3D Trigonometry and Pythagoras - GCSE Higher Maths
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- Опубліковано 2 чер 2024
- A video explaining how to solve problems using trigonometry and pythagoras in 3D. This is suitable for the GCSE higher maths course.
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Topic requested by @dzung1969
0:00 Introduction
1:08 Exploring right angled triangles
2:24 Example 1
3:18 Example 2
4:08 Example 3
5:35 Example 4
8:03 Example 5
12:12 Example 6
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Another life saver by 1st Class Maths!
I think we all can't thank you enough.
You’re my favourite maths teacher by far! It’s just a shame your videos don’t cover the whole syllabus
Thanks that is very kind! I am working on it but it takes me about 10 hours per video. I do a lot of research and analysis of past papers to write the questions and the animating, recording and editing takes a while too. Hopefully one day I will have everything covered.
@@1stClassMaths Wow thats a lot, I really appreciate the time and effort you put into these videos. I dont know where I would be without your channel. Thanks so much.
@@1stClassMaths god bless you
@@1stClassMaths great guy
nailed it, I can bet you once he has completed the syllabus he will be beyond Maths Genie
Thankyou stay blessed
it's always the wordings that catches me off, I know how to calculate the angle EGH (for example), but if the question were to ask me to calculate the angle between EF and the base ABCD, I wouldn't know what to do. Could you make a video on that please? 👍Thanks!
I would say drawing out/shading the bases and lines your talking about would help you visualise it. Just connect the letters they say. You got this
Thank you so much . These videos are a life saver
Glad you like them!
What if in example 3, we were instead asked to find the length of the angle GC, how do you do that? please reply quick
How would we know which triangles we draw on are right angled or not
Thank you sir 👍
Welcome!
I like that you mentioned to wait until the end to round. I've seen a number of other math channels not adhere to that idea. It always bugs me, as I always try to keep amounts as exact as possible until the end (inverse trig functions are particularly annoying in these cases, as there often are no "exact" amounts other than the trig expression itself), so my solutions come out slightly different. This can make it more difficult to verify I got the right answer, especially if I came about it via a different method than the instructor...
Yes that is premature rounding and they shouldn't be doing that!
can you do area and capacity problem solving please
Thankyou so much this saved me the night before my test 😅
You're welcome 😊Hope the test went ok.
I think you can help me. This is the challenge. A 20f container needs to be lifted from the bottom and the angle at the top must be at 90 angle betwee diagonal chains. What is the length of the chains. Container dimensions. L 6.06m H 2.59m W 2.44m
what’s f in 20f, I can help
very clear thank you
Welcome 😊
U require more recognition all the people u could help imma definitely get a 6-7 thx to u! U earned by sub
Very kind of you
@@1stClassMaths :)
Absolutely. Couldn't agree more.
IB Student?
Can we use formula d^2 = a^2 + b^2 + c^2 for 3D pythagoras? Does the mark scheme allow it for edxcel GCSE? Do we still get full marks for correct answer?
Yes
Thank you for such a quick reply.
I've just found your channel and love it.
If you didn’t use the full value of EA on Q5 for the last part would you loose the mark
Possibly. Sometimes exam boards give a random of answers to it might need to be between 2 set values. The best, most accurate and safest thing you can do though is not round until the end.
if you were given the base length in example 6, lets say for example it was 10cm. could you draw a line from M to the midpoint of CD and use pythagoras to find your perpendicular height using 15 as the slant height and 5 as your base height since M to the midpoint of CD would be half your base height which would be 5?
I am afraid that would not work. The length from E to your new point at the middle of CD would not be 15. Look at the triangle EDC and you can see that your line goes right down the middle splitting it into two right-angled triangles. This means the hypotenuse is 15 but your line would be the height and not the same length. Hope that makes some sense!
Basically it isn't 15 all the way around the pyramid.
@@1stClassMaths thank you for explaining makes sense now i thought it was 15 all the way around the pyramid
can u go through conditional probability?thank you
Working on this one.
hi sir, would we get the formula for the volume of the pyramid for 2024 gcse's
No I think you need to learn this one.
Please make predication paper 2
can you do mensuration please?
He's covering topics in Mensuration part 2.
Pls do calculus🥺
How are we supposed to know which triangles you draw on are right angled or not?
Like going through the shape it's not clear which if any angles are right angled
This is like cognito alternative
ye lol
Cognito improvement*
Tall as for the angle theorem 😮😮😮
5:42 and i got paper 2 at 9. im so cooked
Yes
Yes
Sir make videos on congruent triangle theorems