Example Problem - Hydrostatic Pressure on Curved Surfaces (2)

The hemispherical dome in the figure below weighs 30 kN, is filled with water, and is attached to the floor by 6 equally-spaced bolts.
What is the force in each bolt required to hold down the dome?

[@cherrytree5026]

thank you very much i would love to see more of these videos

[@charliepinckney]

For the volume of the small cylinder, it would be 1.5 cm instead of 3 cm since 1.5 cm is the radius

[@SirEx12345678]

He did that part correctly. He knew he was using the diameter instead of the radius, hence the pi/4 instead of just pi.

[@KristenMariePalian]

I think its 58.64 not 56.64 for the volume displaced

[@phucngo129zz]

hey, can someone explain how the hydrostatic force equal to the weight of missing water ?

[@nkirchnerb5456]

What if there was no displaced volume (perfect cylinder filled with water)? then forces up would be 0, hence FB+30kN=0? the force of the bolts would be negative?

[@marsssss]

why is there a 1/4 in the volume of cylinder? isn't the formula for cylinder just pi(radius)^2h?

[@unknownotaku2894]

Hmm

[@unknownotaku2894]

It's because he used the diameter not the radius

[@giovannigiorgio0]

why you found the space volume i dont understand. Can we just calculated the water volume ?

[@서리-i3e]

just think about the buoyant force. consider the volume 'replace with air' be in water. the buoyant force has a magnitude equal to the weight of the fluid displaced by the body and is directly vertically upward.