The Wallis product for pi, proved geometrically

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  • Опубліковано 19 кві 2018
  • A geometric proof of a famous Wallis product for pi.
    Help fund future projects: / 3blue1brown
    An equally valuable form of support is to simply share some of the videos.
    Special thanks to these supporters: 3b1b.co/wallis-thanks
    If you want to dive into the relevant ideas required to make this proof more rigorous, the relevant search term is "dominated convergence".
    en.wikipedia.org/wiki/Dominat...
    Here's a good blog post on the topic:
    www.math3ma.com/blog/dominate...
    In the video, I referenced our own blog post expanding on this argument. Unfortunately, it managed to get lost during a website transition.
    Another approach to this product by Johan Wästlund:
    www.math.chalmers.se/~wastlund...
    With more from Donald Knuth building off this idea:
    apetresc.wordpress.com/2010/1...
    Music by Vincent Rubinetti:
    vincerubinetti.bandcamp.com/a...
    ------------------
    3blue1brown is a channel about animating math, in all senses of the word animate. And you know the drill with UA-cam, if you want to stay posted on new videos, subscribe, and click the bell to receive notifications (if you're into that).
    If you are new to this channel and want to see more, a good place to start is this playlist: 3b1b.co/recommended
    Various social media stuffs:
    Website: www.3blue1brown.com
    Twitter: / 3blue1brown
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КОМЕНТАРІ • 1 тис.

  • @alexpotts6520
    @alexpotts6520 6 років тому +830

    There's always a moment in these videos where I suddenly realise "oh, I can see where this is heading now", and I immediately grasp how a bunch of mathematical ideas I thought had nothing to do with each other are actually working closely together.
    That moment never fails to bring a broad smile to my face.

    • @Hlkpf
      @Hlkpf 5 років тому +12

      suuuuuuuper nice :-)
      like meeting an old friend in an unexpected place

    • @henryg.8762
      @henryg.8762 5 років тому +1

      Yes.

    • @sharpnova2
      @sharpnova2 4 роки тому

      why did you say "broad"? wasn't that overly emotional?

    • @hybmnzz2658
      @hybmnzz2658 3 роки тому +1

      @@sharpnova2 no

    • @knotwilg3596
      @knotwilg3596 2 роки тому

      7:30 is that moment for me

  • @tonynixon9715
    @tonynixon9715 6 років тому +1081

    What's better than a 3Blue1Brown video?
    A 3Blue1Brown video with an original proof by the creators

    • @Moinsdeuxcat
      @Moinsdeuxcat 6 років тому +15

      tony nixon Have you ever heard of Mathologer? If not, you'll like what happens there, the guy does that all the time :)

    • @awawpogi3036
      @awawpogi3036 6 років тому +6

      Béranger Seguin i love mathologer long time ago but when i saw his video proving that numberphile is wrong, i was like mathologer sucks.

    • @user-el2pe5sh5v
      @user-el2pe5sh5v 6 років тому +21

      what is better than a 3blue1brown video? it is 2 3blue1brown videos

    • @tonynixon9715
      @tonynixon9715 6 років тому +2

      Béranger Seguin yes. I do watch mathologer videos. Very inspiring

    • @SpaghettiToaster
      @SpaghettiToaster 6 років тому +64

      So, you went from loving his videos to thinking he sucks when he *proved* that someone is wrong. Very reasonable.

  • @tesseraph
    @tesseraph 6 років тому +2046

    Novel mathematical proofs being presented on UA-cam is proof to me that we live in the future.

    • @jacksainthill8974
      @jacksainthill8974 6 років тому +43

      Well, you said that twelve hours ago so... Yes, now we do. ;)

    • @shreyassarangi6106
      @shreyassarangi6106 6 років тому +11

      Putting it that way certainly does make it clear how far we've come

    •  6 років тому +6

      We live beside the future.

    • @lethiac698
      @lethiac698 6 років тому +2

      seems to me that the more future, the harder it is to be novel. I think the novelty means we're still finishing up the. past

    • @chazmania3644
      @chazmania3644 6 років тому

      Seán O'Nilbud in, beside, underneath, above... the future is our climbing frame.

