in order to calculate this, we must first understand the thickness of a sheet of paper (around 0.1 mm) then we can use the simple formula of doubling: x(2^n) x will represent the thickness, n is the number of instances we will double. now we can calculate: 0.01(2^42) = 439,804,651,110.4 mm divide by a factor of 1,000,000 (1,000,000 mm= 1km) we will achieve the number 439,804.6511104 km the moon is only 384,400 km away from the earth, so 42 folds will infact reach the moon, and beyond. hopefully this cleared any confusion.
Hi Peter, many thnaks for this video tutorial. It really helped me alot. May I kindly request you provide me with the reference of the equation you used to calculate the doubling time? I would want to include it in my thesis. Thanks once again.
The Ln is essentially the opposite of the e exponential. So if we used the Ln to cancel the e and bring its powers down, when we finish the calculation we should also put Ln(101.5) into a calculator for 4.62 (a more precise answer.) I also think Peter kindly left the Ln in that form until 5:30 so that we could see the components of this equation :)
Awesome! Finally I get it. Thank you!!!
Thank you, it has been the best video and I know that is with the formula of Monod how my professor wants
Excellent explanation , one of best learning videos I ever have seen.
in order to calculate this, we must first understand the thickness of a sheet of paper (around 0.1 mm)
then we can use the simple formula of doubling: x(2^n)
x will represent the thickness, n is the number of instances we will double.
now we can calculate:
0.01(2^42)
=
439,804,651,110.4 mm
divide by a factor of 1,000,000 (1,000,000 mm= 1km)
we will achieve the number 439,804.6511104 km
the moon is only 384,400 km away from the earth, so 42 folds will infact reach the moon, and beyond.
hopefully this cleared any confusion.
thank you very much, it very helpful me.
very well explained. Many thanks!
Thank you!!!!
thank you, it was so useful for me :)
Hi Peter, many thnaks for this video tutorial. It really helped me alot. May I kindly request you provide me with the reference of the equation you used to calculate the doubling time? I would want to include it in my thesis. Thanks once again.
Thank you so much for this wonderful explanation
Thank you doctor ❤️
great, we get good highlight
can I use the same method if im given an optical density instead of cell count
Naomi Jenkins yes, you can - no problem.
I got lost at the 0.693.I have a similiar problem I can’t solve with minutes instead of hours
How can one measure the number of cells?
How did u get ln?
How did you get 4.62 at 5.33???
The Ln is essentially the opposite of the e exponential. So if we used the Ln to cancel the e and bring its powers down, when we finish the calculation we should also put Ln(101.5) into a calculator for 4.62 (a more precise answer.) I also think Peter kindly left the Ln in that form until 5:30 so that we could see the components of this equation :)
Could we use the same equation with OD values?
Yes, you can.
@@pk11kent thank you!