Enthalpy of Formation Reaction & Heat of Combustion, Enthalpy Change Problems Chemistry

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  • Опубліковано 28 лис 2024

КОМЕНТАРІ • 253

  • @TheOrganicChemistryTutor
    @TheOrganicChemistryTutor  10 місяців тому +2

    Thermochemistry - Free Formula Sheet: bit.ly/3TP4U4u
    Final Exams and Video Playlists: www.video-tutor.net/
    Full-Length Videos & Worksheets: www.patreon.com/MathScienceTutor/collections

  • @zacharyh5419
    @zacharyh5419 5 років тому +263

    I was stuck for hours on combining equations of formation to make a regular equation and the first 10 seconds of your video enlightened me. God bless you

  • @charlene.w.6124
    @charlene.w.6124 4 роки тому +150

    When you have to learn Chemistry else where because you're under lock down and your teacher won't answer your emails ....
    btw. you just taught me something is less than 20 mins, which i've been trying to understand for the past 6 days so thanks

  • @aishahasan686
    @aishahasan686 4 роки тому +595

    This man has been carrying my grades from high school into college lolol

  • @FarrOutt1
    @FarrOutt1 Рік тому +25

    I stopped listening during Chemistry lessons cause I literally don't understand my teacher's teaching..I just can't wait to come home and listen to your explanation on this topic...Thank you...I'm now the highest scorer in Term 1 ..Just scored (98/100)...Everyone was shocked..I'm just sad that I discovered your channel late...I'm now in my last year of high school...Should have started watching you from Junior level 😢😢....

  • @hollysu1
    @hollysu1 6 років тому +36

    I cannot thank you enough for your videos!!! I went and bought some chemistry books but they hardly give any practice problems! You make it much easier and approach problems from different angles, thank you!!!!

  • @awaisahmed5489
    @awaisahmed5489 3 роки тому +594

    Best luck all of you for exam tomorrow 🤣🤣

  • @afaceonthewater
    @afaceonthewater 3 роки тому +35

    No one teaches this as simply as you do. Thank you

  • @robertsterenchak8431
    @robertsterenchak8431 6 років тому +101

    Thank god this video exists....

    • @degraj418
      @degraj418 4 роки тому +2

      Thank him...but then he IS god

    • @datboi1861
      @datboi1861 4 роки тому +2

      @@degraj418 Woah chill

  • @GSU_Panther_Nation
    @GSU_Panther_Nation Рік тому +7

    Thank you. You are a blessing when it comes to straight to the point lectures. In fact, better than Khan Academy, and teaches way better than my chemistry professor. Just have to search the textbook for a certain topic and then search it on UA-cam

  • @AkinOla-bi4ob
    @AkinOla-bi4ob Рік тому +7

    It's a great pleasure meeting a wonderful teacher make difficult topic more clearer. I now understand better now.
    Put it up and God will bless you

  • @basketballmentality5407
    @basketballmentality5407 5 років тому +79

    I learn here more than in my class

  • @georgesadler7830
    @georgesadler7830 6 місяців тому +1

    Professor Organic Chemistry Tutor, thank you for a step by step explanation of How to Calculate the Enthalpy Change of a reaction using Enthalpy of Formations in AP/General Chemistry. The problem selection for this material are excellent. Every problem in this video also reviews the concept of balancing Chemical Equations in Modern Chemistry. This is an error free video/lecture on UA-cam TV with the Organic Chemistry Tutor.

  • @caitygart
    @caitygart 5 років тому +19

    Thank you so much! All of your videos have been a huge help for my first year of pharmacy school. Cheers!

  • @RambunctiousVA
    @RambunctiousVA 5 років тому +159

    woah I didn't know a 1/2 coefficient was allowed

    • @feitan8033
      @feitan8033 5 років тому +23

      The coefficient of the product has to be 1 unless stated otherwise, so a 1/2 is required for the reactants

    • @feitan8033
      @feitan8033 4 роки тому +1

      @Megan choo To form water you need one oxygen and 2 hydrogen atoms

    • @yabombo8145
      @yabombo8145 3 роки тому +1

      Do you like black people?

