Answer to Practice Quiz Questions given in description of this video are - 1. Correct Answer 2. Wrong Answer - As bob continues projectile motion after leaving circular path, there is no angular amplitude can be defined as it is defined only in periodic motion of bob 3. Correct Answer 4. Correct Answer - As minimum speed to complete VCM at horizontal string position is √3gL = 10√3 m/s for L=10m 5. Correct Answer - As in this case effective value of g is √(a²+g²) = 10√2 m/s² so min required speed for projectile motion is √[5g(eff)L] = 18.8 m/s (In next video releasing today evening, sir will explain concept of vertical circular motion in accelerated frame)
Sir i had a doubt As the car is accelerated the bob at eqm (in frame of car) will be slightly up from the bottom most pt. So how can the min speed at that point be √(5geff*l) . √5gl would be if the bob was at bottom most point right ?? Sir or any student please help 🙏
Below are Five practice questions for students out of which in ONE question given answer is wrong. Students need to identify that question and post in comment section. 1. Find the angular amplitude of a pendulum bob of string length 5m which is horizontally projected from bottom point at speed 10m/s. What is the angular amplitude of this pendulum ? [90°] 2. In previous question no 1 if projection speed is 10√2 m/s then angular amplitude becomes approximately 130°. True or False ? [True] 3. In previous question no 2 bob follows projectile motion after leaving circular path. True or False ? [True] 4. In quetion no 1 if string length is doubled and bob is pulled aside so that string becomes horizontal and bob is projected vertically down at speed 10√3 m/s then bob will complete the vertical circular motion. True or False ? [True] 5. If pendulum of question no 1 is suspended inside a box car on one of its side vertical wall along the motion direction (not front or back wall). The box car is accelerating on a horizontal flat road at 10m/s². From equilibrium position what should be the minimum projection speed of the pendulum bob so that it can complete the vertical circular motion in frame of box car. [18.8 m/s]
In q.5 i feel it depends on which vertical wall the pendulum is suspended ..suppose it is supposed on the back side ( whose area vector is in the direction of acceleration of block ) then the pseudo force acting will not affect the net geff acting on VCM and the minimum velocity will √(5×10×5) = √250 = 15.8 Pls explain me if I am wrong
I think pim is sufficient to score well in mains and advance because these small small videos you can watch any time and no of time unlike checklist videos because they are long videos so my request is that please do not stop these pim series
SIR thank you for this video I was very confused in this topic as it was covered properly in coaching also thank you sir your way of teaching is very nice and you understand the importance of time in students life so many concepts in less time 👌👌
Sir could u also make a PiM video covering the concept of closest approach .please Thanks for your extraordinary support Your videos have made me love physics
Dear sir it's a great way to teach physics . Physics in minutes is super efficient and less time consuming. Please make more such short imp topic videos . Thankyou sir , it's really helpful and the technical team(if you have any) is just amazing. A very clear view.
a question for you all try if you can solve a rod is hinged of mass m and length l and ball of mass m is applied to it find minmum velocity to complete a circle
Sir while taking work energy theorm in very beginning why didn't u consider the potential energy of Bob at the second position ....it's equation should be mgh=1/2mv2+mgl(1-sinp) cause it has some height also ...at time 2:09 ...can u plss clarify it sir or any1
Sir applied work energy theorem ...work done by gravity = change in kinetic energy mgh= 1/2mv² You are suggesting total energy conservation..then you have to consider the potential energy of bob at starting point also. 0 + mgl = 1/2 mv² + mgl(1-sinø) 1/2 mv² = mgl - mgl(1-sinø) 1/2mv² = mgl - mgl + mglsinø 1/2mv² = mglsinø Here we have taken lsinø as h Thus...1/2mv² = mgh.
When you say work done by gravity it means ...Ui (initial PE) - Uf (final PE). It means that we have considered Potential energy of both the positions in the work done expression only. So no need to take it twice.
