Professor I would like you give me a feedback about the following "euristic" line of reasoning about the cause of the voltage drop across a resistor. From the microscopic version of Ohm's law (J=oE ) , keeping the resistance's value the same , if current through a resistor increases then a stronger E field is required in order to accelerate the electrons through the resistor (by increasing their drift speed). But since the E field is the negative gradient of the potential then a greater magnitude of E field inside the resistor means an "high slope of the hill" (using your lecture's analogy) resulting in an higher difference in terms of height (potential difference and so voltage) between the resistor's endpoints . Therefore the cause of the voltage drop across a resistor is the needing of a stronger E field to accelerate the electrons through the resistor.
In a rc circuit or simple resistance circuit when we closed key ( time t=0 ) we observes that initial current is V/R. But in RI (resistance-inductance) circuit when we switch on of circuit we see that there is zero current initially in wire. Why? If possible make a short solution video to answer my question with detailed analysis.
Thank you for caring so much about teaching!
Professor I would like you give me a feedback about the following "euristic" line of reasoning about the cause of the voltage drop across a resistor.
From the microscopic version of Ohm's law (J=oE ) , keeping the resistance's value the same , if current through a resistor increases then a stronger E field is required in order to accelerate the electrons through the resistor (by increasing their drift speed). But since the E field is the negative gradient of the potential then a greater magnitude of E field inside the resistor means an "high slope of the hill" (using your lecture's analogy) resulting in an higher difference in terms of height (potential difference and so voltage) between the resistor's endpoints . Therefore the cause of the voltage drop across a resistor is the needing of a stronger E field to accelerate the electrons through the resistor.
THANKS .
In a rc circuit or simple resistance circuit when we closed key ( time t=0 ) we observes that initial current is V/R. But in RI (resistance-inductance) circuit when we switch on of circuit we see that there is zero current initially in wire. Why?
If possible make a short solution video to answer my question with detailed analysis.
Is that blue ink in the palm of your left hand?
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Probably. If I write notes on my hand, I can't lose the note. Or at least if I do lose the note, whatever the note said is no longer important.