Did it virtually the same. Found equation of tangents at both points. Worked out where both crossed the x-axis. Lead to a+1-p=0 and b+1-q=0, set them equal gives answer C.
I didn't bother to solve it I was just looking at the variants and I think all of them involving p-a or p+a are situationally false so I would g o with A. Line equation is obviously y-e^t=e^t(x-t) when t is the point of tangency finding a: y=0 t=p -e^p=e^p(a-p) a-p=-1 and for b and Q it would result b-q=-1 Intuition too stronk :)
Did it virtually the same. Found equation of tangents at both points. Worked out where both crossed the x-axis. Lead to a+1-p=0 and b+1-q=0, set them equal gives answer C.
I did it without (much) calculation. If a line has slope e^p, how long does it take that line to rise from 0 to e^p?
I didn't bother to solve it I was just looking at the variants and I think all of them involving p-a or p+a are situationally false so I would g o with A.
Line equation is obviously
y-e^t=e^t(x-t) when t is the point of tangency
finding a: y=0 t=p
-e^p=e^p(a-p)
a-p=-1 and for b and Q it would result b-q=-1
Intuition too stronk :)
It’s good to have intuition, but it’s also a good idea to check if your intuition is right! I’ve had incorrect intuition in many of my videos!