    • @Abcsefghijklmnopqrstuvwxy
      @Abcsefghijklmnopqrstuvwxy 3 роки тому +2

      The reason being is that the atoms of oxygen always exist in pairs; that’s why there’s a subscript of 2 in front of O. All diatomic elements are this way (H2, N2, F2, etc). If diatomic elements are always in pairs, how do we get just one atom of it? You would have to multiply the subscript 2 with something to give you one. The only way you would get one atom is by multiplying it by 1/2. Does this make sense? The 1/2 doesn’t mean half of one atom; it is half of 2 which we know is 1. It is another way of writing one atom of Oxygen in this equation.

    • @someoneelse361
      @someoneelse361 3 роки тому

      @@yabombo8145 what does this have to do with anything?

  • @vicv5828
    @vicv5828 3 роки тому +5

    Better than my chemistry professor by a mile

  • @nicolasaq523
    @nicolasaq523 2 роки тому +1

    Organic Chemistry Tutor The GOAT

  • @niche5006
    @niche5006 6 років тому +37

    The enthalpy changes are measured kJ instead of kJ/mol since you multiply everything by moles. Love all your videos btw.

  • @helpontheway7856
    @helpontheway7856 6 років тому +8

    So glad I waited for you to graduate before beginning this journey. Much love bro. South Florida love

  • @77eeq
    @77eeq Рік тому +1

    Thank you so much ur carrying my grades from 9th grade to 11th grade thank youu so much

  • @abrahamande1508
    @abrahamande1508 4 роки тому +1

    this guy is a gem

  • @rafimonir5112
    @rafimonir5112 5 років тому +2

    THIS VIDEO IS GOLD 🥺🥺

  • @laithahssan8253
    @laithahssan8253 3 роки тому +2

    1:31 you have to put graphite because its the main form of carbon (solid) and thanks alot great video

  • @georgia5026
    @georgia5026 3 роки тому +1

    That does it. Imma start building a shrine for this guy.

  • @minsungkim6792
    @minsungkim6792 5 років тому +3

    Thank you for this! Not many textbooks explain this concept properly.

  • @herminioserguei5540
    @herminioserguei5540 5 років тому +3

    You should be my professor!

  • @Mejustme74
    @Mejustme74 5 місяців тому

    3:31 for making this more understandable we can say whenever 1mole compound is form then enthalpy of reaction becomes eq to enthalpy of formation and when 2 or 3 etc moles of compounds are form then we have to divide the moles from enthalpy of reaction to get enthalpy of formation.

  • @ronncarlfaminialan7525
    @ronncarlfaminialan7525 6 років тому +2

    We have an exam in thermo chemistry today. thank you for making this video. Wish me luck!

    • @milindbordia
      @milindbordia 6 років тому

      Ronn Carl Faminialan how’d u go?

    • @AksamRafiz
      @AksamRafiz 5 років тому +2

      @@milindbordia he probably died

  • @SZombo-wt5ds
    @SZombo-wt5ds 5 років тому +1

    Your tutorials have saved me once again, thank you

  • @Jessicaah1
    @Jessicaah1 4 роки тому +12

    Great video, I'm wondering though why you don't use reactants minus products in the combustion reaction of c2h5oh, since it's a combustion reaction that includes oxygen. I've learned that combustion reactions are always exothermic, so in this case it brings a negative sign which means exothermic, so I'm good with that, but HOW do I know when to use products minus reactants or reactants minus products? Do I just switch signs if I get a positive value when I know it's a combustion reaction? Little confused here. Thankful for answers.

    • @aadarsha1487
      @aadarsha1487 4 роки тому

      ikr shouldve dlne Reactants - Products in that one its the rule isn't it

    • @sasmitpandey4980
      @sasmitpandey4980 2 роки тому +1

      Is there a balanced synthesis equation for ethanol, or does ethanol only form through combustion?