Sir I have a doubt Suppose the Bob is given a low speed And it oscillates in the first quadrant only Then at its amplitude when the v=0, If the string is cut down and tension becomes 0. Then the particle follows which of the following path. 1.straight downward under free fall 2.radially outwards parabolically. 3.radially inwards parabolically. I
Bro only Coaching Material and try to revise it 4-5 times After that for Physics: HCV, IRODOV, Anurag Mishra Chem: Ms Chauhan, VK Jaiswal,Vishal Joshi, Neeraj Kumar, K. Kumar Maths: Adv. problems by Balaji, Sameer Bansal Calculus
@@physicsgalaxyworld thnk u sir Sir i came to know that sir had taken booster classes a few years back Can u get me its link also It will be a great help sir
Hello sir. Please make a detailed video on self notes making or notes modification. Questions from class notes can add on self notes or notes. How to make self notes of mathematics. You are amazing teacher. I hope you helped me.
@@bangtangirl6580 see them ...make short notes ...see sirs video for that its 30 mins ....then solve book and pyq and add additional learning points to it ...do it for all chapters and keep adding mistakes done in test ...in last 7 days ...revise them seven times
If you are considering the problem in bob refrence frame than you need to apply two pseudo forces one along the radius and second along the tangent because the motion is not with uniform velocity and in bob's frame it should be at rest therefore it can't have any tangential motion. You are switching from one frame to another according to your convince which is not the right approach. The answer may be right but the method is flawed.
Sir please make a video of physics in minutes for work energy theorem of conservative and non conservative forces in RBD non sliding and trapped case please 🙏 A HUMBLE Request
Sir the answer to Q2) is wrong and therefore False, since the angular amplitude is non existent as the bob won't be able to reach the expected angular amplitude i.e. 180 degree, and stops at 130 degree and performs projectile motion. Am I Right?
Not sure if I'll get an answer from you out here after years, but the problem is that, I think Normal acceleration in semicircular oscillation here should be, or in any case should be a= v^2/l + g sin (theta) or depending on situation the sine could also be cosine but the point I want to make is that, from inertial frame of reference, to see it moving in tangential direction the normal acceleration should have something more than v^2/l as we're taking the other component to be g cos (theta) or depending on situation sine could also be used, but the Normal acceleration you talked about has got me really confusing.
The velocity in second case v=√(u^2-2gl(1-cos∅)) Is same as v=√(u^2+2as) Here u=u s=l(1-cos∅) a=-g. Hope it helps in remembering the formula. Also in first case it's same just a=+g s=lsin∅ And u=0. 😊. I am in class 9th.
Yes. Whole of JEE Main 2020 paper and JEE Advanced 2020 paper concepts were already there in our concept videos... Soon sir will make a short video explaining the mapping of this years paper que with all our concept videos and PG book series
Sir you had described pulley tension including friction too in mechanics physics galaxy book . Sir my ques. Is can our exam ask such that type of questions.?
Answers: 1: 90° 2: False, it will be 180° 3: True, delta will be 130° so it will follow projectile 4: True 5: 13.39 m/s is coming.. (if wrong Plz tell the method for solving) 😄
answer of 2nd ques is true as tension is becoming is zero at 130 angle only so bob will not go further than that. i think here ques 5 must be wrong(as other four are correct) , i am not able to solve it
@@hmmletssee3809 due to acceleration of car... You have to resolve acceleration into two components for equilibrium... Find angle theta at equilibrium then apply WET for finding Velocity May or may not be correct 🤔
Sir I think second question 's answer is wrong because it's the tension which is becoming zero at 130° not velocity as angular amplitude is point where v=0 .... Can pg please tell me in vertical wall question the horizontal acceleration of Bob will be 10 m/S2 or not
Answer to Practice Quiz Questions given in description of this video are -
1. Correct Answer
2. Wrong Answer - As bob continues projectile motion after leaving circular path, there is no angular amplitude can be defined as it is defined only in periodic motion of bob
3. Correct Answer
4. Correct Answer - As minimum speed to complete VCM at horizontal string position is √3gL = 10√3 m/s for L=10m
5. Correct Answer - As in this case effective value of g is √(a²+g²) = 10√2 m/s² so min required speed for projectile motion is √[5g(eff)L] = 18.8 m/s
(In next video releasing today evening, sir will explain concept of vertical circular motion in accelerated frame)
Thank you sir for correcting my mistakes and also clearing my doubt....
Sir 2022 ke liya plzzz video bnayo sir plzz
yes, sir , it helps a lot in building my concepts, many among these , i have done wrong
No
Sir i had a doubt
As the car is accelerated the bob at eqm (in frame of car) will be slightly up from the bottom most pt. So how can the min speed at that point be √(5geff*l) . √5gl would be if the bob was at bottom most point right ??
