Applying King Property to a Complicated Integral

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  • Опубліковано 16 січ 2025

КОМЕНТАРІ • 16

  • @maximusideal
    @maximusideal 3 роки тому +7

    Wow, the way pi and ln came out in the answer was really elegant.

  • @ammarjutt359
    @ammarjutt359 3 роки тому +3

    Very well explained 👏

  • @manla8397
    @manla8397 3 роки тому +3

    My question is when we can know King property is applicable to what types of questions.

  • @thetanishkamurthy
    @thetanishkamurthy 3 роки тому +4

    Waiting for the day I can actually understand this; great video tho 😂

  • @benextinction__144
    @benextinction__144 3 роки тому +2

    A very well made video. I followed the entire process until the introduction of I. What is I and why is an entire integral "clearly equal to it"?

    • @philipyao5989
      @philipyao5989 3 роки тому +1

      At the very beginning of the video, I represented the integral he was trying to solve

    • @benextinction__144
      @benextinction__144 3 роки тому

      @@philipyao5989 ah I'm not sure how I missed that haha. Thanks for the explanation

  • @Kun_aaL
    @Kun_aaL 2 роки тому +2

    Jee aspirants be like ; Hold my beer 🍺🍺

  • @parthsoni-vl2xc
    @parthsoni-vl2xc Рік тому

    Bro please do sum example of jee advanced 😂

  • @elfingourmeto1230
    @elfingourmeto1230 2 роки тому

    wait, 1 = pi/4 ????