Thanks very much for your kind words! We took a break over summer but we are about to start doing more videos to help students this year. I am glad we can help!
if the distance too short, the gradient of the ray(or the slope of line between P1 and P2 may be too steep to be drawn to determine the refraction angle which can cause unreliable result, greater the distance and the slope of the line is much more accurate
omg thank you very much... i solved mayjune10 p61 and the spring question when i measured it i got it as 28 and in the marking scheme it's 29 .... plz solve lots f papers for us pllz
I am working at trying to get as many paper 6's out as possible before your exam. Also I sent a response to the question that you asked earlier on. If you didn't get it it may be in your spam folder.
Q2 part f how is the statement supported cuz one angle is 30 and another 50, thats a huge difference or does he consider X which varies between 21 and 19?? someone pls help
You're lucky I've been looking through the comment section as I have my exam tomorrow, lol. Anyways, it appears you misunderstood the teacher's explanation. Basically, the answer didn't state that 30 and 50 together are within limits of accuracy, of course those numbers are not and they're completely different. What he means is, in our diagram we obtained an angle of beta and angle of incidence that were both 30° if you noticed. And in the other procedure with that student, they end up getting an angle of incidence and beta that are 52° and 50°, which are very close values so they're within the limits of accuracy. The question wanted proof that the angle of incidence must be equal to the angle of beta, so those two procedures, the one we did and the one the student did, prove that. We're using both of them separately as a proof and not literally linking them together because both are just separate results that prove the same thing(that the angle of incidence must be equal to the angle of beta.) Hope this helps and best of luck for whatever you need the answers for!
In Q5 it gives the variable resistor in the list of available equipment however as a general rule: a fixed resistor will help to keep the current low. A variable resistor will allow you to change the voltage and current around other objects in the circuit. A thermistor is needed if you need the resistance to go down (and current through or voltage across other components to go up) as the temperature rises and a light dependent resistor is required if you need the resistance to increase as it gets dark. In this particular example though it states that the power supply varies between 0 and 3V so you can use the power supply to change the voltage and current about the circuit. - Hope that helps and thanks for watching!
Hello Bilal Khan - I could use a fixed resistor to help keep the voltage low but it would probably be better just to use the variable resistor that is in the list of apparatus in the question. However, in this case, neither of these are necessary. The power supply is listed as 0-3V and because of this it should be possible to control the voltage directly through the power supply. If the power supply was not 0-3V (i.e. 12V) then I would have to use a resistor either variable or otherwise to ensure the voltage and current were small. Although we assume that the normal connection wires have little to no resistance we are specifically measuring the resistance of the wire samples. This means that the circuit itself is not a short circuit. This was a very good question. I hope that the answer clarifies - many thanks.
i understand the video but i dont understand the purpose of the light and transparent block experiment, could you tell why the pins are used i dont like route learning thats why i was asking even though i solve the question easily lol
The experiment just shows us how light changes direction when it passes through the block. The pins mean that we can mark 2 points on a line (it's difficult to look along the paper but we can easily line up 2 pins - like looking at posts along a fence). Then we have 2 points on a line and we can join the points to make up the line they are on.
Generally 3 is best. If you have 1sf and 1sf then 1 or 2 sf. If you have 1sf and 2sf then use 2 sf. If you have 2sf and 2sf either 2 or 3 sf. If you have 2 sf and 3 sf use 3 sf. As a general rule that will work most of the time - use 3 sf.
Excellent explanation with your very calm voice. Thanks . It gave me confidence 👍
Thanks for your support! I am very pleased I could help :)
Thank you so much for the time and effort put into these :)
Thank you very much you
I was really in a big trouble
Thanks
waiting for 2015 past papers and thank you for all your
help
You are the best! Please make more videos like this. It is very helpful for me
Thanks very much for your kind words! We took a break over summer but we are about to start doing more videos to help students this year. I am glad we can help!