  • @3blue1brown
    @3blue1brown  6 років тому +651

    Even though the argument given here is new, the Wallis product has been known a long time, and there are other arguments for it than the one given here. For example, just as our previous video on 1 + ¼ + 1/9 + … was based on a paper by Johan Wästlund clearly showing the connection between that sum and circles, there is also a beautiful paper by Wästlund showing a connection between the Wallis product and circles via a different approach than we’ve taken here, which you may find interesting. Donald Knuth has also put out descriptions building off this work by Wästlund. You can check both of those out in the links below. And of course there’s Wallis’s original 17th century argument, based on analysis of certain integrals, though this can make the connection to circles hard to see directly.
    But, naturally, we’re fondest of the proof we ended up giving here, for its simplicity, for the directions in which it generalizes, and, hell, for the opportunity to re-use our lighthouse animations. And we hope you enjoyed it too.
    *Edit*: It looks like some people are asking about why the segment at 12:33 is okay, given that it feels like taking 0/0. Keep in mind, the actual goal at that spot is to find a polynomial whose roots are L_1, L_2, ... L_{N-1}, so the concrete result being stated is that (x - L_1)(x - L_2)...(x - L_{N-1}) will expand out to become 1+x+x^2+....x^{N-1}. No division by zero issues there. Sure, plugging in x=1 to (x^N - 1)/(x - 1) is undefined (at least before explicitly stating the intention to extend the function via a limit), but the reason for doing that polynomial division was just to see how (x - L_1)(x - L_2)...(x - L_{N-1}) would expand. All that division is asking is (x - 1)(...what?...) = (x^N - 1).
    Here, to give a really simple example, it's like saying x^2 - 1 has roots at 1 and -1, so dividing it by (x - 1) gives a polynomial with just a root at -1, namely (x^2 - 1) / (x - 1) = x + 1. "But wait!", someone could say, "you can't plug x = 1 into that fraction!". For sure for sure dude, but that doesn't change the fact that x + 1 is legitimately a polynomial which just has -1 as a root. Maybe you justify that division by saying something about limits, or about analytic continuation, or just by reframing to say what you care about is the question (x - 1)(...what?...) = x^2 - 1, but that's all kind of beside the point.
    Also, many of you are asking "Isn't the 'distance is proportional to angle' approximation only valid for lighthouses near the observers? What about all the lighthouses on the far end of the circle?". The key is that the product we are ultimately interested in is made up of the asymptotic contributions of each particular lighthouse (in the sense of, e.g., "The 53rd lighthouse after the keeper"), in the limit as N goes to infinity. Whatever particular lighthouse you are looking at, in that limit as N goes to infinity, it will be bunched right next to the observers, and so distances will be proportional to angles for computing its asymptotic contribution.
    As noted in the section on formalities, Dominated Convergence then rigorously assures us that it's ok to equate "The product of each particular lighthouse's asymptotic limit contribution" (which is the product we're interested in: the Wallis product, or sine product more generally) with "The asymptotic limit of the product of the contributions from each particular lighthouse" (which is the asymptotic limit of the products we have an easy time calculating: the distance-products our lemmas directly address). For more technical details on this use of Dominated Convergence, see the supplemental blogpost.
    Our supplemental blogpost:
    www.3blue1brown.com/sridhars-corner/2018/4/17/wallis-product-supplement-dominated-convergence
    Another cool way of approaching the Wallis product:
    www.math.chalmers.se/~wastlund/monthly.pdf
    apetresc.wordpress.com/2010/12/28/knuths-why-pi-talk-at-stanford-part-1/

    • @MrxstGrssmnstMttckstPhlNelThot
      @MrxstGrssmnstMttckstPhlNelThot 6 років тому +3

      3Blue1Brown why did you reupload?
      Amazing video both times I saw it.

    • @richardreynolds6304
      @richardreynolds6304 6 років тому +1

      ArpholomuleNutt He made a small mistake with the original.

    • @abrarshaikh2254
      @abrarshaikh2254 6 років тому +3

      3Blue1Brown
      sin(fX)/fX=product of {1-(X/N)^2)}
      But your result is different!!!

    • @MrxstGrssmnstMttckstPhlNelThot
      @MrxstGrssmnstMttckstPhlNelThot 6 років тому +1

      Richard Reynolds what was it?

    • @Moinsdeuxcat
      @Moinsdeuxcat 6 років тому +2

      Your result is true when you sum over positive integer. He sums over both positive and negative. You can find your result if you combine k and -k in the same factor.

  • @diabl2master
    @diabl2master 6 років тому +441

    You're a freaking math communication genius dude

  • @othmanesafsafi
    @othmanesafsafi 6 років тому +527

    A mathematical proof first shown on youtube by the best mathematical youtube channel ... What a time to be alive !!

  • @le_science4all
    @le_science4all 6 років тому +596

    Woooow!! Congrats for the beautiful proof! This is both extremely cool and hugely impressive!

    • @dappermink
      @dappermink 6 років тому +34

      S4A? You here? Ah, I see you're a man of culture as well :')

    • @3blue1brown
      @3blue1brown  6 років тому +75

      Thanks dude!

    • @baptistebauer99
      @baptistebauer99 6 років тому +1

      Oh hello there, comment ça va? xD

    • @ely_mine
      @ely_mine 6 років тому +2

      No one ever misses 3B1B videos x)

    • @christophem6373
      @christophem6373 6 років тому

      Hé Lê (@Science4All) tu as vu la dernière de Mathologer (ua-cam.com/video/yk6wbvNPZW0/v-deo.html ) elle aussi elle est pas mal même si visuellement elle n'atteint pas le niveau de 3Blue1Brown

  • @112BALAGE112
    @112BALAGE112 6 років тому +133

    The sheer quality of this content is quickly surpassing not only everything else but itself as well. When I thought 3b1b couldn't get any better it does twofold yet again.

    • @vivekthomas8
      @vivekthomas8 6 років тому +3

      112BALAGE112 Don't fucking jinx it!

  • @TNTPablo
    @TNTPablo 6 років тому +580

    TAU SPOTTED

    • @dcs_0
      @dcs_0 6 років тому +52

      YES! Finally. The Tauist revolution has begun!

    • @ganaraminukshuk0
      @ganaraminukshuk0 6 років тому +3

      I was wondering about the taus, by the way.

    • @elijahbuck6499
      @elijahbuck6499 6 років тому +6

      Tau! may i redirect any pi-ists to tauday.com ?

    • @Phroggster
      @Phroggster 6 років тому +29

      π is dead. Long live the vastly superior τ.

    • @raffimolero64
      @raffimolero64 6 років тому +4

      Euler used Pi like Theta.
      I personally believe Tau is simply the limit of pi.
      Limits are awesome.

  • @parzh
    @parzh 6 років тому +149

    I keep noticing, how many interesting ideas come out when you connect square-related and circle-related concepts!

    • @DrJules-gi5jo
      @DrJules-gi5jo 6 років тому +8

      I have had similar thoughts. It seems, as an observation on the large-scale structure of mathematics, that it is a number-line emphasis on the "line" and so much of "mathematical weirdness" comes from forcing a line to bend or a circle to be straight. These are different metrics and live in different worlds, they do not really want to talk to one another unless forced to. Lines really only want to be a grid!

    • @Molybdaenmornell
      @Molybdaenmornell 5 років тому +1

      The Poincaré conjecture is a case in point, I suppose.

