You are the best thank you for thoroughly explaining the reasoning behind the changes in units and each step before proceeding. I took chem 1 3 1/2 years ago and now I'm doing chem 2 for my grad school prerequisites, the review on ALEKS is requiring these problems and I have been so stuck until now!
How come we use the moles of C4H6 when we're calculating the kJ/mol for water specifically? Wouldn't we want to use the moles of water instead? Also I can't thank you enough for all the hard work you do, your videos are the only reason ALEKS hasn't made me lose all my sanity yet
We are using the temperature change for water to calculate the heat (kJ) for the reaction, but we are calculating the kJ/mol for the reactant, which is C4H6 in this example.
You are the best thank you for thoroughly explaining the reasoning behind the changes in units and each step before proceeding. I took chem 1 3 1/2 years ago and now I'm doing chem 2 for my grad school prerequisites, the review on ALEKS is requiring these problems and I have been so stuck until now!
You're very welcome! This is a really hard topic! I'm glad you're getting through it!
I just noticed you go to SVC from the tabs, TY SO MUCH FOR ALL THE CHEM HELP YOU ARE A LIFE SAVER WITH THIS STUFF!!
Hey! Are you local to me? SVC is pretty small - I wouldn't expect people to recognize it!
yes it’s my hometown, it was crazy when I noticed the videos that have been carrying me throughout chem are being made from svc :))
haaaaayyyyy that's so cool. Just think, you could have been my student if you stayed here, lol :)
You are amazing, have been stuck for so long until I found this video
Yay! This is a really tough problem! I'm glad you got through it!
How come we use the moles of C4H6 when we're calculating the kJ/mol for water specifically? Wouldn't we want to use the moles of water instead? Also I can't thank you enough for all the hard work you do, your videos are the only reason ALEKS hasn't made me lose all my sanity yet
We are using the temperature change for water to calculate the heat (kJ) for the reaction, but we are calculating the kJ/mol for the reactant, which is C4H6 in this example.
i got the same problem as u lol thank youuuu
Lucky!!!!!
GOD BLESS YOU THANK YOU SO MUCH
You're welcome!