Teachers like Nitin Sir play a crucial role in shaping our understanding of complex subjects like Permutation and Combinatorics , This is best lecture ever i have seen on P & C
Babut accha Sanajh aa Gaya Sirji kindly cover whole P&C in details Maine ek coaching join kar Rakhi hai NIMCET ke liye bohot famous hai but Vo teacher Bilkul bhi ache se samjha nahi pate hai aapke videos hi dekh dekh kar Maths seekh rahe hai so please sir continue this series till our exams 🙏
Sir bahot hi badhya samjh aa gay Bohot dino se Permutation and probability me struggle kar rahe the ab lag raha hai ho jayeha ye dono topics acche se Aap nitin sir bohot accha padate hai kaash main aapse pad sakta coaching me 😢
Nhi 999 hi hoga Mai bhi pehle yahi soch rha tha ek ring m ek correct hoga but Aisa krke fayda nhi successful lock open hone k liye ek hi bar possible h jab teeno ring m correct aa jaye aur waisa sirf ek bar hoga Tum successful lock open wala check kro 1*1*1=1 hoga Agar unsuccessful 9*9*9=729 hoga to fir to total -729= successful ka possibility 1 se jada hoga jo wrong h
In the question no 20, repetition of 5 is not allowed, but it doesn't say anything about repetition allowed or not about other digits, so shouldn't the answer be 225?
Nitin Sir respect button 🔘
Thanks Shivam 😊
@@INPSCLASSES You are really creating great content for every math lovers.👏👏
Teachers like Nitin Sir play a crucial role in shaping our understanding of complex subjects like Permutation and Combinatorics , This is best lecture ever i have seen on P & C
Thank you Vishal
Best Video on Permutation Thank you sir removed all the basic doubts of multiplication.
Most welcome
In question 4 38:53 it is asking 3 different digits how can you apply repetition property
same doubt
in question 20 to
He said that answer totally wrong, It will be 26*25*10*9*8
Sir aapne 38:00 min me jo question karaya he wo glt he kuki usme different no. Bola gaya he toh usme
Hum 26×25×10×9×8 = 468000 karenge
You are absolutely right
Yes
I was thinking the same too
Essa hi hoga right???
@@samardeepsworld920 yes
lovely teaching
Glad you think so!
Iss lecture ki bhut jyada need thi sir thank you so much ❤
Keep watching
Sir 2 different letters and 3 different digits bola gya hai ques me in 39:00 . pls reply and solve my doubt.
Hmm sir ne glt kara he .. usme hum 26×25×10×9×8 karenge.. kuki usme different bola he
Thank you so much for your hardwork! ❤
You're so welcome!
Babut accha Sanajh aa Gaya Sirji kindly cover whole P&C in details
Maine ek coaching join kar Rakhi hai NIMCET ke liye bohot famous hai but Vo teacher Bilkul bhi ache se samjha nahi pate hai aapke videos hi dekh dekh kar Maths seekh rahe hai so please sir continue this series till our exams 🙏
really me ?
Thank you
Great lecture ❤
Glad you think so!
Sir bahot hi badhya samjh aa gay
Bohot dino se Permutation and probability me struggle kar rahe the ab lag raha hai ho jayeha ye dono topics acche se
Aap nitin sir bohot accha padate hai kaash main aapse pad sakta coaching me 😢
Thank you Animesh
Sir Probability start kar dije vo jada important hai
After P& C
kya ye playlist P&C ki enough hogi cuet or nimcet 2025 k liye?? please sir reply...
Yes
Sir aap aise hi saare chapters ko cover kar dijiye please sir
Noted
Full Video is based on the main concept🙌❤
1:23:33 for every letter there's 10 choices, and only 1 choice is right and other 9 choices are wrong, so ans should be 9*9*9, not 999??
Nhi 999 hi hoga Mai bhi pehle yahi soch rha tha ek ring m ek correct hoga but Aisa krke fayda nhi successful lock open hone k liye ek hi bar possible h jab teeno ring m correct aa jaye aur waisa sirf ek bar hoga
Tum successful lock open wala check kro 1*1*1=1 hoga
Agar unsuccessful 9*9*9=729 hoga to fir to total -729= successful ka possibility 1 se jada hoga jo wrong h
in q4 they asked for different digits that mean number should not repeat na?
Yes you are right
Sir nimcet ke based maths ko le kar sare acche se upload kar dijiye and calculus bhi basic se le kr 🙏🏻
Noted
Sir app NIMCET point off view se pdao ge naa iss chapter ko.. ?
Yes ☑️
In the question no 20, repetition of 5 is not allowed, but it doesn't say anything about repetition allowed or not about other digits, so shouldn't the answer be 225?
Yeah, Repetition of other numbers should be allowed.
Eske baad binomial theorem fir probability start kar dijiye
Sure
1:23:40
Is it the portion in cuet mca permutation and combinations
Yes
Sir question number 4is wrong
4th questions answer is wrong sir...answer is 26*25*10*9*8 ways as the things should not be repeated.
Sir can i get decent marks in MAH MCA CET by studying one and half month?😢
@khushi_prabhudessai are you sure ?