    • @wrog7616
      @wrog7616 5 років тому +1

      if you think about it it really is squares... here is what I mean:
      2/1*2/3*4/3*4/5*...
      = 4/3 * 9/8 * 16/15 * 25/24 * 36/35 * 49/48 * 64/63 * ...

    • @pietervannes4476
      @pietervannes4476 4 роки тому +3

      @@wrog7616 isn't it 4/3 * 16/15 * 36/35 * 64/63 * ... ?

    • @wrog7616
      @wrog7616 4 роки тому +2

      @@pietervannes4476 Yeah. Thanks. lol

  • @joshuaflackua
    @joshuaflackua 6 років тому +22

    Your videos are the most creative representations of mathematic principals I’ve ever seen, it’s always such a joy sitting down to watch one of these. You’ve turned math back into the beautiful and elegant process that I lost touch with, please never stop doing what you do

  • @ZardoDhieldor
    @ZardoDhieldor 6 років тому +11

    Every time I watch one of your videos I feel the urge to tell you how awesome your channel is. This connection between the roots of unity and the product expansions of sine is something I didn't know yet, explained in such an intuitive gemetric way! Seriously. Thanks for doing all this!

  • @amankarunakaran6346
    @amankarunakaran6346 6 років тому +26

    Sridhar Ramesh! That guy's writing on Quora is pretty awesome, good to see he's joined the 3B1B team. Great proof, and I'm proud that I caught the technicalities myself; was going to write a comment about them, but as usual, you have addressed them yourself!

  • @unhealthytruthseeker
    @unhealthytruthseeker 6 років тому +3

    The Wallis product looks very musical to me. 2 is going up an octave, 2/3 is going down a perfect fifth, 4/3 up a fourth, and so on. I don't know if it's possible, but it would be interesting if there's some kind of proof from this direction. Basically, the Wallis product gives a series of musical intervals that converges to a "note" that is pi/2 above the starting note, which works out to about 782 cents, a rather flattened minor sixth.

  • @nandankulkarni2628
    @nandankulkarni2628 6 років тому +10

    I love the little introductions before each video. It's interesting to hear some background on why exactly you made it. It's always an amazing feeling when you stumbled upon something new like in this one!

  • @italyball2166
    @italyball2166 6 років тому +11

    I, as a 10th year student, haven't understood anything, but that give me more interest in studying maths! So, great job! It means that your videos are really interesting and that you're encouraging more young people like me to study the beauties of maths!😀

    • @A320step
      @A320step 4 місяці тому

      I am 10 too and I understand 20%😢

  • @Ricocossa1
    @Ricocossa1 6 років тому +17

    You're a genius educator, I mean it. Every single one of these videos is so carefully made. Even though I'm already familiar with most of the concepts I find myself learning. It really blows my mind.
    I just wanted to say that ^^ Congratulations for the proof!

  • @tricanico
    @tricanico 6 років тому +32

    Noo! That poor Pi creature at 3:03 became a skeleton!

    • @pranavlimaye
      @pranavlimaye 4 роки тому +7

      Rather, it got petrified! This is some Medusa-level sorcery and I shall NOT tolerate it
      #PrayForPi

  • @15october91
    @15october91 5 років тому +1

    I always have to rewind and rewatch your videos so that I’m sure I have really grasped everything that is going on. I’ve been watching your videos for a few years now and I love them!

  • @Fictionarious
    @Fictionarious Рік тому +4

    I was looking for a way to "generate" pi out of this product from scratch, so to speak, but this is the next best thing I could have possibly asked for. Your use of infinitely large circular lakes with lighthouses, observers, and light-reception-metrics to prove facts about infinite products and sums is by a significant margin the most beautiful mathematics I have ever (and probably will ever) encounter. I would love to see more of this kind of thing, even if its another video explaining another set of previously known results.

  • @Piffsnow
    @Piffsnow 6 років тому +6

    I'm blown away with every new video. I said it before and I say it again : this channel is pure youtube gold !
    Thank you, I genuinely thank you.

  • @thomasaudet1976
    @thomasaudet1976 6 років тому +3

    This is really cool, and that is not even my favorite video of yours. As you mention in the beginning, a big part of the value in your videos is attributable to the presentation and the communication of the result and I would like to say that you do a fantastic work in this matter. The representations you propose are always very insightful on top of beeing beautiful.
    In essence, thank you for the hard work and keep doing such intersesting an wonderful videos !
    (Sorry for the approximative english, hope you still get the message =) )

  • @NicholasKujawa
    @NicholasKujawa 3 роки тому

    I love how you lead me to an understanding.
    When you teach, I grok.
    The way you build up clues for me to start piecing things together is akin to being lead through the plot of a great mystery novel. You first help one to construct an intuition and then you reinforce it. This wonderfully developed skill-set you weild shows the beauty of your mind.
    Because of you (and a few other brilliant minds) I am able now to learn anything mathematical if I just think about it geometrically/trigonometrically.
    Array manipulation perceived as translation and rotation through 'N' Dimensional space has changed the way I see the world. I love you for this.
    Thank you for sharing your understandings in such a beautiful way!

  • @donnypassary5798
    @donnypassary5798 6 років тому +2

    I always had a hard time convincing to myself the infinite product representation of sin z in complex analysis class. It all make sense to me now. Thank you so much!

  • @atharvas4399
    @atharvas4399 4 роки тому +3

    Mathologer and 3Blue1Brown are honestly legends, revolutionaries. You guys change the world with every video. Absolutely amazing communicators, a skill sadly rare in higher education and complex topics. decades from now, you guys will be like the Feynman of math education. Keep up the amazing work

  • @AndriiMalenko
    @AndriiMalenko 6 років тому +20

    24:47 "=" sign is missing in 1/1^2 + 1/2^2 + ... = pi^2/6

  • @otka4al4o
    @otka4al4o 6 років тому +4

    My mind has never not been blown by this channel!

