How to calculate exponential growth of bacteria
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- Опубліковано 7 гру 2017
- Biological exponential growth is the exponential growth of biological organisms. When the resources availability is unlimited in the habitat, the population of an organism living in the habitat grows in an exponential or geometric fashion. ... In other words, the population is experiencing exponential growth.
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My Prof didn't bother showing us an example, it's a shame because it only took you 3 minutes to explain. Thank you!
Thank you so much I finally understand it.
simplest thus far...thank you
Thank you, I learned the calculation by watching this one time. I'm subscribing! I have a test tomorrow and did not know how do to this!!!! Thank you...
Best of luck!
This was extremely helpful!! Thank you so much
Glad it was helpful!
You're a legend. Thanks!
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I have a word problem for my micro class and I used the formula, but the answer seems so wrong. Here’s the question: suppose meat is contaminated with S. aureus and that the initial population is 150. The generation time is 15 minutes at a room temperature of 82 degrees Fahrenheit. What is the final population of bacteria if growth is allowed for 10 hours? My answer was 164,926,744,166,400
Your answer is correct. 1.65x10^14
Thank you so much!
You're welcome!
Love your teaching method
Thank you!
Beautiful explanation
Thanks for liking
thank you for sharing, this video helped me
You're welcome!
Thank you so much sir for amazing explanation 😊😊
Most welcome 😊
Keep it up Mashallah
I will try my best
Thank you
You're welcome
in my calculation, 3 divided by 30 is 0.1. I didn't get 6. please help me understand that part
I think he converted the hours into minutes and then divided it by 30 mins. So, 1 hour = 60 mins and in the word problem it stated for 3 hours. You multiply 60 mins * 3 hrs = 180 minutes then you take the 180 and divide it by 30 minutes and you should get 6. The whole point of that was just to get it in the same units (minutes). :)
I went 3/ 0.5 as half of 1 is 0.5 ( half of 1 hour is 30mins) and i got the same answer
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Sir can you please answer this question e coli has a cylindrical shape about 1um diameter and 3 um long. the doubling time of e coli when grown on nutrient agar is about 25 minutes. after 12 hours of growth a colony is roughly 2 mm in diameter and 1/2 mm high. how many cells does the colony contain
1) 10^5 cells
2) 10^7 cells
3) 10^9 cells
4)10^11 cells
This is geometry problem, you have to find how many small cylinders will fit into the large one.
okay thank you sir........
Volume of the colony in um 3,14x1000^2x500=1.5708x10^9
Volume of the bacteria in um 3,14x0,5^2 x3=2.35619
number of bacteria 1570800000/2.35619=666669496.1 which is 6.7x10^8
I just took pure math - but in real Iife bacteria need some live space, so hard to say what kind of answer your professor is looking for.
Thank a lot sir for your answer. the question is not from my professor. i got it from one of the question papers........
Sir, need your help. QUestion 1-15
apply the principle of exponential growth of a culture as
described in Question 1-13 to the cells in a multicellular
organism, such as yourself. there are about 1013 cells
in your body. assume that one cell acquires a mutation
that allows it to divide in an uncontrolled manner (i.e., it
becomes a cancer cell). some cancer cells can proliferate
with a generation time of about 24 hours. if none of the
cancer cells died, how long would it take before 1013 cells in
your body would be cancer cells? (Use the equation
N = N0 × 2t/G, with t, the time, and G, the length of each
generation. hint: 1013 ≈ 243.)
These questions are too long to use them for a video. And the formula is wrong.
@@GeneticsLessons Sir , if possible on a sheet of paper with proper explation in writing will suffice. Regaed.
@@sukadeva108 Here is the correct formula N= N0 x 2^(t/g)
Thank you sir, i have got it finally.
Welcome 👍
👍
"with common sense and logic". haha, that was amazing. thank you
Glad it helped!
i forgot this method
But how you know know n=2?
2 means doubling.
@@GeneticsLessons sry n=6?
QUestion 1-13
natural selection is such a powerful force in evolution
because cells with even a small proliferation advantage
quickly outgrow their competitors. to illustrate this process,
consider a cell culture that contains 1 million bacterial cells
that double every 20 minutes. a single cell in this culture
acquires a mutation that allows it to divide faster, with a
generation time of only 15 minutes. assuming that there is
an unlimited food supply and no cell death, how long would
it take before the progeny of the mutated cell became
predominant in the culture? (Before you go through the
calculation, make a guess: do you think it would take about
a day, a week, a month, or a year?) how many cells of either
type are present in the culture at this time? (the number of
cells N in the culture at time t is described by the equation
N = N0 × 2t/G, where N0 is the number of cells at zero time
and G is the generation time.)
This formula is wrong - here is the correct formula N= N0 x 2^(t/g)
Ok, use this problem and solution as a guide (Problem is a similar but numbers are different - just put your numbers instead)
Natural selection is such a powerful force in evolution because cells with even a small growth advantage quickly outgrow their competitors. To illustrate this process, consider a bacterial culture that contains 10^6 (1,000,000) cells that double every 32 min. One cell acquires a mutation that enable it and its progeny to divide with a generation time of only 27 min. Assuming there is nothing to limit the growth of the culture (e.g. unlimited food supply) and no cell death, how long should it take for the mutant cells to overtake the culture? Give your answers in hours (hr) rounded to the first decimal place. The number of cells N in the culture at time t is given by where N0 is the number of cells at time zero and G is the generation time. (Eqn: N= N0 x 2^(t/g)
OK, so what you have to do is to figure out the population of each type as a function of time.
For the wild-type, it's
10^6 * 2^(t/32)
and for the mutant it's
1 * 2^(t/27)
Now just set these equal to each other and solve for t. So:
10^6 * 2^(t/32) = 1 * 2^(t/27)
or 10^6 = 2^(5t/(32*27))
if we take the log2 of both sides we get:
log2(10^6) = log2(2^(5t/(32*27)) or
19.93156857 = 5t/(32*27)
17220.87524 = 5t or
t = 3444.175049 minutes
@@GeneticsLessons Great, Sir, Atleast I've got the right answer for the exponential growth rate in time t as in your video. I am calculating two different set for the same Q,- 13 : a. 999,999 bacterias in 60/20 t ( 3 G per hour), and the b. is 1 bacteria ln 60/15 t ( 4 G per hour). My difficulty is the 1 mutant bacteria out numbers the rest in t time ?
Please follow the solution step by step.
@@GeneticsLessons 57.402917 / hour Right sir?
i am here coz i am coding some shiet XD, ty for the vid really helpful
Glad it helped!
Земляка уж узнаю