Sir or any student please help 🙏
Below are Five practice questions for students out of which in ONE question given answer is wrong. Students need to identify that question and post in comment section.
1. Find the angular amplitude of a pendulum bob of string length 5m which is horizontally projected from bottom point at speed 10m/s. What is the angular amplitude of this pendulum ?
[90°]
2. In previous question no 1 if projection speed is 10√2 m/s then angular amplitude becomes approximately 130°. True or False ?
[True]
3. In previous question no 2 bob follows projectile motion after leaving circular path. True or False ?
[True]
4. In quetion no 1 if string length is doubled and bob is pulled aside so that string becomes horizontal and bob is projected vertically down at speed 10√3 m/s then bob will complete the vertical circular motion. True or False ?
[True]
5. If pendulum of question no 1 is suspended inside a box car on one of its side vertical wall along the motion direction (not front or back wall). The box car is accelerating on a horizontal flat road at 10m/s². From equilibrium position what should be the minimum projection speed of the pendulum bob so that it can complete the vertical circular motion in frame of box car.
[18.8 m/s]
In q.5 i feel it depends on which vertical wall the pendulum is suspended ..suppose it is supposed on the back side ( whose area vector is in the direction of acceleration of block ) then the pseudo force acting will not affect the net geff acting on VCM and the minimum velocity will √(5×10×5) = √250 = 15.8
Pls explain me if I am wrong
@@rishikeshpandey4927 You are right, the case is valid when it is side vertical wall...
MATH QUESTION
Integral sec x by using complex number
ua-cam.com/video/0s_AvXlXT3M/v-deo.html
See one time
Answer of Q4 is incorrect.
@@rishikeshpandey4927 hi. not sure if you're still active but were you preparing for JEE?
These types of videos are really helpful sir, thanks for this and please continue this series
3:56
alpha= tan^-{ at (tangential)/ac(centripetal) }.
Do correct if I'm wrong .
I am confused by the same thing to cause I think it should be what you said
How?
Correct abso.
Its correct bro
Centripetal force is same as normal force
An/At = Ac/At
But ur wrong sab ulta kar diye ho😅
Came here with speed of light 😁😎
Yo🤟
then subscribe too with the speed of light !
@@physicsgalaxyworld I've subscribed that's why I got notified so... 😁
@@utkarshkumarjha5579 😂🙌
Same bro
4:00 aplha should be tan inverse At/An not An/At
True...
Yes
Yes
better explanation than pw,, 1 ghnte ki video dekhkar bta rha hu,, sir apne 20 minutes me sb clear kar diya thanks 🙏
@ 4:14 isnt it taninv ulta
Technology + best teacher = no need to say
Sir plz restart hybrid physics lectures because all the concept of PiM will be cover in hybrid physics lectures.
Ikr! We've all been demanding this for so long now.. I really hope Sir listens to us.
@@Yash-lm9yd I think sir should know about this what we're demanding.
Haa sir continue classes please
MATH QUESTION
Integral sec x by using complex number
ua-cam.com/video/0s_AvXlXT3M/v-deo.html
See one time
Sir alpha tan inverse a(tangential)/ a(normal) hoga na
7:43
Yes
yes
Yes
You are right
Yea same here
Sir at 7:40 alpha should be equal to tan^(-1)(tangential acceleration/normal acceleration)
Mai bhi yehi comment karne wala tha, from Reliable?
Bhai 4:02 pe bhi
Ek aur baat ki normal acc = v square by l + g sin theta hoga
Me bhi yhi comment krne aaya tha
@@TawhidCodex How bro ? Plz Explain.... I'm not getting it..
I got an amazing teacher with amazing techniques in this teaching world...
I think pim is sufficient to score well in mains and advance because these small small videos you can watch any time and no of time unlike checklist videos because they are long videos so my request is that please do not stop these pim series
@ 10:45 same sir mai bhi hindi medium ka hu UP board se par mainr aapki videos se hi padha hai aur mujhe sab samajh bhi aaya hai. Thank you sir🙏
Sir you are very good faculty and you are doing a very great job by providing free education . Hats of to you sir
SIR thank you for this video I was very confused in this topic as it was covered properly in coaching also thank you sir your way of teaching is very nice and you understand the importance of time in students life so many concepts in less time 👌👌
3:59 shouldn't alpha be =tan inv aT/aN ??