  • @omarcusmafait7202
    @omarcusmafait7202 6 років тому

    It's amazing how your videos keep getting better and better!

  • @HenrikRuep
    @HenrikRuep 6 років тому +3

    Great that you talked about the issue with limits and infinite products !

  • @atalapepperdew4254
    @atalapepperdew4254 4 роки тому +12

    Who else had no idea what he's actually talking about but can't stop watching his videos

    • @icecream6256
      @icecream6256 2 роки тому

      Yeah relatable
      Ngl highschool math is a joke compared to following his videos in real time, if i want to underatand it i would have paused, and replay the video probably 5 times

  • @AnshuKumar-oj8ww
    @AnshuKumar-oj8ww 6 років тому

    The vibes of the start of your videos are amazing! Always encourage us to be curious about mathematics.

  • @tommykornfeld2470
    @tommykornfeld2470 5 років тому +1

    I love your voice. It helps me fall asleep. You’re not boring but rather quite calming

  • @benztvshows3768
    @benztvshows3768 6 років тому +14

    Thanks ♥ for you efforts and for these amazing videos, Please we want another episodes about deep learning and Machine learning algorithms (RNN, K-means, Logistic regression, SVM/SVR, ....) ♥

  • @stephenphelps920
    @stephenphelps920 5 років тому +72

    "local mathematicians"
    i don't think my town has any

    • @mannyheffley9551
      @mannyheffley9551 4 роки тому +2

      @@lanye2708 primary school too ?

    • @yashuppot3214
      @yashuppot3214 4 роки тому +3

      @@lanye2708 most school level math teachers majored in econ or finance

    • @Pablo360able
      @Pablo360able 2 роки тому +1

      If you don't know any local mathematicians, that's because you're the local mathematician.

    • @stephenphelps920
      @stephenphelps920 2 роки тому +1

      @@Pablo360able my self-esteem is boosted

  • @ramnarayan7641
    @ramnarayan7641 6 років тому +2

    Such a wonderful presentation of this concept, something that is so abstract is explained in such a lucid, pleasant, logical and visual manner ! Way to go ! I am a big fan. Binge watching math videos first time in life :D

  • @caloz.3656
    @caloz.3656 3 роки тому

    everytime i watch a 3b1b video i always manage to get lost, then completely enlightened at the end. insane quality vids

  • @wonder9692
    @wonder9692 6 років тому +3

    It is one of the most understandibale and captivatng explanation I've ever seen. Thank you!

  • @StreuB1
    @StreuB1 6 років тому +29

    The level that I love this channel, cannot be expressed with real or imaginary numbers.
    I am 40 and a 3rd try 1st year Calculus student but the amazing thing, to me at least. Is that there are small snippets of videos like this, that I understand or look "familiar" to me in some way. I view that as my own personal mathematical enlightenment developing. Honestly, that makes me love maths even more; even though I struggle horribly with it. I have a brilliant calculus teacher who thankfully seems to have patience with me as well as the host of tutors that help me every week. I hope one day, I can look back on these videos and either expound upon them, or say "Ahh, yes. It is that way" and actually understand why.
    Thank you Grant and everyone that contributes to these visual dialog, and that includes people in the comments who push questions with more questions.

    • @catherinesanderson9298
      @catherinesanderson9298 6 років тому +1

      Did you watch his essence of calc series

    • @StreuB1
      @StreuB1 6 років тому

      I have, several times. Its amazing.

    • @topilinkala1594
      @topilinkala1594 2 роки тому

      Check Wikipedia about inaacessible cardinals if you want bigger numbers than complex numbers.

  • @huegass1650
    @huegass1650 6 років тому +304

    I’m a simple man, I see 3B1B, I click like.

    • @Super1337357
      @Super1337357 6 років тому +10

      I'm a simpler man. I see a video I like, I click like.

    • @nerdy5999
      @nerdy5999 6 років тому

      Same. No matter what.

    • @Barriertriostruckapose
      @Barriertriostruckapose 6 років тому +8

      I think if you were a simple man, you wouldn't be interested in math channels

  • @benjaminbaron3209
    @benjaminbaron3209 6 років тому

    I'm happy that firstly I had the time to watch the whole video at once and secondly it was that long. Keep it up. I keep recommending your channel.

  • @diabl2master
    @diabl2master 6 років тому +31

    I appreciate the comments about convergence of a product. I'm not an analyst, but I felt like you'd done something a bit naughty in the final steps of the proof.

    • @__-cx6lg
      @__-cx6lg 6 років тому +9

      Davy Ker
      i know, right? before he mentioned the subtleties i had assumed that the mathematics mafia would show up or something to "take care of" him

  • @46pi26
    @46pi26 6 років тому +10

    8:14
    The tau rebellion will never die

  • @agr.9410
    @agr.9410 6 років тому

    A new 3b1b video on 4/20? You never fail us

  • @wroscel
    @wroscel 6 років тому +2

    I also notice that, taken in pairs, this product is prod[ n^2 / (n^2 -1) ] for n even, and is also 2 * prod[(n^2 -1) / n^2 ] for n odd. It seems that those forms should provide a relationship to the Basel problem and thus also to sines.
    The most interesting thing to me about Euler's solution to the Basel problem is that it only uses the coefficient of one of the powers of x in the expression for the sine.

