sensitivity of wheatstone bridge || EMI by ushendra's engineering tutorials

[@kalyanachakravarthi2736]

The expression which you said is right sir....
wkt, R1R3=R2R4
From this we can calculate the value of R2, so R2=R1R3/R4
if we substitute this value in our expression R1/R1+R2 =R4/R3+R4, then
R1/R1+R2= R1/R1+(R1R3/R4)
=R1/((R1R4+R1R3)/R4)
=R1R4/(R1R4+R1R3)
cancelling the like terms i.e R1 we get
=R4/R4+R3
Hence proved

[@tarunteja8340]

Nuvu kuda UA-cam channel Petey bro

[@praptibishen3169]

thank you for this explanation sir!!!! it is awesome

[@Babu-im4hq]

You are the best brother... Keep moving

[@ushendrasengineeringtutori4259]

Thank you so much 😀

[@vasurajana6780]

A clear explanation.. good

[@amadhukar1114]

Good going sir..keep it up
👏👏👏👍👏👏👏

[@kudajohnthamous2457]

Nice explanation sir

[@saichaitanya5175]

Good explanation

[@kiranthapa8856]

It would be more easy to understand if you give some values and solve it because of only R1,R2 it is being more complicated

[@crazygamerdattu8702]

Nice

[@mounika4639]

👌👌👌

[@ushendrasengineeringtutori4259]

Tq. Keep supporting plz 🙏

[@FREEFIRE-pd7xf]

Hi sir....following ur lectures can you start pdc also simultaneously ur lectures easy to learn

[@thinkunique5817]

Automation in digital instruments.. like auto ranging auto polarity indication n zeroing. Sir..

[@FREEFIRE-pd7xf]

Hi sir....following ur lectures can you start pdc also simultaneously ur lectures easy to learn