Great sir ...now I love with physics ... just because of you
Sir told that he will start doubt clearing session in physics in physics galaxy app. When will it start?
Sir could u also make a PiM video covering the concept of closest approach .please
Thanks for your extraordinary support
Your videos have made me love physics
Sir I have a question, how can we find the time period of vertical circular motion when ball has minimum velocity at the bottom?
Thank you so much sir.... You explains in a very nice way... Thank you 🙏🙏🙏
Sir in last question number 5 answer will be - 14.4
Since, using square root of (4gl) is equal to Vmin to complete rotation
the visuals really helped me understand all the cases, thank you!
NOW STARTED LOVING PENDULUM
Dear sir it's a great way to teach physics . Physics in minutes is super efficient and less time consuming. Please make more such short imp topic videos .
Thankyou sir , it's really helpful and the technical team(if you have any) is just amazing. A very clear view.
At 7:26 tan alpha ulta hona chahiye dono case mein I think 🤔
a question for you all try if you can solve a rod is hinged of mass m and length l and ball of mass m is applied to it find minmum velocity to complete a circle
How these videos are made??
Yah now video for Class 11 #Jee 2022. Also make Strategy Videos
coming up very soon!
@@physicsgalaxyworld Ok I am eagerly waiting
Sir at 3:56 angle alpha should be equal to a(tangential)/a(normal) i think so plz tell
Yes. Sir made a mistake
Sir please upload strategy video for Jee 2022 please sir.
Sir Will you be covering entire physics through "physics in minutes" before jee 2021? is it for Jee 2021 Revision
Sir laptop Konsa le
ab yeh sir thodi na batayenge... kisi technical admi se poocho jo iss field mei ho... cs ki vho badhiya bataeyga
Aman dhattarwal ki video dekh le achhi hai
Sir while taking work energy theorm in very beginning why didn't u consider the potential energy of Bob at the second position ....it's equation should be mgh=1/2mv2+mgl(1-sinp) cause it has some height also ...at time 2:09 ...can u plss clarify it sir or any1
Sir applied work energy theorem ...work done by gravity = change in kinetic energy
mgh= 1/2mv²
You are suggesting total energy conservation..then you have to consider the potential energy of bob at starting point also.
0 + mgl = 1/2 mv² + mgl(1-sinø)
1/2 mv² = mgl - mgl(1-sinø)
1/2mv² = mgl - mgl + mglsinø
1/2mv² = mglsinø
Here we have taken lsinø as h
Thus...1/2mv² = mgh.
When you say work done by gravity it means ...Ui (initial PE) - Uf (final PE). It means that we have considered Potential energy of both the positions in the work done expression only. So no need to take it twice.
Sir
I have a doubt
Suppose the Bob is given a low speed
And it oscillates in the first quadrant only
Then at its amplitude when the v=0,
If the string is cut down and tension becomes 0.
Then the particle follows which of the following path.
1.straight downward under free fall
2.radially outwards parabolically.
3.radially inwards parabolically.
I
1
Dislikers are those who dont know how to study physics .great sir
No I am angry with the buyjus ad😭
Sir you are God of physics
Your each words almost cover everything in such a small time frame
Thank you very much, sir
Please upload more and more videos
You are is bless for us.🙏🙏🙏
Thanks a lot for ur support to us all
This video is for 10 million views not for 10k views👍👍👌👌
Thanks a lot . Tremendous strategy more consepts ..... Minute time ..... God bless
Others: We have best physics material.
Ashish sir: Hold my marker.
Thanks sir clear all concept about vertical circular motion
Another concept revised
Sir should I solve numericals with exact digits or should I go for approximations?Please guide me sir
approximations
Sir alpha should be tangential acceleration upon normal acceleration
Thanks a lot, sir.
But sir I've doubt which force I should divide into two part mg or Fc??
Sir, accelerate total is tangential divided by normal, please consider at 4.04
App na ulta likha ha😇😇😇
Sir please tell which books should i solve if I am a coaching student.
Please make a jee 2022 strategy for main and advanced.
