I could not understand this at university, while everything is easy with your video 👌
could you please explain where you are getting the numbers that are being multiplied? I'm a bit confused.
Watch this video: ua-cam.com/video/liGCU9gaLcM/v-deo.html
It goes over problems in more detail.
From India
THANK YOU!
Didn't get it🤔
4 years later and I am here to tell you, you are heaven sent!
Thank you❤
the video is short but soooooooooo useful thanks alot
! ^^
amazing 😍
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thanks
Nice one |
Wao Awesome Tricks
Thank you
Thanks
You made this so simple for me .
Thank you so much..