attempting this before the video starts 8^log(x) - 2^log(x) = 5! 5! is trivially 120. 8^log(x) - 2^log(x) = 120 (2^3)^log(x) - 2^log(x) = 120 (2^log(x))^3 - 2^log(x) = 120 let u = 2^log(x) u^3 - u = 120 u(u^2 - 1) = 120 (u-1)u(u+1) = 120 after factorizing 120 and using the simple process of using your eyes, we get 4 * 5 * 6 = 120. therefore u = 5 2^log(x) = 5 log(x) = log_2(5) x = 10^log_2(5) approx. 209.85924
attempting this before the video starts
8^log(x) - 2^log(x) = 5!
5! is trivially 120.
8^log(x) - 2^log(x) = 120
(2^3)^log(x) - 2^log(x) = 120
(2^log(x))^3 - 2^log(x) = 120
let u = 2^log(x)
u^3 - u = 120
u(u^2 - 1) = 120
(u-1)u(u+1) = 120
after factorizing 120 and using the simple process of using your eyes, we get 4 * 5 * 6 = 120.
therefore u = 5
2^log(x) = 5
log(x) = log_2(5)
x = 10^log_2(5) approx. 209.85924
=>(2^log×)^3-2^log×
=120=5^3-5
=>2^logx=5
&logx=log@2 (5)
=>×=10^log@2(5)