I'm studying for the SAT and each time I face a problem I come and see your videos . You approximately solved every type of question that I need to survive SAT . Thank you so much
That formula saved my life! Nowhere does my book mention it, and I've been scratching my head for a few hours now trying to figure out what was happening. Thank you so much!
Professor Organic Chemistry Tutor, thank you for a solid introduction to Mixture Problems in AP/ General Chemistry. Everything in life uses some form of Chemistry. Mixtures problems are common in all levels of Chemistry. The equation that's given in this video is a good starting point when solving mixture problems. This is an error free video/lecture on UA-cam TV with the Organic Chemistry Tutor.
@@SOPHIA-kx1mp you okay now? I’m assuming you just had a bad day and decided to be an asshole to a random on the internet. Using your logic, why even reply to the comment? Everyone could’ve been okay without your reply.
I thought this video help me to solve the problem in 10sec cause i can solve it for less than minute For the first problem. Just use 2 equation 2 unknown. x+y=20 y=20-x. Eq. 1 0.2(x) + 0.4(y) = 0.28(20) eq. 2 Put eq. 1 in eq. 2 0.2(x) + 0.4(20-x) = 0.28(20) x=12
Im in an Hvac class at my community college but have to take an applied math class. I have been struggling with this all week and you just made my life 100% easier god bless you so much.
6:37 problem 2. What is the concentration of the mixture? The mixture is 200 L (50 from the 15% alcohol solution and 150 from the 35% alcohol solution). let y = percentage of alcohol concentration of the mixture, then y 200 L = the total amount of alcohol in the mixture. The first solution has 7.5 L of alcohol (50 x 15%) and the second solution has 52.5 L (15% x 150) and this equal to total alcohol in the mixture of y 200 L. solving for y will give the concentration of alcohol of the mixture, so 7.5 + 52.5 = y 200 or 60=y 200 or y = 6/20 or 3/10, 3/10 is the same as 30/100 or 30%. Therefore the mixture has a 30% alcohol solution. Ans 30% 10:03 alcohol solution or 60 L of alcohol is in it.
Amazing video, i used to be really scared of mixture problems, you explained it amazingly, they never mention this formula in my book, nonetheless, worked 10outta10 times. thanks a lot!
Thank you!! I took organic chemistry 20 years ago and was trying to calculate mixing solutions of 3% and 10% to get a 6% 3.5 ML solution, I need 2 ml of 3% and 1.5 ml of 10% to get my goal 6%. Thanks again :)
Thank you very much sir. Your lecture helps a lot for understanding the problems. I love how you do it, step by step sir. God bless and keep safe. 🙏🙏🙏🙏🙏😇😇😇😇😇😇
thank you so much!!! i was literally about to cry cuz i didn't understand my math and i'm scared of my teacher cause he always wants to check how i'm doing in my math class, but now i know what's going on and i'm reliefed. thank you again, and have a great day
This works for 10:53 as well. 60L is 3* bigger than 20L. Adding 60L of water to a 20L 28% concentration can be represented as (0*3+28)/4 = 7% concentration
Mass is conserved. Volumes of liquids are not necessarily. (10 L of A + 10 L of B will not necessarily produce 20 L of a mixture.) Differences can be significant. Without density data, isn't it better to use weights rather than volumes?
For the first problem. Just use 2 equation 2 unknown. x+y=20 y=20-x. Eq. 1 0.2(x) + 0.4(y) = 0.28(20) eq. 2 Put eq. 1 in eq. 2 0.2(x) + 0.4(20-x) = 0.28(20) x=12
Wait…what? If the student mixed 40% and 20% and ended up with 20ml of 28% Are you saying adding 12 ml of the 20% gives him a 20 ml 32% ? I’m confused….Did he start with a 20 ml container of 28% or did he start with a container of 20 ml of 32%?
Hi, I get how to use the equation to solve these types of problems. However, I’m not too sure on how you came up with the equation. Could you explain how to derive the equation?
Will you please solve this problem? Brine is a solution of salt and water. If a tub contains 50 gallons of a 5% solution of brine, how much water must evaporate to change it to an 8% brine solution?
