Prove that the sensitivity of Wheatstone Bridge becomes maximum if its four resistances are equal

Current Electricity 02 & Electric Measurement : Sensitivity of Wheatstone Bridge is the angle deflection of its galvanometer per unit relative change in its adjustable resistance ; Angle of deflection is directly proportional to the potential difference between the two ends of the galvanometer ; If the sensitivity (S = Angle of deflection/ Relative change in resistance) is maximum, d/dR(S) = 0 ; Hence , P=Q=R=x ....Class 12 Physics

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Amazing sir.... What an explanation..... Thank you