CORRECTION FOR W 🙏🙏🙏 W = 2.69 kN Hence, summation of Fy = 91.5 kN And resultant force FR = 126.9 kN Angle theta = 46.1 degree And W(cylinder) = 91.4 kN Apologize for putting the decimal point wrongly in the video 🙏🙏🙏
teacher i don't understand why you use the area of the imaginary rectangle instead of the area of the circle to calculate the vertical force. Please can you explained this
CORRECTION FOR W 🙏🙏🙏
W = 2.69 kN
Hence, summation of Fy = 91.5 kN
And resultant force FR = 126.9 kN
Angle theta = 46.1 degree
And W(cylinder) = 91.4 kN
Apologize for putting the decimal point wrongly in the video 🙏🙏🙏
teacher i don't understand why you use the area of the imaginary rectangle instead of the area of the circle to calculate the vertical force. Please can you explained this
wow you made it simple, I can't believe my prof Hasan Hacisevki couldn't explain it
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😅😅😅
thank you. this is helpful for my exam tumoro
JazakAllah may Allah bless you 🖤
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love from pakistan karachi NEDUET
Thank You so much🙌🙌
Thank you
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thx
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Hey nice man
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hc is 5.6 actually (:
Yes, I got 5.6 m too..I used h(bar)1
the calculation of W is wrong
Thanks for highlighting. I have written the correction in the pinned comment and description
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Zooom plz
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