Dear Srinivas... In this example, 50 is in percentage form. This is a reason we have multiplied with 10. There is other way too. Just convert percentage in to normal form. For example, 50%/100 =0.5 and sqrt root of 0.5 is 0.7071. Now convert 0.7071 in to percentage 0.7071*100 = 70.71% I hope you understood.
Flow is directly proportional to differential pressure but what about constant of proportionality which is considered based c and beta etc, is it mean all these factors are also incorporated in the transmitter Simple q is approximately equal to dp what if exact flow is to be inquired secondly what other factors needs to be considered as well
dear sir please the calibration range 0-- 500 m bar for differentiation transmitter how to calculate square root the out 4 to 20 mA flow rat 21 bopod as max pipeline 8"
Square root extractor is only used when we measure flow by using differential pressure. Since flow is proportional to square root of differential pressure. All other variable such as temp, level does not have such relationship
Linear(%)= (x)^2*100 For example, if you want to convert 86.66% to linear %. First Convert Percentage to normal number 86.66/100 =0.866 Linear(%)= (0.866)^2*100= 0.74.99*100 =74.99% =75% Hope you understand. Please feel free to ask me your question in comment box.
Dear Sir I am having Siemens DP transmitter, I want to calibration flow with respect to pressure, and why we take square root for flow calculation WRT pressure transmitter pls explain sir.
It is because flow rate is directly proportional to square root of differential pressure. And in order to convert this differential pressure to linear, we take square root in DP Transmitter. Please feel free to ask me, if you have any further queries.
In linear percentage to square root percentage conversion formula why we multiply with 10 . What is the reason behind it. Plz and me one person asked me in an interview.
Hello Ajay Thanks for asking this question. Linear Value is in percentage. And we need to convert this percentage value into normal Value. This is reason we are multiplying with 10. For Example.=50% This is a percentage value. There is also other way. You can also divide 50 by 100 then take square root. 50/100 = 0.5 Square Root of 0.5 is 0.707 If you convert this value into percentage. 0.707*100=70.7 %. I hope you get your answer.
@@InstrumentCalibration thanks for information. your explanation very well. Can I ask questions in different topics also? Like thermocouple or radar level tx.
Dear Sir, I wanna ask some questions 1. Linear Output is signal from transmitters delta P. converting 4-20mA? 2. Flow rate is proportional to squareroot delta P. So linear output needs to be converted to squareroot output?
1. Yes, But you need to select square root function from transmitter to convert into linear mA. 2. In order to cancel square root, you have to select square root function at transmitter side or at PLC or DCS side. Hope you will get your answer
Dear Sir,
Good Explanation sir... everything understood but Why we multiply by 10 in the %
Dear Srinivas...
In this example, 50 is in percentage form. This is a reason we have multiplied with 10. There is other way too. Just convert percentage in to normal form. For example, 50%/100 =0.5 and sqrt root of 0.5 is 0.7071. Now convert 0.7071 in to percentage
0.7071*100 = 70.71%
I hope you understood.
@@InstrumentCalibration Thank you for your support marvelous answer...
@@srinivasv3214 You are welcome... please do ask me question whenever you have confusion.
@@InstrumentCalibration thank you & from which country yours sir
@@srinivasv3214 You are welcome
Dear sir
Really very good example for understanding
Thanks ..Keep supporting
Thanks A lot for sharing informative calculation about flow
Thanks
Please define in detail what is linear non linear and why we convert into linear value... difference between square root linear and linear value...
Hello Khan
Thanks for asking this question. Please watch following video to get ur answer.
ua-cam.com/video/3NSL_2CYAh4/v-deo.html
Hi sir! Could you please make a video on dp type ft calibration
Hi Shabab
I have already made video on Dp Type FM Calibration.
ua-cam.com/video/nDGVIH_sMDA/v-deo.html
Flow is directly proportional to differential pressure but what about constant of proportionality which is considered based c and beta etc, is it mean all these factors are also incorporated in the transmitter
Simple q is approximately equal to dp what if exact flow is to be inquired secondly what other factors needs to be considered as well
dear sir
please the calibration range 0-- 500 m bar for differentiation transmitter
how to calculate square root the out 4 to 20 mA
flow rat 21 bopod as max
pipeline 8"
why square root extractor is not used in level and temperature measurement?
Square root extractor is only used when we measure flow by using differential pressure. Since flow is proportional to square root of differential pressure. All other variable such as temp, level does not have such relationship
@@InstrumentCalibration THANK YOU SIR YOUR VALUABLE ANSWER.
How we can convert square root % to linear %
Linear(%)= (x)^2*100
For example, if you want to convert 86.66% to linear %.
First Convert Percentage to normal number
86.66/100 =0.866
Linear(%)= (0.866)^2*100= 0.74.99*100
=74.99% =75%
Hope you understand.
Please feel free to ask me your question in comment box.
Dear Sir
I am having Siemens DP transmitter, I want to calibration flow with respect to pressure, and why we take square root for flow calculation WRT pressure transmitter pls explain sir.
It is because flow rate is directly proportional to square root of differential pressure. And in order to convert this differential pressure to linear, we take square root in DP Transmitter. Please feel free to ask me, if you have any further queries.
@@InstrumentCalibration Thank you sir👍. Do you have any WhatsApp group or blog?
@@samuelsolomon2028 At Present, we do not have any. But we will let yo know when we will make it in future.
In linear percentage to square root percentage conversion formula why we multiply with 10 . What is the reason behind it. Plz and me one person asked me in an interview.
Hello Ajay
Thanks for asking this question. Linear Value is in percentage. And we need to convert this percentage value into normal Value. This is reason we are multiplying with 10.
For Example.=50% This is a percentage value.
There is also other way. You can also divide 50 by 100 then take square root.
50/100 = 0.5
Square Root of 0.5 is 0.707
If you convert this value into percentage.
0.707*100=70.7 %.
I hope you get your answer.
@@InstrumentCalibration thanks for information. your explanation very well.
Can I ask questions in different topics also? Like thermocouple or radar level tx.
Dear Sir,
I wanna ask some questions
1. Linear Output is signal from transmitters delta P. converting 4-20mA?
2. Flow rate is proportional to squareroot delta P.
So linear output needs to be converted to squareroot output?
1. Yes, But you need to select square root function from transmitter to convert into linear mA.
2. In order to cancel square root, you have to select square root function at transmitter side or at PLC or DCS side.
Hope you will get your answer
Please dont show subtitles it disturbing the screen
Ok...we will do it.
@@InstrumentCalibration Thank you
Ok sure..we will make changes
Remove the caption not able to see properly
Thank you for feedback. I will make sure to remove caption in next videos