    • @sasmitpandey4980
      @sasmitpandey4980 2 роки тому +1

      Never mind, I found it.

  • @hussnainshakeel2372
    @hussnainshakeel2372 5 років тому +155

    who's studying for finals with me 🥴

    • @davidgn40
      @davidgn40 5 років тому +1

      Lmao right here

    • @andrewhill1570
      @andrewhill1570 5 років тому +1

      Right here 🥴

    • @hussnainshakeel2372
      @hussnainshakeel2372 5 років тому

      Good luck to both of y’all

    • @davidgn40
      @davidgn40 5 років тому +3

      @@hussnainshakeel2372 had mine. This video saved me on the Enthalpy questions haha. Thanks. Hope your finals go/went well too.

    • @sansamman4619
      @sansamman4619 4 роки тому +3

      I am studying for the finals that I will have one year from now xd, this Thermochemistry stuff is one hell of a challenge I am studying on a text book, I also have a few other "note book" things that should help with the text book, I have 50 practice problems, I have like 30 tabs opened, I will watch the mit open course ware lectures on thermochemistry and then I will be done. I don't know why I told you this, but after writing it down I feel a little better :')

  • @fynngreen00
    @fynngreen00 3 роки тому +1

    I have an exam tomorrow and I still don’t understand Heat of Combustion 😀 wish me luck before I head to my certain doom!

  • @iconicahlly9377
    @iconicahlly9377 Місяць тому

    you've saved me for tomorrow

  • @Swetha-ii
    @Swetha-ii 4 роки тому

    A PRODUCTIVE VIDEO....KUDOS TO THE TEAM

  • @islamwasel2023
    @islamwasel2023 5 років тому +4

    Please strongly explain to me what is the relationship that connects the heat of combustion with the heat of the formation

  • @moatlhodibagayi-vk5gt
    @moatlhodibagayi-vk5gt Рік тому

    You are the best man🙏king

  • @titusmwape2938
    @titusmwape2938 2 роки тому

    Well explain and easy to understand

  • @akazozo99
    @akazozo99 2 роки тому

    Thank you so much sr.You save me from failing the exam.😞

  • @LilJollyJoker
    @LilJollyJoker Рік тому +1

    Thank you so much for this!

  • @karaborose1940
    @karaborose1940 4 роки тому

    You simply the best

  • @lild7me
    @lild7me 9 місяців тому

    I wish I could know which grade this lesson is for, bc I am taking it in high school second grade in Saudi Arabia, and thanks man for this video ❤❤

  • @tommywagner6692
    @tommywagner6692 2 роки тому +1

    He's the best

  • @lorenzdequina2306
    @lorenzdequina2306 4 роки тому +1

    Thanks alot bro, it make's easy to understand thermochem

  • @liamnotlast4571
    @liamnotlast4571 Рік тому +1

    Why am I watching this? It's 2 minutes to midnight and I don't even go to school anymore!

  • @jenm1
    @jenm1 3 роки тому

    You explain things so well. Are you a TA or prof or something?

  • @CuriousAndCuriouser1865
    @CuriousAndCuriouser1865 Місяць тому +1

    9:19 why is the result in kJ per mol? It looks like it should be for the entire reaction.

  • @qualityff3458
    @qualityff3458 2 роки тому

    how can this piece of flesh can teach that amazing !!

  • @kuzon2132
    @kuzon2132 Рік тому

    Learned a lot

  • @aymanwhite5902
    @aymanwhite5902 2 роки тому +2

    Absolutely Brilliant 👏 👌 Thank you so much 😊

  • @myax4500
    @myax4500 4 роки тому +1

    Thank youuuu this is so helpful

  • @amogh_veena
    @amogh_veena 4 роки тому

    Thanks you soo much brooo made my life easier

  • @chiamakanwazue6237
    @chiamakanwazue6237 4 роки тому +6

    It’s second period and my test is fifth period, wish me luck 🥴

  • @MohammedHimedah
    @MohammedHimedah 7 місяців тому

    Thank you very much man you're AMAZING

    • @bumxrr
      @bumxrr 7 місяців тому

      welcome

  • @amrithabhat5019
    @amrithabhat5019 4 роки тому

    you are the best dude!