Bro only Coaching Material and try to revise it 4-5 times
After that for
Physics: HCV, IRODOV, Anurag Mishra
Chem: Ms Chauhan, VK Jaiswal,Vishal Joshi, Neeraj Kumar, K. Kumar
Maths: Adv. problems by Balaji, Sameer Bansal Calculus
Thnk u sir love you
Thnk u pg team
If possible can u plz provide me link of booster classes and fundamental classes lec taken by sir
Sure.
ua-cam.com/users/physicsgalaxy74playlists?view=50&sort=dd&shelf_id=1
ua-cam.com/users/physicsgalaxy74playlists?view=50&sort=dd&shelf_id=5
@@physicsgalaxyworld thnk u sir
Sir i came to know that sir had taken booster classes a few years back
Can u get me its link also
It will be a great help sir
Hello sir.
Please make a detailed video on self notes making or notes modification. Questions from class notes can add on self notes or notes.
How to make self notes of mathematics.
You are amazing teacher.
I hope you helped me.
MATH QUESTION
Integral sec x by using complex number
ua-cam.com/video/0s_AvXlXT3M/v-deo.html
See one time
Sir aap paugi ko kese bulate h ?
Sir 2021 ke liye lecture start kar dijiye youtube par please......
Best teacher
Sir, can we expect checklist again for jee 2021 or we have to follow 2020 checklist only? By the way thanks a lot for great content sir.
same hi toh hai ...use use karlo bro
@@AdityaBansalyt bro will you tell me how to use these checklist?
@@bangtangirl6580 see them ...make short notes ...see sirs video for that its 30 mins ....then solve book and pyq and add additional learning points to it ...do it for all chapters and keep adding mistakes done in test ...in last 7 days ...revise them seven times
@@AdityaBansalyt Bro i am not feeling confident that I will be able to do mains level question. How to solve this issue?
@@bangtangirl6580 prepare for ur state entrance then....if u r feeling so...it's much easier
If you are considering the problem in bob refrence frame than you need to apply two pseudo forces one along the radius and second along the tangent because the motion is not with uniform velocity and in bob's frame it should be at rest therefore it can't have any tangential motion. You are switching from one frame to another according to your convince which is not the right approach. The answer may be right but the method is flawed.
Sir, at 4:00 shouldn't the angle alpha be equal be arctan(at/an) and not arctan(an/at)??
yes it is... you are right.
In quick solving sir has taken its inverse...
Sir please cover system of particles and rotational motion in hybrid physics please it's a request 🙏🏻🙏🏻🙏🏻🙏🏻
Dear Ayushmaan, you can watch these from PG Concept videos!
@@physicsgalaxyworld sir who are you we don't know but plz inform ashis sir that we want hybrid physics lectures.
@@physicsgalaxyworld sir plz make block strategy for jee 2021 aspirant as the time is very less for jee Jan attempt
Sir please make a video of physics in minutes for work energy theorem of conservative and non conservative forces in RBD non sliding and trapped case please 🙏 A HUMBLE Request
Meanwhile cover it in depth from PG Concept videos:
ua-cam.com/video/WEriI0hK0lc/v-deo.html
@@physicsgalaxyworld sir when will ofline classroom classes will begain
MATH QUESTION
Integral sec x by using complex number
ua-cam.com/video/0s_AvXlXT3M/v-deo.html
See one time
Thank you sir you teach the concepts so well
Excellent
Strategy for jee 2021 please 🙏
coming up soon!
@@physicsgalaxyworld thanks
Pls upload Jee mains 2021 strategy to score atleast 200 in the remaining 90days as soon as possible
sure, subscribe and stay connected so you get notified when we do
Sir yeh btado ki physics ke liye for mains abhi kya Krna chaiya?
Aapki revision checklist+advance illustrations( Is it sufficient?)
love you sir
When will doubt solving came
Yes sir pls tell.
Due to some technical issue, it is getting delayed. We will inform you whenever it will start.
Sir hm normal force ku consider nhi kr rhe he?
Sir when this pim video will be completed...... Can it be completed before jee mains 2021 jan
Sir the answer to Q2) is wrong and therefore False, since the angular amplitude is non existent as the bob won't be able to reach the expected angular amplitude i.e. 180 degree, and stops at 130 degree and performs projectile motion. Am I Right?
