Fluid Mechanics: Topic 4.1 - Hydrostatic force on a plane surface
Вставка
- Опубліковано 4 бер 2016
- Want to see more mechanical engineering instructional videos? Visit the Cal Poly Pomona Mechanical Engineering Department's video library, ME Online: www.cpp.edu/meonline
Explained with ease in just 10 min video literally this is the stuff that someone want for clear understanding
This channel has some good ass videos and all of them too. Helps me recounter what is taught in class with a better understanding
ua-cam.com/video/pgRdVOrpzGY/v-deo.html
..
Thank you sir, without wasting a single minute u explained everything neatly and precise. Most underrated channel in UA-cam
Tell all your friends. :D
@@CPPMechEngTutorials Definitely 👍😁
This is the best explaination so far in youtube for this topic! So many thanks to you!!!
We're happy to help.
These videos are excellent, deserve so many more views!
Thanks. More on the way in the near future!
instablaster
I love you brother! I could not find anyone to explain this well until I found you
ua-cam.com/video/pgRdVOrpzGY/v-deo.html
...
Excellent! What clarity in your explanation!
We're glad you liked it.
these videos are awesome
Your Explanation very good
Thanks very much on discussion an important topic of fluid mechanics
Thanks a lot,Concept is clear after watching your video,Great effort by you :)
We're glad it helped.
lucid and crystal clear explanation. Thanks
:)
Phenomenal videos. So clearly explained, helps to visualise everything.
Thanks!
thanks a lot I have been straggling with this my whole afternoon.
The topic has a lot of weird notations and angles. It takes a while to get used to them.
bro i actually love you man, u saved me
ua-cam.com/video/pgRdVOrpzGY/v-deo.html
...
Thank you very much for this lucid lecture. Well-explained and nicely visualized to explain it very well.
Thanks!
ua-cam.com/video/pgRdVOrpzGY/v-deo.html
.
seriously awesome lecture...u clarified everything.... keep it up
If you insist. :)
6:55, in another word, to find y_c, you must find the y-component of the centroid of the cross-section area first, then find the distance from the free surface to that point, correct?
Very well understood
Excellent 🔥🔥
Beautiful
thank you so much. Condensed an entire class period into 8 minutes.
That's what we do.
ua-cam.com/video/pgRdVOrpzGY/v-deo.html
...
great sir
one of the best videos ive ever seen :D
:D
This video was a lifesaver!! Thank you so much!
Saving lives is what we do.
ua-cam.com/video/pgRdVOrpzGY/v-deo.html
..
@@CPPMechEngTutorials Absolutely 😅! Your channel deserves so many more views! ☺
I want to as a question on The resultant force due to fluid pressure of the bottom wall. The d do i need to sub a negative value to it, since upward motion take as positive
thank you
really appreciate this... really a very good explanation ♥️
Beautifully explained and presented,thank You Sir...
No, thank you. :)
pls explain boundary layer concepts... I am awaiting
Thank youuuu so much !
Thanks for the positive feedback.
why in pressurized tank, Patm is not included in the final equation?
Sir please make this kind of conceptual videos on heat transfer also..
Thank you :)
You're welcome.
The resultant force acts on CP or CG ?
This is golden
24 karat gold!
Y coordinate of the centroid.
How did u find this result??
well explained.. .
Glad it helped.
Why do I pay for university and books when this is 20x better
thanks soooo much
You are soooo welcome
What's the name of this app and can we use it in Android?
Keep it up.
More are coming.
Is there an example?
in this topic resultant... force is likely act on the centroid but in center of pressure topic resultant force also act on center of pressure.
so i get confused... which is the right one?
what do you mean ''the centroid and the center of mass is the same if the density is constant'' ? Do you mean the location of them?
Yes, the location of the centroid and center of mass are the same if the wall density is constant.
when ever tank pressurised with internal pressure then there is any effect of atmospheric pressure in resultant ....?
From the derivation, the force from atmospheric pressure cancels out. However, if the tank is pressurized above (or below) atmospheric, then you need to account for this. See 7:30 in the video.
when the force acts on an horizontal plane the center of pressure = the center of gravity ?
please answer me :)
If the surface is horizontal, then the center of pressure coincides with the centroid of the surface. If the surface has uniform density, then the center of mass, center of pressure, and centroid all coincide.
is gamma the density of the fluid times gravity?
