Dynamics: Derivation of Polar Velocity & Acceleration Equations
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- Опубліковано 25 лют 2020
- Here, we go through the proof of how to derive the Velocity and Acceleration components of an object that is being tracked using an r (radius) and theta (angle) coordinate system
On of the clearer explanations on YouTUbe
thank you very much!
bruh this derivation was insane, nice video
thanks!
what a greeat video ....thanks alot
If velocity is always tangential, what will be the direction of acceleration in this example? How do we determine its direction in general?
You make an excellent point. The direction of acceleration cannot simply be determined like velocity can. To determine the direction of acceleration, you have to know the values of the two components of acceleration (radial component and transverse component). The using the resulting right triangle (with the two components as the legs and the total acceleration as the hypotenuse), an angle for the acceleration can be determined...
I hope this makes sense! Ask more questions if you have them!
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at 10:16 I couldn't understand how it is perpendicular because magnitude of r_i and r_f are equal and 1, so isn't that angle being 90 degrees geometrically impossible?
I think i get where you're coming from. The answer is that the very small angle in between r_f and r_i is soooo small (much smaller than the unit vectors of 1) that the dr is coming out perpendicularly from the r_i
It'll help if you draw this one out yourself.
Take an entire sheet of paper and do the vector addition: r_i + dr = r_f
Make sure you draw r_i and r_f to be very big (relative to the very small angle d_theta). I think you'll see the 90 degree angle. Let me know how it goes
Incrível!!
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@@eng1048 Your voice is actually quite low. Even at max volume.
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