  • @apurbabiswas7218
    @apurbabiswas7218 6 років тому +3

    This video is a lot harder to digest than your previous content. But that means I get to rewatch this video multiple times until I think I get it.
    Great animations though :-)

  • @calyodelphi124
    @calyodelphi124 6 років тому +33

    I see that subtle easter eggy use of tau instead of pi to record the complex number's phase angle around the unit circle when talking about roots of unity. ;) Makes it so much easier to communicate radians relative to a complete turn of the unit circle~

    • @mjtsquared
      @mjtsquared 6 років тому +3

      B...but pi looks more beautiful. Me don’t like pi dead

    • @calyodelphi124
      @calyodelphi124 6 років тому +7

      Pi doesn't have to die. There's areas of math where it's more useful than tau. ;) I personally find myself on the side of preferring mathematical notation that is also intuitive. Using tau over pi does a lot of that where appropriate. But tau doesn't always work better than pi everywhere.

    • @agr.9410
      @agr.9410 6 років тому

      AHHHHH HERESY!!!!!

    • @Seltyk
      @Seltyk 6 років тому +5

      "tau doesn't always work better than pi everywhere"
      This. There are equations and infinite sequences that, in whatever way, simplify down to something based on pi. Say, pi^2/6 or pi/2. But then there's using rcis(theta) on the Argand plane, or simple harmonic motion in physics which makes better use of tau
      I'd say both should be in frequent use for wherever they make the most sense

    • @calyodelphi124
      @calyodelphi124 6 років тому +1

      Agreed 100% wundrweapon :)

  • @pythagorasaurusrex9853
    @pythagorasaurusrex9853 6 років тому +1

    Great video as always. The fact, that I did not understand the "keeper/sailor" idea is my fault of lack of brain mass. A very complicate proof. The one shown in a Mathologer video is more intuitive and easy. But anyway, I like the lighthouse concept a lot! Brought much insight to me.

  • @emanuellandeholm5657
    @emanuellandeholm5657 6 років тому

    Nice! I think you also almost demonstrated the gamma function reflection relation for the sine cardinal there.

  • @jbtechcon7434
    @jbtechcon7434 6 років тому +4

    Math totally aside, damn your graphics are well done. The foggy effect around those LED-palette lighthouses against a night background really pulls me in for some reason. Your graphics are very good on your other vids too, but this one made me think to pause and comment on it.

  • @UAslak
    @UAslak 6 років тому +5

    This is so good I feel equal parts joy and sadness. Joy over how great it is and sadness over how poorly math was communicated throughout all my years of studying it.

  • @maksimhashko7499
    @maksimhashko7499 6 років тому +2

    Very elegant. Thank you for your hard work!

  • @TommasoGianiorio
    @TommasoGianiorio 6 років тому +1

    Beautiful, thank you for sharing such a satisfactory result.

  • @artemonstrick
    @artemonstrick 6 років тому +3

    This is the best channel on youtube!

  • @rgbplaza5945
    @rgbplaza5945 6 років тому +3

    Your use of colour in your videos is always beautiful. Keep it up :)

  • @quanta_reletum6643
    @quanta_reletum6643 2 роки тому

    There comes a time when I'm not actually able to get what are you talkin' 'bout but still I watch it further..and I realize that I'm digesting it now!

  • @jusmirtic
    @jusmirtic 6 років тому +2

    Great Viedo (watched the unlised one), just thought I'l let you know you did a great job, as per usual. This one does take it to a new level tho :D

  • @ck7671
    @ck7671 6 років тому +14

    Everything is linked. That's awesome! Euler would have loved this video:)

  • @anantdixit3831
    @anantdixit3831 6 років тому +7

    11:59, a fancy way of dividing by zero without the universe ending. :)

  • @sanath8483
    @sanath8483 6 років тому +1

    Just came back from school, and I'm ready for more learning.

  • @richardreynolds6304
    @richardreynolds6304 6 років тому

    I recently saw your appearance on HFS with Hank Greene, I must say, you were an excellent guest! I'd love to see you collaborate with other channels more. Have a great day!

  • @jadissa3841
    @jadissa3841 6 років тому +5

    This is just.... hell, how did you get such ideas?! They're so convoluted I don't see a way for someone to 'notice them.'

    • @screwhalunderhill885
      @screwhalunderhill885 6 років тому

      that's why it's called a trained mathematician

    • @ChenfengBao
      @ChenfengBao 6 років тому +2

      Many ideas in this video that may appear convoluted to a layman is actually very "natural" to someone with a solid higher education in a math related field. You spent years playing with complex numbers and polynomials and what not, eventually they become part of your intuition.

  • @ioncasu1993
    @ioncasu1993 6 років тому +5

    How can you dislike this guy?

  • @Czeckie
    @Czeckie 6 років тому +2

    Im just doing my thesis on abelian number fields, hence lots of cyclotomic fields stuff is in play (thanks to Kronecker-Weber). I wouldn't be surprised if this was burried somewhere in the bast literature, but it is cool as heck. I would love to see more.

  • @nabeelhasan81
    @nabeelhasan81 6 років тому

    Your mathematical visualisation left me with no words how to exactly admire them, keep up the good work
    Can i make a suggestion plz bring this material to virtual reality too, like the platform of oculus go .

  • @ForteGX
    @ForteGX 6 років тому +6

    I'm glad I watched enough mathologer videos to instinctively question the commuting of limits and interweaving of infinite products. While, I can't determine when those are possible, it's still nice to know I learned something.

  • @baptistebauer99
    @baptistebauer99 6 років тому +16

    Casually gonna demostrate de Wallis product of pi and the sin formula
    Mindblowing dude, just mindblowing. Don't be scared at all to explain more, and more slowly as well. I'm always afraid of losing details. I would even recommend you to make 2-parts videos, at least I ould recommend you consider doing it. I mean, you don't make such a beautiful proof everyday...

    • @rashidisw
      @rashidisw 4 роки тому

      if you trace Wallis product step-by-step you would get impression that Pi/2 is a rational number, but that can't be because Pi is a irrational number.
      The result of Rational Number times 2 can not be an irrational number.

