Redox titrations | Chemical reactions | AP Chemistry | Khan Academy

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  • Опубліковано 13 вер 2014
  • A redox titration is a titration in which the analyte and titrant react through an oxidation-reduction reaction. As in acid-base titrations, the endpoint of a redox titration is often detected using an indicator. Potassium permanganate (KMnO₄) is a popular titrant because it serves as its own indicator in acidic solution. View more lessons or practice this subject at www.khanacademy.org/science/a...
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КОМЕНТАРІ • 87

  • @user-kt6wv2pn6k
    @user-kt6wv2pn6k 8 років тому +68

    That's amazing! I finally understand what we've done last half year on chemistry lessons, even if i am not a native speaker, the whole stuff is brilliantly explained!

  • @joni2417
    @joni2417 4 роки тому +8

    I'm German and you explained it much better than my Chemics Teacher. Thank You

  • @mmstutorhuraira5672
    @mmstutorhuraira5672 Рік тому +6

    just WOW! LITERALLY CLEARED EACH CONCEPT IN 7 MINUTES

  • @isharadinho2898
    @isharadinho2898 7 років тому +13

    thanks Khan Academy, i had a lot of problems understanding this topic, thanks to your video now i can.

  • @TheRealQuickSilver
    @TheRealQuickSilver 6 років тому +11

    Thank you so much! You just saved me from getting a C in AP chem this semester.

  • @sidrazeitouni5673
    @sidrazeitouni5673 Рік тому +3

    Perfect amazing! I finally could understand the whole concept which is very useful since I am preparing for my exam… BIG THANK YOU!!

  • @zachstarattack7320
    @zachstarattack7320 2 роки тому +2

    THANK YOU! I never get these labs as the other kids do them, now I see the light!

  • @Shreyaagrawal_1657
    @Shreyaagrawal_1657 2 роки тому +3

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    Thankyou so much. You guys are lifesaver

  • @user-yo6dk6jh2b
    @user-yo6dk6jh2b 2 роки тому +2

    이해가 잘되네요 감사합니다 시험 잘 볼게요♡

  • @adityashijikumar1131
    @adityashijikumar1131 Рік тому +1

    THANK YOU FOR EXPLAINING THE REDOX REACTION!

  • @arbindapandey1711
    @arbindapandey1711 5 років тому +3

    Thank you Khan Academy!

  • @HEAR_Instrumentals
    @HEAR_Instrumentals 5 років тому +1

    subbed, perfectly explained!

  • @black_jack_meghav
    @black_jack_meghav 2 роки тому +1

    Thanks khan academy! You guys are great!

  • @grade7science310
    @grade7science310 Місяць тому

    A good explanation . Thank u

  • @user-rw5nr8co7c
    @user-rw5nr8co7c 2 місяці тому

    Finally found a video that explains redox titration in detail

  • @bokuwatobi954
    @bokuwatobi954 4 роки тому +1

    Brilliant!!

  • @fakhrulnawawi9681
    @fakhrulnawawi9681 6 місяців тому

    Clearly explained, thanks

  • @moritzroh9361
    @moritzroh9361 5 років тому +8

    1 day before my German oral chemistry exam for the abitur...(like a levels)
    Thank u!

    • @bulitoni
      @bulitoni 4 роки тому +1

      What's oral chemistry

    • @alexh5040
      @alexh5040 4 роки тому +3

      @@bulitoni oral exam in chemistry

  • @vsalukir7019
    @vsalukir7019 5 років тому +8

    I'm having a lot of problems with the way that formal charge seems to be used interchangeably with oxidation state. I'm trying to image the Lewis dot structures and the separation of charges in things like MnO4- and Cr(OH)4- that would allow for the given oxidation states, and I can't do it. This makes me feel like I couldn't solve these problems on my own. I mean how does Chromium give up electrons or charge to hydroxide ions that want to give up charge?