Geez that formula is SO HELPFUL!!!! BTW- just curious how come the % isn't converted to a decimal before multiplying? (I feel like I would do that systematically, and hinder the equation....)
no because the factor was cuz of the increase of the second L to the total L. You have to consider than it is only one compound. Water is not included in the equation so it doesn't affect it. Try to do the same to other compounds. He said that it is only done when adding water to a pure, only.
problem 1 let p = liters of the 20% acidic solution, then that solution has 1/5 p liters of acid Since the total liters produced = 20 liters, then the other 40% acidic solution is (20-p) liters and thus has 2/5 (20-p) liters of acid. Both 20% and 40% acidic solution are said to produce 20 liters of a 28% acidic solution or (20 liters x .28) 5 and 3/5 liters of acid. equation , 1/5 p + 2/5 (20-p)= 5 3/5 or 1/5 p + 8- 2/5 p = 5 3/5 or -1/5 p= - 2 2/5 or 1/5 p= 2 2/5 or 1/5 p =12/5 multiply both sides by 5 gives p=12 liters. Ans: 12 liters of the 20 % acidic solution was needed
Yes, but I kept 28% as 28 for two reasons. (1) It will not affect my final answer. (2) My final answer will be a percentage and not decimal. You can do it both ways. You should still get the right answer.
10:46. A student adds 60 liter of water to an alcohol solution of 20 liters and 28% alcohol . So the student adds 0 liter of alcohol to a solution that has 5.6 liters of alcohol (20 L x 28%) TO PRODUCE 80 liters (60 +20) of an unknown PERCENTAGE of alcohol. Let that unknown % of alcohol in the mixture = R so R% (80) liters of alcohol was in the final solution. Therefore 80 R% = 5.6 + 0 or 80 R= 5.6 or R% = 5.6/80 = 56/800 or 7/100 or 7%. Answer: the solution now contain just 7% of alcohol.13:49
Can someone answer this mixture problem for me tyia. A flask contains 500ml of an 80% alcohol solution in water. how much of this solution must be drawn off and replaced by water to obtain a solution having concentration of 25% alcohol?
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there's a special place in heaven saved for organic chemistry tutor :)
Absolutely.
Oh am sure!
Hey respect for heaven man!
I think ur wrong, that's an underestimatement
100%
I'm studying for the SAT and each time I face a problem I come and see your videos . You approximately solved every type of question that I need to survive SAT .
Thank you so much
Already taken your SAT?
He's god for Indian students like us
@@dayoff11 he’s god for everyone
SAT!? I’m stuck doing this in the first year of middle school
@@sweepasey8727 first year?? i just learnt about this in grade 6!
That formula saved my life! Nowhere does my book mention it, and I've been scratching my head for a few hours now trying to figure out what was happening. Thank you so much!
this is not a formula this is logic haha
It's a very word logic, this clears it up
There's no formula for it in math books as they phrase it by doing rational equations, but I remember this one from my middle school chemistry book
FRL
Professor Organic Chemistry Tutor, thank you for a solid introduction to Mixture Problems in AP/ General Chemistry. Everything in life uses some form of Chemistry. Mixtures problems are common in all levels of Chemistry. The equation that's given in this video is a good starting point when solving mixture problems. This is an error free video/lecture on UA-cam TV with the Organic Chemistry Tutor.
Mixture problems always freaked me out until now :)
This saved me 3 hours of math homework
why even comment on this video? it’s not like someone cares that it saved you 3 hours of math homework. 💀
ok so why did you waste time commenting lmao it’s not like anyone cares :)
@@SOPHIA-kx1mp you okay now? I’m assuming you just had a bad day and decided to be an asshole to a random on the internet. Using your logic, why even reply to the comment? Everyone could’ve been okay without your reply.
I thought this video help me to solve the problem in 10sec cause i can solve it for less than minute
For the first problem.
Just use 2 equation 2 unknown.
x+y=20
y=20-x. Eq. 1
0.2(x) + 0.4(y) = 0.28(20) eq. 2
Put eq. 1 in eq. 2
0.2(x) + 0.4(20-x) = 0.28(20)
x=12
@@SOPHIA-kx1mp stfu :)
Im in an Hvac class at my community college but have to take an applied math class. I have been struggling with this all week and you just made my life 100% easier god bless you so much.
i have a finals exam on this tomorrow. pray for my soul
How did you score?
oh same! my finals are tom and rip my soul :)
Maybe I'm a little late but 😂😂
so how did it turn out?
He didn't make it.
Thank you. You have made mathematics become so much easier for me. You make math more understandable and enjoyable.
6:37 problem 2. What is the concentration of the mixture? The mixture is 200 L (50 from the 15% alcohol solution and 150 from the 35% alcohol solution). let y = percentage of alcohol concentration of the mixture, then y 200 L = the total amount of alcohol in the mixture.
The first solution has 7.5 L of alcohol (50 x 15%) and the second solution has 52.5 L (15% x 150) and this equal to total alcohol in the mixture of y 200 L. solving for y will give the concentration of alcohol of the mixture, so 7.5 + 52.5 = y 200 or 60=y 200 or y = 6/20 or 3/10, 3/10 is the same as 30/100 or 30%. Therefore the mixture has a 30% alcohol solution. Ans 30% 10:03 alcohol solution or 60 L of alcohol is in it.