THANK YOU VERY MUCH!! THIS WAS SO HELPFULL! 😃💪✌
why using a larger pin separation helps to obtain reliable results time 21:50 ??
if the distance too short, the gradient of the ray(or the slope of line between P1 and P2 may be too steep to be drawn to determine the refraction angle which can cause unreliable result, greater the distance and the slope of the line is much more accurate
omg thank you very much... i solved mayjune10 p61 and the spring question when i measured it i got it as 28 and in the marking scheme it's 29 .... plz solve lots f papers for us pllz
I am working at trying to get as many paper 6's out as possible before your exam. Also I sent a response to the question that you asked earlier on. If you didn't get it it may be in your spam folder.
Thank you so much this video is much appreciated
Q2 part f how is the statement supported cuz one angle is 30 and another 50, thats a huge difference or does he consider X which varies between 21 and 19?? someone pls help
You're lucky I've been looking through the comment section as I have my exam tomorrow, lol.
Anyways, it appears you misunderstood the teacher's explanation. Basically, the answer didn't state that 30 and 50 together are within limits of accuracy, of course those numbers are not and they're completely different.
What he means is, in our diagram we obtained an angle of beta and angle of incidence that were both 30° if you noticed. And in the other procedure with that student, they end up getting an angle of incidence and beta that are 52° and 50°, which are very close values so they're within the limits of accuracy.
The question wanted proof that the angle of incidence must be equal to the angle of beta, so those two procedures, the one we did and the one the student did, prove that. We're using both of them separately as a proof and not literally linking them together because both are just separate results that prove the same thing(that the angle of incidence must be equal to the angle of beta.)
Hope this helps and best of luck for whatever you need the answers for!
THANK YOU SO MUCH FOR THESE!
You are very welcome :-) Have a wonderful day!
what if i measure the length from the top of the clamp
how will we know if we have to use which type of resistor? and thx for the great videos
In Q5 it gives the variable resistor in the list of available equipment however as a general rule: a fixed resistor will help to keep the current low. A variable resistor will allow you to change the voltage and current around other objects in the circuit. A thermistor is needed if you need the resistance to go down (and current through or voltage across other components to go up) as the temperature rises and a light dependent resistor is required if you need the resistance to increase as it gets dark. In this particular example though it states that the power supply varies between 0 and 3V so you can use the power supply to change the voltage and current about the circuit. - Hope that helps and thanks for watching!
pls solve 2019 feb march atp paper
This helped a lot
Why didn't u draw a fixed resistor in the last question diagram?
Hello Bilal Khan - I could use a fixed resistor to help keep the voltage low but it would probably be better just to use the variable resistor that is in the list of apparatus in the question. However, in this case, neither of these are necessary. The power supply is listed as 0-3V and because of this it should be possible to control the voltage directly through the power supply. If the power supply was not 0-3V (i.e. 12V) then I would have to use a resistor either variable or otherwise to ensure the voltage and current were small. Although we assume that the normal connection wires have little to no resistance we are specifically measuring the resistance of the wire samples. This means that the circuit itself is not a short circuit. This was a very good question. I hope that the answer clarifies - many thanks.
hello can u plz help me i need some assistance with physics paper i have my exam after dayys
thank you very much for these videos ............ pllllz solve mayjune10 paper61 pllz plllz plz help me i have my exam after days
Thank You very much Sir
Thank you very much !!
Thank you for watching them!
i need some help with physics
i understand the video but i dont understand the purpose of the light and transparent block experiment, could you tell why the pins are used
i dont like route learning thats why i was asking even though i solve the question easily lol
The experiment just shows us how light changes direction when it passes through the block. The pins mean that we can mark 2 points on a line (it's difficult to look along the paper but we can easily line up 2 pins - like looking at posts along a fence). Then we have 2 points on a line and we can join the points to make up the line they are on.
thk man rlly appreciate it
atp ig tmorrow thank you
for how many s.f. should i round my answer to ????
Generally 3 is best.
If you have 1sf and 1sf then 1 or 2 sf. If you have 1sf and 2sf then use 2 sf. If you have 2sf and 2sf either 2 or 3 sf. If you have 2 sf and 3 sf use 3 sf.
As a general rule that will work most of the time - use 3 sf.
thank you so much .👍❤
Thank you so much this video is much appreciated