  • @jameswilson8270
    @jameswilson8270 6 років тому +1

    Amazing amazing video! Thank you Sweether and Grant!

  • @zuggrr
    @zuggrr 6 років тому +2

    I don't want to imagine all the work put in !

  • @BobStein
    @BobStein 6 років тому +9

    3:03 when an extra gets a part in the movie

  • @Supremebubble
    @Supremebubble 6 років тому +27

    I had to present a proof of the stirling formula last semester and the main part of it was proving the Wallis product (after you have this the rest is more or less trivial). I also had an geometrical approach based on a paper I found but it wasn't as visual as this here of course. I must say that I didn't like this as much as the Basel problem video because it was more algebraicly playing around than geometrical intuition. I also think think that this approach is a bit harder to make rigorous for a non-mathmatician audience. If I don't have a rigorous proof then I can't be sure that my intuition is correct. So this proof here is not ideal for my taste but I really like that you try to make "nice" proofs for already proven things :)
    EDIT: I just saw that the the sorce I used for my proof was the one by Johan Wästlund in the description. I of course rephrased a lot of stuff he did to make it easier to understand. I think his method is easier for everyone and could even be done in schools but the main problem is the proof is pretty boring in the middle when deriving a lot of side stuff algebraicly.

    • @OnTheThirdDay
      @OnTheThirdDay 6 років тому

      The boring parts is where you say, "Exercise!"
      And then follow it with, "Justkidding. You can read the boring derivation in the book."
      Then everyone feels like they've been sold short, but the lesson is not too uninteresting.

    • @Supremebubble
      @Supremebubble 6 років тому

      David Herrera The thing is that I did not do that at all. Like I said my proof was rigorous, no matter how small I proved every single step. I even needed an inequality with e for the final proof that is a common exercise in analysis and I sat there for quite a while trying to figure out how to make this complete but also understandable for people without a math background. As I tested it with friends I knew that my proof was pretty much that, the most difficult thing was knowing what the number e is. I personally hate leaving stuff out, I even had to reformulate the last steps because I didn‘t want to use rules about asymptotic approximations ~ that I wouldn‘t prove so I only used the definition of the ~ symbol. Like I said in the end the proof was a bit boring cause in the middle part were a lot of lemmas that I proved which made everything easier to follow but not really exciting. At the end however when I showed the geometry, how to interprete the results as circles and area and so on went cool again. If Inwould make it again I would try to think of a way to make the middle part better

    • @OnTheThirdDay
      @OnTheThirdDay 6 років тому

      I wasn't saying that you did that. It was a recommendation made in jest.

  • @jaronfeld123
    @jaronfeld123 6 років тому +2

    "When all the algebraic dust settles..." Haha that is a great term I'm definitely using this soon. I am teaching surface integrals and there can be a lot of algebra involved with taking cross-products of vectors in, say, spherical coordinates. Funny term

  • @atharvas4399
    @atharvas4399 4 роки тому

    Your music soothes my soul. my BP drops immediately and i feel happy.

  • @Masterfortinero97
    @Masterfortinero97 6 років тому +3

    I used to think imaginary and complex numbers where something stupid. How wrong I was. Now I know that even the most abstract ideas in math can allow us to find very deep and interesting relations between things

  • @yuzezhou2769
    @yuzezhou2769 6 років тому +3

    OH YES. Another 3b1b Video.

  • @zeqizhang5860
    @zeqizhang5860 6 років тому

    I wish a more standard mathematical proof was also provided alongside with the long paragraphs of discussion in the blog. Its good to provides insights on how the proofs were constructed, but there are still other technicalities underlying the proof. I know you guys defintely are capable of doing so.
    For example, another issue I am considering is that although all of the ratios are converging to its numerical limits, the speed of which they are converging is slower and slower going down the sequence, i.e. terms are not uniform convergence. I suspect that causes the interchange of the orders generate a different ''value'' for the limit, rather than "absolute convergence" you mentioned in the blog post.

  • @alexanderlevakin9001
    @alexanderlevakin9001 2 роки тому +1

    This video is part of math history now. In math books of my school-time there was "interesting fact" text insertions to make pupil more interested in a subject. In the math books of future they will give link to this video.

  • @thedutchflamingo9973
    @thedutchflamingo9973 6 років тому +11

    Am I missing something? At 12:33 when O = 1, the fraction on the left becomes 0/0, so how can you still conclude that it equals a partial sum of the geometric series?

    • @dekrain
      @dekrain 6 років тому +1

      Use calculus and its limits.

    • @mzg147
      @mzg147 6 років тому

      Just like x/x -> 1 when x->0. When you have a 0/0 limit, you just rephrase it in different way to get the solution.

    • @3blue1brown
      @3blue1brown  6 років тому +12

      Just wrote a little thing in the pinned comment to address that. Hope it helps!