Amazing video, i used to be really scared of mixture problems, you explained it amazingly, they never mention this formula in my book, nonetheless, worked 10outta10 times. thanks a lot!
Bro explains this better than my college professor 😭 I love you
im doing this in hs?
Thank you!! I took organic chemistry 20 years ago and was trying to calculate mixing solutions of 3% and 10% to get a 6% 3.5 ML solution, I need 2 ml of 3% and 1.5 ml of 10% to get my goal 6%. Thanks again :)
Thank you very much sir. Your lecture helps a lot for understanding the problems. I love how you do it, step by step sir. God bless and keep safe. 🙏🙏🙏🙏🙏😇😇😇😇😇😇
Thanks for posting this kind of tutorial. I salute you! Hoping to see more math videos. 👏😍
Is no one talking about how on point and crisp his mic is?
u r fantastic! Hope u know that u r appreciated by many who can recognize the value of ur videos!
Thank you so much for this, it helped tonnes
THANK YOU SO MUCH!!! Im pretty sure I failed my algebra quiz and the teacher is giving the whole class a retake tomorrow
Thank you for a wonderful lesson. Awesome teacher. I will try to watch all your videos until I become as great as you. Thanks.
give me more of this topic teacher please
thank you so much!!! i was literally about to cry cuz i didn't understand my math and i'm scared of my teacher cause he always wants to check how i'm doing in my math class, but now i know what's going on and i'm reliefed. thank you again, and have a great day
You have helped me soo much with my school. Your like second teacher. Thank you
This works for 10:53 as well. 60L is 3* bigger than 20L. Adding 60L of water to a 20L 28% concentration can be represented as
(0*3+28)/4
=
7% concentration
you just said what he said, but you didnt add that part where he mentions that it can only be done when adding pure water.
is this for the math sat or is it in the wrong playlist
Yes ,he will live forever! Thank you for keeping our existence,without study Iam dead and dome...
Thanks mate, really helped me learn mixing problems.
Thank you, it's a big help for me.
Mass is conserved. Volumes of liquids are not necessarily. (10 L of A + 10 L of B will not necessarily produce 20 L of a mixture.) Differences can be significant. Without density data, isn't it better to use weights rather than volumes?
This is soooo much easier than using systems of equations! Tysm!!!
bro thank u , if only there would be more people like u
For the first problem.
Just use 2 equation 2 unknown.
x+y=20
y=20-x. Eq. 1
0.2(x) + 0.4(y) = 0.28(20) eq. 2
Put eq. 1 in eq. 2
0.2(x) + 0.4(20-x) = 0.28(20)
x=12
Thx for saving me during BYU eras
Thank you, you are a life saver. Keep up the good work :)
Wait…what? If the student mixed 40% and 20% and ended up with 20ml of 28%
Are you saying adding 12 ml of the 20% gives him a 20 ml 32% ?
I’m confused….Did he start with a 20 ml container of 28% or did he start with a container of 20 ml of 32%?
I'm confused too !
Thank you so much for this video. We were stuck on a problem and this video plus the book answered all our questions.
This is very helpful ❤
Thank you so much
Asante sana Sir
I have aircraft maintenance school enterance exam tomorrow. And this is being really helpful.
Now, am studying for pilot school enterance exam on next Monday. LONG LIVE FOR MY BROTHER!!!! I wish I know your name! 😄😄😄
Very helpful, you are my savior.
When you single handedly save generations' educations with free videos.
Hi, I get how to use the equation to solve these types of problems. However, I’m not too sure on how you came up with the equation. Could you explain how to derive the equation?
Drive? 😄😆 just take what you are given man!!
@@ibeeadane4430 for people like you i feel smart, you sure as hell believe in god or some shi you don't question anything
Thank you for posting these lessons it helps me alot!!!!
This video safe my life
Very good I highly appreciate you in indeed
6:27, why 32% not 28% as in the original question?
because 28% is given in the question
I suppose, it meant to be 28%
Thank you for this!!! I finally get it!
Thanks! I was answering a question like this a while ago. Lmao I was chanting "Inhale...exhale" as if I was persevering pain in my body. 😂
lol
Gave me great insight
Your explanation is great!! Thanks!! Keep making videos!!😁
Could you please do a composition of mixtures video?
YOU ARE MY GOD!!! Damn that helped loads!! So did your number sequence videos. Keep up the amazing work and thank you!