I can not understand
3:54 sir i think aplha is the angle between total acc and tangential acceleration
Please correct me if i am wrong🙏🙏🙏
Correct bro
sir please make a video on calculation and manipulation techniques..
Not sure if I'll get an answer from you out here after years, but the problem is that, I think
Normal acceleration in semicircular oscillation here should be, or in any case should be
a= v^2/l + g sin (theta)
or depending on situation the sine could also be cosine but the point I want to make is that,
from inertial frame of reference, to see it moving in tangential direction the normal acceleration should have something more than v^2/l as we're taking the other component to be g cos (theta) or depending on situation sine could also be used, but the Normal acceleration you talked about has got me really confusing.
The velocity in second case v=√(u^2-2gl(1-cos∅))
Is same as v=√(u^2+2as)
Here u=u
s=l(1-cos∅)
a=-g.
Hope it helps in remembering the formula.
Also in first case it's same just a=+g
s=lsin∅
And u=0.
😊.
I am in class 9th.
Hello sir please help us to make a daily routine
Great Udayan, subscribe and stay connected
@@physicsgalaxyworld already subscribed and pressed the bell icon
Sir, which chapter of maths are important for physics olampiad?
Is jee advance level of maths sufficient for it?
Please help.
sir time kaise nikaalenege for bob to reach horizontal position agar bob ko 2√gl se horizontal se feka ?
Sir....Maine ye video...3 baar dekha muze nahi samj raha....sayad
..maine ...concept build nahi kiya hai....main phirse dekhunga ye video
Sir aap allen jaipur me aajkl bhot kam lecture le rhe ho...... Aisa kyu.....
I suggest to also watch check list video of circular motion. You can clear almost every concept of circular motion..
sir in the first pendulum case why can't we take normal acceleration of the bob to be 3g sin theta(as T=3mg sin theta )
Thank you sir🙏🙏🙏🙏
Are the checklist video's enough for jee advance??
You'd have to cover advanced illustrations too but checklist videos are an ext. important subset for JEE Adv preparation
Sir please take a look on impulse please
Thank you !
Came here in a parabolic path
Sir plz make work energy power concepts. Plz sir
sir plz.. reply
does concept video of your channel covers all JEE topics (covering all present topics asked in JEE)
Yes. Whole of JEE Main 2020 paper and JEE Advanced 2020 paper concepts were already there in our concept videos... Soon sir will make a short video explaining the mapping of this years paper que with all our concept videos and PG book series
Sir alpha angle sahi kya sir
Sir you had described pulley tension including friction too in mechanics physics galaxy book . Sir my ques. Is can our exam ask such that type of questions.?
Sir why it doesn't become projectile motion when tension force becomes zero at the top ????? Please answer sir 🙏🙏
Sir my doubt is that at 4:25 tan@=a(tangential)/a(normal) as per diagram .Isn't it?
Yes
Why in Normal acceleration gsintheta add nahi kiya 3:05
we are writing equation in radial direction (along string)
Bhai ho gaya ab mera
Main bhi adv bhi
Ab college me hu 🤣
Answers:
1: 90°
2: False, it will be 180°
3: True, delta will be 130° so it will follow projectile
4: True
5: 13.39 m/s is coming.. (if wrong Plz tell the method for solving)
😄
How did u solve 5th one
answer of 2nd ques is true as tension is becoming is zero at 130 angle only so bob will not go further than that.
i think here ques 5 must be wrong(as other four are correct) , i am not able to solve it
@@tanishqjain4109 But it is only asked what will be the angular amplitude that is alpha... 😕
@@hmmletssee3809 due to acceleration of car... You have to resolve acceleration into two components for equilibrium... Find angle theta at equilibrium then apply WET for finding Velocity
May or may not be correct 🤔
@@yathartharana7956 no in question sir has asked to complete circle what condition will we apply for this???
sir in 1st case tantheta=at/an right??
love u sir
Sir please make a short video on how to find time period in shm by both normal and energy method. It's Really Confusing
After solving sir book irodov seem too easy now in 12 2021 I will try ss krotov
Sir I think second question 's answer is wrong because it's the tension which is becoming zero at 130° not velocity as angular amplitude is point where v=0 ....
Can pg please tell me in vertical wall question the horizontal acceleration of Bob will be 10 m/S2 or not