Fixed End Moments

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  • Опубліковано 15 гру 2024

КОМЕНТАРІ • 89

  • @pkr786ind
    @pkr786ind 11 місяців тому

    For the case where you apply fixed end moments, where you’ve shown a rectangular moment diagram, the deflected shape is incorrect since it has positive and negative curvature whereas the moment will result in only a single constant negative curvature. Furthermore, the end conditions, shown as fixed, are incorrect as there is no way you can get a deflected shape with them present, for the applied end moments, since those moments will go into the supports, not into the beam.

  • @vtriveni5765
    @vtriveni5765 5 років тому +4

    Superb...u spoke how that formula came . Thanks a lot sir.every one is dictating the formula but not explaining but u didn't do that.plz continue ur videos like this

  • @Goodvibes4me
    @Goodvibes4me 2 роки тому

    Now I can become fully fledged engineer

  • @FranCoVids
    @FranCoVids 6 років тому +1

    So, what would be the FEM equations if you had two unequal concentrated loads and are spaced equally apart?

    • @CivilEnggLectures
      @CivilEnggLectures  6 років тому

      It could be done by taking each load separately for calculation of Fem and then adding both

  • @KazeTdr
    @KazeTdr 2 роки тому

    Sir what's this method of equating the 2 areas for calculating moment is called?

    • @CivilEnggLectures
      @CivilEnggLectures  2 роки тому

      Actually I used the concept of Equilibrium... Load equals to response..

  • @rishabhpasi98
    @rishabhpasi98 6 років тому +1

    sir one basic ques...how these fixed end moments are developed??

    • @CivilEnggLectures
      @CivilEnggLectures  6 років тому +1

      Cos when member is loaded joints are required to rotates.. if joint is fixed it does not allow any rotation by developing resisting moment.. this is how it is developed

  • @gowthamiv4841
    @gowthamiv4841 4 роки тому

    Worth watching.. great ahead.. expecting more to watch...

  • @sushantpathak2986
    @sushantpathak2986 7 років тому +4

    Brother your videos are really very helpful and very easy to understand..... Plz continue....

  • @therose4872
    @therose4872 5 років тому +1

    Sir What if the force was parellal to the member ? What is the formula of fixed end moment

    • @CivilEnggLectures
      @CivilEnggLectures  5 років тому

      No fixed end moment is developed for parallel forces..

  • @msrinivasakannan
    @msrinivasakannan 4 роки тому +1

    In this method we are unable to solve
    1. Uvl triangular load
    2. Max at center triangular load
    Pls assist

  • @utsav8530
    @utsav8530 7 років тому +4

    please menage videos in playlist which wil be helpful to find videos

  • @huffaz_group
    @huffaz_group 4 роки тому

    Can you do a detailed example of kanis method?

  • @mohammadanasbeg5000
    @mohammadanasbeg5000 3 роки тому

    اسلام علیکم
    Sir please drive one more case for eccentric point load

  • @abdelsattar6007
    @abdelsattar6007 4 роки тому

    How to calculate the FEM in case of temperature variation or settlement?!

  • @TreatSpin
    @TreatSpin 6 років тому +1

    I don't understand. If there is no sagging or hoggging, there will be no deflection. In this beam there will be definitely be a deflection, so I do not see why you equate the two areas

    • @CivilEnggLectures
      @CivilEnggLectures  6 років тому

      Sagging and hogging is there..
      More or less it is equal..
      Sagging will be more at midspan and hogging will be more at end of beam or at rigid joints..

    • @mahesh4943
      @mahesh4943 3 роки тому

      @@CivilEnggLectures but sir sagging and hogging are not exactly equal then why u equate both areas?

  • @debanjanpaul767
    @debanjanpaul767 6 років тому

    you are great ... very nice video ... keep it up and make other video ...

  • @raisuddinbiswas2614
    @raisuddinbiswas2614 4 роки тому

    How i contact you plz help i have some questions problem

  • @deepanjanpal6014
    @deepanjanpal6014 5 років тому +1

    Thanks bro, it cleared all my doubts

  • @rojab861
    @rojab861 2 роки тому

    Nice explanation

  • @arunndinesh
    @arunndinesh 7 років тому

    sir, is there any standard formulae for fixed end moments of a beam with trapezoidal loading?

    • @CivilEnggLectures
      @CivilEnggLectures  7 років тому

      Arun dinesh yeah

    • @arunndinesh
      @arunndinesh 7 років тому

      Please give me the link or formulae description..

    • @CivilEnggLectures
      @CivilEnggLectures  7 років тому

      Already you know it... trapezium can be converted into two figure.. rectangular and triangular.. rectangular means udl and triangular means uvl.. you need to add udl and uvl

    • @arunndinesh
      @arunndinesh 7 років тому

      Sir, I am looking for trapezoidal load distribution from a 2 way slab,not the typical trapezium one you're saying. So I'm not getting formulae. Please help me with your idea.