+Bardh Limani You are correct. The specific weight is defined in an earlier video (Topic 1.3) -- ua-cam.com/video/S8pL3np5kvc/v-deo.html
In this video you considered the inclined surface as the wall of container. If it was submerged inclined plane (not a container wall) then would there be a change in resultant force, if not then why?
If a surface is completely submerged in a fluid, then you only need to consider the buoyant force on the surface.
@@CPPMechEngTutorials OK thanks
You said that FR is applied to where CP is. Then why did you use hc in finding FR? Please enlighten me
i have the same doubt
I love you
\
So all we had to do is create fluid mechanics videos to win your affection? We should have made the videos much earlier.
what is the meaning of specific weight of the water? if it is the weight of the water then why it is multiplying the depth of the water as inside of the bracket should be the pressure instead of the force... @1:04
This concept is defined in an earlier video. It is the density of a fluid times the gravitational acceleration g (9.81 m/s^2)
CPPMechEngTutorials okay thanks :)
Thank You much! Can you provide notes in pdf?
Sorry, but there are no plans to post the slides at this time.
CPPMechEngTutorials please upload notes. it will help us alot and will save alot of our time too .
Why am I just finding these and my final is in 7 days?!?
Share with your friends taking the course next term... hopefully more than 7 days before their final.
Mines in 2 hrs haha
@@serious-power3085 Good luck!
How did it go?
My test is in 10 hours 😂
what is CP.....Is its centre of pressure? ? right??? and what's C .??? is it centroid????? so my question is that you take an inclined plan....have uniform thinness.....and fluid incompressible.......but where this resultant force act on plan ????? you said on CP.....Why????? answer plz.....I am in trouble 😢😢😢😢😢
The resultant force acts at the center of pressure.
Resultant force will act on CP not in Centroid. Because the fluid pressure acting on the surface is not equal, It changes along with the depth. More the depth more will be pressure. So resultant force will act at a point which is below Centroid i.e. CP.
thanks jigar.........it will help.......
ok....sir....thankyou..
one thing more i want to ask.......first moment of area.....i can say easily rotation about any axis by applying force multiplying by perpendicular distance from axis of rotation,,,,example Mx=f *y ......right? but what is 2nd moment of area or inertia......what's concept behind it ........is it same rotation with double perpendicular distance about an axis or something like resistance ? tell
what is gamma here?
Specific weight (density times gravitational acceleration). It is covered in an earlier video.
Your mistake is assuming the force is a function of hydrostatic pressure , impossible since a liquid is incompressible, as I show in my experiment and explain in my video on hydrostatics.
You missed the part where you actually explain what everything you say actually is.
Can you explain what you mean?
First of all i want to congratulate you for taking the time to read comments and show the interest required for one to improve his videos. I also want to apologize for the rude nature of my comment, i just got frustrated with teaching videos not explaining in the way that i am expecting them to.
Searching for this video it means that i don't want to see someone solving the exercise , i want to understand what a centroid is, why do i care for the centre of pressure, why do i use the technique illustrated to solve an exercise of that nature. why do i need to consider a small part and then intergrate?
I know that these questions require for you to " spoonfeed" me information. But as soon as teachers realise that spoonfeeding is the best way to go, the better for the world of education. After all if you don't know how to explain something with simple words you don't understand it yourself. At least something similar is what Einstein said
Eventually we will create example videos for the fluid mechanics videos. The current set of videos are meant to explain important concepts and derive equations only.
6:16 , Pc = garma*Hc +Pa, why missed Pa
Is that the correct timestamp? Where do you see the "+Pa"?
Are we the only who noticed that ? I don't understand why Pc = gamma*Hc
great explanation but you talk a little too fast for me.
You can slow down the video by clicking on the Settings icon (looks like a gear).
هو احنه عربي ما مدبريها انوب انكليزي
You said that FR is applied to where CP is. Then why did you use hc in finding FR? Please enlighten me
Because the derivation says so. :)