    • @tomatochemist
      @tomatochemist 3 роки тому +1

      formal charge and oxidation state are not the same thing. They exchange electrons which affect their charge, but they aren’t exchanging charges

  • @emanbadry8642
    @emanbadry8642 Рік тому

    Thank you for this video

  • @dibb1e374
    @dibb1e374 3 роки тому

    Epic Dr. Skipper

  • @Bananakid11
    @Bananakid11 7 років тому +1

    nice
    thanks

  • @shreyajain5814
    @shreyajain5814 6 років тому

    thanks!

  • @aneeghagunasena5217
    @aneeghagunasena5217 6 років тому +10

    Can't thank this video enough😻

  • @enasabuelqmpoz749
    @enasabuelqmpoz749 6 років тому +1

    very thank

  • @kumarirashmi8293
    @kumarirashmi8293 6 років тому +1

    great mam

  • @johanan9987
    @johanan9987 8 років тому +2

    helpful and handsome!

  • @nikhilpatel2442
    @nikhilpatel2442 4 роки тому

    Is It possible to titrate a colored solution such as Iron(III) Oxide?

  • @chenyijia8836
    @chenyijia8836 5 років тому +1

    Why is the final solution colourless? Isn't Mn2+ pale pink and Fe3+ yellow?

  • @veronicawicker5273
    @veronicawicker5273 8 років тому +3

    How do you know that you havn't run out of H+ instead of Fe^2+? How would you know how much acid(H+) to add if the concentration of Fe^2+ is unknown?

    • @gonzaloayalaibarre
      @gonzaloayalaibarre 7 років тому +4

      I guess an answer isn't of use to you anymore, but I guess someone else can read this. This reaction is supposed to happen in very acidic mediums (high H+ concentrations, low pH) in which the Mn+7 will accept 5 electrons and be reduced into Mn+2.
      The Mn+7 can be reduced to +2;+3;+4;+6 at different pHs.

    • @veronicawicker5273
      @veronicawicker5273 7 років тому +2

      Thanks. I'm not in chemistry this semester but I will be taking organic chemistry next semester. This reminded me that I need to review chemistry2 before then.

    • @spookywizard4980
      @spookywizard4980 6 років тому +1

      if in doubt add some acid and see if the color persists

  • @rowenaabbie995
    @rowenaabbie995 6 років тому +1

    thanks this really help

  • @bilalkadri8851
    @bilalkadri8851 3 роки тому

    Isn't Fe3+ brown in colour, so it won't form a colourless solution ?

  • @rakshithamrakshitham1627
    @rakshithamrakshitham1627 3 роки тому

    How to calculate Ecell for 0 ml addition of titrant??

  • @Ongneko
    @Ongneko 2 роки тому

    Niceeee

  • @rxa4_tm
    @rxa4_tm 2 роки тому

    I'm waching this 30 minutes before the test

  • @topnup3288
    @topnup3288 3 роки тому

    Plss add more volume

  • @amiramostafa7335
    @amiramostafa7335 6 років тому +2

    please I need some help
    how can I compar between potassium permenganate and ceric ions as standard??

  • @johnprice8458
    @johnprice8458 3 роки тому

    Iron (lll) which is a product is pale yellow and not colourless, even in dilute concentration!

  • @user-hn4bm9hc2i
    @user-hn4bm9hc2i Рік тому

    ❤❤❤

  • @mayaaljundi5279
    @mayaaljundi5279 2 роки тому +1

    can we know how many grams (m) of Fe +2 were needed for the titration?

    • @satyamraj5570
      @satyamraj5570 2 роки тому

      Yes you can just use,
      Mole= Constituent weight/Molecular weight of that Constituent

  • @victoriagong2620
    @victoriagong2620 7 років тому +4

    How in the world is that permanganate molarity so precise?