    • @CivilEnggLectures
      @CivilEnggLectures  7 років тому

      +Firoz Nadaf what you are asking is not trapezium loading...
      Its a load distribution on beam in case of two way slab.. which is nothing but udl

  • @shahzadali4801
    @shahzadali4801 4 роки тому

    Nice explanation 👍

  • @febinlalu5543
    @febinlalu5543 6 років тому

    sir how we calculate fixed end moment when both udl and point load acting on same beam

    • @CivilEnggLectures
      @CivilEnggLectures  6 років тому +1

      Febin Lalu calculate fixed end moment separetly for loadings and add it...

    • @hemrajkharka1467
      @hemrajkharka1467 2 роки тому

      Principle of superposition

  • @rm3108
    @rm3108 5 років тому

    I want solution for the trapezoidal load condition.can you please help me with the proof of the formula (-wl^2)/30?

    • @CivilEnggLectures
      @CivilEnggLectures  5 років тому +1

      you can do it by using force or displacment Method.. Try it.. if not let me know.. but first try by yourself

    • @msrinivasakannan
      @msrinivasakannan 4 роки тому

      @@CivilEnggLectures pls explain... unable to do

    • @CivilEnggLectures
      @CivilEnggLectures  4 роки тому

      What's the condition of load

    • @CivilEnggLectures
      @CivilEnggLectures  4 роки тому

      @@msrinivasakannan what's the condition of load?

    • @msrinivasakannan
      @msrinivasakannan 4 роки тому

      1. Uvl triangular - max load at any edge..
      2. Uvl triangular - max load at center
      3. Uvl trapezoidal laod
      All cases for fixed beams

  • @udaysampath009
    @udaysampath009 6 років тому +1

    Thank you

  • @ruhiprawin1159
    @ruhiprawin1159 4 роки тому

    Very nice 👌 sir

  • @sanjeevreddy1756
    @sanjeevreddy1756 6 років тому

    Thq

  • @xhsldnjd
    @xhsldnjd 2 роки тому

    so useful sir

  • @aamirdurrany
    @aamirdurrany 6 років тому

    Very well explained. Where are you from btw?

  • @Goodvibes4me
    @Goodvibes4me 2 роки тому

    Gud explaination

  • @kirankumar4863
    @kirankumar4863 4 роки тому

    But Mfab and Mfba are in opposite direction why the sign is not changing

  • @voiceofemaan3125
    @voiceofemaan3125 7 років тому +1

    PLEASE MAKE VIDEO ON MDM FAME

  • @minminmibang7617
    @minminmibang7617 7 років тому +1

    Nice video very informative

  • @ashokgupta-wv5cn
    @ashokgupta-wv5cn 6 років тому

    Sir plse resolve eccentric loading of fixed beam by area moment method..

  • @arizkhan2183
    @arizkhan2183 7 років тому

    great work sir ......doing a great job 😊

  • @rigelsirius
    @rigelsirius 4 роки тому

    Thank you!

  • @rupeshmpradhan3871
    @rupeshmpradhan3871 6 років тому

    Excellent sir

  • @tusharkashyap8688
    @tusharkashyap8688 5 років тому

    Thanks dude! u explained really well!

  • @ashfaqt1605
    @ashfaqt1605 6 років тому

    Partial UDL ke liye bhi batao

  • @nirajmaharjan7160
    @nirajmaharjan7160 6 років тому

    Very well explained

  • @utsav8530
    @utsav8530 7 років тому +1

    and yes your videos are awesome

  • @yusraal-sabahi5309
    @yusraal-sabahi5309 5 років тому

    Thanks

  • @prasadb4842
    @prasadb4842 7 років тому +1

    great bro. well done. Hugely help full... keep going...

  • @sanjeevsinghyadav9462
    @sanjeevsinghyadav9462 4 роки тому

    For UG physics
    ua-cam.com/users/institutembw

  • @hcStructuralDesigns
    @hcStructuralDesigns 6 років тому

    sir upload more problems

  • @princedhinakarrekala9962
    @princedhinakarrekala9962 6 років тому

    super sir

  • @abhijitp
    @abhijitp 6 років тому

    Thanks man

  • @Deepak-sl9fg
    @Deepak-sl9fg 5 років тому +7

    How come wl/8

  • @vibhore9624
    @vibhore9624 5 років тому

    Left support has anti clockwise moment and right support has clockwise moment....
    Why you consider both moments negative...
    Not LHS moment negative and RHS moment positive...

    • @CivilEnggLectures
      @CivilEnggLectures  5 років тому

      Positive and negative sign does not merely depends on signs but on sagging and hogging..
      Sagging positive and hogging negative..

  • @jeetmondal6451
    @jeetmondal6451 5 років тому

    not a good vedio i cant understand for which i open it