  • @nevemaltus8275
    @nevemaltus8275 5 років тому +11

    This guy sounds like Mark Whalberg

  • @nutritionbyelsa
    @nutritionbyelsa 2 роки тому +2

    my goal is to fulfill my purpouse in life to the same degree you have fulfilled yours

  • @janieli
    @janieli 4 роки тому

    thank you. thank you. god bless you.

  • @koysensei4424
    @koysensei4424 2 роки тому +2

    How do i know if the product is gas liquid or solid?

  • @alweenasolaiman8139
    @alweenasolaiman8139 11 місяців тому +1

    Good luck y'all for finals 😅

  • @shaisaroussi5324
    @shaisaroussi5324 3 роки тому +1

    Question:
    Enthalpy of formation of H2O is 0 or -286? What do I miss?
    Thank you!

    • @noraax
      @noraax 3 роки тому +2

      This is probably a bit late but it’s -286 because H2O (L) is not a “standard state”, it’s created from the formation of H2(g) and O2(g). So the H2 and O2 are 0 not the H2O

  • @karroten
    @karroten 5 років тому +1

    Another great video. Thank you!

  • @saeedmohamed7008
    @saeedmohamed7008 5 років тому +1

    Thank u so much good job keep going.

  • @Arxxa
    @Arxxa Рік тому +1

    Whats the point of listening in class for 45 minutes and not understanding when I can listen to your 15 minute videos and understand everything.

  • @namballalakshmanarao3831
    @namballalakshmanarao3831 6 років тому +1

    thanku sir.....awesome lecturing

  • @adycerriteno3230
    @adycerriteno3230 2 роки тому

    THANK YOU SO MUCH! CAN you make for heat of combustion please...

  • @oluwakemiadelana7803
    @oluwakemiadelana7803 5 років тому

    Beautiful video. Nice job

  • @zettagbayani9227
    @zettagbayani9227 2 роки тому

    Thankyou so much for the awesome videos!

  • @fezii9043
    @fezii9043 3 роки тому +3

    What about calculating the enthalpy change of formation if given the enthalpy change of combustion?

    • @hectorokereke9268
      @hectorokereke9268 Рік тому

      Enthalpy change of combustion is enthalpy change of reaction
      And to solve for that is
      ∆Hproducts - ∆H reactants
      you can use algebra and finish up

    • @fezii9043
      @fezii9043 Рік тому

      @@hectorokereke9268 thank you

  • @aidenwolf3558
    @aidenwolf3558 4 роки тому

    will the carbon dioxide and water formation enthalpy always be the same for problems or does it rely on the textbook

  • @degraj418
    @degraj418 4 роки тому +1

    Thank you for such a great video :)

  • @tane1038
    @tane1038 3 роки тому

    Thank you. This is great!

  • @hayin2041
    @hayin2041 7 місяців тому

    May I ask how is it possible if we undergo combustion raction while still staying at standard condition (1 atm, 298 K)?

  • @aliyahmoreno4913
    @aliyahmoreno4913 25 днів тому

    my goat 🐐

  • @abhishekshyam3427
    @abhishekshyam3427 4 роки тому +1

    ohh man you are awesome

  • @jiminpark3865
    @jiminpark3865 4 роки тому

    This is so easy.

  • @averyredonnett
    @averyredonnett 20 днів тому

    If I am not given the KJ/mol of the compound how and I supposed to figure out the heat formation of a compound?

  • @Joe_Joe1203
    @Joe_Joe1203 Рік тому

    Around 9:30
    I have a similar question where butane is burned to produce CO2 and H2O. My professor insists that the value for liquid water is to be used in the formula instead of the water vapor one. What I don't understand is why does the value of water vapor not apply to this situation. I don't remember cooking on the butane gas stove with liquid water coming out of it.
    Any explanation that can convince me?