    • @1998bigkiller
      @1998bigkiller 6 років тому +1

      That is a completely reasonable question. Well, I would say there are several ways you can be convinced about that fact. The first is there is no problem about the denominator being ''0'' because that was an algebraic identity, this is, a formal identity, no matter about evaluating at specific values. You need basically the fact that (I denote by P a ''pi'' letter of product) P (x-j) (with j taking values of complex n-th roots of unity distinct to 1) is equal to x^(n-1)+...+x+1. He somehow deduces this identity by dividing the whole product P (x-j) (this time including the n-th root 1) by x-1 (the factor you don't want) to get x^n-1/x-1 which is in fact the same as before. As I have mentioned, this can be just understood ad ''formal'' equalities not being worried about evaluating on a specific value. Recall that this is true even for a more general field with unity 1. When we say x^n-1/x-1 = x^(n-1)+...+x+1 ''in a formal way'' we are actually saying that x^n-1=(x^(n-1)+...+x+1)(x-1), this last identity is true even considering evaluations for complex x. This is also an equality of polynomials. Since x^n-1 = (x-1) * P (x-j) (product over j distinct to 1) we can deduce (x^(n-1)+...+x+1)(x-1)= (x-1) * P (x-j) (product over j distinct to 1) . And then just delete x-1 on both sides. Does it make sense to delete x-1 on that equation? What if x=1? Well, they are just polynomials, x-1 is an element of a ring (ring C[x] of complex polynomials) which is also an integral domain (this means the ring has unity, is commutative and, the most important property in this case, it does not have zero divisors, this is, if a and b are nonzero then ab is, too, and this is precisely the property that allows us to delete nonzero numbers on a equation of the above type, for example, if az=bz and z is nonzero then z(a-b)=0 and then a-b=0 because there aren't zero divisors, and this is the same as deleting z on the equation ;) ) and as I was saying x-1 is nonzero so that it can be cancelled on the equation. Once we have (x^(n-1)+...+x+1)=P (x-j) (product over j distinct to 1) making j=1 we get n=the desired product. One last comment, you can also understand the discussed fact by observing the smoothness of the equation. I mean, you would agree that the equation written on the video with O-1 on the denominator is true whenever O is not 1. Well, do not evaluate at O=1, but since you are tallking about polynomials then make the limit O--->1, and by the continuity of the involved functions this will behave in a good way, and so what do you get? The desired equation anyway. I hope to have been clear enough :)

    • @columbus8myhw
      @columbus8myhw 6 років тому +2

      The RHS is a polynomial that, when multiplied by x-1, gives x^N-1. There is only one polynomial like that, namely, x^{N-1}+x^{N-2}+\dots+x+1. Thus, they must be equal… for all values of x, including x=1.

  • @michaelyshong9506
    @michaelyshong9506 6 років тому +4

    Great video again!
    Just one small suggestion. I found 9:00 quite confusing at first, as I thought the distance is not simply (O-L_i) but |O-L_i|, and the magnitude of a multiplication of the former is not a multiplication of the latter. Then I did search around and found the property for complex numbers that |xy|=|x||y|. Maybe it would be helpful to note this property somewhere for people who are not that familiar w/ complex numbers.

    • @Supremebubble
      @Supremebubble 6 років тому

      The property |xy| = |x||y| has always been true for the real numbers so he probably thought that it wouldn't cause that much confusion when he also used it for complex numbers

    • @LB-qr7nv
      @LB-qr7nv 10 місяців тому

      Thank you!

  • @cbelsole
    @cbelsole 6 років тому +1

    Thanks for making these videos.

  • @giovannisimioni
    @giovannisimioni 6 років тому +1

    Beautiful proof and beautiful video. Really a great job!

  • @NirDodge
    @NirDodge 6 років тому +14

    I think it wouldn't hurt to quickly mention that the absolute value of a product is the product of absolute values also when talking about complex numbers

    • @gregoryfenn1462
      @gregoryfenn1462 5 років тому +1

      Yes I agree, although the proof of this is so easy both to state and to visualise that maybe it slipped their mind! (write z1 = n*e^(i*a), z2 = m*e^(ib), where n, m >= 0 are real magnitudes. Then z1*z2 has a magnitude of n*m -- that's half of the definition of complex multipation. the other half being the new angle of (a+b) mod_tau. Or you can manually prove it algebraically z1 = a_ib, z2 = c + id, but this doesn't seem very natural to me.)

  • @KalikiDoom
    @KalikiDoom 6 років тому +3

    AMAZING!

  • @asenlearning4831
    @asenlearning4831 8 місяців тому +1

    In all the videos I just think and at the end I realize how elegant the solution is.

  • @ejvalpey
    @ejvalpey 6 років тому

    Oh my god, this makes the Poisson Binomial distribution (distribution of total successes over N trials with independent success probabilities) and its calculation method so much more clear!

  • @steveblackplay
    @steveblackplay 6 років тому +2

    Notification squad here. Been waiting for the video to come out :)

  • @alphahelix5526
    @alphahelix5526 6 років тому +5

    I'm in love 😍 with 3B1B

  • @JustinShaw
    @JustinShaw 6 років тому +1

    Long time viewer first time commenter ;-) Thanks for the amazing math videos. I love to share them at work and at home. I was a little troubled by this proof when the distance ratios are near to halfway around the circle where the small angle approximation no longer holds. What am I missing?

  • @jackpisso1761
    @jackpisso1761 6 років тому +2

    This is an amazing video. Just one thing: I can't view this in HD because it's 60 fps and my device doesn't support that and UA-cam forces me to use 480p. I think if you upload at 30 fps more people can watch this at HD quality. In my opinion, 30 fps should be enough for nice animations. Resolution is much more important.

  • @wasabithumbs6294
    @wasabithumbs6294 2 роки тому +3

    3Blue1Brown: explains an exclusively arithmetic complex problem with a very specific solution
    Also 3Blue1Brown: so you're probably wondering how this relates to geometry

  • @benkah5055
    @benkah5055 6 років тому +3

    Great job guys :)

    • @benkah5055
      @benkah5055 6 років тому

      I can't wait to see what you guys come up with next

  • @physicalanish
    @physicalanish 6 років тому +2

    And like every other 3b1b video, THIS WAS MIND-BLOWING

  • @MTd2
    @MTd2 6 років тому

    You can also repeat the same method of physics analogy of the light house. The difference it is that the you have 1 dimension and only 1 light house. Likewise the other case, you also embed the light house in a circle, but the light will wind around the circle, similar to 2 mirrors in front of the others. Then, instead of Sailors and Keepers light house, you get a ratio between images in a mirror. So, you can relate the same problem of finding the pi with an S1 universe, with a single light house. I think you can generalize this method for finding the integers of Dirichlet eta function given the similarity to harmonic series of the arc tan. The non integer values can be compared to a diffusion rate (which is the general justification for using the physical analogy).