  • @sumairasardar8666
    @sumairasardar8666 7 років тому +1

    Isn't this guy the same one that makes math videos. He speaks exactly the same

  • @xbbyhunny
    @xbbyhunny 6 років тому +4

    when i tried the mv=mv equation, my answer came out as 0.05M Fe x 5 moles = 0.05M of Fe why didnt it come out as 0.2M

    • @vsalukir7019
      @vsalukir7019 5 років тому +8

      Okay, let's try this using the MV method. For the KMnO4 it would be .020 M x .020 L = .01 L x X M. Solving for X we get .04 M. But then you have to consider that a molar quantity of MnO4 can react 5 times as much Fe, so you need to multiply the MV answer by 5. And 5 x .04 M = 0.20 M.

  • @NikRakiqta
    @NikRakiqta Рік тому

    For the concertrarion can't we use the formula C1 x V1 = C2 x V2
    C1 - conc. of Fe solution
    V1 - volume of Fe solution
    C2 - conc. of MnO4 solution
    V2 - volume of MnO4 solution
    So we can solve for C1

    • @samantharubinstein2699
      @samantharubinstein2699 Рік тому

      Thats the dilution formula, but there is a similar titration formula ; CaVa/a=CbVb/b, where a and b are the stoichiometric ratio of the reactants, so you could do CaVa/a=CbVb/b where
      Ca- conc. of Fe solution
      Va-- volume of Fe solution
      a=5
      Cb- conc. of MnO4 solution
      Vb- volume of MnO4 solution
      b=1
      Hope this helps!

  • @rkjstuff7402
    @rkjstuff7402 6 років тому +11

    Improve sound pls

    • @janeemmanuel8885
      @janeemmanuel8885 6 років тому

      rkj stuff hi

    • @dr.rupeshkushwah
      @dr.rupeshkushwah 5 років тому

      redox titration(full hd)/must watch n subscribe
      ua-cam.com/video/-d_E5hfGqWw/v-deo.html

  • @tiagomarques9153
    @tiagomarques9153 4 роки тому

    Why can't you cancel the fives of the irons if they're on both sides?

    • @Misha-iw6kd
      @Misha-iw6kd 4 роки тому

      Because they are two different ions. On the left he has Fe 2+ and on the right he has Fe 3+

    • @tiagomarques9153
      @tiagomarques9153 4 роки тому

      Misha but why does he have the fives in the first place?

  • @avishrohil929
    @avishrohil929 4 роки тому +1

    I'm confused. How does KMnO4 become MnO4 in the reaction

    • @walterwhite4699
      @walterwhite4699 4 роки тому +2

      MnO4-is the ion

    • @andrewhan2894
      @andrewhan2894 4 роки тому +3

      @@walterwhite4699 K is a neutral ion, so really it's just MnO4.

    • @nowwhatdana373
      @nowwhatdana373 4 роки тому +10

      The potassium is considered a spectator ion...it does not impact the reaction and is not included when the reaction is written this way. The same goes for the HSO4- which contributes hydrogen ions. It was sulfuric acid (H2SO4) before, but the HSO4- part of the compound is only a spectator ion.

    • @avishrohil929
      @avishrohil929 4 роки тому

      @@nowwhatdana373 thankss

  • @champagnemoneyabuelo
    @champagnemoneyabuelo 6 років тому +2

    why didn't we mention potassium when writing the equation?

    • @zack150
      @zack150 6 років тому +3

      ahmd1221 net ionic equation

    • @kingcuber7796
      @kingcuber7796 5 років тому

      @@zack150 ahhhhh, now i get it !!

  • @spamspam7919
    @spamspam7919 2 роки тому +2

    Going too fast not explaining enough.

  • @smp219
    @smp219 4 роки тому

    Sir your voice is too loud to hear pls speak loudly

  • @IfeomaOkeke-rw9wm
    @IfeomaOkeke-rw9wm 2 місяці тому

    WASSCE 2024 PRACTICAL

  • @adnansubzibag9353
    @adnansubzibag9353 7 років тому +15

    sound quality is poor

  • @kelvinhuang4710
    @kelvinhuang4710 4 роки тому

    Thank you so much 😊 but you sound so nasally.

  • @dhirajadhikari6918
    @dhirajadhikari6918 Місяць тому

    Abe angrej ke aawald hindi me samjha