Michael Brauer your god? 😭
1. 0.2x + 0.4 (20-x) = 20(0.28)
2. 50(0.15)+ 150(0.35) = 200x
3. 60(0%) + 20(28%) = 80x -----> 0 + 560 = 80x -----> x = 7%
By using the weighted average method
Great
Thank you man
Thank you so much for great explanation!! It is truly way easier now to solve mixture problems.))
thanks bro
You are the best!
Are mixture problems same as dilution problems?
thank you
What is that it has to do with SAT Math?
I think he added it by accident 😂
you're a GODDAMN GODSEND thank you mr man sir
Thank you bro
Do you have a video containing questions pertaining to solute?
Very helpful video. Thanks. Also, amazing voice man!
enjoy the way you say acid very much i gotta say
brilliant!
got an entrance exam in a few days, hopefully i get in
good job
Will you please solve this problem? Brine is a solution of salt and water. If a tub contains 50 gallons of a 5% solution of brine, how much water must evaporate to change it to an 8% brine solution?
Gracias 😎
Im in 9th grade and probably bit too late...
But what grade do you give this in? 12th grade?
Geez that formula is SO HELPFUL!!!!
BTW- just curious how come the % isn't converted to a decimal before multiplying? (I feel like I would do that systematically, and hinder the equation....)
If you use decimals, your answer will be converted to percentage later so it doesn't matter.
8:00
I quickly thought of this but cant we do "(15+35*3)/4"
for the problem? this is because 150 is 3* bigger than 50
no because the factor was cuz of the increase of the second L to the total L. You have to consider than it is only one compound. Water is not included in the equation so it doesn't affect it. Try to do the same to other compounds. He said that it is only done when adding water to a pure, only.
tell me, tell me why im learning this before im even a junior in high school and there are comments about studying for SATs. pray for us all dear LORD
i like to use x and y for these kinds of problems
Thank you ! I've learned so many techniques from you..
The percent is disregarded? Or nah?
Thanks legend
my bros voice is even better than khan academy guy's voice.
not even joking
Am I supposed to be doing chemistry in calc?
If god ever ask who should be in heaven, it is this guy
Only If he believe in Jesus christ ..
how about if there are 3 elements in the problem
For the 3rd problem c1v1=c2v2 could've been used
So nice
thank man 😊
problem 1 let p = liters of the 20% acidic solution, then that solution has 1/5 p liters of acid
Since the total liters produced = 20 liters, then the other 40% acidic solution is (20-p) liters and thus has 2/5 (20-p) liters of acid. Both 20% and 40% acidic solution are said to produce 20 liters of a 28% acidic solution or (20 liters x .28) 5 and 3/5 liters of acid.
equation , 1/5 p + 2/5 (20-p)= 5 3/5 or 1/5 p + 8- 2/5 p = 5 3/5 or -1/5 p= - 2 2/5 or 1/5 p= 2 2/5 or 1/5 p =12/5 multiply both sides by 5 gives p=12 liters. Ans: 12 liters of the 20 % acidic solution was needed
Whatever happened to the decimals in the percentages?????? Shouldn't 28% multiplied by 20 be 5.60?.........Not 560.....
Yes, but I kept 28% as 28 for two reasons. (1) It will not affect my final answer. (2) My final answer will be a percentage and not decimal. You can do it both ways. You should still get the right answer.
Nice
6:20 how do you get 32%?
10:46. A student adds 60 liter of water to an alcohol solution of 20 liters and 28% alcohol .
So the student adds 0 liter of alcohol to a solution that has 5.6 liters of alcohol (20 L x 28%) TO PRODUCE 80 liters (60 +20) of an unknown PERCENTAGE of alcohol. Let that unknown % of alcohol in the mixture = R so R% (80) liters of alcohol was in the final
solution. Therefore 80 R% = 5.6 + 0 or 80 R= 5.6 or R% = 5.6/80 = 56/800 or 7/100 or 7%.
Answer: the solution now contain just 7% of alcohol.13:49
why is the video so quiet/
C1V1+C2V2= C3V3
you said you were making 28% and at the end you said 32%. I think you said the wrong thing at the end.
Can someone answer this mixture problem for me tyia. A flask contains 500ml of an 80% alcohol solution in water. how much of this solution must be drawn off and replaced by water to obtain a solution having concentration of 25% alcohol?
Up
No!!! 28% not 32%
(15%*50) + (35%*150) = 60, not 6000
6:18 where does 32% come from?
It should be 28% ,
You are making this so complicated just write and solve the equation 0.20x+0.40(20-x)=20*0.28
He's breaking it down into simpler concepts so we can understand the process
🙏🙏🙏