Dynamics 02_14 Polar Coordinate Problem with solutions in Kinematics of Particles
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- Опубліковано 5 вер 2024
- solution for The piston of the hydraulic cylinder gives pin A a
constant velocity v= 3 ft/sec in the direction
shown for an interval of its motion. For the instant
when 30 , determine , , , and where r = OA
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Why are we using values for acceleration? Acceleration doesn't move on a curve in this question so how can there be acceleration when velocity is constant? I think the correct way is to set the acceleration which is zero to its polar coord expression and solve each component equal to zero for r dot dot and theta dot dot.
Thanks Buddy appreciated
Thanks buddy
Sir can u explain atheta = atangential?
how does the normal acceleration has positive value in 9:03
I believe the acceleration in the radial direction is: ar = r' ' - r * theta ' not ar = r' ' + r * theta ' . At least, this is what I've learned from class. Please let me know why you did a sign change.
Yes, you are correct. It is corrected on the video after clip ⏲15:02 (minutes of video).
Thank you for your comment.
.577*4.5^2-11.7 = 0
Which means r^.. = 0. Thank you so much for helping with everything else
Yeah I thought I was going crazy...
Hi,
From Which book you have taken this problem?
Meriam
Thanx man
You are welcome!