  • @mohammedfahmy6715
    @mohammedfahmy6715 6 років тому +64

    8:18 LONG LIVE TAU!

    • @dcs_0
      @dcs_0 6 років тому +4

      And at 6:33!

    • @awawpogi3036
      @awawpogi3036 6 років тому

      Dont be conceited if tau appears, idiots.

    • @andrewxc1335
      @andrewxc1335 6 років тому

      As stated in this year's Pi Day video, all of the Greek letters in Euler's day were just variables; it was just some one mathematician who decided that pi should be taken as a constant, based on a recurring statement by Euler: "Let pi be the ratio of the semicircumference to the radius of the given circle."

    • @looney1023
      @looney1023 4 роки тому

      This video is literally a giant proof for a pi/2 identity. Where's your tau nau?

  • @UCrafter5000
    @UCrafter5000 6 років тому +6

    I like how some people dislike the video when it’s only been up for 2 minutes and the video is 25 minutes long...

    • @N0Xa880iUL
      @N0Xa880iUL 6 років тому

      UCrafter5000 not fully true.
      On original non reuploaded video it was 235 likes and 0 dislikes. Now it has 3 dislikes already.

  • @nibblrrr7124
    @nibblrrr7124 6 років тому +1

    3Blue1Brown I think you could improve the sound quality a lot by dialing out a bit of low end + low mids (the proximity effect of your mic) with a HPF & EQ; it's a bit boomy and makes it harder to understand as is.
    Anyway, love your work!

  • @jake1996able
    @jake1996able 6 років тому +2

    Man, you do a very good job in bringing down math to an intuitive level!
    It's interesting, how math reveals all the suttle relationships between certain things, that seen to be totally separate from each other.
    Even with things in the real world.
    Like circles and infinite sums and products and their connection to physical quantities.
    Now, there still remains a question to me:
    x^N - 1 = (x - L1) ... (x - L2)
    was justified by saying, that both are equal to 0 at all the points x = L_{0 to N}.
    But how then can you generalize that to any point x on the complex plane for every N?

  • @Jorvanius
    @Jorvanius 6 років тому +5

    19:55 I didn't get that, why is the limit of the collumns 1? :/

    • @PresAhmadinejad
      @PresAhmadinejad 4 роки тому +1

      I also had to go back and rewatch this to understand what he meant. He's taking the limit of the series of numbers in each column, which will always tend to 1 for large enough N since there's only one 7 in the column. His point is that if you take the product of each column's limit of index N as N -> inf, it's not equal to the limit of the product of each column's index N (i.e. row N) as N -> inf, so the product of limits isn't equal to the limit of products.

    • @briangronberg6507
      @briangronberg6507 3 роки тому

      @@PresAhmadinejad the limit of the infinite sum of the columns tends to infinity, not 1. I’m not sure what I’m missing.

    • @PresAhmadinejad
      @PresAhmadinejad 3 роки тому

      @@briangronberg6507 he’s not taking a limit of a sum, he’s taking the limit of a series of numbers. In the first case, that series is the product of row i from i=1 to inf, and in the second case it’s simply the numbers in a given column. In the first case, the limit of those products is 7 since every number in the series is 7, and in the second case the product of the limits of those series is 1, since each column’s series tends to 1 for large enough N.

    • @briangronberg6507
      @briangronberg6507 3 роки тому

      @@PresAhmadinejad Thank you. That’s much clearer!

    • @PresAhmadinejad
      @PresAhmadinejad 3 роки тому

      @@briangronberg6507 you’re welcome!

  • @pirmelephant
    @pirmelephant 6 років тому +3

    Why is (at 19:52) the limit of 7*1*1*1*1...=1?
    That doesn't make sense to me.

    • @seanspartan2023
      @seanspartan2023 6 років тому

      Frederik Huber because for each sequence, at a certain point the sequence will be all 1's.

    • @pirmelephant
      @pirmelephant 6 років тому

      To write a limit formaly correct, it should be like for example: lim( sum of 1/2^n) for n->infinity, which is 2.
      How does the correct form of this look like?
      What goes to infinity here exactly?

    • @shahtamzid
      @shahtamzid 6 років тому +3

      Frederik Huber The limits taken vertically are not based on the products of the columns (notice the lack of dots between numbers in the vertical direction as opposed to the dots in the horizontal rows). The vertical limit is simply the value that the sequence approaches, i.e., the limit of the nth term (not the limit of partial products). Since each sequence eventually only has 1's, the limit of the nth term is 1.
      i.e., the rows are lim(Product of n terms) and the columns are lim(nth term) as n --> ∞.

    • @pirmelephant
      @pirmelephant 6 років тому

      Aha! Yeah that makes a lot more sense.
      Rewatching this I noticed I overlooked that the limit of 7, 7, 7, ... = 7, which wouldn't make sense if it was a product.
      Thanks!

    • @shacharh5470
      @shacharh5470 6 років тому

      You can view it as a sequence of functions, fn = 1*1*1.... n times * x (with x = 7 in the particular example). When n goes to infinity you "lose" the x...
      This is an example of a sequence of functions that converges pointwise but not uniformly because, as you said so yourself, at any finite n there's still a 7 there.

  • @Sciencationelle
    @Sciencationelle 6 років тому +1

    I would freaking love to be so accurate on the graphics of my videos. Yours are so awesome... Very a great job you've done here !

  • @VerSalieri
    @VerSalieri 6 років тому +1

    Great content my friend.. I wish I discovered your channel a bit sooner.