  • @andyoohhh2061
    @andyoohhh2061 5 місяців тому

    Why wouldn't your units "mole" cancel out when solving for the heat of reaction? I think it should.

  • @toxicgamer5723
    @toxicgamer5723 3 роки тому +1

    Why is the enthalpy change of the reaction is equal to the enthalpy change of the copustion of 1 mole

  • @niladrichakraborty3795
    @niladrichakraborty3795 4 роки тому

    Good one sir.

  • @christopherloughran9029
    @christopherloughran9029 3 роки тому

    What would happen if Aluminium had a value (hypothetically)? How would you isolate X ?

  • @sasmitpandey4980
    @sasmitpandey4980 2 роки тому +1

    What is the balanced synthesis equation for ethanol?

  • @nshimyumukizaonesime2525
    @nshimyumukizaonesime2525 3 роки тому

    Do you only put elements on the reactants side?

  • @islamicbrotherhood9574
    @islamicbrotherhood9574 7 років тому +4

    Some tough numericals needed#IITJEE ....PLZ.....ON THERMOCHEMISTRY

  • @rosyskysong8590
    @rosyskysong8590 4 роки тому +1

    Could you explain why dH(rxn) is -1396kJ PER MOL at play time 9:25. I thought dH(rxn) is -1396kJ for 4mol-NH3 and 7mol-O2.

    • @cam.r.7052
      @cam.r.7052 3 роки тому

      For anyone else who wonders, I believe he made a mistake writing /mol and it should just be kJ. If you follow the units of each number on your head, the moles cancel.

  • @Shahan-m1g
    @Shahan-m1g 3 роки тому

    333K views. 3 years ago
    Nice ❤️

  • @arinzeanthony7447
    @arinzeanthony7447 2 роки тому

    I thought that the Heat heat of combustion (being an exothermic reaction), the heat of reactants> the heat of products.
    Therefore it Should be heat of reactants - products in this case..

    • @ES-qe1nh
      @ES-qe1nh Рік тому

      Wrong. If it is exothermic, the enthalpy change sign is *negative* since the reactants have lost energy

  • @AdityaDalvi-ok8ys
    @AdityaDalvi-ok8ys 4 роки тому

    thankyou so much.........

  • @seeyameanie7607
    @seeyameanie7607 4 роки тому

    Not sure if this is a dumb question or not but if I have an equation with with no pure element that is in its standard state that equals 0, then how do I find the zero to make my math work? How do I determine what the pure element is if there is none already set up in my equation?

  • @tokytahmid4894
    @tokytahmid4894 4 роки тому

    life saver !

  • @Ashraf0304
    @Ashraf0304 3 роки тому

    Its 8:36 and my test is at 9:20 wish me luck 🥲

  • @neetuneetu373
    @neetuneetu373 3 роки тому

    Sir how to find the value of reactants and products ??

  • @Joshy1313
    @Joshy1313 6 років тому +1

    Thank you.

  • @garyyouth9354
    @garyyouth9354 2 роки тому

    Shouldn't the final answer be in KJ not KJ/Mol since you multiplied the Molar Enthalpies by the moles in the equation?

  • @AmaKwakyewaa-y7r
    @AmaKwakyewaa-y7r 3 місяці тому

    Thanks 🎉

  • @shanuruppi2051
    @shanuruppi2051 6 років тому

    thanks for this video

  • @rmsattar
    @rmsattar 4 місяці тому

    So,how do I figure out that sodium chloride is a liquid?

  • @vkrs3315
    @vkrs3315 4 роки тому

    Thanks

  • @BlessedAkue-yy8hg
    @BlessedAkue-yy8hg 18 днів тому

    Thank you🇳🇬🇳🇬🇳🇬

  • @WILBROADBANDA
    @WILBROADBANDA 4 місяці тому

    Iyee mwelesa what are we going to write tomorrow